Parent - child - hierarchy - display in report output?

<b>CHILD          PARENT       LEVEL       HIERARCHY</b>
140339991000     901589991000     1     /901589991000
140349990000     901589991000     1     /901589991000
140359999000     901589991000     1     /901589991000
991539998000     906349995000     3     /901589991000/140359999000/906349995000
991539998000     906339996000     3     /901589991000/140359999000/906339996000
991539998000     951309993000     2     /901589991000/140359999000/
In my report I need to display these as levels. Example level1 displays only those numbers with level1. Level 2 on following frame displays level 2 children with the parent numbers. Similarly, level 3 in next frame displays children and parent one below the other. How can I achieve this?
Something like this:
level 3
level2
level1

If you have a limited number of levels, then you may have a frme for each possible value for a level. And you would print frame_level1 only when :field_level=1 (you use the format trigger for frame_level1), print frame_level2 only when :field_level=2 and so on ...
In case you have a large number of levels, then I simply can't imagine how you wish to have the data printed.
HTH

Similar Messages

  • Parent Child Hierarchy - Display other dimension fields against parent

    Hi,
    I have a Dimension for Customer with a parent child hierarchy.  The problem I have is with additional fields within the dimension.  See data below:
    Row Labels
    Customer Group   Description
    Value
    500116 - OOO "Starline"
    30
       500116 - OOO "Starline"
    A - Dealer
    5
       818781 - OKNO
    Direct / End User
    10
       400464 - OKNO TV
    Other
    15
    500123 - VIDAU SYSTEMS
    300
      500123 - VIDAU SYSTEMS
    A - Dealer
    100
      400396 - VIDAU SYSTEMS
    Other
    200
    Grand   Total
    330
    I want the Customer Group to show "A - Dealer" for the parent of the first row (against "500116 - OOO "Starline"), but its shown blank.  Also, I would like other fields to do the same.  As the parent relates to a row in
    my dimension table, this should be possible?
    Thanks in advance,
    Dominic

    Hi,
    Sorry it took me a while to come back to this.
    My dimension has the following columns:
    ID
    Customer
    Customer Group
    Parent
    1
    500116
    A - Dealer
    NULL
    2
    818781
    Direct / End User
    1
    2
    400464
    Other
    1
    My measure has 3 rows:
    customerKey
    value
    1
    5
    2
    10
    3
    15
    So when this is presented in the cube, the 3 items with values are correctly presented but my problem is that the "Customer Group" doesnt show against record 1 (the parent).  In usual circumstances my users will not expand the hierarchy, i
    just want the associated row value shown.
    Does this make more sense?  I hope so, and i hope somebody can help me resolve it.
    Thanks,
    Dom

  • How to output the outline parent-child relationship using a report script?

    I'd like to extract the outline's dimension members with it's parent-child relationship using a report script. Anybody can provide a sample script? Thanks.
    Example:
    DimensionX
    -----MemberX
    ----------ChildX
    Output:
    Dimension X MemberX
    MemberX ChildX
    Edited by: obelisk on Jan 11, 2010 5:16 PM

    Sorry a report script won't do it. You have two options
    1. Use at Essbase Outline API to walk the outline and get it for you
    2. Use the Outline extractor available from Applied Olap (it is a free download). It can be run interactively of as a bat file.
    Frankly, I would rather use 2 since I don't have to code it myself

  • OBIEE 11g Parent Child hierarchy

    Hi,
    I'm trying to setup a parent-child hierarchy dimension. I have setup a new hierarchy dimension using numeric keys but want to display another field in the hierarchical column on a report e.g. employee fullname & not the member_key based on a numeric value. Can this be done & how do you do it? All the examples I have seen use varchar2 type columns as the keys to do this.
    Thanks in advance, Phil
    My Setup
    =============
    Dimension - logical level
    ===============
    member key = employee_id
    parent-child table source
    ===============
    member key = employee_id
    parent key = supervisor_id
    relationship distance = levels_removed
    leaf node identifier = isleaf
    Employee logical folder
    ==============
    employee_id ( number)- primary key
    full_name (varchar2) - unique key
    supervisor_id ( number)
    Closure table
    =========
    employee_id ( number)
    supervisor_id ( number)
    level ( number)
    isleaf ( number)

