Please explain on this interface

can anyone help me on this Interface points that I have put in my resume to make a impressive resume...but it is not clear for me...
Interfaces· . Sales order interface: Developed the inbound interface to create sales orders using BAPI_SALESORDER_CREATEFROMDAT2.Custom IDOC was used by WBI to send data into SAP.
· Purchase Order Interface: Developed the purchase order interface using BAPI_PO_CREATE1.Business object BUS2105 was used by WBI to transmit data into SAP.
· Designed the Receipt confirmation interface to notify the client that the goods were received into the warehouse.
Please do explain it will help me for my technical interview...
Thanks,

Hi Bhagya
Interfaces are nothing but a program that you write to transfer data into SAP or for other purposes.Here your interfaces all represent data transfer..
My advice is don't put anything in your resume which you have not worked.Mention whatever you have worked surely that will help you.Best of luck.I am having interview questions for ABAP if you want then i can forward it to your mail id.
Regards,
Abdul

Similar Messages

X-Fi Fatal1ty + Inspiron 5.1 5500D, tech/admin PLEASE explain me thi

(First of all please explain me this tech/admin, PLEASE)
Hi !
I have been trying to resolve this since like 2 YEARS ago !
The more i think the more i cannot understand ! WHY THE HELL u sell speakers incompatible for ure soundcards ! STOP IT ! I hoped this could be resolved in this new card (since i have just removed sb li've 5.d)
sbli've 5.D incompatible with inspire 5. 5500D (incredible...)(Only real 5. with ac3 signals) and now with X-Fi same again ! if the only way to get real 5. in all Applications/games is to have ANALOGIC speakers ... JUST SAY IT BEFORE BUYING THE SPEAKERS ! Yes i can get sound in all chanels but not in Real 5. ! God ! both speakers and soundcard are yours ! this is frustating is like a bad joke ! Now I must spend another 200? to get new ANALOGIC speakers !?!?!?!?!?!?!?
Speakers box/manual/web says ... great 5. sound ! ..... ejoy youre music/games ! .... ejoy what ! "mix" stereo sound ? have i spend 200? for this? this is a thymus! YES IT IS !
have no words to explain how i feel ...
I don't want excuses, I want solutions (maybe any adaptor or something to resolve it without buying new speakers?)!
Sorry but im really really really angry ! and sorry for my english ...
Message Edited by Istarth on 0-2-2006 04:00 AM

The Inspire 5500D is meant for consoles like the Xbox 360 ( which can create a Dolby Digital 5. encoded signal ) and there's another version which supports DTS on the PS3 (with some games).
Your best bet is to get a Dolby Digital Li've certified soundcard like the ones made by C-Media or someone else like this one: http://www.diamondmm.com/XS7DDL.php ( note if you do get a card for this by C-Media, make absolutely certain that 'tis the version which supports DD Li've as they have an identical model without it).
I don't mean to be offensi've, but if you decide to change yer speakers, read a few reviews first. This issue with Creative soundcards not supporting Dolby Digital encoding (DD Li've ) has been known since 200, when the nVidia nForce came out with it. There have been and still are many people who try to connect their Creative soundcards to receivers, way more expensi've than your 5500s, via a digital connection and find out that they only get stereo.
If you have the Inspire 5500D version which supports DTS ( please check that it does before you do this!!!!! ) you could get Creative's real time DTS encoder ( http://www.creative.com/products/product.asp?category=3&subcategory=55&product=49 ) which could encode a soundcard's 5. channel output into a SPDIF/TOSLINK DTS stream. There're two versions of the 5500D, one which supports Dolby Digital and another which only supports DTS, so if you go down this route make sure you have the right one.
If yer connecting digitally, you should be able to get discrete 5. channel sound with DVDs. For this to work, you need to disable the X-Fi's internal decoder and set yer DVD player software to output in SPDIF mode.Message Edited by nvidiot on 0-2-2006 07:08 AM

Can you please explain how this query is fetching the rows?

here is a query to find the top 3 salaries. But the thing is that i am now able to understand how its working to get the correct data :How the data in the alias table P1 and P2 getting compared. Can you please explain in some steps.
SELECT MIN(P1.SAL) FROM PSAL P1, PSAL P2
WHERE P1.SAL >= P2.SAL
GROUP BY P2.SAL
HAVING COUNT (DISTINCT P1.SAL) <=3 ;
here is the data i used :
SQL> select * from psal;
NAME SAL
able 1000
baker 900
charles 900
delta 800
eddy 700
fred 700
george 700
george 700
Regards,
Renu

