Pipe delimiter string into rows using regular expression

hi Can anyone please help writing pipe' l 'delimiter values to rows
sample data 'something1|something2|something3'
i tried with below query
SELECT LEVEL,
TRIM ('"' FROM RTRIM (REGEXP_SUBSTR ('something1|something2|something3' || '|',
'".*?"||[^|]*|',
1,
LEVEL
'|'
) sub_str
FROM dual
CONNECT BY LEVEL <= LENGTH (REGEXP_REPLACE ('something1|something2|something3' , '".*?"|[^|]*')) + 1

SQL> ed
Wrote file afiedt.buf
1 with t as (select 'something1|something2|something3' as txt from dual)
2 -- end of sample data
3 select REGEXP_SUBSTR (txt, '[^|]+', 1, level)
4 from t
5* connect by level <= length(regexp_replace(txt,'[^|]*'))+1
SQL> /
REGEXP_SUBSTR(TXT,'[^|]+',1,LEVE
something1
something2
something3
SQL>

Similar Messages

How to convert column with delimited string into rows

I have a string value in a single column, delimited by colon. The number of items in the string is variable. I need to select the data from this column into separate rows based on the delimiter. I can write a function with a loop but if there is a way to do this in SQL it would be better.
Table contains a column with data value:
12:130:1400
And I want to select data and return as:
12
130
1400
This in in Oracle 9i.
Please don't post "look for pivot or transpose in the forum" as that is not a helpful answer (I have already done that).
Thanks!
Message was edited by:
splinternet

SQL> create table mytable (id,value)
2 as
3 select 1, '12:130:1400' from dual union all
4 select 2, '483' from dual union all
5 select 3, '1:2:3:4:5:6:77:888' from dual union all
6 select 4, null from dual
7 /
Tabel is aangemaakt.
SQL> select id
2       , trim(':' from v) value
3       , substr
4         ( v
5         , instr(v,':',1,t.column_value) + 1
6         , instr(v,':',1,1 + t.column_value)
7           - instr(v,':',1,t.column_value) - 1
8         ) part
9    from ( select id, ':' || value || ':' v from mytable ) m
10       , table
11         ( cast
12           ( multiset
13             ( select level l
14                 from dual
15              connect by rownum <= length(m.v) - length(replace(m.v,':')) - 1
16             )
17           as sys.dbms_debug_vc2coll
18           )
19         ) t
20   order by m.id
21       , t.column_value
22 /
        ID VALUE                PART
         1 12:130:1400          12
         1 12:130:1400          130
         1 12:130:1400          1400
         2 483                  483
         3 1:2:3:4:5:6:77:888   1
         3 1:2:3:4:5:6:77:888   2
         3 1:2:3:4:5:6:77:888   3
         3 1:2:3:4:5:6:77:888   4
         3 1:2:3:4:5:6:77:888   5
         3 1:2:3:4:5:6:77:888   6
         3 1:2:3:4:5:6:77:888   77
         3 1:2:3:4:5:6:77:888   888
         4
13 rijen zijn geselecteerd.Regards,
Rob.

How to split a delimited string into rows

Hi Everyone,
I have a field in my EMPLOYEE table named "OLD_USER_IDS" which stores all the old system ID's that the employee was once assigned to. This field is comma separated like so: "USERID1,USERID2,USERID3". My question is: how can I write a SELECT query that splits each individual User ID into its own row?
For example:
EMP_ID USER_ID
10 USERID1
10 USERID2
12 USERID3
15 USERID4
15 USERID5
15 USERID6
Thank You
-Sam

I think you should search this forum first for similar questions. I keep track of some interesting stuffs posted in this forum in a file, and from that
WITH t AS (SELECT 'USER1,USER2,USER3' str FROM DUAL
select substr(str,
                    decode(level,
                           1,
                           1,
                           instr(str, ',', 1, level - 1) + 1),
                    decode(instr(str, ',', 1, level),
                           0,
                           length(str),
                           instr(str, ',', 1, level) -
                           decode(level,
                                  1,
                                  0,
                                  instr(str, ',', 1, level - 1)) - 1)) the_value
        from (select str from t)
      connect by level <=
                 length(str) - length(replace(str, ',')) + 1;

