Patters for avoiding the '/' (in java.util.regex)

Hi all ,
i wanted to knw the pattern format (in java.util.regex) for avoiding the '/' at the begenning of a line ....... hope to get the best answers ....
thnx 'n cheers
max

first of thnx for the quick responses .... !
what i am really trying to do here is to avoid all lines which are starting with a comment ( '//' or '/*' ) .
-> I am checking for all lines and inserting a line of code just before a particular statement , the only thing is that statement which i am looking for should not be inside a comment ( '//' or '/*' ) .... hope u got the thing
thnx
max

Similar Messages

Regular Expressions (java.util.regex)

I am developing using a product that must
use java 1.2.2_05a but I want to use regular
expressions, does anybody know where I can
get of the package java.util.regex without
having to download the whole java 1.4 release.
Or does someone know of an alternative that
I can use ?

There is another regex pack for java available from Apache Foundation Project. You can try it.
Take a look at http://jakarta.apache.org/

RFC used for java.util.regex

Hi,
Does anyone know the RFC used for java.util.regex ??
Thanks & Regards,
Gurushant Hanchinal

Can you please give me the link to view to specifications for java.util.regex.. I have tried the link which is available in :
http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html page with name " Java Language Specification"
on click of this link, i am getting page not found error..
Please give me any other alternate links to view the regular expression specifications..
Thanks,
Gurushant Hanchinal

About the error of java.util.regex in jdk1.4's docs

In java.util.regex,the class Pattern's document says:
Greedy quantifiers
X? X, once or not at all
X* X, zero or more times
X X, one or more times
X{n} X, exactly n times
X(n,} X, at least n times
X{n,m} X, at least n but not more than m times
Why don't metion �X+�?
I think that should be "X+ X, one or more times",right?

Agreed. I use Regex in many places (and used
Oromatcher before 1.4), and I've verified that I
use the + operator in several places-- it works.

Who use sql-mapping with java.util.regex?

Hi everyone:
I use the IBatis SQL-Mapping and I think it is very good.Now I want to add the search function to my BBS forum.I also want to display the content high light like jive.I mean that if I want to find the string "ibatis",then the search result "ibatis" will be high light displayed.
So I must use the java.util.regex in jsdk1.4.But the problem is that what I get is a List if I use sql-mapping.For example:
          String resource="conf/XML/sql/lyo-sql-map.xml";
          Reader reader=Resources.getResourceAsReader(resource);
          sqlmap=XmlSqlMapBuilder.buildSqlMap(reader);
          List articlelist=sqlmap.executeQueryForList("selectSiteArticle","%"+icontent+"%");
The result I get is a List and I have no time to use regex.
I don't know whether I could do this:
Iterate the List,use the regex and later place all the object back to the List.
It's right?
How to use regex with sql-mapping?Thks

Any idea? :(

Parsing xhtml using java.util.regex

I am parsing an XHTML file using the java.util.regex package and I am perplexed at why the following doesn�t work.
The lines I wish to match are either like this:
Some String.</td>
or
Some String.</td>
The code I use to try to achieve this is:
Pattern somePattern = Pattern.compile(".*()?(.*)[.]()?</td>.*");
String s = null;
while((s = br.readLine()) != null) {
if(somePattern.matcher(s).matches()) {
System.out.println("0:" + eventMatcher.group(0));
System.out.println("1:" + eventMatcher.group(1));
System.out.println("2:" + eventMatcher.group(2));
System.out.println("3:" + eventMatcher.group(3));
I expect to get as output
0:Some String.</td> 1:
2:Some String
3:
or
0:Some String.</td>
1:null
2:Some String
3:null
depending on which lines provide the match as mentioned above. Instead I get:
0:Some String.</td>
1:null
2:(empty string)
3:
or
0:Some String.</td>
1:null
2:(empty string)
3:null
Any ideas? Thanks in advance.

Consider the terms of ".*()?(.*)[.]()?</td>.*"
.* - greedily collect characters
()? - optionallly collect information taht will always be matched by the previous .* pattern so will be empty.
(.*) - greedily collect characters that will also have been swallowed by the first .* so will be empty
[.] - a single .
()? - optionally collection
</td> - must be there
.* - collect the rest of the charcters in the line.
Therefore in general groups 1 and 2 will be empty because the first .* will have collected the information you wanted to capture!
You could just make the first .* non-greedy by using .*? but this may fail for other reasons.
So, in general terms, what are you trying to extract?

