Outer join with NVL function

Hello
I am trying to translate the following Sybase Query to Oracle . I am running the query on a 10gR1 database.
The problem is with the NVL clause on the join I am getting a runtime exception .
Is there a way to re-write this query without breaking the functionality.
SELECT t1.*,
NVL(t2.Branch_name, t3.Branch_name)
FROM table1 t1
LEFT OUTER JOIN
table2 t2
ON (t1.Account_id = t2.Account_id)
LEFT OUTER JOIN
table3 t3
ON (t1.Account_id = t3.Account_id)
LEFT OUTER JOIN
table4 t4
ON (NVL(t2.Branch_Name, t3.Branch_Name) = t4.cost_centre);
Thanks

The original query had a insert statement and it was failing with ORA-01400 even though the select query fetched 0 rows
Insert into Branch_Master
SELECT t1.*,
NVL(t2.Branch_name, t3.Branch_name)
FROM table1 t1
LEFT OUTER JOIN
table2 t2
ON (t1.Account_id = t2.Account_id)
LEFT OUTER JOIN
table3 t3
ON (t1.Account_id = t3.Account_id)
LEFT OUTER JOIN
table4 t4
ON (NVL(t2.Branch_Name, t3.Branch_Name) = t4.cost_centre);
ksedmp: internal or fatal error
ORA-01400: cannot insert NULL into ("<<schema_name>>"."Branch_Master"."BRANCH_NAME")
I have re-written the query using a Inline view . Can you please review and let me know if it is ok
select * from
( SELECT t1.*,
NVL(t2.Branch_name, t3.Branch_name) Branch_name_final
FROM table1 t1
LEFT OUTER JOIN
table2 t2
ON (t1.Account_id = t2.Account_id)
LEFT OUTER JOIN
table3 t3
ON (t1.Account_id = t3.Account_id) ) IV_Temp
LEFT OUTER JOIN Table4 on (IV_temp.Branch_name_final = T4.cost_centre ;

Similar Messages

How to achieve an outer join with existsNode() function

I have a requirement to do an outer join with existsNode() function in my where clause. At present my where clause for join is like below
WHERE A.SOME_ID= “XYZ”
AND existsNode (B.SOMEXML_FEILD , …. ) = 1
AND existsNode (C.SOMEOTHERXML_FEILD , …. ) = 1
In this case if the existsNode fails on B or C, I still want data from A to be selected. How to rewrite this query to achieve that? I kinda want to achieve an outer join

Hi,
is this what you are looking for:
SQL> with t as(select 1 id1,'A' name from dual union all
2            select 2 ,'B' name from dual union all
3            select 3,'C' from dual)
4      ,x as(select 1 id2,xmltype('<a>a</a>') xcol from dual union all
5            select 2 ,xmltype('<b>b</b>') xcol from dual)
6 select *
7 from t,x
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9    and (existsNode(x.xcol,'/a')=1 or x.xcol is null);
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Left outer join with NVL as part of the join criteria

Hi,
I have query like this:
Select
Main.X_ID,
NVL(Option1.Y_ID, Option2.Y_ID),
Main.Z_ID
from TableMain Main
left join (Select X_ID, Y_ID from TableOption where type_cd = 'Type1') Option1
on Main.X_ID = Option1.X_ID
left join (Select X_ID, Y_ID from TableOption where type_cd = 'Type2') Option2
on Main.X_ID = Option2.X_ID
left join TableSub Sub
on Main.Z_ID = Sub.Z_ID
and Sub.Y_ID = NVL(Option1.Y_ID, Option2.Y_ID)
where Sub.Z_ID is null and Sub.Y_ID is null
Basically i want to show all in Z_IDs TableMain that are not in TableSub where the joining Y_ID is Type1 and if there is not a Y_ID for Type1, then use the Y_ID for Type2.
The query works if Type1 exists but doesnt if Type1 doesnt and Type2 does.
Is NVL the correct function to use in the join? Or is there a better way to write such a query?
Any help would be greatly appreciated. Thanks!!
FYI all IDs are NUMBERs.

