Oracle analytic functions
Hello,
I must use the integral operator in PL/SQL.
Does anybody know if Oracle provides a PL/SQL procedure or package to apply directly the integral operator?
Or is there some package with statistics functions? E.g: Gaussian distribution?
If not, could you help me with some ideas on how to develop a procedure that calculates the integral of a function?
Thanks a lot for your help,
Martha
Martha:
Maybe it would be better to export the data to Excel and then apply the functions you want.
Just a thought.
There are ohter statistical packages (not Oracle) which you can also use once you expert the data.
Hope this helps.
Similar Messages
-
Oracle Analytic function tuning
Hi all,
Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - 64bi
PL/SQL Release 10.2.0.3.0 - Production
CORE 10.2.0.3.0 Production
TNS for IBM/AIX RISC System/6000: Version 10.2.0.3.0 - Productio
NLSRTL Version 10.2.0.3.0 - Production
I have a query which has analytic function uses large space on temporary tablespace resulting in direct path temp read and direct path temp write wait events taking too much time. Is there any way to tune such query?
Thanks in advance.user9074365 wrote:
Hi all,
Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - 64bi
PL/SQL Release 10.2.0.3.0 - Production
CORE 10.2.0.3.0 Production
TNS for IBM/AIX RISC System/6000: Version 10.2.0.3.0 - Productio
NLSRTL Version 10.2.0.3.0 - Production
I have a query which has analytic function uses large space on temporary tablespace resulting in direct path temp read and direct path temp write wait events taking too much time. Is there any way to tune such query?
With your version of Oracle, and high-volumes of data going through analytic function, it's likely that this blog note applies. You may need an upgrade or special patch. http://jonathanlewis.wordpress.com/2009/09/07/analytic-agony/
Regards
Jonathan Lewis -
Help with Oracle Analytic Function scenario
Hi,
I am new to analytic functions and was wondering if someone could help me with the data scenario below. I have a table with the following data
COLUMN A COLUMN B COLUMN C
13368834 34323021 100
13368835 34438258 50
13368834 34438258 50
13368835 34323021 100
The output I want is
COLUMN A COLUMN B COLUMN C
13368834 34323021 100
13368835 34438258 50
A simple DISTINCT won't give me the desired output so i was wondering if there is any way that I can get the result using ANALYTIC FUNCTIONS and DISTINCT ..
Any help will be greatly appreciated.
Thanks.Hi,
Welcome to the forum!
Whenever you have a question, please post your sample data in a form that people can use to re-create the problem and test their solutions.
For example:
CREATE TABLE table_x
( columna NUMBER
, columnb NUMBER
, columnc NUMBER
INSERT INTO table_x (columna, columnb, columnc) VALUES (13368834, 34323021, 100);
INSERT INTO table_x (columna, columnb, columnc) VALUES (13368835, 34438258, 50);
INSERT INTO table_x (columna, columnb, columnc) VALUES (13368834, 34438258, 50);
INSERT INTO table_x (columna, columnb, columnc) VALUES (13368835, 34323021, 100);Do you want something that works in your version or Oracle? Of course you do! So tell us which version that is.
How do you get the results that you want? Explain what each row of output represents. It looks like
the 1st row contains the 1st distinct value from each column (where "first" means descending order for columnc, and ascending order for the others),
the 2nd row contains the 2nd distinct value,
the 3rd row contains the 3rd distinct value, and so on.