... Please help me in understanding the query.
Your query looks like anything but a Top-N query.
If you run it in steps and analyze the output at the end of each step, then you should be able to understand what it does.
Given below is some brief information on the same:
test@ora>
test@ora> --
test@ora> -- Query 1 - using the non-equi (theta) join
test@ora> --
test@ora> with psal as (
2    select 'able' as name, 1000 as sal from dual union all
3    select 'baker',   900 from dual union all
4    select 'charles', 900 from dual union all
5    select 'delta',   800 from dual union all
6    select 'eddy',    700 from dual union all
7    select 'fred',    700 from dual union all
8    select 'george', 700 from dual union all
9    select 'george', 700 from dual)
10 --
11 SELECT p1.sal AS p1_sal, p1.NAME AS p1_name, p2.sal AS p2_sal,
12         p2.NAME AS p2_name
13    FROM psal p1, psal p2
14   WHERE p1.sal >= p2.sal;
    P1_SAL P1_NAME     P2_SAL P2_NAME
      1000 able          1000 able
      1000 able           900 baker
      1000 able           900 charles
      1000 able           800 delta
      1000 able           700 eddy
      1000 able           700 fred
      1000 able           700 george
      1000 able           700 george
       900 baker          900 baker
       900 baker          900 charles
       900 baker          800 delta
       900 baker          700 eddy
       900 baker          700 fred
       900 baker          700 george
       900 baker          700 george
       900 charles        900 baker
       900 charles        900 charles
       900 charles        800 delta
       900 charles        700 eddy
       900 charles        700 fred
       900 charles        700 george
       900 charles        700 george
       800 delta          800 delta
       800 delta          700 eddy
       800 delta          700 fred
       800 delta          700 george
       800 delta          700 george
       700 eddy           700 eddy
       700 eddy           700 fred
       700 eddy           700 george
       700 eddy           700 george
       700 fred           700 eddy
       700 fred           700 fred
       700 fred           700 george
       700 fred           700 george
       700 george         700 eddy
       700 george         700 fred
       700 george         700 george
       700 george         700 george
       700 george         700 eddy
       700 george         700 fred
       700 george         700 george
       700 george         700 george
43 rows selected.
test@ora>
test@ora>This query joins PSAL with itself using a non equi-join. Take each row of PSAL p1 and see how it compares with PSAL p2. You'll see that:
- Row 1 with sal 1000 is >= to all sal values of p2, so it occurs 8 times
- Row 2 with sal 900 is >= to 9 sal values of p2, so it occurs 7 times
- Row 3: 7 times again... and so on.
- So, total no. of rows are: 8 + 7 + 7 + 5 + 4 + 4 + 4 + 4 = 43
test@ora>
test@ora> --
test@ora> -- Query 2 - add the GROUP BY
test@ora> --
test@ora> with psal as (
2    select 'able' as name, 1000 as sal from dual union all
3    select 'baker',   900 from dual union all
4    select 'charles', 900 from dual union all
5    select 'delta',   800 from dual union all
6    select 'eddy',    700 from dual union all
7    select 'fred',    700 from dual union all
8    select 'george', 700 from dual union all
9    select 'george', 700 from dual)
10 --
11 SELECT p2.sal AS p2_sal,
12         COUNT(*) as cnt,
13         COUNT(p1.sal) as cnt_p1_sal,
14         COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
15         MIN(p1.sal) as min_p1_sal,
16         MAX(p1.sal) as max_p1_sal
17    FROM psal p1, psal p2
18   WHERE p1.sal >= p2.sal
19 GROUP BY p2.sal;
    P2_SAL        CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
       700         32         32               4        700       1000
       800          4          4               3        800       1000
       900          6          6               2        900       1000
      1000          1          1               1       1000       1000
test@ora>
test@ora>Now, if you group by p2.sal in the output of query 1, and check the number of distinct p1.sal, min of p1.sal etc. you see that for p2.sal values - 800, 900 and 1000, there are 3 or less p1.sal values associated.
So, the last 3 rows are the ones you are interested in, essentially. As follows:
test@ora>
test@ora> --
test@ora> -- Query 3 - GROUP BY and HAVING
test@ora> --
test@ora> with psal as (
2    select 'able' as name, 1000 as sal from dual union all
3    select 'baker',   900 from dual union all
4    select 'charles', 900 from dual union all
5    select 'delta',   800 from dual union all
6    select 'eddy',    700 from dual union all
7    select 'fred',    700 from dual union all
8    select 'george', 700 from dual union all
9    select 'george', 700 from dual)
10 --
11 SELECT p2.sal AS p2_sal,
12         COUNT(*) as cnt,
13         COUNT(p1.sal) as cnt_p1_sal,
14         COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
15         MIN(p1.sal) as min_p1_sal,
16         MAX(p1.sal) as max_p1_sal
17    FROM psal p1, psal p2
18   WHERE p1.sal >= p2.sal
19 GROUP BY p2.sal
20 HAVING COUNT(DISTINCT p1.sal) <= 3;
    P2_SAL        CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
       800          4          4               3        800       1000
       900          6          6               2        900       1000
      1000          1          1               1       1000       1000
test@ora>
test@ora>
test@ora>That's what you are doing in that query.
The thing is - in order to find out Top-N values, you simply need to scan that one table PSAL. So, joining it to itself is not necessary.
A much simpler query is as follows:
test@ora>
test@ora>
test@ora> --
test@ora> -- Top-3 salaries - distinct or not; using ROWNUM on ORDER BY
test@ora> --
test@ora> with psal as (
2    select 'able' as name, 1000 as sal from dual union all
3    select 'baker',   900 from dual union all
4    select 'charles', 900 from dual union all
5    select 'delta',   800 from dual union all
6    select 'eddy',    700 from dual union all
7    select 'fred',    700 from dual union all
8    select 'george', 700 from dual union all
9    select 'george', 700 from dual)
10 --
11 SELECT sal
12 FROM (
13    SELECT sal
14      FROM psal
15    ORDER BY sal DESC
16 )
17 WHERE rownum <= 3;
       SAL
      1000
       900
       900
test@ora>
test@ora>
test@ora>And for Top-3 distinct salaries:
test@ora>
test@ora> --
test@ora> -- Top-3 DISTINCT salaries; using ROWNUM on ORDER BY on DISTINCT
test@ora> --
test@ora> with psal as (
2    select 'able' as name, 1000 as sal from dual union all
3    select 'baker',   900 from dual union all
4    select 'charles', 900 from dual union all
5    select 'delta',   800 from dual union all
6    select 'eddy',    700 from dual union all
7    select 'fred',    700 from dual union all
8    select 'george', 700 from dual union all
9    select 'george', 700 from dual)
10 --
11 SELECT sal
12 FROM (
13    SELECT DISTINCT sal
14      FROM psal
15    ORDER BY sal DESC
16 )
17 WHERE rownum <= 3;
       SAL
      1000
       900
       800
test@ora>
test@ora>
test@ora>You may also want to check out the RANK and DENSE_RANK analytic functions.
RANK:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions123.htm#SQLRF00690
DENSE_RANK:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions043.htm#SQLRF00633
HTH
isotope

