Oracle DB: How to parse XML where element names are non-standard ?

I'm in the unfortunate situation that I have illegal XML that I would like Oracle to parse. By 'illegal' in my case is that there are element names that start with an illegal character, such as a digit. Apart from this the XML is syntactically valid.
Here is an example of the XML I have stored as a column in the database:
<schedule>
    <1stweek>
    </1stweek>
    <2ndweek>
    </2ndweek>
</schedule>Right now I'm doing text search-and-replace on the XML text before I let Oracle parse it, for example replacing '<1stweek>' with '<x1stweek>' and so on. Needless to say this is very slow.
My question is if there is a way to tell the XML parser in the Oracle DB (I'm using version 10.2) to be a bit more forgiving ? ... so that it will accept element names that start with e.g. a digit ? I know that such an option exist in some XML parsers but what about Oracle's and if so how to set the option?
And before you ask I'll answer myself: No, I'm not the one who created the non-standard XML. It is from a third-party application which I cannot change myself and cannot get the vendor to change either.
Thank you.

if you cast your clob to an xmltype then you can search and extract values based on tags.
Heres an example where the table is a clob and value is cast and I'm looking for an existing attribute_name.
Check out the Oracle XML developers Guide
select u.*
FROM preload_xml
, XMLTable(
'/ApplicationProfile/ScriptFragment' PASSING xmltype(xml)
COLUMNS name varchar2(50 char) PATH '/ScriptFragment/@Name'
) u

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Alexandre,
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i've searched on how to parse xml against xsd,dtd,etc.. without the needs of internet connection..
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javax.xml
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import java.io.IOException;
import java.net.MalformedURLException;
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Thanks a lot Sir DrClap..
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LSResourceResolver Implementation
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How to parsing xml data in sql statement??

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null

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Thank you for reading this email...
If I have a **DTD** like:
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<!ATTLIST person
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>
<!ELEMENT name ((family, given) | (given, family))>
<!ELEMENT age (#PCDATA)>
<!ELEMENT family (#PCDATA)>
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the **XML** like:
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Thank you for your help, Yo