If that's what you want, here's one way to get it (in Oracle 9 and up):
WITH got_nums AS
SELECT columna, columnb, columnc
, DENSE_RANK () OVER (ORDER BY columna ) AS a_num
, DENSE_RANK () OVER (ORDER BY columnb ) AS b_num
, DENSE_RANK () OVER (ORDER BY columnc DESC) AS c_num
FROM table_x
SELECT MAX (a.columna) AS columna
, MAX (b.columnb) AS columnb
, MAX (c.columnc) AS columnc
FROM got_nums a
FULL OUTER JOIN got_nums b ON b.b_num = a.a_num
FULL OUTER JOIN got_nums c ON c.c_num = COALESCE (a.a_num, b.b_num)
GROUP BY COALESCE (a.a_num, b.b_num, c.c_num)
ORDER BY COALESCE (a.a_num, b.b_num, c.c_num)
;I've been trying to find a good name for this type of query. The best I've heard so far is "Prix Fixe Query", named after the menus where you get a choice of soups (listed in one column), appetizers (in another column), main dishes (in a 3rd column), and so on. The items on the first row don't necessaily have any relationship to each other.
The solution does not assume that there are the same number of distinct items in each column.
For example, if you add this row to the sample data:
INSERT INTO table_x (columna, columnb, columnc) VALUES (13368835, 34323021, 99);which is a copy of the last row, except that there is a completely new value for columnc, then the output is:
` COLUMNA COLUMNB COLUMNC
13368834 34323021 100
13368835 34438258 99
50starting in Oracle 11, you can also do this with an unpivot-pivot query. -
Oracle Analytic Function Issue
Hi, I have created a simple table contaning 3 columns and 3 records.
Insert into MYTABLE (ID, AMOUNT, RESULT) Values (1, 1, 1);
Insert into MYTABLE (ID, AMOUNT, RESULT) Values (2, 4, 1);
Insert into MYTABLE (ID, AMOUNT, RESULT) Values (3, 7, 0);
COMMIT;
I can SUM the AMOUNT using the analytic functions as
SELECT ID, AMOUNT, RESULT, SUM(AMOUNT) OVER() as TOTAL
FROM MYTABLE;
ID AMOUNT RESULT TOTAL
1 1 1 12
2 4 1 12
3 7 0 12
What I want to be able to do is summing the AMOUNTs by RESULT in this case 0 and 1.
To get the following result, how should I rewrite the query?
ID AMOUNT RESULT TOTAL RESULT_0_TOTAL RESULT_1_TOTAL
1 1 1 12 7 5
2 4 1 12 7 5
3 7 0 12 7 5SELECT ID, AMOUNT, RESULT
, SUM(CASE WHEN RESULT = 0 THEN AMOUNT ELSE 0 END) OVER() as TOTAL_0
, SUM(CASE WHEN RESULT = 1 THEN AMOUNT ELSE 0 END) OVER() as TOTAL_1
FROM MYTABLE; -
BO4 - Oracle Analytic Function within agg_aware measure
Hi,
We can use an analytic function within idt tool and when in a measures by itself it parses ok.
However when include in an agg_aware measure it gives an ORA-00937 not a single group group function.
When create queries with the agg_aware measure behaves ok, generates sql ok and runs ok - please advise.
ThanksNice, am I coming in here to read the English docs again?
-
How to use sum analytic function in adf
Hi
jdev 11.1.1.5
oracle 11g r2
I want to use analytic function (sum,count,avg and ...) .
I see [url http://andrejusb.blogspot.co.uk/2013/02/oracle-analytic-functions-for-total-and.html]Oracle Analytic Functions for Total and Average Calculation in ADF BC
and use it in my vo and jsf page,my vo have too much record and I want to have sum in table footer on demand (because of performance) and if user do not want to see the sum in footer of table it do not calculate sum,
what is your idea?Before I read that blog I use another vo for sum but after that blog decide to use analytic fuction becuase we have some page that have to many dvt graph and table and know we use seperate vo for them and it has not good performance and too many query must run in database ,I want to have 1 vo with some analytic function for graph and tables
-
Error using Analytic function in reports
Hi,
I am trying to use Oracle analytic function (lag) in a report. But am getting the below error:
Encountered the symbol "(" when expecting one of the following:
,from into bulk
This is the code in the formula column:
function extend_lifeFormula return VARCHAR2 is
l_extend_life VARCHAR2(80);
l_life_in_months VARCHAR2(80);
l_asset_id NUMBER;
begin
SRW.REFERENCE(:P_BOOK_NAME);
SRW.REFERENCE(:ASSET_ID);
SELECT asset_id,
lag(life_in_months,1,0) over (PARTITION BY asset_id
ORDER BY transaction_header_id_in) Extend_Life
INTO l_asset_id,
l_life_in_months
FROM fa_books
WHERE book_type_code = 'US GAAP'
AND asset_id = 1;
return life_in_months;
end;
Has anyone experienced this error before? Does client pl/sql engine not support Analytic functions? The above query runs fine in SQL.