Please explain me this elements in a script

hi,
can any one please explain how the co-ordinates are defined and explain this code in a simple way
FO791,105A0B,374,413CI13FRFN999FS
FO1015,626A0B,88,96CI13FRFN998FS
BY7,2.9FO104,126B3B,N,348,N,YFRFN997FS
FO483,169A0B,189,243CI13FRFN996FS
BY4,3.0FO941,1237BCR,176,N,Y,N,AFRFN995FS
FO847,1146A0B,85,86CI13FRFN994FS
IF &WA_ZZE46SERIAL-ZPRINT& = 'X'
FO778,1668A0B,43,56CI13FRFB256,0,0,LFN993^FS
ENDIF
FO715,88A0B,46,46CI13FR
FDCountry of destinationFS
FO61,1708A0B,42,61CI13FR
FDPackage noFS
FO934,704A0B,42,63CI13FR
FDDelivery noFS
    ^XZ
    ^XA
    ^XFZB_PAC-EMN.ZPL
    FN999FD&T005T-LAND1&^FS
    FN998FD&VBPLA-VBELN&^FS
    FN997FD&V_PACKAGE&^FS
    FN996FD&VEKP-EXIDV&^FS
    FN995FD&V_SERIAL_BAR&^FS
    FN994FD&V_SERIAL&^FS
   IF &WA_ZZE46SERIAL-ZPRINT& = 'X'
    FN993FD&V_TEXT&^FS
   ENDIF
    ^PQ1,0,1,N
    ^XZ
    ^FX End of job
even little information is of more help for me

