PDW : Hierarchy parent/child
Hi,
I'm working with a PDW Appliance as source and destination.
I need to create a parent/child hierarchy.
My child surrogate key is generated inside my dataflow, then I'm doing the initial loading of all my data minus the surrogate key for the parent column.
I'd like to avoid to run update statements against my destination table (because of the replication) and/or have to create temp tables.
I thought about keeping in memory (Recordset Destination) all my dataset and then doing the look up in a script component before doing the final insert in append mode but the performance are awful.
Any idea ?
Thx for your help.
Bertrandr
Thanks to have remind me about the CacheTransform component :)
The dataset is about 200 000 rows.
I have also tested another option.
Instead of performing an initial load and then look up
I'm doing a multicast pointing to 2 RecordSet Destination.
Both are the same except it's 2 differents object variables.
Then in another dataflow I read both dataset and use a MergeJoin on the business key to get my parent surrogate key.
It works but I need to compare performances with your solution.
Thanks a lot !
Bertrandr
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No data for Parent-child hierarchy column in Pivot table view
Hi all,
I used OBIEE 11.1.1.6.2 Version.
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regards,
AnneHi,
Yes, I have the same problem with pivot table for hierarchy dimension.
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Parent Child Hierarchy Issue in OBIEE 11g
Hi All,
I am in OBIEE 11G v6. I have a sales fact table where the grain is one sale. So I have one row for every sale done.
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David >>Richard>>Sean
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Thanks
RonnySo basically this means that if I build a parent child hierarchy on table A having the stucture like
--David (Manager)
-----James (Off1)
--------Bill (Off2)
and in my sales fact table for let's say today, I have only rows for Bill (Off2) because he is the only officer who did the sales today. Now when I will join my fact table to parent child hierarchy table A I will NOT get any data ? because there is no James who is the parent of Bill. So obiee need to have parent pulled off in the data (ANCESTOR) to be able to roll up the child.(IS_LEAF = 1)
I testes this and if my data only contains only rows for Bill (or I limit on ROLE = Off2) then it won't show the hierarchy. The query which OBIEE fires is to look for either ANCESTOR_KEY = NULL OR (DISTANCE = 1 AND ANCESTOR KEY IN (Bill). Therefore it doesn't I am wondering then what is the use of builiding the parent child hierarchy when we need to pull in all the ancestors (like in this case James for bill and David for james) because in real scenarios there can be cases wherein we would want to filter the data based on other dimensions to which the parent child hierarchy joins ? -
How to update a parent child hierarchy in OBIEE
Hello All
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Dynamic hierarchy in parent child hierarchy table??
Do you have any experience to handle the requirement of dynamic hierarchy in universe/webi?
We have some data in parent child hierarchy as below u201CCustomeru201D table.
Customer
Parent Child
Z A
Z B
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ID Amt
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notes **
the level of hierarchy is dynamic
Any suggestion is appreciated. Thanks.Hi,
The only way to do it is to create recursive derived table that flatten you parent child hierarchy with a given maximum depth.
Here is a sample I built a long time ago to flatten a parent-child hierarchy on Employees table in Foodmart database (SQL Server).
Didier
SELECT DISTINCT
Z.employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
A.supervisor_id_6,
A.employee_id_6,
A.full_name_6,
Z.supervisor_id AS supervisor_id_7,
Z.employee_id AS employee_id_7,
Z.full_name AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
Z.supervisor_id AS supervisor_id_6,
Z.employee_id AS employee_id_6,
Z.full_name AS full_name_6
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
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A.supervisor_id_4,
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A.full_name_4,
Z.supervisor_id AS supervisor_id_5,
Z.employee_id AS employee_id_5,
Z.full_name AS full_name_5
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
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employee_id AS employee_id_1,
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FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
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WHERE A.employee_id_1 = Z.supervisor_id
) A
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) A
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SELECT DISTINCT
A.employee_id_6 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
A.supervisor_id_6,
A.employee_id_6,
A.full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
Z.supervisor_id AS supervisor_id_6,
Z.employee_id AS employee_id_6,
Z.full_name AS full_name_6
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
Z.supervisor_id AS supervisor_id_5,
Z.employee_id AS employee_id_5,
Z.full_name AS full_name_5
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
WHERE A.employee_id_4 = Z.supervisor_id
) A
WHERE A.employee_id_5 = Z.supervisor_id
) A
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A.employee_id_5 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
Z.supervisor_id AS supervisor_id_5,
Z.employee_id AS employee_id_5,
Z.full_name AS full_name_5
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
WHERE A.employee_id_4 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_4 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
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SELECT DISTINCT
A.employee_id_3 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
NULL AS supervisor_id_4,
NULL AS employee_id_4,
NULL AS full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
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A.supervisor_id_1,
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A.full_name_1,
A.supervisor_id_2,
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A.full_name_2,
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NULL AS employee_id_3,
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NULL AS employee_id_4,
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NULL AS supervisor_id_6,
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NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
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A.employee_id_1,
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Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_1 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
NULL AS supervisor_id_2,
NULL AS employee_id_2,
NULL AS full_name_2,
NULL AS supervisor_id_3,
NULL AS employee_id_3,
NULL AS full_name_3,
NULL AS supervisor_id_4,
NULL AS employee_id_4,
NULL AS full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A -
Parent child hierarchy and measure using lookup
Hi,
I'm using OBIEE 11.1.1.5 and I have an issue with a parent child hierarchy, which is setup like case 4 in this example . When I create a simple analysis using the hierarchy and a simple measure, it works fine. But when I try to use a calculated measure using a lookup formula, I get the following error:
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 43113] Message returned from OBIS. [nQSError: 43119] Query Failed: [nQSError: 46036] Internal Assertion: Condition pTableRef->GetLeftTable() && pTableRef->GetLeftTable()->IsTableReference(), file server/Query/Optimizer/ServiceInterfaceMgr/Src/SQOIDriveJoinGenerator.cpp, line 568. (HY000)
Does anyone know how to get past this error?