Thanks,
AshishFrom our version of 6i Reports Builder Help, I got ...
Oracle ORACLE PL/SQL V8.0.6.3.0 - Production
You may check yours. -
I have records that has repeating load dates.
I would like to pick the records that has the maximum load_dates.
My source data looks like this -
( select 60589 as C_number, to_date('01/08/2012','DD/MM/YYYY') as load_dt from dual union all
select 60768, to_date('01/08/2012','DD/MM/YYYY') from dual union all
select 60888, to_date('01/08/2012','DD/MM/YYYY') from dual union all
select 12345, to_date('01/09/2012','DD/MM/YYYY') from dual union all
select 54321, to_date('01/09/2012','DD/MM/YYYY') from dual union all
select 66666, to_date('01/10/2012','DD/MM/YYYY') from dual union all
select 55555, to_date('01/10/2012','DD/MM/YYYY') from dual)
I would like to pick records with the max load_dt that means
C_number load_dt
666666 01-Oct-12
555555 01-Oct-12
I have written an oracle analytic function but it's not working the way it should be -
My query looks like this -
select a.*
from
select
c_number,
load_dt,
max(load_dt) over (partition by load_dt) as mx_dt
from table_name
where
load_dt = mx_dt;
It returns all the rows for some reason.
Any help or guidance is highly appreciated
PJwithout analytical..
with mydata as
( select 60589 as C_number, to_date('01/08/2012','DD/MM/YYYY') as load_dt from dual union all
select 60768, to_date('01/08/2012','DD/MM/YYYY') from dual union all
select 60888, to_date('01/08/2012','DD/MM/YYYY') from dual union all
select 12345, to_date('01/09/2012','DD/MM/YYYY') from dual union all
select 54321, to_date('01/09/2012','DD/MM/YYYY') from dual union all
select 66666, to_date('01/10/2012','DD/MM/YYYY') from dual union all
select 55555, to_date('01/10/2012','DD/MM/YYYY') from dual)
select *
from mydata
where load_dt = (select max(load_dt) from mydata); -
Help - tuning analytic functions
Where can I find information on hints to speed up oracle analytic functions?
The table xyz has about 12 million rows.
The col1 / col2 combinations are effective dated and have an Active /Inactive status.
Table xyz: col1, col2, effdt, status.
Goal: I want to eliminate the col1 / col2 combinations where all rows over time have an Inactive status.
The sq I wrote looks like this:
select * from
select col1, col2,
SUM (1) OVER (PARTITION BY f.col1, f.col2 ORDER BY fcol1, f.col2) total_cnt,
SUM (CASE WHEN f.status = 'I' THEN 1 ELSE 0 END) OVER
(PARTITION BY f.col1, f.col2 ORDER BY f.col1) inactive_cnt
from table xyz f
where total_cnt > inactive_cnt
Thanks,
FrankHave a look at these standard threads:
How to post a tuning request:
HOW TO: Post a SQL statement tuning request - template posting
When your query takes too long:
When your query takes too long ... -
Replacing Oracle's FIRST_VALUE and LAST_VALUE analytical functions.
Hi,
I am using OBI 10.1.3.2.1 where, I guess, EVALUATE is not available. I would like to know alternatives, esp. to replace Oracle's FIRST_VALUE and LAST_VALUE analytical functions.
