PRG Pattern in web applications

Hi,
How to create PostRedirectGet(PRG) pattern based java web application which avoids duplicate submission problem.
Any links are really appreciated.
Thanks.

Because a redirect is performed by the browser (it becomes a new GET request); a forward is done on the server and is done within the same request; the browser doesn't even know it happened. The proof of that is the URL bar - when you do a forward, the URL doesn't change.If you redirect, the URL shown is the page you redirect to.
See it from the perspective of the browser history.
GET (fetch form page)
POST (submit form; server software processes form submission)
GET (fetch result page after form submission is processed)
If at this point the user presses the browser's back button, he goes back to that GET request and the result page is shown again (likely a cached instance of it too).
Now if it were a forward, the history is like this:
GET (fetch form page)
POST (submit form; server software processes form submission and forwards control to the result page)
If at this point the user presses the browser's back button, he goes back to the POST request and you'll get that nagging dialog box from the browser warning against resubmission.

Similar Messages

What is the design pattern for web application with struts & hibernate?

Hi everyone,
I am new to web application developement.I am using struts for MVC framework & Hibernate for ORM framework.I am little confused that struts used bean representation for collecting form fields(Bean 1),value objects(DTO) for passing value to the JSP(Bean 2) & hibernate use the bean like representation for persistent object(Bean 3).Whether we must use all the bean's which are similar to each other or any reusable bean recommended?

I'm sure why it didn't work. That is how I bundle the JRE. The only disadvantage about bundling is the size of the installer file will be pretty large. In my opinion, relying on a public version is not a good idea if you have no control of the target box. The user might, for some reason, decide to uninstall java or upgrade to a new incompatible version and your app. may stop working. I'm sure many on here will disagree with this though.
I always use the marner .exe wrapper:
http://www.megaupload.com/?d=FYZAVM77
and inno installer:
http://www.jrsoftware.org/isinfo.php
They're both free to use and I've had no problems with them. Another wrapper is Javaround:
http://sourceforge.net/project/showfiles.php?group_id=234356

How can I develop a web application using EJB design pattern?

I have searched over the web and found quite a lot of tutorials on how to use the EJB design pattern.
I know that there will be a home interface, EJB object interface and a SessionBean.
But the tutorials often only cover a single class, this made me unable to get a complete picture of how EJB design pattern can be implemented into a whole system.
I am now required to devleop an online shopping web application using EJB and JSP page.
I think I will need to create a lot of classes: Member, ShoppingCart, Product...etc.
What I want to ask is that, do I need to create a home interface, EJB object interface and a SessionBean for each of these classes?
I really need some ideas on how to develop this system using EJB + JSP pages.
Many thanks to you all.

For every EJB that you want to create, you will need to code a home and remote interface and a bean class.
You could start getting your ideas here
http://www.theserverside.com/books/wiley/masteringEJB/
http://www.coreservlets.com

Does any body have any design patterns of JSF Web Application Developping?

Can any one answer me some questions?
#1.I am an amatuar of people who develop Web Application.For some reason,We choose the JSF to develop our item.through some introduction,I know the UI component of JSF is resided in Server side,is it right?but I am a little confused that:if there are many users who are exploring our jsf website.(to simplify my question,image I had just one web page and just one button)How many UI components(buttons) will be there?How it(they?) works?
#2.Does any body have the success experience (for example design pattern)to develop web applications?if We just concern about the Add,Delete,Modify,Query operations of some data.
I just do my job according to my feeling.
I will give every page a pagebean(backing bean),and I am not sure how to combine the business data with the pagebean.some one suggested that I should use delegate pattern to separate my business log and page logic.But I am still confused by following things:
#2.1 does JSF have the same ability to help us construct the model dialog just like swing to
help us control the operation flow?
#2.2 If there is not,Does the following way work?I put every tabledata's property as corresponed component.if user choosed the row in the table,My Listener will syncronize the row data to the components.But
#2.2.1 if JSF has the components according to the web users' number,how can My Listener tell which component should be update?Should I maintain the map?
#2.2.2 If the problem I imaged above is false,Does any body can tell me how to custom the ListDataModel,so I can use it like Swing?because now I can just use some view data to insert into ListDataModel,but after some selection operation,my business object must be find according to the selected data,it is not an interesting job!
I am waiting for your advice!

