Parsing hexadecimal strings

im an fresher currently in a project on secure hash algorithm
my project is stopped due to certain reasons , further which i cannot proceed.
i woud be grateful to u if some one provides solution to my problem.
int a = (word[i] << 1) or (word[i] >> 32-n)
word is an array that consist of hexadecimal string .
the thing here is for instance , 0x2g46778, 2g46778
when u print(both, individually) using System.out.println yields different results.
the scenario is i have derived word array that consist only number without 0x extension ,
but result yielded is wrong as for the reason mentioned above.
but when i take an array that consist of 0x as string and concat it with every element of word array i get the full number (i.e 0x 2hg4kr7)
again the problem is parsing the hexadecimal string(with ox as extension)
Query:
please tell me whether their is any way for parsing hexadecimal string as ox is not recognized.
or
how to proceed with it such that my string get parsed.
thank u
sincerly
hari hara ganesh dharmarajan
india`

Could you post some sample input and desired output for your project?
What is an array of hex string?
Is it String[] with the contents of each string consisting of the char a-f and 0-9? Eg String[] xx = new String[] {"1234", abcd"};
What does "parsing a hex string" mean? Give an example please.

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I want to parse a string such as
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A bit of a "sticky tape"-solution...
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How to Parse a string into an XML DOM ?

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Download Xerces from xml.apache.org. Place the relevant JAR's on your classpath. Here is sample code to get a DOM document reference.
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Parsing formatted String to Int

How can I parse formatted string to Integer ?
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I tried something like this
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I am working on the JSP file that provides
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That's why I get it as a formatted string and why I
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Converting a Hexadecimal String to a Binary String

Hello NG,
I would like to convert an 8 Bit Hexadecimal String (example C0034000)
to it´s equivalent in binary (in this case---> 1100 0000 0000 0011...
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talking about the simple representation on the front pannel. Some
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> I would like to convert an 8 Bit Hexadecimal String (example C0034000)
> to it´s equivalent in binary (in this case---> 1100 0000 0000 0011...
> and so on), I didn´t find any possible way to do this. I´am not
> talking about the simple representation on the front pannel. Some
> Postings say that this ist possible with the "Format Value" Function
> adding an "%b" to the entring, but in my case it does not function.
The task here is to convert a string to a different string. The easiest
way to do this is to convert the string to a numer, then format the
number as a binary string.
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change a hex string into a numeric integer. The Format to String with
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Converting a hexadecimal string to ASCII-characters.

I have long hexadecimal strings that I wish to convert to their corresponding ascii-characters. I know there are a series of functions for doing things like this - hex to number, number to string etc.
At the moment, however, I am stuck at entering the hexadecimal string. I connect it to "hexadecimal string to number". What I get out is the decimal value of the two last digits of the hexadecimal number. No other wires are connected to the function. This means data is lost. How do I get around this? Is this particular function at all suitable for what I am trying to do?

Hi Tzench,
"hexadecimal string" isn't very accurate and conversion questions have been discussed many times before...
See example on conversion of two different "hexadecimal" strings. There are other conversion methods, but those are most easiest to understand
Message Edited by GerdW on 12-08-2008 11:27 AM
Best regards,
GerdW
CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
Kudos are welcome
Attachments:
HexString_LV71.vi ‏35 KB

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Thanx a lot !

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Date contructor deprecation : Parsing a String to Date

Hi All,
In Java 1.5 the Date() constructor Date(String s) is deprecated. As per the API Documentation DateFormat.Parse() method is used.
The following code from Java 1.4 version has to be upgraded to Java 1.5.
Existing Code:
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Modified Code:
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Hi All,
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The following code from Java 1.4 version has to be
upgraded to Java 1.5.
Existing Code:
Date dDate = new Date(sDate);
Modified Code:
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Date dDate = df.parse(sDate);
Here the DateFormat accepts a default formatting
style as "Feb 01, 2007" and parses the String.
If the String sDate belongs to any other formatting
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Please give your thougts on this issue to parse the
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>
Thanks,
Rajesh.

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This might help you. If you want to handle the cursor in java, then convert the below into a function which returns the cursor.
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2 /
Table created.
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1 row created.
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2 AS
3 TYPE EmpCurTyp IS REF CURSOR;
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Hi All,
I want to parse a string and rank it in a given order.
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Parsed string order
D 1
C 2
B 3
A 4
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A database version would help us providing you with a relevant solution.
Starting with 10g, you can do :
SQL> var my_str varchar2(30)
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PL/SQL procedure successfully completed
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3 from (
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5    from dual
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D                          1
C                          2
B                          3
A                          4
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2 from xmltable(
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D                   1
C                   2
B                   3
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Edited by: odie_63 on 11 janv. 2012 12:56 - added 11.2

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END IF
LOOP
I have incorporated the same logic in PL/SQL but I am looking for something similar to the ReplaceA function in PB, that will replace at a certain point in a string. I use an '*' as a placeholder and measure the length. Below is the PL/SQL code:
t_pos NUMBER;
t_old_pos NUMBER;
t_length NUMBER;
BEGIN
t_old_pos := 0;
t_pos := INSTR(in_model_list, '*');
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NULL;
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t_pos := INSTR(in_model_list, '*', t_pos + 1);
END IF;
NULL;
END LOOP;
Here is the data, what it looks like: William 112,* 500-A,* 500-U,* 520,* 560-A,* 560-E,* 680-E,* 680-F,* 680-V*
Any help would be much appreciated.
Thank you,
William
Edited by: William on Feb 28, 2012 6:56 AM

Frank Kulash wrote:
[example]I played with your example and came to this:SQL> WITH my_string AS
2         (SELECT '1234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890'
3                   AS mt
4            FROM DUAL)
5     , line_length AS
6         (SELECT 13 AS chars
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9             ||chr(10)
10             ||substr(mt,-mod(LENGTH (mt),line_length.chars)) as wrapped_text
11        FROM my_string
12        CROSS JOIN line_length
13 CONNECT BY LEVEL < 1+LENGTH (mt) ;
WRAPPED_TEXT
1234567890123
4567890123456
7890123456789
0123456789012
3456789012345
6789012345678
9012345678901
2345678901234
5678901234567
8901234567890
1234567890123
WRAPPED_TEXT
4567890123456
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SQL>*[Edit]* annotated that this is 11g only...
Edited by: T.PD on 29.02.2012 21:17

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Hi,
I'm having a problem with parsing a string. Basically, I want to take a string for example: "TomWentToTheShop" and divide it into a coherent sentence (Tom went to the shop).
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thanks.
char[] charRequestTypeArray = string.toCharArray();
for (int i = 1; i < (charRequestTypeArray.length -1); i++) {
char c = charRequestTypeArray;
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I'm trying to find an easy way to parse a string like this
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String toParse=(Sony)(VZ-12324)(1);Is there a simple way of parsing the string to the "(" and ")" are omitted and brand=Sony;
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number="1";
???

String toParse = "(Sony)(VZ-12324)(1)";
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int number = Integer.parseInt(parts[5]);
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System.out.println(model);
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