I want to track some changes. For example, there are four methods of travel - Air, Train, Road and Sea. Would like to know traveler's first method of traveling and the last method of traveling in an year. If both of them match then a certain action is taken. If they do not match, then another action is taken.
I tried as under.
1. Get Sequence ID for each travel within an year per traveler as Sequence_Id.
2. Get the Lowest Sequence ID (which should be 1) for travels within an year per traveler as Sequence_LId.
3. Get the Highest Sequence ID (which could be 1 or greater than 1) for travels within an year per traveler as Sequence_HId.
4. If Sequence ID = Lowest Sequence ID then display the method of travel as First Method of Travel.
5. If Sequence ID = Highest Sequence ID then display the method of travel as Latest Method of Travel.
6. If First Method of Travel = Latest Method of Travel then display Yes/No as Match.
The issue is cells could be blank in First Method of Travel and Last Method of Travel unless the traveler traveled only once in an year.
Using Oracle's FIRST_VALUE and LAST_VALUE analytical functions, I can get a result like
Traveler | Card Issue Date | Journey Date | Method | First Method of Travel | Last Method of Travel | Match?
ABC | 01/01/2000 | 04/04/2000 | Road | Road | Air | No
ABC | 01/01/2000 | 15/12/2000 | Air | Road | Air | No
XYZ | 01/01/2000 | 04/05/2000 | Train | Train | Train | Yes
XYZ | 01/01/2000 | 04/11/2000 | Train | Train | Train | Yes
Using OBI Answers, I am getting something like this.
Traveler | Card Issue Date | Journey Date | Method | First Method of Travel | Last Method of Travel | Match?
ABC | 01/01/2000 | 04/04/2000 | Road | Road | <BLANK> | No
ABC | 01/01/2000 | 15/12/2000 | Air | <BLANK> | Air | No
XYZ | 01/01/2000 | 04/05/2000 | Train | Train | <BLANK> | No
XYZ | 01/01/2000 | 04/11/2000 | Train | <BLANK> | Train | No
Above, for XYZ traveler the Match? clearly shows a wrong result (although somehow it's correct for traveler ABC).
Would appreciate if someone can guide me how to resolve the issue.
Many thanks,
Manoj.
Edited by: mandix on 27-Nov-2009 08:43
Edited by: mandix on 27-Nov-2009 08:47Hi,
Just to recap, in OBI 10.1.3.2.1, I am trying to find an alternative way to FIRST_VALUE and LAST_VALUE analytical functions used in Oracle. Somehow, I feel it's achievable. I would like to know answers to the following questions.
1. Is there any way of referring to a cell value and displaying it in other cells for a reference value?
For example, can I display the First Method of Travel for traveler 'ABC' and 'XYZ' for all the rows returned in the same column, respectively?
2. I tried RMIN, RMAX functions in the RDP but it does not accept "BY" clause (for example, RMIN(Transaction_Id BY Traveler) to define Lowest Sequence Id per traveler). Am I doing something wrong here? Why can a formula with "BY" clause be defined in Answers but not the RPD? The idea is to use this in Answers. This is in relation to my first question.
Could someone please let me know?
I understand that this thread that I have posted is related to something that can be done outside OBI, but still would like to know.
If anything is not clear please let me know.
Thanks,
Manoj. -
Grouping error in Oracle's analytic function PERCENTILE_CONT()
Hi,
I have a question regarding the usage of Oracle's analytic function PERCENTILE_CONT(). The underlying time data in the table is of hourly granularity and I want to fetch average, peak values for the day along with 80th percentile for that day. For the sake of clarification I am only posting relevant portion of the query.
Any idea how to rewrite the query and achieve the same objective?