Hi, Yo,
Thank you very much for your help. And I Wish you are there...I'm. And I plan to stay - It's sunny and warm here in Honolulu and the waves are up :)
A bit more question for dear people:
In the notes, it's mainly focus on JAXB,
1. Is that mean JAXB is most popular parser for
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2) "Tree" (e.g. DOM in JAXP, or it's better cousin JDOM): You call a parser that in one swoop creates an entire hierarchy that corresponds to the XML document. You don't get called on each tag as with SAX, you just get the root of the resulting tree. Drawback: All the nodes in the tree have the same type! You probably want to know which tags are in the document, don't you? Well, you'll have to traverse the tree and ask each node: What tag do you represent? And what are your attributes? (You get only strings in response even though your attributes often represent numbers.) Unless you want to display the tree - that's a nice application, you can do it as a tree model for JTree -, or otherwise don't care about the individual tags, DOM is not of much help, because you have to keep track where in the tree you are while you traverse it.
3) Enter JAXB (or Castor, or ...): You give it a grammar of the XML documents you want to parse, or "unmarshall" as the fashion dictates to call it. (Actually the name isn't that bad, because "parsing" focuses on the input text while "unmarshalling" focuses on the objects you get, even though I'd reason that it should be marshalling that converts into objects and unmarshalling that converts objects to something else, and not vice versa but that's just my opinion.) The JAXB compiler creates a bunch of source files each with one (or now more) class(es) (and now interfaces) that correspond to the elements/tags of your grammar. (Now "compiler" is a true jevel of a misnomer, try to explain to students that after they run the "compiler", they still need to compile the sources the "compiler" generated with the real Java compiler!). Ok, you've got these sources compiled. Now you call one single method, unmarshall() and as a result you get the root node of the hierarchy that corresponds to the XML document. Sounds like DOM, but it's much better - the objects in the resulting tree don't have all the same type, but their type depends on the tag they represent. E.g if there is the tag <ball-game> then there will be an object of type myPackage.BallGame in your data structure. It gets better, if there is <score> inside <ball-game> and you have an object ballGame (of type BallGame) that you can simply call ballGame.getScore() and you get an object of type myPackage.Score. In other words, the child tags become properties of the parent object. Even better, the attributes become properties, too, so as far as your program is concerned there is no difference whether the property value was originally a tag or an attribute. On top of that, you can tell in your schema that the property has an int value - or another primitive type (that's like that in 1.0, in the early release you'll have to do it in the additional xjs file). So this is a very natural way to explore the data structure of the XML document. Of course there are drawbacks, but they are minor: daunting complexity and, as a consequence, very steep learning curve, documentation that leaves much to reader's phantasy - read trial and error - (the user's guide is too simplicistic and the examples too primitive, e.g. they don't even tell you how to make a schema where a tag has only attributes) and reference manual that has ~200 pages full of technicalities and you have to look with magnifying glas for the really usefull stuff, huge number of generated classes, some of which you may not need at all (and in 1.0 the number has doubled because each class has an accompanying interface), etc., etc. But overall, all that pales compared to the drastically improved efficiency of the programmer's efforts, i.e. your time. The time you'll spend learning the intricacies is well spent, you'll learn it once and then it will shorten your programming time all the time you use it. It's like C and Java, Java is order of magnitude more complex, but you'd probably never be sorry you gave up C.
Of course the above essay leaves out lots and lots of detail, but I think that it touches the most important points.
A word about JAXB 1.0 vs. Early Release (EA) version. If you have time, definitively learn 1.0, they are quite different and the main advantage is that the schema combines all the info that you had to formulate in the DTD and in the xjs file when using the EA version. I suggested EA was because you had a DTD already, but in retrospect, you better start from scratch with 1.0. The concepts in 1.0 are here to stay and once your surmounted the learning curve, you'll be glad that you don't have to switch concepts.
When parser job is done,
what kind of Java Object we will get? (String,
InputStream or ...)See above, typically it's an object whose type is defined as a class (and interface in 1.0) within the sources that JABX generates. Or it can be a String or one of the primitive types - you tell the "compiler" in the schema (xjs file in EA) what you want!
2. If we want to use JAXB, we have to contain a
XJS-file? Something like:In EA, yes. In 1.0 no - it's all in the schema.
I am very new to XML, is there any simpler way to get
around them? It has already take me 4 days to find a
simple parser which give it XML and DTD, then return
to me Java objects ... I mean if that kind of parser
exists....It'll take you probably magnitude longer that that to get really familiar with JAXB, but believe me it's worth it. You'll save countless days if not weeks once you'll start developing serious software with it. How long did it take you to learn Java and it's main APIs? You'll either invest the time learning how to use the software others have written, or you invest it writing it yourself. I'll take the former any time. But it's only my opinion...
Jan

How to parse xml

Hi All
I want to parse xml document which contains more then one occurrence of particular element.
I want to get some sub elements of that element and want take action on the basis of param tag inside this sub element.
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<appender name="first" class="tempclass...">
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<filter class="">
<param name="LevelToMatch" value="sdsds" />
<param name="OtherParam" value="bla bla" />
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I want values of "File" and "LevelToMatch" for each declaired appender
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I am using DOM parser.
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hi,
i hope u need to get the attribute values, right...
if yes..create the DocumentBuilderFactory for the xml the uisng buildFactory method u will get the parser...from parser u cann go for anything....
if u r not clearly, reply where do u struck...
bye,
suryakant.

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<?xml version="1.0" encoding="utf-8" ?>
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<Rate>980,00</Rate>
<Currency>SEK</Currency>
<Description>Ett genomtrevligt rum</Description>
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<Name>Mellanrummet</Name>
<Type>Enkelrum</Type>
<NumberOfBeds>1</NumberOfBeds>
<Rate>650,00</Rate>
<Currency>SEK</Currency>
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<NumberOfBeds>3</NumberOfBeds>
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                    if (room.getName().equals("ID")) {
          System.out.println("elName.getName() = " + room.getName());
          System.out.println("elName.geText() = " + room.getText(j));
          else if (room.getName().equals("Name")) {
          System.out.println("elName.getName() = " + room.getName());
          System.out.println("elName.geText() = " + room.getText(j));
               } // end for(int j...)
          } // end if (root.getType(i)
          } //for (int i...)
The problem is that I don't know how to get the values out of the tags:
<ID>1</ID>
<Name>Rum 101</Name>
<Type>Dubbelrum</Type>
<NumberOfBeds>2</NumberOfBeds>
<Rate>980,00</Rate>
<Currency>SEK</Currency>
<Description>Ett genomtrevligt rum</Description>
It's no problem to get the value from the firsts i.e. <ID> but I don't know how to get the value from <Name> ... <Description>. I have looked att examples but I don't understand how to do this. Can someone please help me =)

okay, sorry, I only read the half of your problem ;-)
You can read the content using the getText(0) method. the 0 indicates the number of the children which you want to get. That is always a 0 because you have always just one text-children in your text-tags. The content is again a children of type text!
hth
Kay

