Oracle SQL Query

Hi
Need some help with a query
I have a table with the following records (examples)
Title     Initial     Surname     Unique_ID     AccNo_1 Pay_1          AccNo_2     Pay_2
MR     MJ     JACKSON     0002283543 4232080448 2400.00          4262784181      6802.84
MR     MJ     JACKSON     0002283543      4269248501 12000.00     4275330444 0.00
MR     TJ     HOOKER     0005236988      4275207018 5953.20          4275330710 1936.00
MR     TJ     HOOKER     0005236988      4279256421 495.00          4272126429      0.00
I need to show it as below in a query (Showing the Unique ID,Account No and Payment alone is fine as well)
Title     Initial     Surname     Unique_ID     Account_No     Payment
MR     MJ     JACKSON     0002283543     4232080448     2400.00
MR     MJ     JACKSON     0002283543      4262784181     6802.84
MR     MJ     JACKSON     0002283543 4269248501     12000.00
MR     MJ     JACKSON     0002283543      4275330444     0.00
MR     TJ     HOOKER     0005236988     4275207018     5953.20
MR     TJ     HOOKER     0005236988      4275330710     1936.00
MR     TJ     HOOKER     0005236988     4279256421     495.00
MR     TJ     HOOKER     0005236988     4272126429     0.00

SQL> SELECT SUBSTR(T_NAME,1,10) T_NAME, SUBSTR(T_ACNO,1,5)ACNO1, T_VAL, SUBSTR(T_ACNO2,1,5) ACNO2, T_VAL2 FROM TMP
  2 
SQL> /
T_NAME     ACNO1      T_VAL ACNO2     T_VAL2
ABC        1234         100 1111         200
ABC        5678         200 2222         300
DEF        1234         100 3333         400
DEF        5678         200 4444         500
SQL> SELECT SUBSTR(T_NAME,1,5) TNAME, SUBSTR(T_ACNO,1,5) TACNO, T_VAL
  2  FROM
  3  (
  4  SELECT T_NAME, T_ACNO, T_VAL
  5  FROM TMP
  6  UNION ALL
  7  SELECT T_NAME, T_ACNO2, T_VAL2
  8  FROM TMP
  9  )
10  ORDER BY 1
11  /
TNAME TACNO      T_VAL
ABC   1234         100
ABC   5678         200
ABC   1111         200
ABC   2222         300
DEF   1234         100
DEF   5678         200
DEF   3333         400
DEF   4444         500
8 rows selected.
SQL>

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    What is your expected output... The query I posted just removes them, it never replaces them with spaces..your string already has space.. if you want to remove space as well .. try this...
    SELECT TRANSLATE ('TESTING ! ABC 123 #', '-~!@#$%^*/\+:;|<>?_, ', ' ') FROM DUAL;
    Output:
    --TESTINGABC123
    Else post your expected output..
    Cheers,
    Manik.

  • A Oracle sql query is needed, please help me out

    Hi,
    I have a table similar to scott.emp table and i should get first three recently joined employees salaries according to their joined date from each deptno
    output should like this:
    deptno firstempsalary secondemplsal thirdemploysalary
    10 xxx xxx xxxx
    20 xx xx
    30 xx xxx xxxx
    40 xx
    50 xx xxxx xxx
    60 xx xx
    70 xx
    it means that 70 dept having only one employee and 20 dept having only two employees and 10 dept having more than three employees but we should get only three recently joined employees salaries from 10 dept.
    Hope this is clear .. please give me a query to get this info ..
    oracle is 10g version
    great thanks in advance.

    select deptno,
    max(case jd_rank when 1 then salary end) firstempsal,
    max(case jd_rank when 2 then salary end) secondempsal,
    max(case jd_rank when 3 then salary end) thirdempsal
    from
    (select salary, deptno, row_number() over(partition by deptno order by join_date desc) jd_rank from emp)
    group by deptno
    Problem here is what to do when employees have the same join date? This example will arbitrarily choose their order and if, for example, three employees share the same (most recent) join date then they will arbitrarily be classed as "first", "second" and "third". If four employees join at the same time, one of them will be ignored at random!
    Edited by: user10548434 on 03-Dec-2008 06:27

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