SELECT TRUNC (sdd.ts) AS ts,
max(sdd.maxvalue) AS max_value, avg(sdd.avgvalue) AS avg_value,
PERCENTILE_CONT(0.80) WITHIN GROUP (ORDER BY sdd.avgvalue ASC) OVER (PARTITION BY pm.sysid,trunc(sdd.ts)) as Percentile_Cont_AVG
FROM XYZ
WHERE
XYZ
GROUP BY TRUNC (sdd.ts)
ORDER BY TRUNC (sdd.ts)
Oracle Error:
ERROR at line 5:
ORA-00979: not a GROUP BY expressionYou probably mixed up the aggregate and analytical versin of PERCENTILE_CONT.
The below should work, but i dont know if it produces the desireed results.
SELECT TRUNC (sdd.ts) AS ts,
max(sdd.maxvalue) AS max_value, avg(sdd.avgvalue) AS avg_value,
PERCENTILE_CONT(0.80) WITHIN GROUP (ORDER BY sdd.avgvalue ASC) as Percentile_Cont_AVG
FROM XYZ
sorry, what is this where clause for??
WHERE
XYZ
GROUP BY TRUNC (sdd.ts)
ORDER BY TRUNC (sdd.ts) Edited by: chris227 on 26.03.2013 05:45 -
Analytical Function in Oracle 8.1.5
I am using the following sql
select empno,ename,count(*) over()
from emp;
But it shows the error
ORA-00923: FROM keyword not found where expected
I am using Oracle 8.1.5
pls help meAnalytical function were introduced in ORACLE 8iBut only for the Enterprise Edition. If the OP has the Standard Edition they can't use Analytic functions.
Cheers, APC -
I have a situation where i have partitioned a record set. If in any of the partition on that recordset, the value of one field(field name- status) is '45' i need to order the result of that partition by- 'outdate' desc, 'receiveddate' desc and order the other partition by 'key' desc,' sequence' desc, 'outdate' desc.
So the query looks like -
select row_number() over (partition by key order by sequence) RowNo, key, seq, status, outdate, receivedate from table1 where .........
order by ????
RowNo Key Seq status outdate receiveddate
1 200 0 24 9/13/2009 9/12/2009
2 200 1 23 9/10/2009 9/09/2009
3 200 2 24 9/09/2009 9/08/2009
1 210 0 24 9/13/2009 9/12/2009
2 210 1 * 45 * 9/09/2009 9/08/2009
3 210 2 24 9/10/2009 9/09/2009
So i need to get the query that will order the first set of partition by 'key' desc,' sequence' desc, 'outdate' desc and the Second set of partition (since the status of '45' exist in second partition) by 'outdate' desc, 'receiveddate' desc .
The output of the query should look like
RowNo Key Seq status outdate receiveddate
1 200 0 24 9/13/2009 9/12/2009
2 200 1 23 9/10/2009 9/09/2009
3 200 2 24 9/09/2009 9/08/2009
1 210 0 24 9/13/2009 9/12/2009
2 210 2 24 9/10/2009 9/09/2009
3 210 1 *45 * 9/09/2009 9/08/2009
I am not sure if this is possible using Analytical function.
I would really appreciate if any one can light me on this.
Thanks in advanceHi,
Welcome to the forum!
You can use analytic functions in the ORDER BY clause.
I don't have your tables, so I'll use scott.emp to illustrate.
The following query sorts by deptno first. After that, the sort order for departments that contain at least one Salesman is:
(a) job
(b) ename
Deptno=30 happens to be the only department with a Salesman, so it is the only one sorted as above.