How to parse xml file, containing image, generaged from JAX-RS connector?

Hi,
We are using JAX-RS connector and just want to call getBusinessObjects() directly using JerseyMe (basically bypassing sync engine). We have used sync engine so far and want to try as how to bypass it. The method produces the text/xml and verified the xml file in the web by giving the full url. The plan is to call the same URL from the Java Me Client using JerseyMe. When I print the bytes at the client I receive the same xml that I have seen in the web. Actually, I am passing an image that I can see in a different character format in xml (assuming this is bcos of UTF-8 encoding). I am wondering as how to parse this xml file and how to decode the "UTF-8" format? Do we need to use SGMP for this or use kxml or java me webservices spec.
I would really appreciate if somebody can answer this one.
I have been observing in this forum that SGMP team is not at all active in answering the questions. Please let us know whether Oracle is keeping this product and we can continue using SGMP1.1. Please let us know so that we can plan accordingly as we are building a product based on SGMP.

Hi Rajiv,
The client library is using org.apache.commons.codec.binary.Base64 internally. We don't have the full Commons Codec library bundled, but you can look up the javadoc for the Base64 class online. All you need to do is call Base64.decode(obj.getBytes()) on the objects you get out of the XML.
In general it isn't a good idea to depend on implementation details of the client library, but in this case, I think it is pretty safe to expect org.apache.commons.codec.binary.Base64 to remain in our library.
--Ryan

How to Parse XML into String in BPEL?

Hi,
Can anyone tell me, how can I parse XML into String?
I am taking input from File Adapter, File adapter is reading that XML.
Then in assign activity i am using XPath expression(built functions) using XMLParser(),doTranslateToNative() etc.. many functions I have tried but XML is not getting parsed into String Variable.
Please help me asap.
Thanks
Shikha

Thanks a lot Eric.
I am trying this, oraext:get-content-as-string('receiveInput_Read_InputVariable','body','/ns3:orders')
but getting this error
<bpelFault><faultType>0</faultType><subLanguageExecutionFault xmlns="http://schemas.oracle.com/bpel/extension"><part name="summary"><summary>XPath expression failed to execute. An error occurs while processing the XPath expression; the expression is oraext:get-content-as-string('receiveInput_Read_InputVariable','body','/ns3:orders'). The XPath expression failed to execute; the reason was: internal xpath error. Check the detailed root cause described in the exception message text and verify that the XPath query is correct. </summary></part><part name="code"><code>XPathExecutionError</code></part></subLanguageExecutionFault></bpelFault>

