[Oracle 8i] How to convert a string (time stamp) into a date?

I'm having difficulty figuring out how to convert a time stamp string into a date (or possibly a number).
The time stamp is 20 positions, character (NOT NULL, CHAR(20))
in the format: YYYYMMDDHHMMSSUUUUUU
where Y = Year, M = Month, D = Day, M = Minutes, S = Seconds, and U = Microseconds
The reason I want to convert this is so that I can compare one time stamp to another (i.e. I want to be able to find the MIN(timestamp), MAX(timestamp), and do inequality comparisons).
Is this at all possible?
Thanks in advance for help on this!

Hi,
As Damorgan said, if all you want to do is find which is the earliest or latest, then you can just compare the strings: they happen to be in a format where that works.
If you need to do other things, such as compare them to today's date, or see the difference between two of your rows in days, then you have to convert them to DATEs. (There's no point in converting them to NUMBERs).
A new data type, TIMESTAMP, which handles fractions of a second, was introduced in Oracle 9.
Since you're using Oracle 8 (according to your subject line), you either have to
(1) ignore the microseconds, or
(2) use a separate NUMBER column for the microseconds.
Either way, use TO_DATE to convert the first 14 characters to a DATE:
TO_DATE ( SUBSTR (txt, 1, 14)
, 'YYYYMMDDHH24MISS'
)where txt is your CHAR column.
To convert the microseconds to a number (between 0 and 999999):
TO_NUMBER (SUBSTR (txt, 15))

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