    Thanks for the link Suresh but the aggregations are working correctly.
    My problem is only at the display level. I need to create a dashboard that displays the complete hierarchy.
    So for example if I have this hierarchy:
    - Steven King
    - Adam Frip
    Alexis Bull
    Anthony Cabrio
    Alberto Erraruriz
    Den Raphaely
    I want the dashboard to display immediately that complete hierarchy. If someone adds a member to the hierarchy in the database, the dashboard should display this new member without having to manually modify the dashboard.
    - Steven King
    - Adam Frip
    Alexis Bull
    Anthony Cabrio
    - Alberto Erraruriz
    Mozhe Atkinson
    Den Raphaely
    Also, if I just manually open the hierarchy and save the dashboard, if "Steven King" is replaced by "Shanta Vollman", the dashboard doesn't like it and returns a result looking like:
    - Adam Frip
    Alexis Bull
    Anthony Cabrio
    - Alberto Erraruriz
    Mozhe Atkinson
    Den Raphaely
    + Shanta Vollman
    So I'm looking for some option that will tell OBIEE to open the hierarchy without having to specify "Drill down on member "Steven King"", "Drill down on member "Adam Frip"...
    I hope I'm explaining correctly...

  • Tabular - Parent/Child hierarchy - hide duplicated rows problem

    Hi All, in all the Tabular parent-child hierarchy examples I could find a measure is created to calculate current node depth. Later that measure [CurrentNodeDepth] is compared with aggregated node depth using MAX/MIN functions. The current node depth measure
    uses ISFILTERED DAX functions like
    CurrentNodeDepth :=     IF (ISFILTERED ('Hierarchy'[Level3]), 3,IF (ISFILTERED ('Hierarchy'[Level2]), 2,     IF (ISFILTERED ('Hierarchy'[Level1]), 1)))
    All works ok until you start filtering the hierarchy - that might happen with very big hierarchies - showing only part of hierarchy to speed up calculations. Once you set a filter there, [CurrentNodeDepth] measure gives wrong output and whole parent-child hierarchy
    doesn't work as it should.

    Can you provide more info on this, how have you modeled the hierarchy with the fact table, are you rolling up the measures for the child to the parent level (modeling as measures) or each employee is showing its own revenue only (modeled as attribute)? If it is modeled as measures where you join the employee table to the closure table and then that to fact table then are you applying any filters in your report ? If you are applying filters in your report and somehow only parent is filtered (and not its children) then you won't be able to drill down, though you will see the + sign against it.

  • Parent Child Hierarchy Issue in OBIEE 11g

    Hi All,
    I am in OBIEE 11G v6. I have a sales fact table where the grain is one sale. So I have one row for every sale done.
    Now I have a ragged employee hierarchy like this with David at the root node.
    David >>Richard>>Sean
    David >>James
    Also, I have a role dimension which gives me what role each employee has performed on a sale. Only one employee can be associated with one sale. This is the way Roles have been asssigned
    David = Manager
    Richard = Off1
    Sean = Off2
    James = Off2
    Both Sean and James can have same Roles. Now I have created a parent child hierarchy for my employee dimension and the closure table. Defined the member key, ancestor key relationship in the parent child setting etc.
    Now in the report when I pull the parent child hierarchy and the sales_amount in the report, it comes out perfect with all the ragged hierarchy resolved. But the issue comes when I try to limit the report on Role = Off2. It gives me an error saying " The layout of this view combined with the data, selection , drills resulted in no data. Undo drill and view prompt values". Basically what i want is to be able to select any role type and then my hierarchy should be adjusted to show me that data. Like when I select Off2, I want to see David at the Top level and Sean and James under him because they are both Off 2 and David is their manager.
    Is that possbile? Also, am I getting this error because when I select Off2 though it gets Sean and James but since David is not Off2, I don't get the data?
    I hope I was able to explain the issue, any help on this would be greatly appreciated.
    Thanks
    Ronny

    So basically this means that if I build a parent child hierarchy on table A having the stucture like
    --David (Manager)
    -----James (Off1)
    --------Bill (Off2)
    and in my sales fact table for let's say today, I have only rows for Bill (Off2) because he is the only officer who did the sales today. Now when I will join my fact table to parent child hierarchy table A I will NOT get any data ? because there is no James who is the parent of Bill. So obiee need to have parent pulled off in the data (ANCESTOR) to be able to roll up the child.(IS_LEAF = 1)
    I testes this and if my data only contains only rows for Bill (or I limit on ROLE = Off2) then it won't show the hierarchy. The query which OBIEE fires is to look for either ANCESTOR_KEY = NULL OR (DISTANCE = 1 AND ANCESTOR KEY IN (Bill). Therefore it doesn't I am wondering then what is the use of builiding the parent child hierarchy when we need to pull in all the ancestors (like in this case James for bill and David for james) because in real scenarios there can be cases wherein we would want to filter the data based on other dimensions to which the parent child hierarchy joins ?

