ORDER BY IN HIERARCHIAL QUERY

Cosider the following record set from the emp table.
empno ename mgr
7839 KING
7566 SCOTT 7839
7566 BLAKE 7839
7782 CLARK 7839
If I use the following hierarchial query to populate a tree in Oracle forms
I will get the result as shown below.
Query
=====
select -1, level, ename, null, ename
from emp
where empno in (7839,7566,7698,7782)
start with ename = 'KING'
connect by mgr = prior empno;
Result
======
KING
JONES
BLAKE
CLARK
Here is my problem. Though diffrent employees can work under a manager,
we have some internal rules that assigns an order to each employee who
works under a manager. This helps us in identifying who should take
charge in the absence of a manager.
I have added one column to the emp table, in order to store the order in
which the employee reports to the manager.
Now the record set becomes
empno ename mgr emp_order
7839 KING 0
7566 SCOTT 7839 1
7566 BLAKE 7839 3
7782 CLARK 7839 2
Now I want the forms tree to be displayed as shown below.
KING
JONES
CLARK
BLAKE
(In short, I want the records in a particular level to be displayed
according to a pre-defined order, rather than getting them displayed
randomly).
Which query can I use for this purpose ?
Please help....
Shibu

Hi Guys,
Thanks a lot for your suggestions.
It really works great in SQL Plus.
I am familiar with Oracle Forms and I know how to use it if I want to build a tree in Forms.
Here is my requirement. I want to build the application using Oracle Portal. I know that there is something called 'Hierarchy' available in Portal. I don't know up to what extend it gives flexibility in programatically populating the tree.
Here is the scenario. I will use the hierarchial query with CONNECT SIBLINGS BY clause to populate the a tree which will show me employees in a department hierarchially.
Eg:
KING
SCOTT
BLAKE
SMITH
Now I like to show the projects assigned to each employee, which itself can be considered as another hierarchy.
Eg of Projects hierarchy.
Projects
Development
Oracle Applications
HRMS
Support
Intranet Applications
Suppose SCOTT is working in HRMS project, the tree should show as,
KING
SCOTT
Projects
Development
Oracle Applications
HRMS
BLAKE
SMITH
I can color code the node which will distinguish between an employee and his assignments.
Is there a way to achieve it in Oracle Portal using the 'Hierarchy' or what may be the best way to go (Applet etc...) ???
Thanks in advance for your help.
Shibu

Similar Messages

Hierarchial Query 3 Levels

Hello All,
I have searched OTN and AskTom and saw many articles on hierarchial query but I just cannot seem to figure out how to apply it to my situation. Based on what I have read I do not believe CUBE or ROLLUP is the answer for this (maybe wrong..).
This data is only a small part of a much larger query used for auditing purposes, so i would need to incorporate the solution for this into the larger query.
Part of my problem is how to actual present this data in a format that would make sense to the end user, when included in a tabular (Excel) report.
I am trying to devise a way to verify that monthly payment is received for each product. In this case, some of the products are "created" under another product and then billed under a 3rd product.
To explain the table
Prod_1 - list all products
Prod_2 - lists only those products that are the parent of an item in the Prod_1 column.
Prod_3 - shows there is a relationship between an item in Prod_1 that is not in Prod_2.
There may be items in Prod_1 that have no relationship to Prod_2 or Prod_3 are those are just billed or *not getting billed BAD*
There are other cases where there is a item in Prod_2 that is the parent of one or more items in Prod_1 but not related to Prod_3 and those are billed.
There are other cases where there is a item in Prod_2 that is the parent of one or more items in Prod_1 but not related to Prod_3 and *not getting billed BAD*
For example:
+1-abcd-efgh, 3-qrst-uvwx and 5-ghij-klmn+ under Prod_1 is created under Prod_2 +1234-2f-maker-taker+ but billed under Prod_3 +87-test-789101+ at $139.11 MONTH_CHARGE.
CREATE TABLE PRODT ( design_id VARCHAR2(50), Prod_1 VARCHAR2(50), Prod_2 VARCHAR2(50), Prod_3 VARCHAR2(50), Month_Charge NUMBER );
INSERT INTO PRODT VALUES ( '8568','1-abcd-efgh', '1234-2f-maker-taker','', 0 );
INSERT INTO PRODT VALUES ( '8569','2-ijkl-mnop', '5678-3f-maker-taker','', 0 );
INSERT INTO PRODT VALUES ( '8570','3-qrst-uvwx', '1234-2f-maker-taker','', 0 );
INSERT INTO PRODT VALUES ( '8571','4-yzab-cdef', '5678-3f-maker-taker','', 0 );
INSERT INTO PRODT VALUES ( '8572','5-ghij-klmn', '1234-2f-maker-taker','', 0 );
INSERT INTO PRODT VALUES ( '9421','1234-2f-maker-taker','','87-test-789101', 0 );
INSERT INTO PRODT VALUES ( '9588','5678-3f-maker-taker','','88-test-123456', 0 );
INSERT INTO PRODT VALUES ( '2531','87-test-789101', '', '1234-2f-maker-taker',139.11 );
INSERT INTO PRODT VALUES ( '2532','88-test-123456', '','5678-3f-maker-taker', 159.45 );
INSERT INTO PRODT VALUES ( '4531','76-test-101568', '', '',145.00 );
INSERT INTO PRODT VALUES ( '3528','6-abcd-efgh', '2234-1f-maker-taker','', 0 );
INSERT INTO PRODT VALUES ( '3529','7-ijkl-mnop', '2234-1f-maker-taker','', 0 );
INSERT INTO PRODT VALUES ( '6261','2234-1f-maker-taker','','', 0 );
COMMIT; Desired Result:
Honestly - I am not sure of the best way to present it - definetly open for suggestions!
The table shows there is a relationship by Product Number, but the table does not make it clear that as in the example above that
all of the underlying products are being billed under +87-test-789101+ at $139.11 per month.
I must still show all of the Prod columns - so for my understanding Cube or Rollup is not a good fit(?).
That is what I am trying to accomplish - in other words I am getting paid for everything or not?
In my mind I see it something like this perhaps:
DESIGN_ID             PROD_1                    PROD_2                       PROD_3                    MONTH_CHARGE                BILL_INDICATOR
8569                    2-ijkl-mnop                 5678-3f-maker-taker         NULL                                 0                         ? (Not sure how to indicate
8571                    4-yzab-cdef                5678-3f-maker-taker         NULL                                 0                         what should be displayed
9588                    5678-3f-maker-taker    NULL                           88-test-123456                     0                         in this new column to make
2532                    88-test-123456          NULL                            5678-3f-maker-taker           159.45                    the Audit process simple *Help Needed*)Thanks for looking!
G
Edited by: GMoney on Aug 22, 2012 12:54 PM
Edited by: GMoney on Aug 22, 2012 12:57 PM