Hopefully this is easier to understand :)
Im using 11g.
DDL and data:
create table tablemain (
x_id number (20),
z_id number (20),
amount number(20)
insert into tablemain values (1, 1000, 6767.45);
insert into tablemain values (1, 1001, 767.45);
insert into tablemain values (1, 1002, 67.85);
insert into tablemain values (1, 1003, 997.85);
insert into tablemain values (2, 1002, 1997.85);
insert into tablemain values (2, 1004, 197.85);
insert into tablemain values (2, 1005, 7.85);
insert into tablemain values (3, 1000, 7.44);
insert into tablemain values (3, 1006, 447.88);
create table tableoption (
y_id number (20),
x_id number (20),
type_cd varchar2(20)
insert into tableoption values (800, 1, 'Type1');
insert into tableoption values (800, 3, 'Type2');
insert into tableoption values (801, 1, 'Type2');
insert into tableoption values (802, 2, 'Type1');
create table tablesub (
y_id number (20),
z_id number (20)
insert into tablesub values (800, 1000);
insert into tablesub values (800, 1001);
insert into tablesub values (800, 1004);
insert into tablesub values (800, 1006);
insert into tablesub values (801, 1001);
insert into tablesub values (801, 1002);
insert into tablesub values (801, 1005);
insert into tablesub values (801, 1006);
insert into tablesub values (802, 1005);
insert into tablesub values (802, 1004);Query:
SELECT Nvl(option1.y_id, option2.y_id) as y_id,
       Nvl(option1.x_id, option2.x_id) as x_id,
       mains.z_id,
       mains.amount
FROM   tablemain mains
       left join (SELECT x_id,
                         y_id
                  FROM   tableoption
                  WHERE type_cd = 'Type1') option1
         ON mains.x_id = option1.x_id
       left join (SELECT x_id,
                         y_id
                  FROM   tableoption
                  WHERE type_cd = 'Type2') option2
         ON mains.x_id = option2.x_id
       left join tablesub sub
         ON mains.z_id = sub.z_id
            AND sub.y_id = Nvl(option1.y_id, option2.y_id)
WHERE sub.z_id IS NULL
       AND sub.y_id IS NULL What the output should be:
y_id ---- x_id ---- z_id ---- amount
800 ---- 1 ---- 1002 ---- 67.85
800 ---- 1 ---- 1003 ---- 997.85
801 ---- 1 ---- 1000 ---- 6767.45
801 ---- 1 ---- 1003 ---- 997.85
802 ---- 2 ---- 1002 ---- 1997.85
Currently the output of the query is:
800 ---- 1 ---- 1002 ---- 67.85
800 ---- 1 ---- 1003 ---- 997.85
802 ---- 2 ---- 1002 ---- 1997.85
It is missing where 801 is type2 only in the tableoption:
801 ---- 1 ---- 1000 ---- 6767.45
801 ---- 1 ---- 1003 ---- 997.85
Edited by: Hazy on Feb 22, 2012 3:25 PM

Outer join with effective date in peoplesoft query

Hi,
I'm trying to join two tables using outer join. Both tables are effective dated:
Dept_Tbl: dept_id, status, effdt
Tips_Tbl: dept_id, tips_id, effdt
Not all records in Dept_Tbl are in Tips_Tbl. I need to get all active depts and their most recent tips_id if they have one.
select a.dept_id, b.tips_id
from dept_tbl a, tips_tbl b
where a.status = 'Active'
and a.effdt =
(select max(a_ed.effdt) from dept_tbl a_ed
where a.dept_id = a_ed.dept_id
and a_ed.effdt <= SYSDATE)
and b.dept_id(+) = a.dept_id
and b.effdt =
(select max(b_ed.effdt) from tips_tbl b_ed
where b.dept_id = b_ed.dept_id
and b.tips_id = b_ed.tips_id
and b_ed.effdt <= SYSDATE)
The query only returns records that are in both tables.
Is there a way for outer join to work with effective dates?
Thanks in advance,
Reg