  • How to update a parent child hierarchy in OBIEE

    Hello All
    Quick question about updating parent child hierarchy in OBIEE.
    As we know, OBIEE 11G allows us to create value based hierarchy by generating table creation script and insert script. In the typical example of employee dimension, the parent child relationship table will be created with the following 4 attributes:
    MEMBER_KEY, ANCESTOR_KEY, DISTANCE, IS_LEAF
    So, what if later in the years some of the employees got promoted, retired or transferred? The value based hierarchy is going to change because person 1 reports to manager 2 now instead of 1. Obviously, the records in employee dimension is going to be updated. When that happens, how to update the parent child relation table with the same information? Do we have to rerun the insert script? How do we keep the history of employee changes and hierarchy changes?
    Please advice
    Thank you

    I guess it will update when the structure changes,Let see the response from other gurus.
    Thanks,

  • Dynamic hierarchy in parent child hierarchy table??

    Do you have any experience to handle the requirement of dynamic hierarchy in universe/webi?
    We have some data in parent child hierarchy as below u201CCustomeru201D table.
    Customer
    Parent          Child
    Z                  A
    Z                  B
    A                  AA
    B                  BB
    AA               AAA
    For example, Company Z is the parent company of Company A.
    Another table, Amount is the amount value of different Customers.
    Amount
    ID               Amt
    AA               10
    AAA            1
    BB                2
    Is there any functionality in Universe designer to build related Classes and objects, So that the web intelligence documents represent the following report with the drilling results?
    When we want to see the ID and Amt, the expected result should be:
    Z                13
    when we drill down Z
    the result should be:
    A                11
    B                2
    when we drill down A:
    the result should be:
    AA              11
    notes **
    the level of hierarchy is dynamic
    Any suggestion is appreciated.  Thanks.