Doubt in Regular Expressions : java.util.regex

I want to identify words starting with capital letters in a sentence and I want to replace the matched word with "#" added in front of it.... For example, if my input sentence is
"Christopher Williams asked Mike Muller a question"
my output should be,
"#Christopher #Williams asked #Mike #Muller a question"
How do I do that using java.util.regex ?
In perl we can can use *"back references"* in *"replacement string"* . Perl replacement accepts back references whereas java replacement method accepts only strings....
Please help me.....

Your replacement is swallowing the space before the uppercase character, and won't match at the beginning of the line.
Also, it's unnecesarily verbose. String has a replaceAll method (that calls the same methods of Pattern and Matcher under the covers)sentence = s.replaceAll("(^| )([A-Z])", "$1#$2");Disclaimer: I'm no prome, sabre or u/a :-) That can probably be simplified.
db

Regular expressions with java.util.regex

Hello Guys,
I wrote last time this
* Uses split to break up a string of input separated by
* commas and/or whitespace.
* See: http://developer.java.sun.com/developer/technicalArticles/releases/1.4regex/
* Change: I have slightly modified the source
import java.util.regex.*;
public class Splitter {
public static void main(String[] args) throws Exception {
// Create a pattern to match breaks
Pattern p = Pattern.compile("[<>\\s]+");
// Split input with the pattern
String[] result =
p.split("<element attributname1 = \"attributwert1\" attributname2 = \"attributwert2\">");
for (int i=0; i<result.length; i++)
if (result.equals(""))
System.out.println("EMPTY");
else
System.out.println(result[i]);
int res = result.length - 1;
System.out.println("\nStringlaenge: " + res);
I wonder, why I got an empty element in reult[0]. Have anyone an idea?
We'll come together next time
... �nhan Inay ([email protected])

What is wrong with this Pattern?
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
This time i used following Split:
p.split("<element attributname1=\"attributwert1\" attributname2=\"attributwert2\">");
I've got a compilation error:
U:\qms_neu\htdocs\inay\Source\myWork\Regex-Samples>javac Splitter.java
Splitter.java:14: illegal start of expression
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:14: illegal character: \92
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:14: illegal character: \92
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:14: unclosed string literal
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:17: ')' expected
p.split("<element attributname1=\"attributwert1\" attributname2
=\"attributwert2\">");
^
Splitter.java:14: unexpected type
required: variable
found : value
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:18: cannot resolve symbol
symbol : variable result
location: class Splitter
for (int i=0; i<result.length; i++)
^
Splitter.java:19: cannot resolve symbol
symbol : variable result
location: class Splitter
if (result.equals("")){
^
Splitter.java:21: cannot resolve symbol
symbol : variable result
location: class Splitter
System.out.println(result[0]);
^
Splitter.java:24: cannot resolve symbol
symbol : variable result
location: class Splitter
System.out.println(result[i]);
^
Splitter.java:25: cannot resolve symbol
symbol : variable result
location: class Splitter
int res = result.length - 1;
^
11 errors

WHERE to find [b]java.util.regex.*[\b] package?

Does anyone know where to obtain a copy of the java.util.regex.* package (separate package)? This is a new package included in version 1.4.0.

Does anyone know where to obtain a copy of the
java.util.regex.* package (separate package)?
This is a new package included in version 1.4.0.Simple:
Go to your java sdk directory
$ jar xvf src.jar
$ cd java/util/regex
$ javac ASCII.java
$ javac Matcher.java
$ javac Pattern.java
$ javac PatternSyntaxException.java
$ cd ../../..
$ jar cvf regex.jar java/util/regex/*.class
et voila; how difficult can that be ? There is no native, JVM depending stuff in there, although I did not check for dependencies on other new stuff inside the jdk.
I'm also unaware if this isn't illegal under the agreement with Sun.