Here is an example of one solution. Note the use of NVL on both sides of the equal sign since both sides could be NULL in the case of the outer join
with dept_tbl as (select 1 dept_id, SYSDATE effdt FROM DUAL),
     tips_tbl as (select 1 dept_id, NULL effdt FROM DUAL)
select a.effdt
from dept_tbl a,
       tips_tbl b
where b.dept_id(+) = a.dept_id
   and NVL(b.effdt, SYSDATE) = NVL((select max(b_ed.effdt)
                                      from tips_tbl b_ed
                                     where b.dept_id = b_ed.dept_id
                                       and b_ed.effdt <= SYSDATE), SYSDATE);
EFFDT
5/7/2007 3:25:00 PM

Problem with outer join with filter on join column

Hi,
In physical layer I have one dimension and two facts, and there's an outer join between the facts.
dim_DATE ,
fact_1 ,
fact_2
Joins:
dim_DATE inner join fact_1 on dim_DATE.DATE = fact_1.DATE
fact_1 left outer join fact_2 on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
When I run a report with a date as a filter, OBIEE executes "optimized" physical SQL:
select fact1.X, fact2.Y
from
Fact_1 left outer join on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
where Fact_1.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD' )
and Fact_2.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD')
The filter on Fact_2.DATE effectively replaces outer join with inner.
Is there a way to disable this "optimization", which is actually very good for inner joins, but doesn't allow outer joins?
Thanks in advance,
Alex
Edited by: AM_1 on Aug 11, 2009 8:20 AM

If you want to perform a Fact-based partitioning with OBIEE (two fact with the same dimension), you have to :
* create in your physical layer for each fact table the joins with the dimension
* create in the Business Model layer ONE star schema with ONE logical fact table containing the columns of your two physical fact table
In this way when you choose minimal one column of your fact1 and one column of your fact2, OBIEE will perform two query against each fact table/dimension, join them with an OUTER JOIN and your problem will disappear.
Cheers
Nico

Outer Join with Where Clause in LTS

HI all,
I have a requirement like this in ANSI SQL:
select p1.product_id, p1.product_name, p2.product_group
from product p1 left outer join product_group p2 on p1.product_id = p2.product_id
and p2.product_group = 'NEW'
In Regular SQL:
select p1.product_id, p1.product_name, p2.product_group
from product p1, product_group p2
WHERE p1.product_id *= p2.product_id and p2.product_group = 'NEW'
In OBIEE, I am using a left outer join between these two in Logical table Source, and also, Gave
p2.product_group = 'NEW' in WHERE clause of LTS.
This doesn't seem to solve purpose.
Do you have any idea how to convert WHERE clause in physical query that OBIEE is generating to something like
product p1 left outer join product_group p2 on p1.product_id = p2.product_id AND p2.product_group = 'NEW'
I am using Version 10.1.3.4.1
Creating an Opaque view would be my last option though.

Hello
I have read your post and the responses as well. and I understand that you have issues with the Outer Join with where Clause in LTS.
Try this solution which worked for me (using your example ) -
1. In the Physical Layer created a Complex join between PRODUCT and PRODUCT_GROUP tables and use this join relationship :
PRODUCT.PROD_ID = PRODUCT_GROUP.PROD_ID AND PRODUCT_GROUP.GROUP_NAME = 'MECHANICAL'
2. In the General Tab of PRODUCT table LTS add PRODUCT_GROUP table and select Join Type as Left Outer Join.
3. Check Consistency and make sure there are no errors .
when you run a request you should see the following query generated -
select distinct T26908.PROD_ID as c1,
     T26908.PROD_NAME as c2,
     T26912.GROUP_NAME as c3
from
     PRODUCT T26908 left outer join PRODUCT_GROUP T26912 On T26908.PROD_ID = T26912.PROD_ID and T26912.GROUP_NAME = 'MECHANICAL'
order by c1, c2, c3
Hope this works for you. If it does please mark this response as 'Correct' .
Good Luck.

