Overriding

Is Overriding is static or dynamic?
The method call is decided during compile time or run time?
public Class SuperClass{
public void methodA(){
System.out.println("Super class method");
public Class SubClass{
public void methodA(){
System.out.println("Sub class method");
in the main method, i create the instances as follows
SuperClass super = new SuperClass();
SubClass sub = new SubClass();
if i invoke the method , as super.methodA() then output will be "Super class method" and if sub.methodA() then output will be "Sub class method". This is obvious.
And if i create a instance of the sub class using the super class reference and invoke the method like
SuperClass super = new SubClass();
super.methodA();
output wll be "Sub Class method".
Is this call is decide during run time or compile time??????

There is an "exception", though, when combining overriding and overloading.
public class Test {
  public static void main(String [] args) throws Exception {
    X x = new Y();
    x.doThing(""); // prints "X"
  static class X {
    void doThing(Object o) { System.out.println("X"); }
  static class Y extends X {
    void doThing(String s) { System.out.println("Y-String"); }
    void doThing(Integer i) { System.out.println("Y-Integer"); }
}

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    is not abstract and does not override abstract method actionPerformed
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    Message was edited by:
    ChargersTule1

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    Forum Support
    Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support, contact
    [email protected]
    Jason Guo
    TechNet Community Support

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