[bug]Jdev 11g:NullPointerException at java.util.regex.Matcher.getTextLength

Hi,
Jdev 11.1.1.0.31.51.56
If somebody of you get the following trace stack when running a jspx using ViewCriteriaRow.setOperator :
There is bug 7534359 and metalink note 747353.1 available.
java.lang.NullPointerException
at java.util.regex.Matcher.getTextLength(Matcher.java:1140)
at java.util.regex.Matcher.reset(Matcher.java:291)
at java.util.regex.Matcher.<init>(Matcher.java:211)
at java.util.regex.Pattern.matcher(Pattern.java:888)
at oracle.adfinternal.view.faces.model.binding.FacesCtrlSearchBinding._loadFilter
CriteriaValues(FacesCtrlSearchBinding.java:3695)
Truncated. see log file for complete stacktrace
Workaround:
If you use
 vcr.setAttribute("Job",job);
or
 vcr.setAttribute("Job","="+job);
than add following line of code:
 vcr.setOperator("Job","="); regards
Peter

Hi,
useful to mention that this happens when setting the equal operator or LIKE operator
vcr.setAttribute("Job","= '"+job+"'");
or
vcr.setOperator("Job","=");
Frank

Please help on java.util.regex.*

Hi all,
My RTF file looks like this:
Project Num\tab N/A
\par Project Name\tab Hook-up Installation and Service
\par
My intension is to read the file until the \tab and store Project Num as a string into a
variable. Similarly read until \par and store the value of Project Num into another variable.
So that i can use those variables further in my program.
I used java.util.regex.* package for this purpose. I could successfully split the sentence whenever it sees \tab and \par but don't know how to get the text before and after the delimeters and store them into variables.
The code which i wrote is:
import java.util.regex.*;
import java.io.*;
import java.nio.*;
import java.nio.charset.*;
import java.nio.channels.*;
public class RegexDemo{
public static void main(String[] args){
// Create a pattern to match breaks
Pattern p = Pattern.compile("\\\\.[a-z][a-z]",Pattern.DOTALL);
try{
File file = new File("sample.rtf");
FileInputStream fis = new FileInputStream(file);
FileChannel fc = fis.getChannel();
// Get a CharBuffer from the source file
ByteBuffer bb = fc.map(FileChannel.MapMode.READ_ONLY, 0, (int)fc.size());
Charset cs = Charset.forName("8859_1");
CharsetDecoder cd = cs.newDecoder();
CharBuffer cb = cd.decode(bb);
// Run some matches
Matcher m = p.matcher(cb);
while (m.find())
System.out.println("Found comment: "+m.group());
}catch(Exception e){
e.printStackTrace();
Please somebody help me in this regard. I have spent lot of time searching the forums but couldn't find any solution.
Thanks in advance
rnallu

Just put target inside parenthesis with delimiters at boundaries.
Example: "(\\w+)\\t(\\d)\\s" will match occurrences of a word followed with a tab char then a digit followed with a whitespace. If target string matches pattern then m.group(1) contains the word and m.group(2) contains the digit.

Java.util.regex error

Hello,
I checked JavaDoc multiple times but do not see what is wrong with
myString.replaceAll("D:\\web\\mars","")which results in
java.util.regex.PatternSyntaxException: Illegal/unsupported escape squence near index 7
D:\web\mars
 ^
 at java.util.regex.Pattern.error(Unknown Source)
 at java.util.regex.Pattern.escape(Unknown Source)
 at java.util.regex.Pattern.atom(Unknown Source)
 at java.util.regex.Pattern.sequence(Unknown Source)
 at java.util.regex.Pattern.expr(Unknown Source)
 at java.util.regex.Pattern.compile(Unknown Source)
 at java.util.regex.Pattern.<init>(Unknown Source)
 at java.util.regex.Pattern.compile(Unknown Source)
 at java.lang.String.replaceAll(Unknown Source)
 at ArticleImageImportProcessor.main(ArticleImageImportProcessor.java:40)
Exception in thread "main" please, every suggestion/hint is most appeciated

You have to "encode" backslash twice, first for String purpose and second time because of special meaning of '\' in regular expressions.
It should looks like
myString.replaceAll("D:\\\\web\\\\mars","")

Import the classes in the package java.util

I haven't taken a class in two years so I have ideas but am unsure of myself, and I most likely am way off base, but is this how you import the classes in the package java.util
import java.util.*;
I would appreciate anyone's help. I have a lot of questions.
Thanks,
rp