Frank,
I was hoping you would cross paths with this post.
I am building on a TOP N query you helped me with in another post.
As I mentioned in my an initial post, I have products that may be in a hierarchical order (or stand alone) could be billed as primary or with secondary or tertiary products that are billed under the primary. Meaning the primary would have a dollar figure associated, and may or may not have secondary or tertiary products related to it.
To explain the table
Prod_1 - list all products
Prod_2 - lists only those products that are the parent of an item in the Prod_1 column.
Prod_3 - shows there is a relationship between an item in Prod_1 that is not in Prod_2.
There may be items in Prod_1 that have no relationship to Prod_2 or Prod_3 are those are just billed or not getting billed BAD
There are other cases where there is a item in Prod_2 that is the parent of one or more items in Prod_1 but not related to Prod_3 and those are billed.
There are other cases where there is a item in Prod_2 that is the parent of one or more items in Prod_1 but not related to Prod_3 and not getting billed BAD
My business requirement is to present all of the results from the initial query as well as adding in the dollar figures from an addition query against another financial table. I need to be able to make it perfectly clear to an end user auditor that each and every product is being billed, and clearly identify the secondary or tertiary items if there are any that fall under that primary product.
My real hung up here is the presentation of the data. I can easily see the correlation between them but it is not likely an end user would.
DESIGN_ID             PROD_1                    PROD_2                       PROD_3                 MONTH_CHARGE       BILL_INDICATOR
8569                    2-ijkl-mnop                 5678-3f-maker-taker         NULL                             0              ? (Not sure how to indicate
8571                    4-yzab-cdef                5678-3f-maker-taker         NULL                             0                 what should be displayed
9588                    5678-3f-maker-taker    NULL                           88-test-123456                 0                 in this new column to make
2532                    88-test-123456          NULL                            5678-3f-maker-taker      159.45 ;          the Audit process simple *Help Needed*) Thanks for looking,
Greg

Hierarchy Query to get parent nodes?

Hi Everyone,
I want to write a hierarchy query which should give me the path starting from given node to its parents(Grand parents). below is the sample data and the output what i am expecting. and also the output what i am getting right now from my query.
CREATE TABLE RELATION (PARENT VARCHAR2(5),CHILD VARCHAR2(5) PRIMARY KEY);
--Data for the tree which starts from the root 'A'
Insert into RELATION (PARENT, CHILD) Values (NULL,'A');
Insert into RELATION (PARENT, CHILD) Values ('A', 'B');
Insert into RELATION (PARENT, CHILD) Values ('A', 'C');
Insert into RELATION (PARENT, CHILD) Values ('B', 'D');
Insert into RELATION (PARENT, CHILD) Values ('B', 'E');
Insert into RELATION (PARENT, CHILD) Values ('D', 'F');
Insert into RELATION (PARENT, CHILD) Values ('C', 'G');
--Data for the tree which starts from the root 'H'
Insert into RELATION (PARENT, CHILD) Values (NULL,'H');
Insert into RELATION (PARENT, CHILD) Values ('H', 'I');
Insert into RELATION (PARENT, CHILD) Values ('H', 'J');
Expected Output by passing values as 'F' which gives the path from bottom to up.
A<-B<-D<-F
My Query:
SELECT substr(sys_connect_by_path(child,'<-'),3)
FROM relation
WHERE connect_by_isleaf = 1
START WITH child = 'F'
CONNECT BY PRIOR parent = child
ORDER BY child;
Output of my query:
F<-D<-B<-A
I am getting the output in reverse order. i can use the reverse string function to reverse the string but the problem is the node can also contain the values like 'AC' 'BA'.. in future.
Can anyone please help me in getting the correct output.
Thank you in advance.