How to use Regular expression

Hi,
I have a file that contains this format (separated by ;(semicolon) ):
user id;user name;email address;password;integer;list of integer(separated by ,(comma))
below is the example data :
abc;Abc;[email protected];password1;1;1,2
def;Def;[email protected];password;2;1,2,3
ghi;Ghi;[email protected];password;2;1
my question is how to verify the valid input for each row using regular expression..? TQ

@Op. Doing a correct validation of e-mailaddresses
is very hard using regular expressions (doingbasic
validation is however easy)
http://www.regular-expressions.info/email.html
I like the RFC 822 compliant regexp :)

How to Identify the count , If multiple parameters are passed using Pipe Delimited string

Hi,
We are passing Pipe delimited string to the parameter and I want to know how many values we are passing to the parameter.
Here is the example
Parameter.Grant: 24|34|54|67
I am using below expression, but it is not giving the right values. Please let me know if I am missing anything or is it possible.
=iif(parameters!Grant.Count>1,"Multiple value selected",parameters!Grant.Value)

Hi NaveenCR,
According to your description, you used pipe delimited multi-value parameter in the report, you want to know how many values passed to the parameter. If that is the case, please refer to the following steps:
In Design view, click Text Box in the Toolbox.
On the design surface, click and then drag a box to the desired size of the text box.
Right-click inside of the text box, then click Expression.
In Expression text box, type the expression like below:
=iif(split(Parameters! Grant.Value,"|").Length>1," Multiple value selected",Parameters!Grant.Value)
The following screenshots are for your reference:
If you have any more questions, please feel free to ask.
Thanks,
Wendy Fu
If you have any feedback on our support, please click
here.
Wendy Fu
TechNet Community Support

Spliting a large string using regular expression which contain special char

I have huge sting(xml) containing normal character a-z,A-Z and 0-9 as well as special char( <,>,?,&,',",;,/ etc.)
I need to split this sting where it ends with </document>
for e.g.
Original String:
<document>
<item>sdf</item>
<item><text>sd</text</item>
</document>
<document>hi</document>
The above sting has to be splited in to two parts since it is having two document tag.
Can any body help me to resolve this issue. I can use StringTokenizer,String split method or Regular expression api too.

manas589 wrote:
I used DOM and sax parser and got few exception. Again i don't have right to change xml. so i thought to go with RegularExpression or some other way where i can do my job.If the file actually comes in lines like what you posted, you should just be able to compare the contents of each line to see if it contains "</document>" or whatever you're looking for. I wouldn't use regex unless I needed another problem.
I got excpetion like: Caused by: org.xml.sax.SAXParseException: The entity "nbsp" was referenced, but not declared.
     at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
     at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Source)
     at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)So then it isn't even XML.
Edit: sorry, I just realized why you're considering all of these heavy-duty ideas. It's just that you don't know how to break the string into lines. You do it like this:
BufferedReader br = new BufferedReader(new StringReader(theNotXMLString));

Using Regular Expressions to replace Quotes in Strings

I am writing a program that generates Java files and there are Strings that are used that contain Quotes. I want to use regular expressions to replace " with \" when it is written to the file. The code I was trying to use was:
String temp = "\"Hello\" i am a \"variable\"";
temp = temp.replaceAll("\"","\\\\\"");
however, this does not work and when i print out the code to the file the resulting code appears as:
String someVar = ""Hello" i am a "variable"";
and not as:
String someVar = "\"Hello\" i am a \"variable\"";
I am assumming my regular expression is wrong. If it is, could someone explain to me how to fix it so that it will work?
Thanks in advance.

Thanks, appearently I'm just doing something weird that I just need to look at a little bit harder.