You must be using Barone software and Zebra printer for printing barcode labels. This is the script generated using barone.
FO791,105A0B,374,413CI13FRFN999FS
FO1015,626A0B,88,96CI13FRFN998FS
BY7,2.9FO104,126B3B,N,348,N,YFRFN997FS
FO483,169A0B,189,243CI13FRFN996FS
BY4,3.0FO941,1237BCR,176,N,Y,N,AFRFN995FS
FO847,1146A0B,85,86CI13FRFN994FS
IF &WA_ZZE46SERIAL-ZPRINT& = 'X'
FO778,1668A0B,43,56CI13FRFB256,0,0,LFN993^FS
ENDIF
FO715,88A0B,46,46CI13FR
FDCountry of destinationFS
FO61,1708A0B,42,61CI13FR
FDPackage noFS
FO934,704A0B,42,63CI13FR
FDDelivery noFS
The first part of the script above is used to display the fixed text that will appear on the label.
^XZ
^XA
^XFZB_PAC-EMN.ZPL
FN999FD&T005T-LAND1&^FS
FN998FD&VBPLA-VBELN&^FS
FN997FD&V_PACKAGE&^FS
FN996FD&VEKP-EXIDV&^FS
FN995FD&V_SERIAL_BAR&^FS
FN994FD&V_SERIAL&^FS
IF &WA_ZZE46SERIAL-ZPRINT& = 'X'
FN993FD&V_TEXT&^FS
ENDIF
^PQ1,0,1,N
^XZ
^FX End of job
The second part above contains the actual data that will be printed on the label. T005T-Land1 will print the country code. VBPLA-VBELN will print the Sales Document No. etc. This data comes from your print program.
Hope this info helps.
Reward points if useful.
Thanks

Please explain Importance of Interfaces ....? [Basic Conceptual Problem..]

Hi everyone..
i am new to java..i want to know the importance of interfaces in java....
interface A{
public void print();
class B implements A{
public void print()
System.out.println("Please explain me the importance of Interfaces");
the class B can also be defined with out interface as the following...
class B {
public void print()
System.out.println("Please explain me the importance of Interfaces");
Both the classes have the same functionality ... then what the use of declaring an Interface and implementing it...?
PLEASE EXPLAIN BASIC USE OF INTERFACES....?
Note: Ignore any syntax errors in the code that i have written above
thanks in advance

In Java, mostly we use inheritance for code reuse.
public class Toy{
public class Ball extends Toy{
}Suppose there is another class Type which doesn't related to Toy family.
public class Tyre{
}Now we know that Ball and Tyre are bouncable. So we will have to implement bounce() method in both class which behave differently.
public class Ball extends Toy{
public void bounce() {
}Suppose there is another class Type which doesn't related to Toy family.
public class Tyre{
public void bounce() {
}*If want to collect bouncable things into a single collection, then how can we do that?*
There is way, we can use abstract class:-
public abstract BouncingThings {
public abstract void bounce();
}Now things that are bouncable can extend BouncingThings class and the collection of bounce things will be
BouncingThings [] bouncingThings;
But there is one problem Java doesn't allow multiple class inheritance. So Ball can't extend both Toy and BouncingThings.
We can use interface:-
public interface Bouncable{
void bounce();
public class Ball extends Toy implements Bouncable{
public void bounce(){
public class Tyre implements Bouncable{
public void bounce(){
Bouncable[] bouncableThings = { new Ball().new Tyre() };Edited by: SandipGaikwad on Oct 16, 2007 12:23 PM

Please explain Virus Scan Interface?

When we run virus scan on SAP server CPU utilization go high ,SAP team advice us to disable the virus scan.
They told us that they Virus interface in SAP. My question how it work is it ok not to install Antivirus softwares on SAP server