I like ListAgg :D
with RELATION(PARENT,CHILD) as(
select NULL,'A' from dual union all
select 'A', 'B' from dual union all
select 'A', 'C' from dual union all
select 'B', 'D' from dual union all
select 'B', 'E' from dual union all
select 'D', 'F' from dual union all
select 'C', 'G' from dual union all
select NULL,'H' from dual union all
select 'H', 'I' from dual union all
select 'H', 'J' from dual)
SELECT ListAgg(child,'<-')
within group(order by Level desc) as revPath
FROM relation
START WITH child = 'F'
CONNECT BY PRIOR parent = child;
revPath
A<-B<-D<-F

Sort siblings of a hierarchial query in oracle8i

Hi,
I have a basic hierarchial query like the following:
select *
from users_table
start with userid = user
connect by manager = prior userid
I would like to sort the employees by name under their manager. Is there an easy way to do this in Oracle8i. I cannot use the ORDER SIBLINGS BY clause until Oracle9i. Thanks for your help.

http://www.quest-pipelines.com/pipelines/plsql/archives.htm#code16

Hierarchy Query For Full Tree ?

Hi Everyone,
I want to write a hierarchy query which should give me the whole path starting from root node to each individual nodes by passing value of any individual tree member. below is the sample data and the output what i am expecting. and also the output what i am getting right now from my query.
CREATE TABLE RELATION (PARENT VARCHAR2(1),CHILD VARCHAR2(1) PRIMARY KEY);
--Data for the tree which starts from the root 'A'
Insert into RELATION (PARENT, CHILD) Values (NULL,'A');
Insert into RELATION (PARENT, CHILD) Values ('A', 'B');
Insert into RELATION (PARENT, CHILD) Values ('A', 'C');
Insert into RELATION (PARENT, CHILD) Values ('B', 'D');
Insert into RELATION (PARENT, CHILD) Values ('B', 'E');
Insert into RELATION (PARENT, CHILD) Values ('D', 'F');
Insert into RELATION (PARENT, CHILD) Values ('C', 'G');
--Data for the tree which starts from the root 'H'
Insert into RELATION (PARENT, CHILD) Values (NULL,'H');
Insert into RELATION (PARENT, CHILD) Values ('H', 'I');
Insert into RELATION (PARENT, CHILD) Values ('H', 'J');
Expected Output by passing values as 'C' which gives the whole tree where the node C is present:
A
A->B
A->C
A->B->D
A->B->E
A->C->G
A->B->D->F
My Query:
select
sys_connect_by_path(child,'->') tree
from
relation
--where (parent ='C' or child='C')
start with
parent is null
connect by
prior child = parent
order by tree;
Output of my query:
->A
->A->B
->A->B->D
->A->B->D->F
->A->B->E
->A->C
->A->C->G
->H
->H->I
->H->J
I am not able to add the condition for the query so that i can get only rows of the tree where the nod 'C' is present. i am just getting whole data from the table with all the unwanted trees.
Can anyone please help me in getting the correct output.
Thank you in advance.

odie_63 wrote:
Another solution, involving analytics : Hierarchical queries and analytic functions do not mix well together in 10g:
SQL> select * from v$version
2 /
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Prod
PL/SQL Release 10.2.0.4.0 - Production
CORE    10.2.0.4.0      Production
TNS for 32-bit Windows: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
SQL> SELECT tree
2 FROM (
3    select sys_connect_by_path(child,'->') tree,
4           max(case when child = 'C' then connect_by_root(child) end) over() root1,
5           connect_by_root(child) root2
6    from relation
7    start with parent is null
8    connect by prior child = parent
9 )
10 WHERE root1 = root2
11 ;
from relation
ERROR at line 6:
ORA-00600: internal error code, arguments: [qctcte1], [0], [], [], [], [], [], []
SQL> Although it is much better in 11g:
SQL> select * from v$version
2 /
BANNER
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
PL/SQL Release 11.2.0.1.0 - Production
CORE    11.2.0.1.0      Production
TNS for 32-bit Windows: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production
SQL> SELECT tree
2 FROM (
3    select sys_connect_by_path(child,'->') tree,
4           max(case when child = 'C' then connect_by_root(child) end) over() root1,
5           connect_by_root(child) root2
6    from relation
7    start with parent is null
8    connect by prior child = parent
9 )
10 WHERE root1 = root2
11 ;
TREE
->A
->A->B
->A->B->D
->A->B->D->F
->A->B->E
->A->C
->A->C->G
7 rows selected.
SQL> SY.

Oracle HRMS Organization Hierarchy query

Dear All,
Could any one provide me Oracle HRMS Organization Hierarchy query, please find the attachment of navigation.
and please find the following query i developed, here i am getting all hierarchies as per attachment.
SELECT distinct pose.D_PARENT_NAME , pose.org_structure_version_id,pose.organization_id_parent,
    haou2.ORGANIZATION_ID PARENT_ID_ORG,
    pose.D_CHILD_NAME
FROM   apps.per_organization_structures_v pos
       ,      apps.per_org_structure_versions posv
       ,      apps.per_org_structure_elements_v pose
       ,      apps.hr_all_organization_units   haou2
WHERE pos.name = 'PIC HR ORGANIZATION HIERARCHY'
AND    pose.D_PARENT_NAME='CHAIRMAN'
AND    pose.org_structure_version_id = posv.org_structure_version_id
AND    posv.organization_structure_id = pos.organization_structure_id
AND    haou2.organization_id = pose.organization_id_child
and    pose.D_PARENT_NAME=nvl(:P_PARENT_NAME,pose.D_PARENT_NAME)
and    pose.D_CHILD_NAME=nvl(:P_CHILD_NAME,pose.D_CHILD_NAME)
and    sysdate between posv.DATE_FROM and nvl(posv.DATE_TO,sysdate)
CONNECT BY PRIOR pose.organization_id_parent = pose.organization_id_child
can any one help me on this??
Thanks in advance..
Best Regards