My assignment is below so that you will know exactly what I am asking. I am being asked to create an instance of LinkedList. I know that this is a part of the java.util. So when you create an instance of LinkedList would that be similar to instance variables? or am I misunderstanding something. I have several ideas, so I will start with the first one.
LinkList();
I really appreciate your taking the time to answer my questions to help me to rebuild my confidence in doing this.
Thanks,
// 2. import the classes in the package java.util
public class MyProgram
     public static void main(String [] args)
          // 3. Create an instance of LinkedList
          // 4. add 5 entries to the list so that it contains
          //     Ann, Bart, Carl, Dirk, Zak
          // 5. display the list on one line using a loop and ADT list methods
          System.out.println("\n\n3. ");
          // 6. display the list using one println
          System.out.println("\n\n4. ");
          // 7. create a ListIterator object for the list
          // 8. display the list on one line using the iterator
          System.out.println("\n\n6. ");
          // 9. restore the iterator to the first item in the list
          // 10. retrieve and display the first item in the iteration,
          //      then advance the iterator to the next item
          System.out.println("\n\n8. ");
          // 11. advance the iterator to the end of the list without displaying anything;
          //      do not use the length of the list
          // 12. display the last item in the list
          System.out.println("\n\n10. ");
          // 13. move back to the beginning of the list without displaying anything;
          //      do not use the length of the list
          // 14. display the first item in the list
          System.out.println("\n\n12. ");
          // 15. advance the iterator to the end of the list without displaying anything;
          // 16. advance the iterator - what happens?
          System.out.println("\n\n14. ");
          // 17. advance the iterator within a try block; catch the exception, display a message,,
          //      and set the iterator back to the beginning of the list.
          System.out.println("\n\n15. ");
          // 18. what does nextIndex and previousIndex return?
          System.out.println("\n\n16. ");
          // 19. move the iterator to the third item in the list; if you were to
          //      execute next(), the third item would be returned and the iterator
          //      would advance to the 4th item.
          System.out.println("\n\n17. ");
          // 20. add the string "New" to the list; where is it inserted relative to
          //      the current item in the iteration?
          System.out.println("\n\n18. ");
          // 21. remove the current item; what happens?
          System.out.println("\n\n19. ");
          // 22. display the current item in the list without advancing the iteration
          //      in 2 ways, as follows:
          // 22A - using only iterator methods
          System.out.println("\n\n20A. ");
          // 22B using an iterator method and list methods
          System.out.println("\n\n20B. ");
          // 23. advance the iterator and remove the current item; which one is removed?
          System.out.println("\n\n21. ");
          // 24. move the iterator back and remove the current item; which one is removed?
          System.out.println("\n\n22. ");
          // 25. move the iterator to the first item in the list and change it to "First"
          System.out.println("\n\n23. ");
     } // end main
} // end MyProgram

The import "java.util.scanner" is not vaild

I am experiment with the java.util.scanner API after compiling the code below I received the following error:
The import "java.util.Scanner" is not valid, since it does not name a type in a package.
I declared a string variable should that suffice?
import java.util.Scanner;
public class Echo {
public static void main (String[] args)
String message;
Scanner scan = new Scanner (System.in);
System.out.println ("enter something:");
message = scan.nextLine();
System.out.println ("hey you entered: \"" + message + "\"");
}

Most IDEs let you select and installed JDK for them to use. Check out that IDE's preferences.
Otherwise, start here and learn to do it with a simple text editor or programmer's editor, and the command line.
http://java.sun.com/docs/books/tutorial/getStarted/cupojava/

Ignore word (Java.util.regex )

Hello All,
Can anyone help me to solve this probelm:
Probelm: I have a text file and i want to search a word or combination of words in that using java.util.regex
Example : in the sentence "things like the Forestry in the Commission (FC)." i want to search "Forestry Commission" while ignoring the word "in the". This ignoring criteria is specific i.e. search return true only if it ignore "in the" word not any other word.
Also how i ignore multiple words in ignore condition.
Thanks in advance.

Try out this line of code:
System.out.println("Forestry in the Commission".replaceAll("Forestry\\s(.*?\\s)?Commission", "Hello"));In EBNF, it looks like this:
match ::= "Forestry" <whitespace> [<character> <whitespace>] "Commission"
whitespace ::= <space> | \t | \n | \x0B | \f | \r
character ::= (any one character)
This, of course, is an ambiguous EBNF definition. The breakdown of the expression, however, reveals why this works. In the string, "\\s" refers to a character of whitespace. "(.*?\\s)?" is where the magic happens: it causes ".*?\\s" to happen either not at all or once. ".*?" will consume as few "." (any character) as possible to make the match, and the following "\\s" is to make sure that strings like "Forestry deCommission" don't match. The EBNF's ambiguity comes from EBNF's lack of ability to describe "reluctant qualifiers": qualifiers that indicate that as few of the given expression should be matched as possible.
Cheers!

Patters for avoiding the '/' (in java.util.regex)

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