Architecture of the Virus Scan Interface & help me in defining Defining Scanner Groups
The structure of the Virus Scan Interface allows you to combine different products, systems, and platforms to scan your applications for viruses. This is possible, since SAP provides a certified interface for the virus scan products of other vendors.
The partners virus scan engines can, for example, have completely different architectures. However, by integrating an adapter using a proprietary connection, any partner can, however, connect any existing virus scan product to the virus scan interface.
On the SAP side, different VSILIB layers are used to include the ABAP and Java worlds, and to deal with platform dependencies (of operating systems and processors, that is, 32 or 64 bit) in the integration of the virus scan interface.
Use
A scanner group combines multiple virus scanners of the same type to allow load balancing. Since you select the virus scan server using the scanner group when maintaining the virus scan profile, you must assign each virus scan server to a scanner group.
Maintain a scanner group for each product class of virus scanners that are connected to the system using the virus scan server. If you include your own virus scanners with the BAdI VSCAN_INSTANCE, create a scanner group for each implementation of your own scanner and identify these as BAdI implementations.
You can store configuration parameters for each scanner group. These are divided into initialization parameters and scan parameters:
        Initialization parameters are transferred to the virus scan server when it is started, and are required to be able to start the virus scan server. If you use the Business Add-In, these parameters for the method of creating the scan instance are transferred. The parameters contain, for example, the path to the virus signatures.
        Scan parameters are transferred for each scan process and control the behavior of the individual request, such as yes/no for activating the scanning of macros.
For information about which configuration parameters are required or supported by the product that you use, see the documentation for the product.
SAP does not deliver any scanner groups.
Procedure
       1.      In the Implementation Guide, choose (IMG) SAP Web Application Server ® System Administration ® Virus Scan Interface.
       2.      Choose the Execute option next to Define Scanner Groups.
The screen View: Change "Scanner Groups": Overview appears.
       3.      Choose New Entries.
The screen New Entries: Overview of Added Entries appears.
       4.      Specify the data for the scanner group.
Data for the Definition of a Scanner Group
For more information please refer to be link this quite helpful
http://help.sap.com/saphelp_nw04s/helpdata/en/68/c9d8375bc4e312e10000009b38f8cf/frameset.htm
I hope it will be helpful to you.
All The Best
Priyanka
Do Reward Points.

Re: please explain me this coding..

Hi,
why don't you use ABAP documentation? Just click on the term which you don't understand and hit F1. That code is pretty simple. There is a definition of macro and one import statement. Both statements are well documented in ABAP documentation.
Cheers

>
SUNITA REDDY wrote:
> hi ,
> if it is simple y dont u explain me plz..
> regards
> sunita
You expect to get answers with this kind of an attitude. Such a shame!!!
Martin's advice was right on the money. You need to hit F1 whereever necessary and read the Help Documentation. But of course, you need a little bit of ABAP knowledge to understand all that, which I see lacking and a will to learn, which also seems to be lacking.
And hence, you are reported to SCN for rule violations and being rude to people who are trying to help you.
Have a nice day.
pk

Please explain why this happened - and what I should do about it!

Hello!
When I clicked on this link elsewhere in the Apple Communities https://discussions.apple.com/message/15579763#15579763
I was whisked away to see THIS message - can anyone explain why and advise of any action I should take?
Thanks,
David B.

Thanks, Tony!

Please explain what this program doing- I see the results but don't underst

public class Mystery2{
public static void main(String []args){
int count = 1;
while (count <= 10){
System.out.println(count % 2==1? "****":"++++++");
++count;
}//end while
}//end main
}//end class

Hello! First of all - where did you find this code (just for information, so it's easier to answer the question)
Secondly, pls be so kind as to use code tags. Here's the same program, reformatted and in code tags:
public class Mystery2
    public static void main (String [] args)
        int count = 1;
        while (count <= 10)
            System.out.println (count % 2 == 1 ? "****" : "++++++");
            ++count;
        }//end while
    }//end main
}//end class

I saved my file as a regular Indesign file, and when I went to open it on a different computer it had a lock on it and will not let me open it. Can someone please explain why this is happening and how to unlock it? It's for a very important and urgent pro

Please help if you can!

Assuming the file is stored on a network server, and the "other computer" is on that network as well; with InDesign not running on either, navigate to the folder where the InDesign file is stored and find the lock file (it will have the extension .idlk). Delete it.

Can somebody please explain me this logic?

array = [1,2,3,4,5,6,7];
newArray = array;
trace ("array: " + array);
newArray = newArray.splice (0, 5);
trace ("array: " + array);
Output:
array: 1,2,3,4,5,6,7
array: 6,7
As you can see, I set a variable equal to another (newArray = array), then splice it. But the problem is, it is affecting the old variable too!
How can that be?
I need to use the complete original "array", but no matter how many variables I create equal to it, when I splice them, it affects all of them!
I might find a solution by turning the variable into string, then back to array or something like that. But what I would like is to understand what's going on in that code. If someone could explain me, i'd appreciate it a lot.