Hi,
Try the following query and adapt as required for your instance (I've used Vision instance):
SELECT DISTINCT pose.d_parent_name,
pose.organization_id_parent,
pose.d_child_name,
pose.organization_id_child
FROM
per_org_structure_elements_v pose,
per_org_structure_versions posv,
per_organization_structures pos
WHERE pos.name                                       = 'Primary Reporting Hierarchy'
AND posv.version_number                              = 1
AND pos.business_group_id                            = 202
AND posv.organization_structure_id                   = pos.organization_structure_id
AND pose.org_structure_version_id                    = posv.org_structure_version_id
AND pose.business_group_id                           = pos.business_group_id
AND posv.business_group_id                           = pose.business_group_id
START WITH pose.d_parent_name                      = 'Vision Operations'
CONNECT BY NOCYCLE PRIOR pose.organization_id_child = pose.organization_id_parent
ORDER BY pose.organization_id_parent, pose.organization_id_child
HTH,
Regards,
Rajen.
P.S: Please mark response as Helpful/Correct (Answered) if it resolves or helps to resolve your issue. Thks.

Hierarchy Query

Hi All..
I have a hierarchy query with description as below
SQL> desc manager_entity;
Name                                      Null?    Type
MANAGER_ENTITY_ID               NOT NULL NUMBER
MANAGER_ENTITY_TYPE_ID      NOT NULL NUMBER
MANAGER_ENTITY_PARENT_ID                  NUMBER
CREATE_USER                          NOT NULL VARCHAR2(50)
CREATE_DATETIME                    NOT NULL DATE
LAST_UPDATE_USER                 NOT NULL VARCHAR2(50)
LAST_UPDATE_DATETIME           NOT NULL DATE
MANAGER_ENTITY_LINK_ID       NOT NULL NUMBERI got the correct relation between the parent and child using the below query
select me.manager_entity_id
,      me.manager_entity_type_id
,      me.manager_entity_parent_id
,      me.manager_entity_link_id
,      level
from manager_entity me
start with me.manager_entity_id=:p_id
connect by prior me.manager_entity_id=me.manager_entity_parent_idWhen I try to join this table with other 3 tables I’m unable to retrieve data. Description of the other 3 tables
SQL> desc manager_product;
Name                                      Null?    Type
MANAGER_PRODUCT_ID                        NOT NULL NUMBER
MANAGER_PRODUCT_NAME                      NOT NULL VARCHAR2(50)
MANAGER_ROOF_ID                           NOT NULL NUMBER
ACT_STRATEGY                                       VARCHAR2(50)
ACT_SUB_STRATEGY                                   VARCHAR2(50)
ACT_DATE_ENTERED                                   DATE
ACT_INCEPTION_DATE                                 DATE
ACT_PEER_GROUP                                     VARCHAR2(50)
BACK_OFFICE_RISK_ID                                NUMBER
AREA_ID                                            NUMBER
ACT_CREATE_DATE                                    DATE
PROCESS_STOP_DATE                                  DATE
TARGET_COMPLETION_DATE                             DATE
REVISIT_DATE                                       DATE
CREATE_USER                                        VARCHAR2(50)
CREATE_DATETIME                                    DATE
LAST_UPDATE_USER                                   VARCHAR2(50)
LAST_UPDATE_DATETIME                               DATE
SQL> desc manager_roof;
Name                                      Null?    Type
MANAGER_ROOF_ID                           NOT NULL NUMBER
MANAGER_ROOF_NAME                         NOT NULL VARCHAR2(50)
ROOF_COMPANY_ID                           NOT NULL NUMBER
CREATE_USER                                        VARCHAR2(50)
CREATE_DATETIME                                    DATE
LAST_UPDATE_USER                                   VARCHAR2(50)
LAST_UPDATE_DATETIME                               DATE
SQL> desc investment_vehicle;
Name                                      Null?    Type
INVESTMENT_VEHICLE_ID                     NOT NULL NUMBER
INVESTMENT_VEHICLE_NAME                   NOT NULL VARCHAR2(255)
INVESTMENT_VEHICLE_ARRT_NAME                       VARCHAR2(255)
INVESTIER_SYSID                                    NUMBER
INVESTIER_ID                                       VARCHAR2(100)
MANAGER_PRODUCT_ID                                 NUMBER
TRADING_STRUCTURE_TYPE_ID                          NUMBER
LEGAL_DESIGNATION_ID                               NUMBER
ADDITIONAL_INVEST_FORM_TYPE_ID                     NUMBER
INVESTMENT_VEH_CLASS_TYPE_ID                       NUMBER
ERISA_PLAN_ASSET_CATEGORY_ID                       NUMBER
SIDE_LETTER_FLAG                                   CHAR(1)
INCEPTION_DATE                                     DATE
ALLOW_ERISA_FLAG                                   CHAR(1)
ALLOW_PLAN_ASSET_FLAG                              CHAR(1)
ALLOW_US_TAXABLE_INVESTOR_FLAG                     CHAR(1)
ALLOW_OFFSHORE_INVESTOR_FLAG                       CHAR(1)
SUB_DOC_DEADLINE                                   NUMBER
WIRE_DEADLINE                                      NUMBER
DOMICILE_COUNTRY_ID                                NUMBER
CREATE_USER                                        VARCHAR2(50)
CREATE_DATETIME                                    DATE
LAST_UPDATE_USER                                   VARCHAR2(50)
LAST_UPDATE_DATETIME                               DATE
PERTRAC_DATA_VENDOR_ID                             VARCHAR2(255)
PERTRAC_DATA_VENDOR_NAME                           VARCHAR2(255)
FTS_NAME                                           VARCHAR2(255)
MATLAB_MANAGER_NAME                                VARCHAR2(255)
ACT_CO_FUND_NAME                                   VARCHAR2(255)
ACT_INVESTMENT_VEHICLE_NAME                        VARCHAR2(255)
SIDE_POCKET_PCT                                    NUMBER
MAX_ILLIQUID_PCT                                   NUMBER
CONTRIBUTION_OPENING_ID                            NUMBER
MANAGEMENT_FEE_PCT                                 NUMBER
INCENTIVE_FEE_PCT                                  NUMBER
SIDE_POCKET_NOTE                                   VARCHAR2(4000)
FTS_ID                                             NUMBERI was trying to join the other 3 tables with the main query as below..
select me.manager_entity_id
,      me.manager_entity_type_id
,      me.manager_entity_parent_id
,      me.manager_entity_link_id
,      level
from manager_entity me
,    manager_roof mr
,    manager_product mp
,    investment_vehicle iv
where me.manager_entity_link_id= mr.manager_roof_id
and   mr.manager_roof_id= mp.manager_roof_id
and   mp.manager_product_id= iv.manager_product_id
start with me.manager_entity_id=:p_id
connect by prior me.manager_entity_id=me.manager_entity_parent_idHere manager_entity_link_id of manager_entity table represents(or has) the primary key of all the other 3 table..like
Enter value for p_id: 1
old   7: start with me.manager_entity_id=&p_id
new   7: start with me.manager_entity_id=1
MANAGER_ENTITY_ID MANAGER_ENTITY_TYPE_ID MANAGER_ENTITY_PARENT_ID
MANAGER_ENTITY_LINK_ID      LEVEL
                1                   1008
                 14793          1
              263                   1009                        1
                 19695          2
              803                   1010                      263
               7031783          3
MANAGER_ENTITY_ID MANAGER_ENTITY_TYPE_ID MANAGER_ENTITY_PARENT_ID
MANAGER_ENTITY_LINK_ID      LEVEL
              804                   1010                      263
               7031782          3
              805                   1010                      263
               7031781          3The above is the output for the hierarchy query
Here the MANAGER_ENTITY_LINK_ID has values (14793, 19695, 7031783 , 7031782 , 7031781)
Where 14793 is the manager_roof_id in manager_roof_table
19695 is the manager_product_id in the manager_product table
7031783 , 7031782 , 7031781 are the investment_vehicle_id’s in the investment_vehicle table…
In the output I need to retrieve manager_roof_name, manager_product_name, investment_vehicle_name..
Thanks in advance
HTH
Edited by: user10280715 on Dec 3, 2008 11:55 AM