Ok I'll try to explain Step by step please correct me if I make any mistake because I have not played much with shared variables.
To create a shared variable to an RT target go to the target if tou have already otherwise add an RT target by right clicking the Project>>Add targets and Devices
Then in the target Right clikc and select the variable as shown below.
Then once the Shared variable settings window opens Enter a variable name and then Select the type "Network Published"
In the right side you can select the data type for the shared variable and even you can choose your custome controls.
After selecting the data type go for the Network and select buffering if required else leave it if you are planning to use the variable just for display purpose.
Then you can enable the RT FIFO if required (Not able to explain how it works and why it is used).
Then after completing the Shared variable setup you can access the variable in the VI in both the Host and the RT.
You can bind the variable to a control so that if any data from the RT is coming you can read the data from that control.
Once you have placed your shared variable in the BD you can change the access typr to read or write depending on your need.
This might not explain the complete shared variable concept but I believe that this would defenelty give you a kick off to start using the shared variable. Please correct or add more comments if anybody know better.
Good luck.
The best solution is the one you find it by yourself

Per Web Application singleton pattern

Hello
I have a application (ear) file that look something like this:
App.ear
-- Web_1.war
----- WEB-INF/lib/helper.jar
-- Web_2.war
----- WEB-INF/lib/helper.jar
-- Web_3.war
----- WEB-INF/lib/helper.jar
inside helper.jar there is a singleton class., which get initialised differently depending on which Web_<X> it is loaded in. This currently works because each lib directory get loaded by each own classloader.
I would really like to move the helper.jar up to the <ear file>/lib directory, but that means it is only loaded by the classloaders once anf thus the 3 singletons break as there is now only one.
I would like to have some sort of "Per Web application" globally reachable "singleton".
I have thought about using ServletContext, but it appears that there is no easy ways for helper classes to look it up, unless it is passed as a parameter.
A second idea would be to use ThreadLocals, but that would rely on the Web container not reusing threads accross web applications. I am not sure if this is guranteed not to happen ...
In any case, what is the best way to handle this ? is there any standard way or a design pattern to follow...

I suppose another way of asking this question is this:
is there a way to use the singleton pattern on a
per-web-application basis without storing the
singleton in the ServletContext? If I can find a way
to do that, I can solve my initial problem.Some web application servers run each webapp in a separate JVM, or at least a separate classloader. If yours does either of those, then each webapp will have its own instance of the singleton. Try it.

Web application and web.xml

i have a web application consisting of 1 servlet and 5 jsps.
the start point would be index.jsp
i use firmwide login page. after login, i want the browser to display index.jsp page.
In web.xml, i have defined -
<welcome-file-list> <welcome-file>/jsp/index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>UtilitiesServlet</servlet-name> <servlet-class>com.gs.fw.sox404.utilities.UtilitiesServlet</servlet-class> <init-param> <param-name>util-log4j-init-file</param-name> <param-value>/WEB-INF/classes/util_log4j.properties</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>UtilitiesServlet</servlet-name> <url-pattern>/UtilitiesServlet</url-pattern> </servlet-mapping>if i define it as just index.jsp in the welcome file list, after successful login, it displays the dir structure of the web app.
if i define it as jsp/index.jsp, then in some of the pages, it tries to find the servlet inside jsp folder.
What would be the best way to get around this?

Well, yes, it's not able to find it because you've not understood the mechanism of how it works clearly. You have to put your welcome file under every directory you want it to be used from. Like I said, it's not a path, it's a filename. So if the container sees that your request URL is for a directory, it'll look for the welcome files from the welcome file list, one by one, in the order of declaration. Whichever one it finds first, it'll serve that. If it doesn't find any, then it'll either give a 404 or a directory listing depending on the server and it's settings.
So your problem is that you've put your index.jsp in your JSP folder but expect it to be served for all URLs. That won't happen, you'll have to put one file named index.jsp into every directory. The reasoning is pretty simple, what if you want different behaviour for each folder?
This should fix your problem :)
People on the forum help others voluntarily, it's not their job.
Help them help you.
Learn how to ask questions first: http://faq.javaranch.com/java/HowToAskQuestionsOnJavaRanch
----------------------------------------------------------------