Thank you.
That helped me out.
I found my problem also in the Flash Documentation. I couldn't find it before because i didn't know what to look for.
Anyway, here's the link if someone wants it:
http://livedocs.adobe.com/flash/9.0/main/wwhelp/wwhimpl/common/html/wwhelp.htm?context=Liv eDocs_Parts&file=00000661.html
It teaches how to create a copy of an array using a "for", but "kglad's" method is much better.

Please explain this code,this is regarding to ODS activation.

Hi,
Please I am unable to understand this code,this exists initial activation of ODS,please can anyone please explain me this
ob started
Step 001 started (program RSPROCESS, variant &0000000055152, user ID ALEREMOTE)
Activation is running: Data target ZYL_O82, from 1.165.349 to 1.165.349
Data to be activated successfully checked against archiving objects
SQL: 20.06.2007 05:34:26 ALEREMOTE
ANALYZE TABLE "/BIC/AZYT_O6240" DELETE STATISTICS
SQL-END: 20.06.2007 05:34:26 00:00:00
SQL: 20.06.2007 05:34:26 ALEREMOTE
BEGIN DBMS_STATS.GATHER_TABLE_STATS ( OWNNAME =>
'SAPR3', TABNAME => '"/BIC/AZYT_O6240"',
ESTIMATE_PERCENT => 1 , METHOD_OPT => 'FOR ALL
INDEXED COLUMNS SIZE 75', DEGREE => 1 ,
GRANULARITY => 'ALL', CASCADE => TRUE ); END;
Thanks & Regards,
Mano

Hi,
Please I am unable to understand this code,this exists initial activation of ODS,please can anyone please explain me this
ob started
Step 001 started (program RSPROCESS, variant &0000000055152, user ID ALEREMOTE)
Activation is running: Data target ZYL_O82, from 1.165.349 to 1.165.349
Data to be activated successfully checked against archiving objects
SQL: 20.06.2007 05:34:26 ALEREMOTE
ANALYZE TABLE "/BIC/AZYT_O6240" DELETE STATISTICS
SQL-END: 20.06.2007 05:34:26 00:00:00
SQL: 20.06.2007 05:34:26 ALEREMOTE
BEGIN DBMS_STATS.GATHER_TABLE_STATS ( OWNNAME =>
'SAPR3', TABNAME => '"/BIC/AZYT_O6240"',
ESTIMATE_PERCENT => 1 , METHOD_OPT => 'FOR ALL
INDEXED COLUMNS SIZE 75', DEGREE => 1 ,
GRANULARITY => 'ALL', CASCADE => TRUE ); END;
Thanks & Regards,
Mano

Can anyone explain how this works (vlans and bridge groups)

Can someone please explain how this works...I have started to have problems but nothing changed. My problems are vlan1 and 1000 getting blocked on the switchport where the root bridge is attached.
ROOT BRIDGE:
ssid state
station-role root bridge
rts threshold 4000
concatenation
interface Dot11Radio0.1
encapsulation dot1Q 1 native
no ip route-cache
no snmp trap link-status
bridge-group 1
bridge-group 1 spanning-disabled
interface Dot11Radio0.911
encapsulation dot1Q 911
no ip route-cache
no snmp trap link-status
bridge-group 5
interface Dot11Radio0.1000
encapsulation dot1Q 1000
no ip route-cache
no snmp trap link-status
bridge-group 2
bridge-group 2 spanning-disabled
interface Dot11Radio0.2001
encapsulation dot1Q 2001
no ip route-cache
no snmp trap link-status
bridge-group 253
bridge-group 253 spanning-disabled
interface Dot11Radio0.2120
encapsulation dot1Q 2120
no ip route-cache
no snmp trap link-status
bridge-group 7
interface Dot11Radio0.2330
encapsulation dot1Q 2330
no ip route-cache
no snmp trap link-status
bridge-group 3
bridge-group 3 spanning-disabled
interface Dot11Radio0.2336
encapsulation dot1Q 2336
no ip route-cache
no snmp trap link-status
bridge-group 4
interface Dot11Radio0.2350
encapsulation dot1Q 2350
no ip route-cache
no snmp trap link-status
bridge-group 6
interface Dot11Radio0.2901
encapsulation dot1Q 2901
no ip route-cache
no snmp trap link-status
bridge-group 255
bridge-group 255 spanning-disabled
interface Dot11Radio0.2902
encapsulation dot1Q 2902
no ip route-cache
no snmp trap link-status
bridge-group 254
bridge-group 254 spanning-disabled
interface FastEthernet0
no ip address
no ip route-cache
interface FastEthernet0.1
encapsulation dot1Q 1
no ip route-cache
no snmp trap link-status
interface FastEthernet0.911
encapsulation dot1Q 911
no ip route-cache
no snmp trap link-status
bridge-group 5
interface FastEthernet0.1000
encapsulation dot1Q 1000 native
ip address 10.0.32.10 255.255.255.0
no ip route-cache
no snmp trap link-status
bridge-group 1
interface FastEthernet0.2001
encapsulation dot1Q 2001
no ip route-cache
no snmp trap link-status
bridge-group 253
bridge-group 253 spanning-disabled
interface FastEthernet0.2120
encapsulation dot1Q 2120
no ip route-cache
no snmp trap link-status
bridge-group 7
interface FastEthernet0.2330
encapsulation dot1Q 2330
no ip route-cache
no snmp trap link-status
bridge-group 3
interface FastEthernet0.2336
encapsulation dot1Q 2336
no ip route-cache
no snmp trap link-status
bridge-group 4
interface FastEthernet0.2350
description 81 River Rd - Labor
encapsulation dot1Q 2350
no ip route-cache
no snmp trap link-status
bridge-group 6
interface FastEthernet0.2901
encapsulation dot1Q 2901
no ip route-cache
no snmp trap link-status
bridge-group 255
bridge-group 255 spanning-disabled
interface FastEthernet0.2902
encapsulation dot1Q 2902
no ip route-cache
no snmp trap link-status
bridge-group 254
bridge-group 254 spanning-disabled
interface BVI1
ip address 10.0.32.10 255.255.255.0
no ip route-cache
ip default-gateway 10.0.32.1