Format string using Regular Expression

Input string output format...
SELECT q'<select ab_c "ABC", efg "EFG" from dual>' str FROM DUAL
Output:
STR
select ab_c "ABC", efg "EFG" from dual
Required output format using regular expression...
STR
select 'ab_c' "ABC", 'efg' "EFG" from dual

Regular expressions have many limitations as parsing tools, and you didn't specify the rules you wanted. This expression puts quotes around the non blank string before a quoted string:
SELECT regexp_replace(q'<select ab_c "ABC", efg "EFG" from dual>',
                      '([^" ]+)( +"[^ ]*")' , '''\1''\2' ) str FROM DUAL;
STR
select 'ab_c' "ABC", 'efg' "EFG" from dual
{code}
It is not robust - a missing " will confuse it, and you should be using bind variables anyway.

String extract using regular expression

Hi
I have text like this "<a>45</a><ct>Hi</ct><R>45 85</R><H>Here</H>" .I want to extract using regular expression or any techniques the text between <R> and </R> also need to replace the space with pipe between 45 and 85 like "45|85"
Edited by: vishnu prakash on Mar 2, 2012 4:42 AM

Hi,
Here's one way:
REPLACE ( REGEXP_REPLACE ( txt
                , '.*<R>(.*)</R>.*'
                , '\1'
     , '|'
     )This assumes there is only one <R> tag in txt.
Always say which version of Oracle you're using. The expression above will work in Oralce 10 and up, but starting in Oracle 11 you can use REGEXP_SUBSTR rather than the less intuitive REGEXP_REPLACE.
Edited by: Frank Kulash on Mar 2, 2012 7:48 AM

Changeparticular characters in a string by using regular expressions ...

Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you

SSU wrote:
Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you
SQL> SELECT
2 regexp_replace('sdfsdf Sdfdfs Sdfd','s|S','X') from dual;
REGEXP_REPLACE('SD
XdfXdf XdfdfX XdfdRegards,
Achyut

Request some help, over procedure's performance uses regular expressions for its functinality

Hi All,
        Below is the procedure, having functionalities of populating two tables. For first table, its a simple insertion process but for second table, we need to break the soruce record as per business requirement and then insert into the table. [Have used regular expressions for that]
        Procedure works fine but it takes around 23 mins for processing 1mm of rows.
        Since this procedure would be used, parallely by different ETL processes, so append hint is not recommended.
        Is there any ways to improve its performance, or any suggestion if my approach is not optimized? Thanks for all help in advance.
CREATE OR REPLACE PROCEDURE SONARDBO.PRC_PROCESS_EXCEPTIONS_LOGS_TT
     P_PROCESS_ID       IN        NUMBER,
     P_FEED_ID          IN        NUMBER,
     P_TABLE_NAME       IN        VARCHAR2,
     P_FEED_RECORD      IN        VARCHAR2,
     P_EXCEPTION_RECORD IN        VARCHAR2
    IS
    PRAGMA AUTONOMOUS_TRANSACTION;
    V_EXCEPTION_LOG_ID     EXCEPTION_LOG.EXCEPTION_LOG_ID%TYPE;
    BEGIN
    V_EXCEPTION_LOG_ID :=EXCEPTION_LOG_SEQ.NEXTVAL;
         INSERT INTO SONARDBO.EXCEPTION_LOG
             EXCEPTION_LOG_ID, PROCESS_DATE, PROCESS_ID,EXCEPTION_CODE,FEED_ID,SP_NAME
            ,ATTRIBUTE_NAME,TABLE_NAME,EXCEPTION_RECORD
            ,DATA_STRUCTURE
            ,CREATED_BY,CREATED_TS
         VALUES
         (   V_EXCEPTION_LOG_ID
            ,TRUNC(SYSDATE)
            ,P_PROCESS_ID
            ,'N/A'
            ,P_FEED_ID
            ,NULL
            ,NULL
            ,P_TABLE_NAME
            ,P_FEED_RECORD
            ,NULL
            ,USER
            ,SYSDATE
        INSERT INTO EXCEPTION_ATTR_LOG
            EXCEPTION_ATTR_ID,EXCEPTION_LOG_ID,EXCEPTION_CODE,ATTRIBUTE_NAME,SP_NAME,TABLE_NAME,CREATED_BY,CREATED_TS,ATTRIBUTE_VALUE
        SELECT
            EXCEPTION_ATTR_LOG_SEQ.NEXTVAL          EXCEPTION_ATTR_ID
            ,V_EXCEPTION_LOG_ID                     EXCEPTION_LOG_ID
            ,REGEXP_SUBSTR(str,'[^|]*',1,1)         EXCEPTION_CODE
            ,REGEXP_SUBSTR(str,'[^|]+',1,2)         ATTRIBUTE_NAME
            ,'N/A'                                  SP_NAME
            ,p_table_name
            ,USER
            ,SYSDATE
            ,REGEXP_SUBSTR(str,'[^|]+',1,3)         ATTRIBUTE_VALUE
        FROM
        SELECT
             REGEXP_SUBSTR(P_EXCEPTION_RECORD, '([^^])+', 1,t2.COLUMN_VALUE) str
        FROM
            DUAL t1 CROSS JOIN
                    TABLE
                        CAST
                            MULTISET
                                SELECT LEVEL
                                FROM DUAL
                                CONNECT BY LEVEL <= REGEXP_COUNT(P_EXCEPTION_RECORD, '([^^])+')
                            AS SYS.odciNumberList
                    ) t2
        WHERE REGEXP_SUBSTR(str,'[^|]*',1,1) IS NOT NULL
        COMMIT;
       EXCEPTION
         WHEN OTHERS THEN
         ROLLBACK;
         RAISE;
    END;
Many Thanks,
Arpit