Thanks,
MihaiHi,
I'm using OBIEE 11.1.1.5 and I have an issue with a parent child hierarchy, which is setup like case 4 in this example . When I create a simple analysis using the hierarchy and a simple measure, it works fine. But when I try to use a calculated measure using a lookup formula, I get the following error:
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 43113] Message returned from OBIS. [nQSError: 43119] Query Failed: [nQSError: 46036] Internal Assertion: Condition pTableRef->GetLeftTable() && pTableRef->GetLeftTable()->IsTableReference(), file server/Query/Optimizer/ServiceInterfaceMgr/Src/SQOIDriveJoinGenerator.cpp, line 568. (HY000)
Does anyone know how to get past this error?
Thanks,
Mihai -
Parent-Child Hierarchy Show No Data
Hi:
OBIEE 11.1.1.6.5
I created a parent-child hierarchy following multiple examples in books and on the web. I can pull the presentation hierarchy--by itself--into a view and drill up and down. But when I add a measurement from the fact table, I receive a no data found error. I copied the SQL into SQL*Developer and ran it, and it too returned no data. I've tried to read and debug the query in SQL*Developer, but I don't understand what it is doing.
The dimension table I am using for the parent-child hierarchy has a cost_Center_id and parent_cost_center_id. I used the Parent-Child dimension wizard to create and populate the new hierarchy table.
I can create a view by using the cost_center item and a fact table measurement without the presentation hierarchy, so it has something to do with the presentation hierarchy.
I've been at this for a few days now, and I've run out of ideas. Can anyone suggest what I may have done wrong?
Thanks.check if there is data in the fact table.. Next check also if the join condition between the dimension and fact is valid.
-
Parent Child Hierarchy for Type 2
I have read the articles on Parent Child hierarchy setup in OBIEE 11g, however, most are based on what seems to be a current snapshot of the Employee-Manager relationship. Has anyone tried to build out a Parent-Child hierarchy/table off a Type 2 dimension. Being able to navigate what the hierarchy may have been on a specific date.
I would welcome any feedback, thanks.Hi,
Thanks for the reply, I'm actually using snapshots. But even with the Type 2 Dim I don't think it will work.
When OBIEE generates the very first sql against the Parent-Child table the fact table is not included in the query. It seems to create 2 queries - one to find the top level parent (ancestor key is null) and then one to find all the leaf nodes.
It does not have any join to the fact table when it does this. So if you have multiple rows in the table (with date stamps) for a single row (person in this case) - it picks up both rows. Therefore, when you have a person who was, say, promoted to manager, and WAS a leaf node, and is now a manager, they show up in the leaf query and don't display in the hierarchy as a manager.
Once it has the leaf nodes and it joins to the fact table everything works (ie the surrogate key join).
I'm trying to figure out if there is any way to influence those initial queries against the parent-child table.
Hopefully that made sense.
Thanks,
Tori -
Parent-Child hierarchy based on two-column key
Hello
Is it possible to create a parent-child hierarchy, if the primary key of the table consists of two columns?
My table looks like:
TRACE_ID | DIAG_ID | SUPER_DIAG_ID
with TRACE_ID and DIAG_ID as PK.
If I define only DIAG_ID as PK, I can add a logical dimension (PC-hierarchy) without problems.
However when I also add TRACE_ID to my PK, I cannot select a member key in the new logical dimension window and therefore not create a logical dimension.
Is this a limitation of OBIEE and I have to merge the two colums (which would be rather bad, as there are FK relations to DIAG_ID) or is there a solution?
Regards
MatthiasDear Gowtham ,
I am very well aware of the level based hierarchy available in BO .
The issue that i have raised is all about the Parent Child Hierarchy which creates the recursive query.
I.e Every Parent has a child and that child can be parent of some other . (See the original example for more illustration)
Maybe you are looking for
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