Maximum number of tables that can be outer joined with one table in a query

Hi All,
Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
Thanks,
Srini

srinu2 wrote:
Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
There is no limit to the number of tables you can outer join as long as you join them correctly.
SQL> with a as
2      (
3      select 1 id, 2 b_key, 3 c_key from dual union all
4      select 2 id, 1 b_key, 4 c_key from dual union all
5      select 3 id, 3 b_key, 1 c_key from dual union all
6      select 4 id, 4 b_key, 2 c_key from dual
7      ),
8      b as
9      (
10      select 1 id, 1 c_key2 from dual union all
11      select 2 id, 5 c_key2 from dual union all
12      select 3 id, 3 c_key2 from dual union all
13      select 4 id, 2 c_key2 from dual
14      ),
15      c as
16      (
17      select 1 key1, 1 key2, '1-1' dta from dual union all
18      select 1 key1, 2 key2, '1-2' dta from dual union all
19      select 1 key1, 3 key2, '1-3' dta from dual union all
20      select 1 key1, 4 key2, '1-4' dta from dual union all
21      select 2 key1, 1 key2, '2-1' dta from dual union all
22      select 2 key1, 2 key2, '2-2' dta from dual union all
23      select 2 key1, 3 key2, '2-3' dta from dual union all
24      select 2 key1, 4 key2, '2-4' dta from dual union all
25      select 3 key1, 1 key2, '3-1' dta from dual union all
26      select 3 key1, 2 key2, '3-2' dta from dual union all
27      select 3 key1, 3 key2, '3-3' dta from dual union all
28      select 3 key1, 4 key2, '3-4' dta from dual union all
29      select 4 key1, 1 key2, '4-1' dta from dual union all
30      select 4 key1, 2 key2, '4-2' dta from dual union all
31      select 4 key1, 3 key2, '4-3' dta from dual union all
32      select 4 key1, 4 key2, '4-4' dta from dual
33      )
34 select d.a_id, d.b_id, c.key1 as c_key1, c.key2 as c_key3, c.dta
35 from
36      c,
37      (
38      select
39          a.id as a_id, b.id as b_id, a.c_key, b.c_key2
40      from a, b
41      where a.b_key = b.id
42      ) d
43 where d.c_key = c.key1 (+)
44 and   d.c_key2 = c.key2 (+);
      A_ID       B_ID     C_KEY1     C_KEY3 DTA
         3          3          1          3 1-3
         4          4          2          2 2-2
         2          1          4          1 4-1
         1          2
SQL>

Outer join With a constant value

Hi all,
In one of query i have found out that the outer join with a constant value like
to_currency(+)='USD'
to_currency is a column name in a table.can any one please explain this outer join condtn.
Thanks in advance
Senthil

Hallo,
if you write var (+) = constant
var can be equal constant, and also can be null
Compare these 2 queries
select e.* from scott.emp e, scott.dept d
where e.deptno = d.deptno(+)
and d.deptno(+) = 10EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7369     SMITH      CLERK      7902     17-Dez-1980     800          20
7499     ALLEN      SALESMAN      7698     20-Feb-1981     1600     300     30
7521     WARD      SALESMAN      7698     22-Feb-1981     1250     500     30
7566     JONES      MANAGER      7839     2-Apr-1981     2975          20
7654     MARTIN      SALESMAN      7698     28-Sep-1981     1250     1400     30
7698     BLAKE      MANAGER      7839     1-Mai-1981     2850          30
7782     CLARK      MANAGER      7839     9-Jun-1981     2450          10
7788     SCOTT      ANALYST      7566     19-Apr-1987     3000          20
7839     KING      PRESIDENT           17-Nov-1981     5000          10
7844     TURNER      SALESMAN      7698     8-Sep-1981     1500     0     30
7876     ADAMS      CLERK      7788     23-Mai-1987     1100          20
7900     JAMES      CLERK      7698     3-Dez-1981     950          30
7902     FORD      ANALYST      7566     3-Dez-1981     3000          20
7934     MILLER      CLERK      7782     23-Jan-1982     1300          10
select e.* from scott.emp e, scott.dept d
where e.deptno = d.deptno(+)
and d.deptno = 10 EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7782     CLARK      MANAGER      7839     9-Jun-1981     2450          10
7839     KING      PRESIDENT           17-Nov-1981     5000          10
7934     MILLER      CLERK      7782     23-Jan-1982     1300          10
As you can see, this (+) is very important
Regards
Dmytro