Regex's are known to be CPU intensive specially when dealing with large number of rows.
If you have to reduce the processing time, you need to tune the Select statements.
One suggested change could be to change the following query
SELECT
             REGEXP_SUBSTR(P_EXCEPTION_RECORD, '([^^])+', 1,t2.COLUMN_VALUE) str
        FROM
            DUAL t1 CROSS JOIN
                    TABLE
                        CAST
                            MULTISET
                                SELECT LEVEL
                                FROM DUAL
                                CONNECT BY LEVEL <= REGEXP_COUNT(P_EXCEPTION_RECORD, '([^^])+')
                            AS SYS.odciNumberList
                    ) t2
to
SELECT REGEXP_SUBSTR(P_EXCEPTION_RECORD, '([^^])+', 1,level) str
FROM DUAL
CONNECT BY LEVEL <= REGEXP_COUNT(P_EXCEPTION_RECORD, '([^^])+')
Before looking for any performance benefit, you need to ensure that this does not change your output.
How many substrings are you expecting in the P_EXCEPTION_RECORD? If less than 5, it will be better to opt for SUBSTR and INSTR combination as it might work well with the number of records you are working with. Only trouble is, you will have to write different SUBSTR and INSTR statements for each column to be fetched.
How are you calling this procedure? Is it not possible to work with Collections? Delimited strings are not a very good option as it requires splitting of the data every time you need to refer to.

One for the Tekkies: How to get this output using REGULAR EXPRESSIONS?

How to get the below output using REGULAR EXPRESSIONS??
SQL> ed
Wrote file afiedt.buf
1* CREATE TABLE cus___addresses (full_address VARCHAR2(200 BYTE))
SQL> /
Table created.
SQL> PROMPT Address Format is: House #/Housename, street, City, Zip Code, COUNTRY
House #/Housename, street, City, Zip Code, COUNTRY
SQL> INSERT INTO cus___addresses VALUES('1, 3rd street, Lansing, MI 49001, USA');
1 row created.
SQL> INSERT INTO cus___addresses VALUES('3B, fifth street, Clinton, OK 74103, USA');
1 row created.
SQL> INSERT INTO cus___addresses VALUES('Rose Villa, Stanton Grove, Murray, TN 37183, USA');
1 row created.
SQL> SELECT * FROM cus___addresses;
FULL_ADDRESS
1, 3rd street, Lansing, MI 49001, USA
3B, fifth street, Clinton, OK 74103, USA
Rose Villa, Stanton Grove, Murray, TN 37183, USA
SQL> The REG EXP query shouLd output the ZIP codes: i.e. 49001, 74103, 37183 in 3 rows.Edited by: user12240205 on Jun 18, 2012 3:19 AM

