Please help me on Following sytax error in Work flows

Hi SAP CRM Gurus,
I am getting following Syntax error while generating object type ERMSSUPRT2.
Points will be rewarded.
Thanks in advance.
Thanks,
Rony.

Ji Jhonney,
I am finding Syntax error in Transaction /nswo1. Syntax error is:
program %_JJ_TESTFRAME_OBJTYPE
"CRMS_ERMS_STRING" must be flat structure. you cannot use internal
tables, strings,references or structures as compnents.
Please help me.
Thanks in advance
Thanks,
Rony.

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Hi CRM Experts,
Please help me on following queries.
1)Can we create multiple follow-up activities for given activity by using action profile?
2)What is the differance between ERP Sale Order and ECC Sales Order in Web-IC?
3)Is there any relationship between Status and Result in Activities?
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Please Help Me Out of The Error

Hello Everyone,
I am executing the following Syntax to create a procedure which will spool all the data of my employee table and dumped into a Text file. The Procedure is creating successfully, but problem is when I am Executing the Procedure I am getting an error.
The Syntax I am using to create the Procedure is:
CREATE OR REPLACE PROCEDURE dump_emp
IS
file_handle UTL_FILE.FILE_TYPE;
BEGIN
file_handle := UTL_FILE.FOPEN('c:\file_dir\','dump.txt','w');
FOR emp_rec IN (SELECT * FROM MANOJIT.EMPLOYEES) LOOP
UTL_FILE.PUT_LINE(file_handle, emp_rec.emp_id || ',' || emp_rec.ename || ',' || emp_rec.department_id || ',' || emp_rec.salary);
END LOOP;
UTL_FILE.FCLOSE(file_handle);
END dump_emp;
The Error I am Getting when I Execute the Procedure is:
ERROR at line 1:
ORA-06510: PL/SQL: unhandled user-defined exception
ORA-06512: at "SYS.UTL_FILE", line 98
ORA-06512: at "SYS.UTL_FILE", line 157
ORA-06512: at "SYS.DUMP_EMP", line 5
ORA-06512: at line 1
Please Help me in this matter.

One of the quirks of UTL_FILE is that its execptions are treated by Oracle as user defined - hence the cryptic message. In order to find which error you're getting you'll need to put in an EXCEPTION section and trap the UTL_FILE exceptions - see the docs for details.
I would guess that the problem you're getting is this: your database is on a server and you're trying to write to your client machine (i.e. your PC). You can't do this. PL/SQL is a server-side language and can only see the directories on the database machine. If you want to dump stuff to your local machine you have to use the SQL*Plus spool command, using DBMS_OUTPUT instead of UTL_FILE if you want complex assemblages.
cheers, APC

Please help with this part of error...

Hi all,
Please help me with this error. What i was trying to do is that when Server send a message to client, it print out on the screen what is sent to Client. For instance, if the Message is called FirstMessage sent to Client, the message FirstClient will display from server console with a specific message such as "First Message from server to client: first Message") and so on. I tried to implement the below code but when compiled it i got error message as follows :
C:\Java\bin>javac QuoteServer.java
QuoteServer.java:60: <identifier> expected
out.close();
^
QuoteServer.java:61: <identifier> expected
in.close();
^
QuoteServer.java:62: <identifier> expected
clientSocket.close();
^
QuoteServer.java:63: <identifier> expected
myserverSocket.close();
^
4 errors
Her is the Server side socket...
import java.net.*;
import java.io.*;
import java.util.*;
class QuoteServer
public static void main(String[] args) throws IOException
ServerSocket myserverSocket = null;
try
myserverSocket = new ServerSocket(4998);
} catch (IOException e)
 System.err.println("Could not listen on port: 4998.");
 System.exit(1);
Socket clientSocket = null;
try
clientSocket = myserverSocket.accept();
} catch (IOException e)
 System.err.println("Accept failed.");
 System.exit(1);
 PrintWriter out = new PrintWriter(clientSocket.getOutputStream(), true);
 BufferedReader in = new BufferedReader(
 new InputStreamReader(
 clientSocket.getInputStream()));
 String inputLine, outputLine;
 QuoteProtocol QP = new QuoteProtocol();
 outputLine = QP.processInput(null);
 Date current = new Date();
 out.println(outputLine);
 String ToClient;
 while ((inputLine = in.readLine()) != null )
 outputLine = QP.processInput(inputLine);
 out.println(outputLine);
 System.out.println(inputLine);
 System.out.println(current.toString());
 /* additional..if doesn't work delete this code*/
 while ((ToClient = in.readLine()) != null)
 System.out.println("Server: " + ToClient);
 if (ToClient.equals("Bye."))
 break;
 /* delete up to break*/
 if (outputLine.equals("Bye."))
 break;
out.close();
in.close();
clientSocket.close();
myserverSocket.close();
Could someone with the expertise advise me what shall i do?
Thank you very much.
Audrea.