The reason result show as no rows selected is your first insert. If fails since column list has 3 columns while values list has 4 values. You probably missed "ORA-00913: too many values" error:
SQL> drop table manager_entity
2 /
Table dropped.
SQL> create table manager_entity(manager_entity_id number,manager_entity_type_id number,manager_entity_parent_id number,manager_entity_link_id number)
2 /
Table created.
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_link_id)
2 values(1,1008,null,14793)
3 /
insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_link_id)
ERROR at line 1:
ORA-00913: too many values
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_parent_id,manager_entity_link_id)
2 values(263, 1009, 1, 19695)
3 /
1 row created.
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_parent_id,manager_entity_link_id)
2 values(803, 1010, 263, 7031783)
3 /
1 row created.
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_parent_id,manager_entity_link_id)
2 values(804, 1010, 263, 7031782)
3 /
1 row created.
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_parent_id,manager_entity_link_id)
2 values(805, 1010, 263, 7031781)
3 /
1 row created.
SQL> drop table manager_roof
2 /
Table dropped.
SQL> create table manager_roof(manager_roof_id number,manager_roof_name varchar2(20))
2 /
Table created.
SQL> insert into manager_roof(manager_roof_id,manager_roof_name)
2 values(14793,'roof')
3 /
1 row created.
SQL> drop table manager_product
2 /
Table dropped.
SQL> create table manager_product(manager_product_id number,manager_product_name varchar2(20),manager_roof_id number)
2 /
Table created.
SQL> Insert into manager_product(manager_product_id,manager_product_name,manager_roof_id)
2 Values(19695,'product1', 14793)
3 /
1 row created.
SQL> drop table investment_vehicle
2 /
Table dropped.
SQL> create table investment_vehicle(investment_vehicle_id number,manager_product_id number,investment_vehicle_name varchar2(20))
2 /
Table created.
SQL> Insert into investment_vehicle(investment_vehicle_id,manager_product_id,investment_vehicle_name)
2 Values(7031781,19695,'inv1')
3 /
1 row created.
SQL> Insert into investment_vehicle(investment_vehicle_id,manager_product_id,investment_vehicle_name)
2 Values(7031782,19695,'inv3')
3 /
1 row created.
SQL> Insert into investment_vehicle(investment_vehicle_id,manager_product_id,investment_vehicle_name)
2 Values(7031783,19695,'inv3')
3 /
1 row created.
SQL> COMMIT
2 /
Commit complete.
SQL>
SQL> select me.manager_entity_id
2 ,      me.manager_entity_type_id
3 ,      me.manager_entity_parent_id
4 ,      me.manager_entity_link_id
5 ,      level
6 from manager_entity me
7 start with me.manager_entity_id=&p_id
8 connect by prior me.manager_entity_id=me.manager_entity_parent_id
9
SQL> /
Enter value for p_id: 1
old   7: start with me.manager_entity_id=&p_id
new   7: start with me.manager_entity_id=1
no rows selectedAs soon as you fix the error:
SQL> drop table manager_entity
2 /
Table dropped.
SQL> create table manager_entity(manager_entity_id number,manager_entity_type_id number,manager_entity_parent_id number,manager_entity_link_id number)
2 /
Table created.
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_parent_id,manager_entity_link_id)
2 values(1,1008,null,14793)
3 /
1 row created.
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_parent_id,manager_entity_link_id)
2 values(263, 1009, 1, 19695)
3 /
1 row created.
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_parent_id,manager_entity_link_id)
2 values(803, 1010, 263, 7031783)
3 /
1 row created.
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_parent_id,manager_entity_link_id)
2 values(804, 1010, 263, 7031782)
3 /
1 row created.
SQL> insert into manager_entity(manager_entity_id,manager_entity_type_id,manager_entity_parent_id,manager_entity_link_id)
2 values(805, 1010, 263, 7031781)
3 /
1 row created.
SQL> drop table manager_roof
2 /
Table dropped.
SQL> create table manager_roof(manager_roof_id number,manager_roof_name varchar2(20))
2 /
Table created.
SQL> insert into manager_roof(manager_roof_id,manager_roof_name)
2 values(14793,'roof')
3 /
1 row created.
SQL> drop table manager_product
2 /
Table dropped.
SQL> create table manager_product(manager_product_id number,manager_product_name varchar2(20),manager_roof_id number)
2 /
Table created.
SQL> Insert into manager_product(manager_product_id,manager_product_name,manager_roof_id)
2 Values(19695,'product1', 14793)
3 /
1 row created.
SQL> drop table investment_vehicle
2 /
Table dropped.
SQL> create table investment_vehicle(investment_vehicle_id number,manager_product_id number,investment_vehicle_name varchar2(20))
2 /
Table created.
SQL> Insert into investment_vehicle(investment_vehicle_id,manager_product_id,investment_vehicle_name)
2 Values(7031781,19695,'inv1')
3 /
1 row created.
SQL> Insert into investment_vehicle(investment_vehicle_id,manager_product_id,investment_vehicle_name)
2 Values(7031782,19695,'inv3')
3 /
1 row created.
SQL> Insert into investment_vehicle(investment_vehicle_id,manager_product_id,investment_vehicle_name)
2 Values(7031783,19695,'inv3')
3 /
1 row created.
SQL> COMMIT
2 /
Commit complete.
SQL>
SQL> select me.manager_entity_id
2 ,      me.manager_entity_type_id
3 ,      me.manager_entity_parent_id
4 ,      me.manager_entity_link_id
5 ,      level
6 from manager_entity me
7 start with me.manager_entity_id=&p_id
8 connect by prior me.manager_entity_id=me.manager_entity_parent_id
9
SQL> /
Enter value for p_id: 1
old   7: start with me.manager_entity_id=&p_id
new   7: start with me.manager_entity_id=1
MANAGER_ENTITY_ID MANAGER_ENTITY_TYPE_ID MANAGER_ENTITY_PARENT_ID MANAGER_ENTITY_LINK_ID      LEVEL
                1                   1008                                           14793          1
              263                   1009                        1                  19695          2
              803                   1010                      263                7031783          3
              804                   1010                      263                7031782          3
              805                   1010                      263                7031781          3
SQL> SY.