Hi,
user12240205 wrote:
... Frank, ʃʃp's method, I understand. But your method, although correct, I find it difficult to understand.
Could you explain how you did this?? What does '.*(\d{5})\D*' and '\1' mean???
Your method is better because it uses only ONE reg expression function. ʃʃp's uses 2.In Oracle 10.2 (I believe) and higher, '\d' is equivalent to '[[:digit:]]', and '\D' is equivalent to '[^[:digit:]]'. I find '\d' and '\D' easier to type, but there's nothing wrong with using '[[:digit:]]' and '[^[:digit:]]'.
'.*' means "0 or more of any character".
'\D*' means "0 or more non-digits".
The whole expression, '.*(\d{5})\D*' means:
a. 0 or more characters (any characters)
b. 5 digits
c. 0 or more non-digits.
'\1' is a Backreference . It means the sub-string that matched the pattern after the 1st '(', up to (but not including) its matching ')'. In this case, that means the sub-string that matched '\d{5}', or b. using the explanation immediately above.
So the entire REGEXP_REPLACE call means "When you see a sub-string consisting of a., follwed immediately by b., followed immedately by c., replace that sub-string with b. alone."

Trying to use regular expressions to convert names to Title Case

I'm trying to change names to their proper case for most common names in North America (esp. the U.S.).
Some examples are in the comments of the included code below.
My problem is that *retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");* does not work as I expect. It seems that the toUpperCase method call does not actually do anything to the identified group.
Everything else works as I expect.
I'm hoping that I do not have to iterate through each character of the string, upshifting the characters that follow spaces.
Any help from you RegEx experts will be appreciated.
{code}
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* DAN MARINO --> Dan Marino
* old macdonald --> Old Macdonald <-- Can't capitalize the 'D" because of Ernst Mach
* ROY BLOUNT, JR. --> Roy Blount, Jr.
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* Tom Jones --> Tom Jones
* ST.LOUIS --> St. Louis
* ST.LOUIS, MO --> St. Louis, Mo <-- Avoid City Names plus State Codes
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
* Basic plan:
* 1. Strategically create double spaces in front of characters to be capitalized
* 2. Capitalize characters with preceding spaces
* 3. Remove double spaces.
// Make the string all lower case
String retName = name.trim().toLowerCase();
// Collapse strings of spaces to single spaces
retName = retName.replaceAll("[ ]+", " ");
// "mc" names
retName = retName.replaceAll("( mc)", " $1");
// Ensure there is one space after periods and commas
retName = retName.replaceAll("(\\.|,)([^ ])", "$1 $2");
// Add 2 spaces after periods, commas, hyphens and apostrophes
retName = retName.replaceAll("(\\.|,|-|')", "$1 ");
// Add a double space to the front of the string
retName = " " + retName;
// Upshift each character that is preceded by a space
// For some reason this doesn't work
retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");
// Remove double spaces
retName = retName.replaceAll(" ", "");
return retName;
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:56 AM
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:57 AM

