Please write a query for given senario

Question

Hai All,
Name Date
anil 05/28/12
anil 05/25/12
anil 05/24/12
anil 05/23/12
anil 05/22/12
anil 05/21/12
anil 05/18/12
anil 05/17/12
anil 05/16/12
anil 05/15/12
suma 05/28/12
suma 05/25/12
suma 05/24/12
suma 05/23/12
suma 05/15/12
This is the only sample data of the employee attendance table.I want know those who are absent in the last 10 days and also not consider the days Sunday and Saturday.
Example
Anil : He had present in all the days, no need to display 'Anil' name
Suma : She had not present in all the day, then show the 'Suma' name with 'Absent Days' (05/22/12,05/21/12, 05/18/12, 05/17/12, 05/18/12)
This is the only sample data.
Edited by: adam on May 28, 2012 3:44 AM
Edited by: adam on May 28, 2012 3:47 AM

Answer 1

First of all, hijacking someone's topic is not welcome. Said that, meditate over the difference:
SQL> with  tab  as (
  2                        select 'anil' name,to_date('05/28/12','mm/dd/rr') dt from dual union all
  3                        select 'anil',to_date('05/25/12','mm/dd/rr') from dual union all
  4                        select 'anil',to_date('05/24/12','mm/dd/rr') from dual union all
  5                        select 'anil',to_date('05/23/12','mm/dd/rr') from dual union all
  6                        select 'anil',to_date('05/22/12','mm/dd/rr') from dual union all
  7                        select 'anil',to_date('05/21/12','mm/dd/rr') from dual union all
  8                        select 'anil',to_date('05/18/12','mm/dd/rr') from dual union all
  9                        select 'anil',to_date('05/17/12','mm/dd/rr') from dual union all
10                        select 'anil',to_date('05/16/12','mm/dd/rr') from dual union all
11                        select 'anil',to_date('05/15/12','mm/dd/rr') from dual union all
12                        select 'suma',to_date('05/28/12','mm/dd/rr') from dual union all
13                        select 'suma',to_date('05/25/12','mm/dd/rr') from dual union all
14                        select 'suma',to_date('05/24/12','mm/dd/rr') from dual union all
15                        select 'suma',to_date('05/23/12','mm/dd/rr') from dual union all
16                        select 'suma',to_date('05/15/12','mm/dd/rr') from dual
17                       )
18  select  s.name,
19          dat.dt
20    from     
21    tab s right outer join (
22               select  trunc(sysdate - level + 1) dt
23                 from  dual connect by    level <= 14
24              ) dat
25         
26            partition by (s.name)
27            on ((s.dt) = (dat.dt))
28    where s.dt is null
29    and to_char(dat.dt ,'d') not in (1,7)
30    order by s.name,
31             dat.dt
32  /
no rows selectedand
SQL> with  tab  as (
  2                        select 'anil' name,to_date('05/28/12','mm/dd/rr') dt from dual union all
  3                        select 'anil',to_date('05/25/12','mm/dd/rr') from dual union all
  4                        select 'anil',to_date('05/24/12','mm/dd/rr') from dual union all
  5                        select 'anil',to_date('05/23/12','mm/dd/rr') from dual union all
  6                        select 'anil',to_date('05/22/12','mm/dd/rr') from dual union all
  7                        select 'anil',to_date('05/21/12','mm/dd/rr') from dual union all
  8                        select 'anil',to_date('05/18/12','mm/dd/rr') from dual union all
  9                        select 'anil',to_date('05/17/12','mm/dd/rr') from dual union all
10                        select 'anil',to_date('05/16/12','mm/dd/rr') from dual union all
11                        select 'anil',to_date('05/15/12','mm/dd/rr') from dual union all
12                        select 'suma',to_date('05/28/12','mm/dd/rr') from dual union all
13                        select 'suma',to_date('05/25/12','mm/dd/rr') from dual union all
14                        select 'suma',to_date('05/24/12','mm/dd/rr') from dual union all
15                        select 'suma',to_date('05/23/12','mm/dd/rr') from dual union all
16                        select 'suma',to_date('05/15/12','mm/dd/rr') from dual
17                       )
18  select  s.name,
19          dat.dt
20    from     
21    tab s
22    partition by (s.name)
23    right outer join (
24               select  trunc(sysdate - level + 1) dt
25                 from  dual connect by    level <= 14
26              ) dat
27            on ((s.dt) = (dat.dt))
28    where s.dt is null
29    and to_char(dat.dt ,'d') not in (1,7)
30    order by s.name,
31             dat.dt
32  /
NAME DT
suma 16-MAY-12
suma 17-MAY-12
suma 18-MAY-12
suma 21-MAY-12
suma 22-MAY-12
SQL> But still, query can produce wrong results. Why? It is NLS-dependent. If your query will be executed by a client in, for example, Germany, your query will filter out Mondays and Sundays. In, for example, Saudi Arabia it will filter out Friday and Saturday.
SY.