Parameter for ORDER BY in DAX query not respected

I have an SSRS table fed by a parameterized DAX query (utilizing the methods in
thesearticles). I have all of my parameters working just fine except for those feeding my closing ORDER BY statement (I am offloading the sorting
to the Tabular for several reasons, including a large tested performance gain over sorting in SSRS). I have defined the ORDER BY as follows:
ORDER BY @Order1, @Order2, @Order3, @Order4
I cannot get even the first parameter to work. I can pass arbitrary strings with no impact on the report returned, though if I hard code the ORDER BY in the query, the ordering is respected, so I know this is a problem with the parameter.
Running a Profiler trace on the server when I fire the SSRS report returns the following as the parameter value for @Order1:
<Parameter>
<Name>Order1</Name>
<Value xsi:type="xsd:string">Dimuser[UserID-Name]</Value>
This is exactly what I want to replace @Order1, and when I hard code that exact string into my query I get the behavior I want.
I have played with \ escaping the brackets to no avail.
Any insight is greatly appreciated.

I have discovered a workable solution to my own problem.
The parameter is passed and interpreted as a quoted string, rather than as a field name.
I altered my query to follow this general format:
ORDER BY
SWITCH( TRUE()
, @Order1 = "User", DimUser[UserID-Name]
, SWITCH( TRUE()
, @Order2 = "User", DimUser[UserID-Name]
In this way I am comparing two quoted strings for equality and providing an unquoted field identifier that Tabular recognizes and can order by.

Group by order by in same query

Hi,
I am wondering whether it is possible to use group by and order by in same query
For example if i have a table like the one below
Col1 Col2 col3
C 36 2
A 25 5
B 12 8
A 25 6
B 12 9
C 36 1
A 25 7
I need a result like below
A 25 5
A 25 6
A 25 7
B 12 8
B 12 9
C 36 1
C 36 2
can the select statement with group by and order by solve this? How?