Outer Join with an 'OR'

I have a very complicated query to construct that requires the use of 'AND', 'OR', and Outer Joins. Oracle's 9i documentation says you can't use an outer join with an 'OR'.
Can you suggest how I may return the correct records under the following conditions. There are 3 tables to join. Table A, Table B, and Table C. Tables A & B join with an = to common fields. The problem is with Table C.
The way the application was designed, it has to track a parent and child relationship. As such, the field to relate may exist in 1 of 2 fields. Let's see if I can draw it out for you.
Table A - Record 1
(ID = 1)
Table B - Record 1
(ID =1 [this relates to Table A.ID]
PID = 12345
CID = 67899
Site = A)
Table C - Record 1
(PID = 12345 [this relates to Table B.PID]
CID = 67899
Site = A)
Table C - Record 2
(PID = 67899 [This relates to Table B.CID]
CID = 12345
Site = A)
Now, I need to relate Table A to Table B where A.ID = B.ID AND
((B.PID = C.PID AND B.CID = C.CID)
OR
(B.CID = C.PID AND B.PID = C.CID))
AND
B.SITE = C.SITE
There may or may NOT be related records in Table C. That's the problem. This is where I need the outer join to get the all the records of the 1st two joins and only those that apply from the last join.
Your help will be greatly appreciated.

I'd create two queries, a join from b to c in each of those manners and then UNION ALL the results together.
drop table junk_a;
create table junk_a (
id number );
drop table junk_b;
create table junk_b (
id number,
pid number,
cid number,
site varchar2(80) );
drop table junk_c;
create table junk_c (
pid number,
cid number,
site varchar2(80) );
insert into junk_a values (1);
insert into junk_b values (1, 12345, 67899, 'A');
insert into junk_c values (12345, 67899, 'A');
insert into junk_c values (67899, 12345, 'A');
commit;
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.pid(+) = b.pid
   AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.cid(+) = b.pid
   AND c.pid(+) = b.cid;
SELECT a.id,
       bc.pid,
       bc.cid,
       bc.site,
       bc.site_c
FROM junk_a a,
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.pid(+) = b.pid
   AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.cid(+) = b.pid
   AND c.pid(+) = b.cid
       ) bc
WHERE bc.id(+) = a.id;