    Hi,
    The only way to do it is to create recursive derived table that flatten you parent child hierarchy with a given maximum depth.
    Here is a sample I built a long time ago to flatten a parent-child hierarchy on Employees table in Foodmart database (SQL Server).
    Didier
    SELECT DISTINCT
         Z.employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         A.supervisor_id_3,
         A.employee_id_3,
         A.full_name_3,
         A.supervisor_id_4,
         A.employee_id_4,
         A.full_name_4,
         A.supervisor_id_5,
         A.employee_id_5,
         A.full_name_5,
         A.supervisor_id_6,
         A.employee_id_6,
         A.full_name_6,
         Z.supervisor_id AS supervisor_id_7,
         Z.employee_id AS employee_id_7,
         Z.full_name AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              A.supervisor_id_1,
              A.employee_id_1,
              A.full_name_1,
              A.supervisor_id_2,
              A.employee_id_2,
              A.full_name_2,
              A.supervisor_id_3,
              A.employee_id_3,
              A.full_name_3,
              A.supervisor_id_4,
              A.employee_id_4,
              A.full_name_4,
              A.supervisor_id_5,
              A.employee_id_5,
              A.full_name_5,
              Z.supervisor_id AS supervisor_id_6,
              Z.employee_id AS employee_id_6,
              Z.full_name AS full_name_6
         FROM employee Z,
              SELECT DISTINCT
                   A.supervisor_id_1,
                   A.employee_id_1,
                   A.full_name_1,
                   A.supervisor_id_2,
                   A.employee_id_2,
                   A.full_name_2,
                   A.supervisor_id_3,
                   A.employee_id_3,
                   A.full_name_3,
                   A.supervisor_id_4,
                   A.employee_id_4,
                   A.full_name_4,
                   Z.supervisor_id AS supervisor_id_5,
                   Z.employee_id AS employee_id_5,
                   Z.full_name AS full_name_5
              FROM employee Z,
                   SELECT DISTINCT
                        A.supervisor_id_1,
                        A.employee_id_1,
                        A.full_name_1,
                        A.supervisor_id_2,
                        A.employee_id_2,
                        A.full_name_2,
                        A.supervisor_id_3,
                        A.employee_id_3,
                        A.full_name_3,
                        Z.supervisor_id AS supervisor_id_4,
                        Z.employee_id AS employee_id_4,
                        Z.full_name AS full_name_4
                   FROM employee Z,
                        SELECT DISTINCT
                             A.supervisor_id_1,
                             A.employee_id_1,
                             A.full_name_1,
                             A.supervisor_id_2,
                             A.employee_id_2,
                             A.full_name_2,
                             Z.supervisor_id AS supervisor_id_3,
                             Z.employee_id AS employee_id_3,
                             Z.full_name AS full_name_3
                        FROM employee Z,
                             SELECT DISTINCT
                                  A.supervisor_id_1,
                                  A.employee_id_1,
                                  A.full_name_1,
                                  Z.supervisor_id AS supervisor_id_2,
                                  Z.employee_id AS employee_id_2,
                                  Z.full_name AS full_name_2
                             FROM employee Z,
                                  SELECT DISTINCT
                                       supervisor_id AS supervisor_id_1,
                                       employee_id AS employee_id_1,
                                       full_name AS full_name_1
                                   FROM employee
                                   WHERE supervisor_id = 0 OR supervisor_id IS NULL
                             ) A
                             WHERE A.employee_id_1 = Z.supervisor_id
                        ) A
                        WHERE A.employee_id_2 = Z.supervisor_id
                   ) A
                   WHERE A.employee_id_3 = Z.supervisor_id
              ) A
              WHERE A.employee_id_4 = Z.supervisor_id
         ) A
         WHERE A.employee_id_5 = Z.supervisor_id
    ) A
    WHERE A.employee_id_6 = Z.supervisor_id
    UNION
    SELECT DISTINCT
         A.employee_id_6 AS employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         A.supervisor_id_3,
         A.employee_id_3,
         A.full_name_3,
         A.supervisor_id_4,
         A.employee_id_4,
         A.full_name_4,
         A.supervisor_id_5,
         A.employee_id_5,
         A.full_name_5,
         A.supervisor_id_6,
         A.employee_id_6,
         A.full_name_6,
         NULL AS supervisor_id_7,
         NULL AS employee_id_7,
         NULL AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              A.supervisor_id_1,
              A.employee_id_1,
              A.full_name_1,
              A.supervisor_id_2,
              A.employee_id_2,
              A.full_name_2,
              A.supervisor_id_3,
              A.employee_id_3,
              A.full_name_3,
              A.supervisor_id_4,
              A.employee_id_4,
              A.full_name_4,
              A.supervisor_id_5,
              A.employee_id_5,
              A.full_name_5,
              Z.supervisor_id AS supervisor_id_6,
              Z.employee_id AS employee_id_6,
              Z.full_name AS full_name_6
         FROM employee Z,
              SELECT DISTINCT
                   A.supervisor_id_1,
                   A.employee_id_1,
                   A.full_name_1,
                   A.supervisor_id_2,
                   A.employee_id_2,
                   A.full_name_2,
                   A.supervisor_id_3,
                   A.employee_id_3,
                   A.full_name_3,
                   A.supervisor_id_4,
                   A.employee_id_4,
                   A.full_name_4,
                   Z.supervisor_id AS supervisor_id_5,