Yes you can - though I am not sure that it is what you want. In your example you do not need to group the data, you just need to order by the first column, then the third. If required, you could also throw in the second column;
SQL> with t as (
   select 'C' col1, 36 col2, 2 col3 from dual union all
   select 'A', 25 ,5 from dual union all
   select 'B', 12 ,8 from dual union all
   select 'A', 25 ,6 from dual union all
   select 'B', 12 ,9 from dual union all
   select 'C', 36 ,1 from dual union all
   select 'A', 25 ,7 from dual)
select col1,col2,col3
from t
order by col1,col3
COL1       COL2       COL3
A            25          5
A            25          6
A            25          7
B            12          8
B            12          9
C            36          1
C            36          2

Need Hierarchial Query

Hi All,
I have below tables,
Tables
1 Employees Type (Tells About Employees Designation)
2.Employee Details (Tells Employee Details)
3.Employee Relation (Tells Relationship between Employees)
Hierarchy
ARC (SENIOR MANAGER)
SUN (MANAGER)
MOON (TECH LEAD)
LITE (EMPLOYEE)
RAG (TECH LEAD)
BESH (TECH LEAD)
CHESH (EMPLOYEE)
PRASAD (EMPLOYEE)
1 Employees Type Data
Type No||Type Name
1|Employee
2|Tech Lead
3|Manager
4|Senior Manager
2.Employee Details
Emp No||Emp Name|Employee Type
10|ARC|4
20|SUN|3
30|RAG|2
40|PRASAD|1
50|MOON|2
60|LITE|1
70|CHESH|1
80|BESH|2
3. Employee Relation
Relation Number|Emp No|Prnt_Relation Number
1|10|NULL
2|20|1
3|30|1
4|40|1
5|50|2
6|60|2
7|70|3
8|80|3
These are my tables structure,
Now I want Hierarchial Query for below,
Input will be Relation Number,
if I give relation number as input I want to display all immediate childern that are Tech Leads and Employees only (it should ignore if it is having any Managers in the result set)
Ex: -
Input is relation number from Employee Relation Table,
If I give input as *1*
Output Should be,
Relation Number|Employee_id|Employee Name
3|30|Rag
7|70|Besh
8|80|Chesh
If I give input as *2*
Output Should be,
Relation Number|Employee_id|Employee Name
5|50|MOON
6|60|LITE,
If I give input as *4*
Output Should be,
Relation Number|Employee_id|Employee Name
<NO Rows Returned>
Thanks,

Hi,
with emp_type as ( select 1 type_id, 'Employee' emp_type from dual
union
                    select 2 type_id, 'Tech Lead' emp_type from dual
union
                    select 3 type_id, 'Manager' emp_type from dual
union
                    select 4 type_id, 'Senior Manager' emp_type from dual),
emp_details as (   select 10 emp_no, 'ARC' fname, 4 type1 from dual
union
                        select 20 emp_no, 'SUN' fname, 3 type1 from dual
union
                        select 30 emp_no, 'RAG' fname, 2 type1 from dual
union
                        select 40 emp_no, 'PRASAD' fname, 1 type1 from dual
union
                        select 50 emp_no, 'MOON' fname, 2 type1 from dual
union
                        select 60 emp_no, 'LITE' fname, 1 type1 from dual
union
                        select 70 emp_no, 'CHESH' fname, 1 type1 from dual
union
                        select 80 emp_no, 'BESH' fname, 2 type1 from dual),
Emp_Relation as (
select 1 Relation, 10 emp_no1, null parent_Relation from dual
union
select 2 Relation, 20 emp_no1, 1 parent_Relation from dual
union
select 3 Relation, 30 emp_no1, 1 parent_Relation from dual
union
select 4 Relation, 40 emp_no1, 1 parent_Relation from dual
union
select 5 Relation, 50 emp_no1, 2 parent_Relation from dual
union
select 6 Relation, 60 emp_no1, 2 parent_Relation from dual
union
select 7 Relation, 70 emp_no1, 3 parent_Relation from dual
union
select 8 Relation, 80 emp_no1, 8 parent_Relation from dual)
select type_id, emp_type,
        emp_no, fname, relation, parent_relation
from    EMP_DETAILS, EMP_TYPE, EMP_RELATION
WHERE   TYPE_ID = type1
AND     EMP_NO = EMP_NO1
AND     LEVEL = 2
CONNECT BY PRIOR RELATION = PARENT_RELATION
START WITH RELATION = :P_RELATION
--START WITH PARENT_RELATION IS NULL -- If want to display the complete heirarchy remove comments for this line and remove "and level = 2" and "START WITH RELATION = :P_RELATION"For p_relation = 1
   TYPE_ID EMP_TYPE           EMP_NO FNAME    RELATION PARENT_RELATION
         3 Manager                20 SUN             2               1
         2 Tech Lead              30 RAG             3               1
         1 Employee               40 PRASAD          4               1
3 rows selected.Not sure how do you get the following and it's not clear on what basis.
If I give input as *1*
Output Should be,
Relation Number|Employee_id|Employee Name
3|30|Rag
7|70|Besh
8|80|CheshFor p_relation = 2
   TYPE_ID EMP_TYPE           EMP_NO FNAME    RELATION PARENT_RELATION
         2 Tech Lead              50 MOON            5               2
         1 Employee               60 LITE            6               2
2 rows selected.For p_relation = 3
   TYPE_ID EMP_TYPE           EMP_NO FNAME    RELATION PARENT_RELATION
         1 Employee               70 CHESH           7               3
1 row selected.For p_relation = 4
no rows selected.Hope this helps
Best Regards
Arif Khadas
Edited by: Arif Khadas on Jun 29, 2010 12:47 PM