Outer Join with the query

I have written the below query, our requirement is, Some employees have "Transport Allowance" but not "Project Allowance". For this, I tried to use OUTER JOIN with this query. But this query takes long time and failed. The following query works fine if the employee has both "Transport Allowance" and "Project Allowance" (without outer join) Now, I also need to retrieve the employees who have "Transport Allowance" but not "Project Allowance". How can I retrieve it?
SELECT DISTINCT papf.employee_number
, peev.screen_entry_value Transport_Allowance
,peev1.screen_entry_value Project_Allowance
FROM apps.per_all_people_f papf
,apps.per_all_assignments_f paaf
,apps.pay_element_types_x petf
,apps.pay_element_types_x petf1
,apps.pay_element_types_x petf2
,apps.pay_element_entries_f peef
,apps.pay_element_entries_f peef1
,apps.pay_element_entries_f peef2
,apps.pay_element_entry_values_x peev
,apps.pay_element_entry_values_x peev1
,apps.pay_element_entry_values_x peev2
,apps.pay_input_values_x pivf
,apps.pay_input_values_x pivf1
,apps.pay_input_values_x pivf2
WHERE
papf.person_id = paaf.person_id
AND paaf.assignment_id = peef.assignment_id
AND paaf.assignment_id = peef1.assignment_id
AND paaf.business_group_id = papf.business_group_id
--Transport Allowance
AND peef.element_entry_id = peev.element_entry_id
AND petf.element_Name = 'Transport Allowance'
AND pivf.element_type_id =petf.element_type_id
AND pivf.name = 'Allowance'
AND peev.input_value_id= pivf.input_value_id
--Project Allowance
AND peef1.element_entry_id = peev1.element_entry_id
AND petf1.element_Name = "Project Allowance'
AND pivf1.element_type_id = petf1.element_type_id
AND pivf1.name = 'Allowance'
AND peev1.input_value_id = pivf1.input_value_id
AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
ORDER BY papf.employee_number
Thanks in advance.

I am using sames tables with alias to retrieve the columns values from the same table.
Here is my query.
SELECT DISTINCT papf.employee_number
, peev.screen_entry_value Transport_Allowance
,peev1.screen_entry_value Project_Allowance
FROM apps.per_all_people_f papf
,apps.per_all_assignments_f paaf
,apps.pay_element_types_x petf
,apps.pay_element_types_x petf1
,apps.pay_element_entries_f peef
,apps.pay_element_entries_f peef1
,apps.pay_element_entry_values_x peev
,apps.pay_element_entry_values_x peev1
,apps.pay_input_values_x pivf
,apps.pay_input_values_x pivf1
WHERE
papf.person_id = paaf.person_id
AND paaf.assignment_id = peef.assignment_id
AND paaf.assignment_id = peef1.assignment_id
AND paaf.business_group_id = papf.business_group_id
--Transport Allowance
AND peef.element_entry_id = peev.element_entry_id
AND petf.element_Name = 'Transport Allowance'
AND pivf.element_type_id =petf.element_type_id
AND pivf.name = 'Allowance'
AND peev.input_value_id= pivf.input_value_id
--Project Allowance
AND peef1.element_entry_id = peev1.element_entry_id
AND petf1.element_Name = "Project Allowance'
AND pivf1.element_type_id = petf1.element_type_id
AND pivf1.name = 'Allowance'
AND peev1.input_value_id = pivf1.input_value_id
AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
ORDER BY papf.employee_number
Thanks in advance.

Outer join with BETWEEN clause

Hi All,
I have 2 tables (A and B) which i need to join. I need all records from table A and matching records from the table B. below is the structure.
TABLE A (total rows = 10)
ROW_WID
GL_DATE
LOCATION_CODE
TABLE B (total = 7)
ROW_WID
START_DATE
END_DATE
LOCATION_CODE
Initially, we were asked to join based on location_code. In the table B, some of the LOCATION_CODE are missing, which is present in table A.
We wrote below query
SELECT A.*, B.START_DATE, B.END_DATE
FROM A, B
WHERE A.LOCATION_CODE = B.LOCATION_CODE (+)
This gives 10 records, where 3 records have START_DATE and END_DATE NULL. because of outer join
It gave all records from the A table. It worked fine. Now i need to add one more condition where A.GL_DATE between B.START_DATE and B.END_DATE
If i write this
SELECT A.*, B.START_DATE, B.END_DATE
FROM A, B
WHERE A.LOCATION_CODE = B.LOCATION_CODE (+)
AND A.GL_DATE BETWEEN B.START_DATE and B.END_DATE
This gives me only 7 records. IS IT POSSIBLE TO ADD OUTER JOIN with BETWEEN clause.