Hopefully someone will still be able to provide a RegEx solution, but until that time here is a working method.
Also, if people have suggestions of other rules for letter capitalization in names, I am interested in those too.
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* carol o'connor --> Carol O'Connor
* DAN MARINO --> Dan Marino
* eD mCmAHON --> Ed McMahon
* joe amcode --> Joe Amcode         <-- Embedded "mc"
* mr.t --> Mr. T                    <-- Inserted space
* OLD MACDONALD --> Old Macdonald   <-- Can't capitalize the 'D" because of Ernst Mach
* old mac donald --> Old Mac Donald
* ROY BLOUNT,JR. --> Roy Blount, Jr.
* ST.LOUIS --> St. Louis
* ST.LOUIS,MO --> St. Louis, Mo     <-- Avoid City Names plus State Codes
* Tom Jones --> Tom Jones
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
     * Basic plan:
     * 1. Strategically create double spaces in front of characters to be capitalized
     * 2. Capitalize characters with preceding spaces
     * 3. Remove double spaces.
    // Make the string all lower case
    String workStr = name.trim().toLowerCase();
    // Collapse strings of spaces to single spaces
    workStr = workStr.replaceAll("[ ]+", " ");
    // "mc" names
    workStr = workStr.replaceAll("( mc)", " $1 ");
    // Ensure there is one space after periods and commas
    workStr = workStr.replaceAll("(\\.|,)([^ ])", "$1 $2");
    // Add 2 spaces after periods, commas, hyphens and apostrophes
    workStr = workStr.replaceAll("(\\.|,|-|')", "$1 ");
    // Add a double space to the front of the string
    workStr = " " + workStr;
    // Upshift each character that is preceded by a space and remove double spaces
    // Can't upshift using regular expressions and String methods
    // workStr = workStr.replaceAll("( [^ ])([^ ]+)", "$1"toUpperCase() + "$2");
    StringBuilder titleCase = new StringBuilder();
    for (int i = 0; i < workStr.length(); i++) {
        if (workStr.charAt(i) == ' ') {
            if (workStr.charAt(i+1) == ' ') {
                i += 2;
            while (i < workStr.length() && workStr.charAt(i) == ' ') {
                titleCase.append(workStr.charAt(i++));
            if (i < workStr.length()) {
                titleCase.append(workStr.substring(i, i+1).toUpperCase());
        } else {
            titleCase.append(workStr.charAt(i));
    return titleCase.toString();
{code}

Using regular expressions to get a customized output

Hi,
I have a string/varchar variable with the data ',a,b,c,' in it.
I want the display as follows:
a
b
c
I would like to get the similar output using regular expressions.
How do I get this output using REGEXP_REPLACE or REGEXP_SUBSTR?
Please do the needful.
Thanks & Regards,
Rakshit

I remember that, however if we look closer, that one has a little flaw: The 2nd row should be null, because ",," indicates an empy field. The MODEL clause solution works just fine in this case:
with t as (select 'aaaa,,bbbb,cccc,dddd,eeee,ffff' col1 from dual)
-- end of sample data
SELECT col_new
FROM t
MODEL
   PARTITION BY (ROWNUM rn)
   DIMENSION BY (0 dim)
   MEASURES(col1, col1 col_new)
   RULES ITERATE(99) UNTIL (ITERATION_NUMBER = LENGTH(REGEXP_REPLACE(col1[0], '[^,]')))
                (col_new[ITERATION_NUMBER] = REPLACE(REGEXP_SUBSTR(col1[0], '(^|,)[^,]*', 1, ITERATION_NUMBER+1), ','))
COL_NEW
aaaa
bbbb
cccc
dddd
eeee
ffff
7 Zeilen ausgewählt.Update: I had this nagging feeling that I missed something, and there it was. If you want to see what the problem with my solution is, change the example to
with t as (select ',aaaa,,bbbb,cccc,dddd,eeee,ffff' col1 from dual)So I went back and tried to fix BlueShadows approach. Here it is:
with t as (select 'aaaa,,bbbb,cccc,dddd,eeee,ffff' txt from dual)
-- end of sample data
SELECT REPLACE(REGEXP_SUBSTR(',' || txt, ',[^,]*', 1, level), ',') col_new
FROM t
CONNECT BY level <= length(regexp_replace(txt,'[^,]*'))+1
;C.

Using regular expressions in java

Does anyone of you know a good source or a tutorial for using regular expressions in java.
I just want to look at some examples....
Thanks

thanks a lot... i have one more query
Boundary matchers
^      The beginning of a line
$      The end of a line
\b      A word boundary
\B      A non-word boundary
\A      The beginning of the input
\G      The end of the previous match
\Z      The end of the input but for the final terminator, if any
\z      The end of the input
if i want to use the $ for comparing with string(text) then how can i use it.
Eg if it is $120 i got a hit
but if its other than that if should not hit.

Pipe delimiter string into rows using regular expression

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