NON-ROOT BRIDGE#2:
ssid state
station-role non-root bridge
rts threshold 4000
concatenation
infrastructure-client
interface Dot11Radio0.1
encapsulation dot1Q 1 native
no ip route-cache
bridge-group 1
bridge-group 1 spanning-disabled
interface Dot11Radio0.1000
encapsulation dot1Q 1000
no ip route-cache
bridge-group 254
bridge-group 254 spanning-disabled
interface Dot11Radio0.2001
encapsulation dot1Q 2001
no ip route-cache
bridge-group 252
bridge-group 252 spanning-disabled
interface Dot11Radio0.2336
encapsulation dot1Q 2336
no ip route-cache
bridge-group 251
bridge-group 251 spanning-disabled
interface Dot11Radio0.2901
encapsulation dot1Q 2901
no ip route-cache
bridge-group 253
bridge-group 253 spanning-disabled
interface Dot11Radio0.2902
encapsulation dot1Q 2902
no ip route-cache
bridge-group 255
bridge-group 255 spanning-disabled
interface FastEthernet0
no ip address
no ip route-cache
hold-queue 80 in
interface FastEthernet0.1000
encapsulation dot1Q 1000 native
no ip route-cache
bridge-group 1
interface FastEthernet0.2001
encapsulation dot1Q 2001
no ip route-cache
bridge-group 252
bridge-group 252 spanning-disabled
interface FastEthernet0.2336
encapsulation dot1Q 2336
no ip route-cache
bridge-group 251
bridge-group 251 spanning-disabled
interface FastEthernet0.2901
encapsulation dot1Q 2901
no ip route-cache
bridge-group 253
bridge-group 253 spanning-disabled
interface FastEthernet0.2902
encapsulation dot1Q 2902
no ip route-cache
bridge-group 255
bridge-group 255 spanning-disabled
interface BVI1
ip address 10.0.32.11 255.255.255.0
no ip route-cache
ip default-gateway 10.0.32.1

Could Somebody Please Explain....