Thanks for the quick reply...
Here is the code with correct open/close braces...
import java.net.*;
import java.io.*;
import java.util.*;
class QuoteServer
public static void main(String[] args) throws IOException
ServerSocket myserverSocket = null;
try
myserverSocket = new ServerSocket(4998);
} catch (IOException e)
 System.err.println("Could not listen on port: 4998.");
 System.exit(1);
Socket clientSocket = null;
try
clientSocket = myserverSocket.accept();
} catch (IOException e)
 System.err.println("Accept failed.");
 System.exit(1);
 PrintWriter out = new PrintWriter(clientSocket.getOutputStream(), true);
 BufferedReader in = new BufferedReader(
 new InputStreamReader(
 clientSocket.getInputStream()));
 String inputLine, outputLine;
 QuoteProtocol QP = new QuoteProtocol();
 outputLine = QP.processInput(null);
 Date current = new Date();
 out.println(outputLine);
 String ToClient;
 while ((inputLine = in.readLine()) != null )
 outputLine = QP.processInput(inputLine);
 out.println(outputLine);
 System.out.println(inputLine);
 System.out.println(current.toString());
 /* additional..if doesn't work delete this code*/
 while ((ToClient = in.readLine()) != null)
 System.out.println("Server: " + ToClient);
 if (ToClient.equals("Bye."))
 break;
 /* delete up to break*/
 if (outputLine.equals("Bye."))
 break;
out.close();
in.close();
clientSocket.close();
myserverSocket.close();
Line 60 starting from out.close(); onwards.
Please help..
Thanks a lot.
Audrea.

Please Help in Buffered Reader getting error.....

Getting error
java.lang.NumberFormatException: For input string: ""
     at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
     at java.lang.Integer.parseInt(Integer.java:468)
     at java.lang.Integer.parseInt(Integer.java:497)
     at charread.main(charread.java:18)
    import java.io.*;
    class charread
        InputStreamReader ir=new InputStreamReader(System.in);
        BufferedReader br=new BufferedReader(ir);
        public void main()throws IOException
            InputStreamReader ir=new InputStreamReader(System.in);
            BufferedReader br=new BufferedReader(ir);
            System.out.println("enter a character");
            char p=(char)(br.read());
            System.out.println("entered character = "+p);
            System.out.flush();
            System.out.println("enter a number");
            String s=br.readLine();
            int n=Integer.parseInt(s);
            System.out.println("enter a number = "+n);
        Please Help.....

JoachimSauer wrote:
First you read a single character, then you read the rest of the line.
You probably entered a character and pressed enter.
read() returned the character, readLine() returned the rest of the line, which is an empty String. And empty String can't be converted to an int.
It's probably the easiest approach to just replace read() with a readLine() and take the first character of that String (after verifying that there is a character and optionally that there's only one character in that String).Alternatively you can call readLine() after you read the char.
However this is merely a quick fix and I am concerned about other aspects of your program.
InputStreamReader ir=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(ir);The alternative to wrapping a BufferedReader around an InputStream is to use a Scanner, contrast the above example with the one below:
Scanner sin = new Scanner(System.in);
System.out.flush();Calling flush in this situation in unnecessary.
int n=Integer.parseInt(s);Place the following code in a try/catch block every single time you parse a String from a user into an Integer in case an Exception occurs, e.g. user enters a word or letter.
Integer n = null;
while(n == null) {
try {
    String s = br.readLine();
    n = Integer.parseInt(s);
} catch(NumberFormatException e) {
    System.out.println("Please enter an Integer");
}Finally onto Class naming conventions, Class names begin with a capital letter, variables and methods begin with a lower case letter.
class charreadAvoid naming methods "void", especially with a return value of null. Or one might think, well in my case anyway that this is the entry point into your application.
public void main()Mel

Please help me on Following sytax error in Work flows

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