                   Z.employee_id AS employee_id_5,
                   Z.full_name AS full_name_5
              FROM employee Z,
                   SELECT DISTINCT
                        A.supervisor_id_1,
                        A.employee_id_1,
                        A.full_name_1,
                        A.supervisor_id_2,
                        A.employee_id_2,
                        A.full_name_2,
                        A.supervisor_id_3,
                        A.employee_id_3,
                        A.full_name_3,
                        Z.supervisor_id AS supervisor_id_4,
                        Z.employee_id AS employee_id_4,
                        Z.full_name AS full_name_4
                   FROM employee Z,
                        SELECT DISTINCT
                             A.supervisor_id_1,
                             A.employee_id_1,
                             A.full_name_1,
                             A.supervisor_id_2,
                             A.employee_id_2,
                             A.full_name_2,
                             Z.supervisor_id AS supervisor_id_3,
                             Z.employee_id AS employee_id_3,
                             Z.full_name AS full_name_3
                        FROM employee Z,
                             SELECT DISTINCT
                                  A.supervisor_id_1,
                                  A.employee_id_1,
                                  A.full_name_1,
                                  Z.supervisor_id AS supervisor_id_2,
                                  Z.employee_id AS employee_id_2,
                                  Z.full_name AS full_name_2
                             FROM employee Z,
                                  SELECT DISTINCT
                                       supervisor_id AS supervisor_id_1,
                                       employee_id AS employee_id_1,
                                       full_name AS full_name_1
                                   FROM employee
                                   WHERE supervisor_id = 0 OR supervisor_id IS NULL
                             ) A
                             WHERE A.employee_id_1 = Z.supervisor_id
                        ) A
                        WHERE A.employee_id_2 = Z.supervisor_id
                   ) A
                   WHERE A.employee_id_3 = Z.supervisor_id
              ) A
              WHERE A.employee_id_4 = Z.supervisor_id
         ) A
         WHERE A.employee_id_5 = Z.supervisor_id
    ) A
    UNION
    SELECT DISTINCT
         A.employee_id_5 AS employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         A.supervisor_id_3,
         A.employee_id_3,
         A.full_name_3,
         A.supervisor_id_4,
         A.employee_id_4,
         A.full_name_4,
         A.supervisor_id_5,
         A.employee_id_5,
         A.full_name_5,
         NULL AS supervisor_id_6,
         NULL AS employee_id_6,
         NULL AS full_name_6,
         NULL AS supervisor_id_7,
         NULL AS employee_id_7,
         NULL AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              A.supervisor_id_1,
              A.employee_id_1,
              A.full_name_1,
              A.supervisor_id_2,
              A.employee_id_2,
              A.full_name_2,
              A.supervisor_id_3,
              A.employee_id_3,
              A.full_name_3,
              A.supervisor_id_4,
              A.employee_id_4,
              A.full_name_4,
              Z.supervisor_id AS supervisor_id_5,
              Z.employee_id AS employee_id_5,
              Z.full_name AS full_name_5
         FROM employee Z,
              SELECT DISTINCT
                   A.supervisor_id_1,
                   A.employee_id_1,
                   A.full_name_1,
                   A.supervisor_id_2,
                   A.employee_id_2,
                   A.full_name_2,
                   A.supervisor_id_3,
                   A.employee_id_3,
                   A.full_name_3,
                   Z.supervisor_id AS supervisor_id_4,
                   Z.employee_id AS employee_id_4,
                   Z.full_name AS full_name_4
              FROM employee Z,
                   SELECT DISTINCT
                        A.supervisor_id_1,
                        A.employee_id_1,
                        A.full_name_1,
                        A.supervisor_id_2,
                        A.employee_id_2,
                        A.full_name_2,
                        Z.supervisor_id AS supervisor_id_3,
                        Z.employee_id AS employee_id_3,
                        Z.full_name AS full_name_3
                   FROM employee Z,
                        SELECT DISTINCT
                             A.supervisor_id_1,
                             A.employee_id_1,
                             A.full_name_1,
                             Z.supervisor_id AS supervisor_id_2,
                             Z.employee_id AS employee_id_2,
                             Z.full_name AS full_name_2
                        FROM employee Z,
                             SELECT DISTINCT
                                  supervisor_id AS supervisor_id_1,
                                  employee_id AS employee_id_1,
                                  full_name AS full_name_1
                              FROM employee
                              WHERE supervisor_id = 0 OR supervisor_id IS NULL
                        ) A
                        WHERE A.employee_id_1 = Z.supervisor_id
                   ) A
                   WHERE A.employee_id_2 = Z.supervisor_id
              ) A
              WHERE A.employee_id_3 = Z.supervisor_id
         ) A
         WHERE A.employee_id_4 = Z.supervisor_id
    ) A
    UNION
    SELECT DISTINCT
         A.employee_id_4 AS employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         A.supervisor_id_3,
         A.employee_id_3,
         A.full_name_3,
         A.supervisor_id_4,
         A.employee_id_4,
         A.full_name_4,
         NULL AS supervisor_id_5,
         NULL AS employee_id_5,
         NULL AS full_name_5,
         NULL AS supervisor_id_6,
         NULL AS employee_id_6,
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