The other departements will be sorted by
(a) sal
(b) job
SELECT deptno
, ename
, job
, sal
FROM scott.emp
ORDER BY deptno
, CASE
WHEN COUNT ( CASE
WHEN job = 'SALESMAN'
THEN 1
END
) OVER (PARTITION BY deptno) > 0
THEN ROW_NUMBER () OVER ( PARTITION BY deptno
ORDER BY job
, ename
ELSE ROW_NUMBER () OVER ( PARTITION BY deptno
ORDER BY sal
, job
END
;Output:
. DEPTNO ENAME JOB SAL
10 MILLER CLERK 1300
10 CLARK MANAGER 2450
10 KING PRESIDENT 5000
20 SMITH CLERK 800
20 ADAMS CLERK 1100
20 JONES MANAGER 2975
20 SCOTT ANALYST 3000
20 FORD ANALYST 3000
30 JAMES CLERK 950
30 BLAKE MANAGER 2850
30 ALLEN SALESMAN 1600
30 MARTIN SALESMAN 1250
30 TURNER SALESMAN 1500
30 WARD SALESMAN 1250
In the small set of sample data you posted, the results you want can be obtained simply using
ORDER BY key
, outdate DESCI assume that's just a coincidence.
If you need help, post some sample data that really requires looking at the status column to get the right results. Post the data in some executable form, such as CREATE TABLE and INSERT statements, olr, as Salim did, a WITH clause. (Perhaps you can just add or change a couple of rows in the sample data Salim already posted.) -
Ugent: Regarding Oracle 10g Analytic functions
Hi,
EMP TABLE:
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
==================================================================
7369 SMITH CLERK 7902 12/17/1980 800 20
7499 ALLEN SALESMAN 7698 2/20/1981 1600 300 30
7521 WARD SALESMAN 7698 2/22/1981 1250 500 30
7566 JONES MANAGER 7839 4/2/1981 2975 20
7654 MARTIN SALESMAN 7698 9/28/1981 1250 1400 30
7698 BLAKE MANAGER 7839 5/1/1981 2850 30
7782 CLARK MANAGER 7839 6/9/1981 2450
7788 SCOTT ANALYST 7566 12/9/1982 3000 20
7839 KING PRESIDENT 11/17/1981 5000
7844 TURNER SALESMAN 7698 9/8/1981 1500 0 30
7876 ADAMS CLERK 7788 1/12/1983 1100 20
7900 JAMES CLERK 7698 12/3/1981 950 30
7902 FORD ANALYST 7566 12/3/1981 3000 20
7934 MILLER CLERK 7782 1/23/1982 1300
================================================================
I would like the output group by manger and the employees under that manager using analytic functions.
Output should look like:
ManagerName EMPNAME
==========================================================
KING JONES,BLAKE,CLARK
JONES SCOTT,FORD
BLAKE ALLEN,WARD,MARTIN,TURNER,JAMES
CLARK MILLER
FORD SMITH
SCOTT ADAMS
Also I would like to run this query in unix shell script in order to create a folder structure like this:
Root Folder: King -> Jones -> SCOTT -> ADAMS
-> FORD -> SMITH
-> BLAKE -> ALLEN
-> WARD
-> MARTIN
-> TURNER
-> JAMES
-> CLARK -> MILLER
On a total 14 folders should be created.
Thanks in Advance
G.Vamsi Krishna
Edited by: user10733211 on Apr 20, 2009 11:30 PMuser10633982 wrote:
hey guys can you please give your personal opinions and remarks out of this thread.
this thread is supposed to be solving query and not for chit chattingNot chit chatting and not just personal opinions, just letting you know how it works around here...
Urgent is it?
Why? Have you forgotten to do your coursework and you'll get thrown off your course if you don't hand it in today?
What makes you believe that your request for help is more important than someone else who has requested help? It's very rude to assume you are more important than somebody else, and I'm sure they would like an answer to their issue as soon as they can get one too, but they've generally been polite and not demanded that it is urgent.
Also, you assume that people giving answers are all sitting here just waiting to answer your question for you. That's not so. We're all volunteers with our own jobs to do. How dare you presume to demand our attention with urgency.
If you want help and you want it answering quickly you simply just put your issue forward and provide as much valuable information as possible.
You will find if you post on here demanding your post is urgent then most people will just ignore it, some will tell you to get lost, and some will explain to you why you shouldn't post "urgent" requests. Occasionally you may find somebody who's got nothing better to do who will actually provide you with an answer, but you really are limiting your options by not asking properly.
