PHP Random Images (Mr. Powers or other PHP Experts)

Hello everyone,
This is the script from David Power's book using arrays and the rand function (Disclosure).
Basically it changes the images randomly on browser load or refresh.
However, I am trying to add an additional, not sure what to call it, a string or another caption for each images.
Instead of this being a caption, it will be a link, so a link will appear under each caption that goes to another page
when it is clicked on for additional info about the image.
I tried adding another caption and adding a like to it but getting syntax error.
Thanks everyone!
Here is the code:
<?php
$images = array(
array('file' => 'image1',
'caption' => 'Caption 1'),
array('file' => 'image2',
'caption' => 'Caption 2'),
$i = rand(0, count($images)-1);
$selectedImage = "graphics/{$images[$i]['file']}.png";
$caption = $images[$i]['caption'];
?>
And here is where the images are written to the page:
<div id="stage">
<img src="<?php echo $selectedImage; ?>" alt="Random image" />
<p id="caption"><?php echo $caption; ?></p>
</div>
Thanks everyone!
WE

Thanks for the helpful link!
I found the solution to the problem it was very simple and I feel a little stupid asking the question in the first place but, that's how learning works.
We sometimes stumble upon knowledge.
The problem is I was adding the second string outside of the array.
Here is the right way:
array('file' => 'image1',
'caption' => 'Hello!',
'link1' => '<a href="http://www.msnbc.com">Read more</a>',<--Instead of putting the link here
link2' => '<a href="http://www.npr.org">Idea Center</a>'
<-- I was putting the link here out side the array and not properly ending the string.
$i = rand(0, count($images)-1);
$selectedImage = "graphics/{$images[$i]['file']}.png";
$caption = $images[$i]['caption'];
$link1 = $images[$i]['link1'];
$link2 = $images[$i]['link2'];
?>
Output here:
<div id="stage">
<img src="<?php echo $selectedImage; ?>" alt="Random image" />
<p><?php echo $caption; ?></p>
<?php echo $link1; ?>
<?php echo $link2; ?>
</div>
WE

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