Hi All,
I'm in a similar situation,
I have a complex query, everything is working fine, except this part (I will simplify everything, removing other stuffs because I need help only on the following condition)
SELECT *
from transaction t, card c
where c.card_id = t.card_id (+)
and t.trn_date between to_date ('01/01/2012','dd/mm/yy') and ('01/01/2013,'dd/mm/yy')
How could i OUTER JOIN the between condition?
I tried with
and t.trn_date between to_date ('01/01/2012','dd/mm/yy') (+) and ('01/01/2013','dd/mm/yy') (+)
but returns a "missing expression" error.
Surely I'm missing some stupid thing about it, could you help me on this? (probably because I'm talking about parameters and I cannot put the outer join on a value)
How can I rewrite the condition in order to satisfy what I'm trying to accomplish?
Thanks in Advance,
Alex
Edited by: 981667 on 14-gen-2013 4.23
Edited by: 981667 on 14-gen-2013 4.24

Join columns of outer join with table have no uniqueness cons

Hi! I'm getting noizy error in alert log from time to time:
Join columns of outer join with table <table_name> have no uniqueness constraints
I've collected all the queries (v$sql, all_source) with montioned table, but non of them produces that error if executed.
Any hints how to reproduce this error or where else to search that buggy sql join?
Edited by: user545083 on 25.10.2010 6:21

Hi
I think this error is output via an materialized view refresh - check for mviews against the given table which fulfil the issue given in the error text.
Thanks
Paul

Case statement resulting into Left outer join with other tables

Hi All ,
I am facing a stuation where a Case statement on one of the logical columns in Answers is resulting into a left outer join with a table in the query.
If we remove the case stmt, the table is not being acessed.
The case stmt is a simple one and no other logical column is being accessed in the case stmt.
Please advice .
Thanks.

Hi Sai,
No ..we dont have any left outer join ...its just that I am selecting measure from F1 which has a confimred dimension D1 with F2.Now when I dont have case stmt on measure from F1(Case stmt is something like : CASE WHEN "- P table"."P Column" = 'Y' THEN 'Right' ELSE 'Wrong' END), then it doesnt query F2.
However as soon as I introduce the case stmt ,the query creates a left outer join with F2.
Thanks.

Inner join Vs Outer join with ABAP code...?

Inner join Vs Outer join with ABAP code...?

Inner Join means, it will not select that recor at all, unless there is a matching entry in the second table.
suppose table VBAK INNER join table VBAP on VBAKVBELN = VBAPVBELN.
In this case, if there are no entries in VBAP, the header entry also will not show up.
But in case of OUTER JOIN, even if there is no items, it will show the header entry(VBAK) with blank columns for fields from item table.(VBAP)
here is one sample for inner join.
SELECT   A~EBELN
           A~EKORG
           A~EKGRP
           A~BSART
           A~LPONR
           A~LOEKZ
           A~LIFNR
           A~RESWK
           B~AEDAT
           B~WERKS
           B~MATNR
           B~MENGE
           B~EBELP
           B~ELIKZ
           B~PLIFZ
           B~PSTYP
           B~KNTTP
           B~MATKL
           B~ZZD_PLANT
           FROM EKKO AS A INNER JOIN EKPO AS B
           ON
           AEBELN = BEBELN
           INTO CORRESPONDING FIELDS OF TABLE T_DATA
           FOR ALL ENTRIES IN T_EKET
           WHERE
           A~EBELN EQ T_EKET-EBELN AND
           A~BSART EQ C_UBSTO      AND
           A~EKORG IN S_EKORG      AND
           A~EKGRP IN S_EKGRP      AND
           A~BSTYP EQ C_BSTYP      AND
           A~LOEKZ EQ SPACE        AND " Order not deleted
           A~RESWK IN S_RESWK      AND
           B~EBELN EQ T_EKET-EBELN AND
           B~EBELP EQ T_EKET-EBELP AND
           B~WERKS IN S_WERKS      AND
           B~MATNR IN S_MATNR      AND
           B~MATKL IN S_MATKL      AND
           B~LOEKZ EQ SPACE.           " Line item not deleted

Help with outer joins? NVL?