How to parse XML document with default namespace with JDOM XPath

Hi All,
I am having difficulty parsing using Saxon and TagSoup parser on a namespace html document. The relevant content of this document are as follows:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
</head>
<body>
    <div id="container">
        <div id="content">
            <table class="sresults">
                <tr>
                    <td>
                        <a href="http://www.abc.com/areas" title="Hollywood, CA">hollywood</a>
                    </td>
                    <td>
                        <a href="http://www.abc.com/areas" title="San Jose, CA">san jose</a>
                    </td>
                    <td>
                        <a href="http://www.abc.com/areas" title="San Francisco, CA">san francisco</a>
                    </td>
                    <td>
                        <a href="http://www.abc.com/areas" title="San Diego, CA">San diego</a>
                    </td>
              </tr>
</body>
</html>
Below is the relevant code snippets illustrates how I have attempted to retrieve the contents (value of <a>):
             import java.util.*;
             import org.jdom.*;
             import org.jdom.xpath.*;
             import org.saxpath.*;
             import org.ccil.cowan.tagsoup.Parser;
( 1 )       frInHtml = new FileReader("C:\\Tmp\\ABC.html");
( 2 )       brInHtml = new BufferedReader(frInHtml);
( 3 ) //    SAXBuilder saxBuilder = new SAXBuilder("org.apache.xerces.parsers.SAXParser");
( 4 )       SAXBuilder saxBuilder = new SAXBuilder("org.ccil.cowan.tagsoup.Parser");
( 5 )       org.jdom.Document jdomDocument = saxbuilder.build(brInHtml);
( 6 )       XPath xpath = XPath.newInstance("/ns:html/ns:body/ns:div[@id='container']/ns:div[@id='content']/ns:table[@class='sresults']/ns:tr/ns:td/ns:a");
( 7 )       xpath.addNamespace("ns", "http://www.w3.org/1999/xhtml");
( 8 )       java.util.List list = (java.util.List) (xpath.selectNodes(jdomDocument));
( 9 )       Iterator iterator = list.iterator();
( 10 )     while (iterator.hasNext())
( 11 )     {
( 12 )            Object object = iterator.next();
( 13 ) //         if (object instanceof Element)
( 14 ) //               System.out.println(((Element)object).getTextNormalize());
( 15 )             if (object instanceof Content)
( 16 )                   System.out.println(((Content)object).getValue());
.This program would work on the same document without the default namespace, hence, it would not be necessary to include ns prefix along in the XPath statements (line 6-7) either. Moreover, I was using org.apache.xerces.parsers.SAXParser to have successfully retrieve content of <a> from the same document without default namespace in the past.
I would like to achieve the following objectives if possible:
( i ) Exclude DTD and namespace in order to simplifying the parsing process. How this could be done?
( ii ) If this is not possible, how to include it in XPath statements (line 6-7) so that the value of <a> is picked up correctly?
( iii ) Would changing from org.apache.xerces.parsers.SAXParser to org.ccil.cowan.tagsoup.Parser make any difference as far as using XPath is concerned?
( iv ) Failing to exlude DTD, how to change the lookup of a PUBLIC DTD to a local SYSTEM one and include a local DTD for reference?
I am running JDK 1.6.0_06, Netbeans 6.1, JDOM 1.1, Saxon6-5-5, Tagsoup 1.2 on Windows XP platform.
Any assistance would be appreciated.
Thanks in advance,
Jack

Here's an example of using a custom EntityResolver with the standard DocumentBuilder provided by the JDK. The code may or may not be similar for the parsers that you're using.
import java.io.IOException;
import java.io.StringReader;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.xml.sax.EntityResolver;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
public class ParseExamples
    private final static String COMMON_XML
        = "<music>"
        +     "<artist name=\"Anderson, Laurie\">"
        +         "<album>Big Science</album>"
        +         "<album>Strange Angels</album>"
        +     "</artist>"
        +     "<artist name=\"Fine Young Cannibals\">"
        +         "<album>The Raw & The Cooked</album>"
        +     "</artist>"
        + "</music>";
    private final static String COMMON_DTD
        = "<!ELEMENT music (artist*)>"
        + "<!ELEMENT artist (album+)>"
        + "<!ELEMENT album (#PCDATA)>"
        + "<!ATTLIST artist name CDATA #REQUIRED>";
    public static void main(String[] argv)
    throws Exception
        // this version uses just a SYSTEM identifier - note that it gets turned
        // into a file: URL
        String xml = "<!DOCTYPE music SYSTEM \"bar\">"
                   + COMMON_XML;
        // this version uses both PUBLIC and SYSTEM identifiers; the SYSTEM ID
        // gets munged, the PUBLIC ID doesn't
//        String xml = "<!DOCTYPE music PUBLIC \"foo\" \"bar\">"
//                   + COMMON_XML;
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        dbf.setValidating(true);
        DocumentBuilder db = dbf.newDocumentBuilder();
        db.setEntityResolver(new EntityResolver()
            public InputSource resolveEntity(String publicId, String systemId)
                throws SAXException, IOException
                System.out.println("publicId = " + publicId);
                System.out.println("systemId = " + systemId);
                return new InputSource(new StringReader(COMMON_DTD));
        Document dom = db.parse(new InputSource(new StringReader(xml)));
        System.out.println("root element name = " + dom.getDocumentElement().getNodeName());
}

Oracle DB: How to parse XML where element names are non-standard ?

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