Could somebody please explain what this section of code is doing with the StopTime? There is plenty more code where that came from, but as I can see it, it is being put into a vector in another section of code as endTime, the vector pdmlist, which I think is where or hows its stored in the vector is being set to null? Then pdmlist is using EndTime value? The StopTime is then being set to a string.
StopTime is then set to blank, then the DateDataFormat is being used. The pdmlist comes back into play, then the df (date format) comes back and it gets converted to uppercase and finally outputted using the outStream.write method to the log file that is created (earlier).
So my quest, as per the other mail, why wont the DB query and order by, order it for the output to the log file. What is the vector doing to it to unsort it? How can I order it?
Vector pdmList = null;
this.setCursor( Cursor.WAIT );
if ( radioAllTime.getChecked() )
pdmList = pdmHelper.buildPDMList( ctx, null, null );
else
pdmList = pdmHelper.buildPDMList( ctx, dateBeginTime.getValue(), dateEndTime.getValue() );
          this.setCursor( Cursor.DEFAULT );
//If nothing was found, then display a message,
          //and return.
          if ( pdmList == null )
               MessageBox.show( "No parametric data found. Log file not generated." , this.getText() );
               return;
if ( pdmList.size() == 0 )
               MessageBox.show( "No parametric data found. Log file not generated." , this.getText() );
               return;
          String Temp;
String Board; // Prodid
String StartTime;
String StopTime;
String Part;
String BoardStatus;
String Actual;
String LoLim;
String HiLim;
String MeasStatus;
String PartType;
String PartNumber;
boolean BoardStatusContext = false;
boolean OneMeasureFailed = false;
java.util.Hashtable htFiles = new Hashtable(10,10);
FileWriter outStream = null;
try
for ( int idx = 0; idx < pdmList.size(); idx++ )
                    //Reset the flags
                    BoardStatusContext = false;
                    OneMeasureFailed = false;
Board = ""; StartTime = ""; StopTime = ""; Part = ""; BoardStatus = ""; Actual = "";
LoLim = ""; HiLim = ""; MeasStatus = ""; PartType = ""; PartNumber = "";
com.ms.wfc.data.DateDataFormat df = new com.ms.wfc.data.DateDataFormat( com.ms.wfc.data.DateFormat.CUSTOM,
"dd-MMM-yy hh:mm:ss" );
// get root context
PDMContext context = ((PDM)pdmList.elementAt(idx)).getContext();
//Make the filename
String fileName = context.getProductName();
if ( fileName == null || fileName.length() == 0 )
fileName = "UNKNOWN";
// Eliminate not allowed characters from the file name
fileName = fileName.replace('\\','_');
fileName = fileName.replace('/','_');
fileName = fileName.replace(':','_');
fileName = fileName.replace('*','_');
fileName = fileName.replace('?','_');
fileName = fileName.replace('\"','_');
fileName = fileName.replace('<','_');
fileName = fileName.replace('>','_');
fileName = fileName.replace('|','_');
fileName += ".log";
if ( htFiles.containsKey( fileName ) )
outStream = (FileWriter)htFiles.get( fileName );
else
File theFile = new File( fileName );
statusBar.getPanels()[0].setText( "File: " + theFile.getAbsolutePath() );
/* if ( ! theFile.canWrite() )
statusBar.getPanels()[0].setText( "Failed: " + theFile.getAbsolutePath() );
MessageBox.show( theFile.getAbsolutePath() + " can not be writen!",
this.getText() );
outStream = new FileWriter( theFile.getAbsolutePath(), false );
htFiles.put( fileName, outStream );
// start writing the log file...
outStream.write( "./" );
StartTime = ((String)df.format( null, context.getStartTime() )).toUpperCase();
StopTime = ((String)df.format( null, context.getStopTime() )).toUpperCase();
Board = context.getProductName();
if ( Board.length() == 0 )
Board = "UNKNOWN";
outStream.write( Board + ".obc[" + StartTime + "\r\n\r\n" );
Sorry the mail is so long. I tried books, but vectors were hard to come by? I've searched through the database on this site too, there are plenty of stuff about sorting and vectors but its hard to use somebody elsed situation for my own circumstances as a guide.
Hope somebody could just shed a bit of light.
Thanks in advance.
Mark.
PS. I will give duke points (when I work out how to add them, but I only have 5....sorry)

Does anybody have any ideas as to what is happening.
Mark.

Please explain the following displayed properties

Hi,
I tried to change the format of displayname under search result rendering setting. I found the following string for displaying display name:
<b>rnd:displayname(contentLink/[1;2-3]/alignTop/space-right=30</b>
please explain how this setting works? for example how that contentLink/[1;2-3] works? is there other setting I can use? like contentLink/1?
Thanks!
T.J.

Hi T.J.
First read this:
http://help.sap.com/saphelp_nw04/helpdata/en/79/a1d23e6b2c3d67e10000000a114084/frameset.htm
There are multiple property renderers available for some properties. Simply using the property name
instead of the property name with rnd: namespace will typically display the property value in a
more primitive way than the formatted rnd: version. For instance, the rnd: version for description
will truncate the text whereas the raw version will not.
The bracket syntax is used to postion the properties in grid renders like the search results layout sets.
Regards,
Darin

Please explain on this interface

Similar Messages

Maybe you are looking for