HI,
I have two reports I am creating, one for October and one for november.
The query is below so you can see what I am trying to do. There is a difference of about two hundred accounts, I want to see which accounts were in October and not in November. How can I view the different accounts and list them along side the november accounts or if this can't be done, how can I at least see the accounts which differ between the months? I am thinking that I need to build one report as an inline-view in the from clause, and then do an outerjoin on that aliased table, but am not sure on the syntax. Also, how can I use the NVL function to put in a value for the NULL columns?
select d.month,
     a.account_no,
     x.first_name||', '||x.last_name,
     d.product,
     d.cycle_forward ,
     d.overusage,
     d.logins,
     d.seconds/3600 hours
from brio_broadcast.monthly_dial_revenue d,
     pin.account_nameinfo_t x,
     pin.account_t a
where month = '2002-10'
and a.POID_ID0 = d.ACCOUNT_OBJ_ID0
and a.poid_id0 = x.obj_id0
order by a.account_no;

SELECT   o.month,
         o.account_no,
         o.name,
         o.product,
         o.cycle_forward,
         o.overusage,
         o.logins,
         o.hours
FROM     (SELECT   d.month,
                   a.account_no,
                   x.first_name || ', ' || x.last_name AS name,
                   d.product,
                   d.cycle_forward ,
                   d.overusage,
                   d.logins,
                   d.seconds / 3600 hours
          FROM     brio_broadcast.monthly_dial_revenue d,
                   pin.account_nameinfo_t              x,
                   pin.account_t                       a
          WHERE    d.month = '2002-11'
          AND      a.poid_id0 = d.account_obj_id0
          AND      a.poid_id0 = x.obj_id0) n,
         (SELECT   d.month,
                   a.account_no,
                   x.first_name || ', ' || x.last_name AS name,
                   d.product,
                   d.cycle_forward ,
                   d.overusage,
                   d.logins,
                   d.seconds / 3600 hours
          FROM     brio_broadcast.monthly_dial_revenue d,
                   pin.account_nameinfo_t              x,
                   pin.account_t                       a
          WHERE    d.month = '2002-10'
          AND      a.poid_id0 = d.account_obj_id0
          AND      a.poid_id0 = x.obj_id0) o
WHERE    o.account_no = n.account_no (+)
AND      n.account_no IS NULL
UNION ALL
SELECT   n.month,
         n.account_no,
         n.name,
         n.product,
         n.cycle_forward,
         n.overusage,
         n.logins,
         n.hours
FROM     (SELECT   d.month,
                   a.account_no,
                   x.first_name || ', ' || x.last_name AS name,
                   d.product,
                   d.cycle_forward ,
                   d.overusage,
                   d.logins,
                   d.seconds / 3600 hours
          FROM     brio_broadcast.monthly_dial_revenue d,
                   pin.account_nameinfo_t              x,
                   pin.account_t                       a
          WHERE    d.month = '2002-10'
          AND      a.poid_id0 = d.account_obj_id0
          AND      a.poid_id0 = x.obj_id0) o,
         (SELECT   d.month,
                   a.account_no,
                   x.first_name || ', ' || x.last_name AS name,
                   d.product,
                   d.cycle_forward ,
                   d.overusage,
                   d.logins,
                   d.seconds / 3600 hours
          FROM     brio_broadcast.monthly_dial_revenue d,
                   pin.account_nameinfo_t              x,
                   pin.account_t                       a
          WHERE    d.month = '2002-11'
          AND      a.poid_id0 = d.account_obj_id0
          AND      a.poid_id0 = x.obj_id0) n
WHERE    n.account_no = o.account_no (+)
AND      o.account_no IS NULL
ORDER BY 2

Outer join with NVL function

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