Get only last level in SQL Hierarchy Query

Hi,
How to get only the last level in Oracle SQL Hierarchy Query?
Thanks

Hi,
1007372 wrote:
Hi,
How to get only the last level in Oracle SQL Hierarchy Query?Depending on your requirements:
WHERE CONNECT_BY_ISLEAF = 1
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only), and also post the results you want from that data.
Explain, using specific examples, how you get those results from that data.
If you can show what you want to do using commonly available tables (such as scott.emp, which contains a hierarchy), then you don't need to post any sample data; just the results and the explanation.
Always say which version of Oracle you're using (e.g., 11.2.0.2.0). This is always important, but especially so with CONNECT BY queries, because every version since Oracle 7 has had significant improvements in this area.
See the forum FAQ {message:id=9360002}

Process to change the order of the hierarchy nodes

Hi,
What is the process to change the order of the hierarchy nodes ( and associated attributes) through import manager? any pdf's or doc's regarding this?

In Import Manager it is not possible to change the order of hierarchy nodes or the order of the linked attributes.
Regards,
Ronen

I need Hierarchial Query

Hi All,
I need supervisor assignment hierarchy query(HRMS), for generating report.
can someone help me on this??
Any help is greately appreciated.
Regards
Gopi

Hello everyone
When i am trying to execute following query, i am getting an error like
ORA-01473
Cannot Have Sub Queries in Connect By Clause
It display the hierarchy starting from our board of directors in a descending manner
SELECT LPAD ('->', 8 * (LEVEL - 1))
|| (SELECT DISTINCT full_name
FROM per_all_people_f
WHERE person_id = paf.person_id
AND PERSON_TYPE_ID '1123' -- 1123 = 'Ex-Employee'
AND SYSDATE BETWEEN effective_start_date
AND effective_end_date)
TREE
FROM per_all_assignments_f paf
WHERE SYSDATE BETWEEN paf.effective_start_date
AND paf.effective_end_date
AND paf.primary_flag = 'Y'
and paf.person_id in
(select pf.person_id from per_all_people_f pf where pf.PERSON_TYPE_ID '1123' and paf.person_id = pf.person_id
AND SYSDATE BETWEEN pf.effective_start_date
AND pf.effective_end_date
START WITH paf.person_id = (select person_id from per_all_people_f where last_name ='Board of') -- Board of Directors
CONNECT BY PRIOR paf.person_id = paf.supervisor_id
AND paf.primary_flag = 'Y'
AND paf.person_id in (select person_id from per_all_people_f pf where paf.person_id = pf.person_id and pf.PERSON_TYPE_ID'1123')
AND SYSDATE BETWEEN paf.effective_start_date
AND paf.effective_end_date
Could anyone help me on this??
Regards
Gopi

Oracle Tree Hierarchy Query

Hi,
Hoping someone can assist with this query:
I am currently using this query to construct a tree hierarchy, i.e.
SELECT "EMP"."MGR" as "MGR",
        "EMP"."EMPNO" as "EMPNO",
        "EMP"."ENAME" as "ENAME" ,
        (select count(*) from "EMP" "EMP2" where "EMP2"."MGR" = "EMP"."EMPNO") BranchCount
from
"EMP" "EMP"
where
"EMP"."MGR" = :BRANCH_IDUsing this query, I also need to retrieve the LEVEL pseudo-column as well for each record retrieved as I need the LEVEL info for trying to determine at what level of the tree I am at.
I would actually like to incorporate the LEVEL column into the above query - is this possible?
Thanks.
Tony.

SQL> desc test
Name Null? Type
COLUMN1 VARCHAR2(10)
COLUMN2 VARCHAR2(10)
MGR VARCHAR2(10)
SQL> select * from test
2 /
COLUMN1 COLUMN2 MGR
1 a 33
3 i 33
2 g 33
4 b 33
5 c 44
6 d 44
22 e
33 f 22
44 h 22
9 rows selected.
SQL> select column1, column2, mgr, level
2 from test
3 start with mgr = '22'
4 connect by prior column1 = mgr
5 order by level
6 /
COLUMN1 COLUMN2 MGR LEVEL
33 f 22 1
44 h 22 1
6 d 44 2
4 b 33 2
5 c 44 2
3 i 33 2
1 a 33 2
2 g 33 2
8 rows selected.

Adding dynamic 'start with' clause in Hierarchial query in Discoverer 4i

I have created a custom folder based upon the following hierarchial guery:
SELECT supervisor_name, level
FROM xxhr084_hr_emps_v
START WITH supervisor_name = 'TEST SUPER'
CONNECT BY prior person_id = supervisor_id
ORDER SIBLINGS by supervisor_name
I want the 'START WITH' value to be based upon a parameter i.e. the User enters the value of supervisor name at runtime.
However, I can't use a parameter within the custom folder and I can't generate the 'start with' condition in my workbook.
Anyone have a solution for populating the start with clause at run-time?
Thanks,
Kevin

Can you create the custom folder without a condition on supervisor_name - i.e. without the supervisor_name = 'X' starts with clause - in the EUL, and then define the condition on the supervisor_name field within the report?
SELECT supervisor_name, level
FROM xxhr084_hr_emps_v
CONNECT BY prior person_id = supervisor_id
ORDER SIBLINGS by supervisor_name
You can then restrict the results that the hierarchical query returns (from the custom folder) within the report, by adding a condition on supervisor_name.
Hope that makes some sense.

ORDER BY IN HIERARCHIAL QUERY

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