How can something being run against the SCOTT schema be something that is "urgent"?
For the first part of your enquiry:
SQL> ed
Wrote file afiedt.buf
1 with emps as (select ename, mgr, row_number() over (partition by mgr order by ename) as rn from emp)
2 select ename as managername
3 ,(select ltrim(sys_connect_by_path(emps.ename,','),',')
4 from emps
5 where emps.mgr = emp.empno
6 and connect_by_isleaf = 1
7 connect by rn = prior rn + 1 and mgr = prior mgr
8 start with rn = 1
9 ) as empname
10 from emp
11* where empno in (select mgr from emp)
SQL> /
MANAGERNAM EMPNAME
JONES FORD,SCOTT
BLAKE ALLEN,JAMES,MARTIN,TURNER,WARD
CLARK MILLER
SCOTT ADAMS
KING BLAKE,CLARK,JONES
FORD SMITH
6 rows selected.
SQL>As for using that output in a unix shell script to create directory structures you should consider asking in a unix forum. -
Need some kind of Analytical Function
Hi Oracle experts
I need a little help from you experts. I have a PARTY table as listed below
The existing data
Party key ID_INTERNAL EID BID
1 11111 123
1 11111 321
1 22222 321 899
1 66666 ------ 888
New records comes
I have to assign a party key to each record based on which attribute is matching
Now the situation is as new records comes.
New records comes
ID_INTERNAL EID BID
22222 555
44444 555
89898 ------ 888
If I match on ID_INTERNAL I may not be able to match ID_INTERNAL 44444 and 89898 and if I match EID or BID the same situation.
Is thera any analytical function which helps me assigning a party key to all the recoords. ALl the above records should be assigned PARTY KEY 1 only.
Please help
Thanks
RajeshJustin
My main goal is to assign a party key from existing set of records to the new records which are being selected/inserted. I have to write my algoritum in such a way that the new values should match their value in existing records.
Example
my first new record has a value of 11111 under ID_INTERNAL and in the same record it has a value of 555 under EID attribute. so based on matching algoritum for ID INTERNAL it will be assigned existing party key 1.
Similarly second new record has a value of 87777 under ID INTERNAL and has a value of 555 under EID and this ID INTERNAL does not exists in the target table. but the value of 555 is available under EID attribute so I have to write algoritum based on EID.
Now the delima is my target table is as follows
Party key PARTYID PARTYNAME
1 11111 ITSID
1 123 EID
1 321 EID
Now when new records come I have to write match algortium for ID_INTERNAL to PARTYID for Partyname='ITSID'
Once matched this record ID INTERNAL=11111 and EID =555 assigned a party key=1. So after first record the output table slooks like
Party key PARTYID PARTYNAME
1 11111 ITSID
1 123 EID
1 321 EID
1 555 EID
Same way for second new record where the values are ID_INTERNAL=87777 and EID=555. I have to write match algortium based on EID because the EID value of 555 already exists in target tabel with party key.
SO after second record the target table will look like
Party key PARTYID PARTYNAME
1 11111 ITSID
1 123 EID
1 321 EID
1 555 EID
1 87777 ITSID
So this is how I have to solve this match algoritum.
Please help me if you need any information I will be glad to provide you all.
Thanks
Regards
Rajesh
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How to disable Switch Profile and Auxilliary Metadata set on UCM checkin screen?
We are using webcenter content 11.1.1.6 with Record Management component installed on top of it While trying to checkin a new document from a normal checkin screen or from Manage attachments screen two options come at the top 'Switch Profile and Auxi
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Hello! 1.I have set a rebate agreement with a quantity scale basis. (C) 2.I created a standard order and a billing document with material #AAA for a quantity of 100 TON and 10,000 $ value. 3. In the Rebate Agreement I checked the sales volume and cou