Unable to access java web application index page on Weblogic server 10.3.6

Hi,
I have deployed a Web application on Weblogic server.
My war file is very basic with just a index page.
I am able to deploy & access its index page properly in OC4J ( applicaton server on soa suite 10g ) and apache tomcat.
But when i deployed same war file in weblogic am not able to access its index page, Getting below error:
Error 503--Service Unavailable
From RFC 2068 Hypertext Transfer Protocol -- HTTP/1.1:
*10.5.4 503 Service Unavailable*The server is currently unable to handle the request due to a temporary overloading or maintenance of the server. The implication is that this is a temporary condition which will be alleviated after some delay. If known, the length of the delay may be indicated in a Retry-After header. If no Retry-After is given, the client SHOULD handle the response as it would for a 500 response.
status=Prepared, Consolidated State=Prepared, Target-Specific State= Prepared.
what does Prepared indicates here?*
Adminserver.log prints blow log when i try to access the index page
####<Dec 26, 2012 8:27:17 AM GMT> <Warning> <netuix> <soa-app-dev-01.am.health.ge.com> <AdminServer> <[ACTIVE] ExecuteThread: '21' for queue: 'weblogic.kernel.Default (self-tuning)'> <501226496> <> <9b375c7445d8c121:79ee4f70:13bc880be7a:-8000-0000000000000209> <1356510437306> <BEA-423420> <Redirect is executed in begin or refresh action. Redirect url is /console/console.portal?_nfpb=true&_pageLabel=WebAppApplicationOverviewPage&WebAppApplicationOverviewPortlethandle=com.bea.console.handles.AppDeploymentHandle%28%22com.bea%3AName%3D*Weblogs*%2CType%3DAppDeployment%22%29.>
My Deployment descriptors are as below:
Web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>Weblogs</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<servlet>
<description></description>
<display-name>SOA11gLogServlet</display-name>
<servlet-name>SOA11gLogServlet</servlet-name>
<servlet-class>com.ge.healthcare.soa.logs.SOA11gLogServlet</servlet-class>
</servlet>
</web-app>
==================================================================
weblogic.xml
<?xml version="1.0" encoding="UTF-8"?>
<wls:weblogic-web-app xmlns:wls="http://xmlns.oracle.com/weblogic/weblogic-web-app" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd http://xmlns.oracle.com/weblogic/weblogic-web-app http://xmlns.oracle.com/weblogic/weblogic-web-app/1.3/weblogic-web-app.xsd">
<wls:weblogic-version>10.3.6</wls:weblogic-version>
<wls:context-root>/Weblogs</wls:context-root>
</wls:weblogic-web-app>
==================================================================
Please help me to resolve the issue,its bit urgent.Let me know in case of anything else required to check and verify.
Thanks in advance.
Regards,
Rahul Aahir
Edited by: 978673 on Dec 26, 2012 4:22 PM
Edited by: 978673 on Dec 26, 2012 4:32 PM

In weblogic 10.3.6, when you deploy using console, you have to click on start button which appears in Deployments page.
Your weblogic.xml file should be as below:
<?xml version="1.0" encoding="UTF-8"?>
<wls:weblogic-web-app xmlns:wls="http://xmlns.oracle.com/weblogic/weblogic-web-app" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd http://xmlns.oracle.com/weblogic/weblogic-web-app http://xmlns.oracle.com/weblogic/weblogic-web-app/1.3/weblogic-web-app.xsd">
<wls:weblogic-version>10.3.6</wls:weblogic-version>
<wls:context-root>/logs</wls:context-root>
<container-descriptor>
<index-directory-enabled>true</index-directory-enabled>
</container-descriptor>
<virtual-directory-mapping>
     <local-path>/opt/oracle/logs</local-path> (as per your path)
     <url-pattern>/logs/*</url-pattern>
     <url-pattern>*.log</url-pattern>
</virtual-directory-mapping>
</wls:weblogic-web-app>

A web developer problem while running a web application

Hi all,
I'm novice to J2EE.
I've encountered a problem while accessing the deployed module in weblogic 8.1 server.
I'm sure that the webapplication module is deployed as i saw my module in administration console & also the status said that it is deployed.
when i access my web application by specifying the proper server and port no and context root it is showing
either 505 - resource not found error(http://localhost:7001/Suresh-2/Suresh) or 404 - not found error.( http://localhost:7001/Suresh-2/Suresh)
Now let me elaborate what i've done till now.
My webapplication folder structure is : C:\bea\user_projects\domains\mydomain\applications\Suresh\WEB-INF\classes\Sai\ServExamp.class
My servlet is ServExamp.java
I created a folder called "Suresh". In that folder created another folder called "WEB-INF". In WEB-INF created a folder called "Classes".
Since my servlet is in package "Sai", the .class file reside in \Suresh\WEB-INF\Classes\Sai\ServExamp.class
The source code is :
package Sai;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
public class ServExamp extends HttpServlet
public void doPost(HttpServletRequest req,HttpServletResponse res)throws IOException
PrintWriter out=res.getWriter();
java.util.Date today=new java.util.Date();
out.println("<html>"+"<body>"+
"<h1 align=center>HF\'s Chapter1 Servlet </h1>"
+"<br>"+today+"</body>"+"</html>");
Now i'm almost done creating a web application. Next, I constructed a simple web.xml descriptor that gives a web friendly name for my servlet, and points to the servlet. I constructed web.xml descriptor file in the WEB-INF folder (C:\bea\user_projects\domains\mydomain\applications\Suresh\WEB-INF\).
The web.xml file source is :
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<display-name>Hello World Web Application</display-name>
<description>Test Servlet</description>
<servlet>
<servlet-name>ServExamp</servlet-name>
<servlet-class>Sai.ServExamp</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ServExamp</servlet-name>
<url-pattern>/Suresh</url-pattern>
</servlet-mapping>
</web-app>
Now I have told Weblogic that the URI /Suresh corresponds to my servlet "Sai.ServExamp".
My Web Application is ready to be deployed at this point. I logged onto Weblogic's admin console,
1) clicked on deployments, then navigated to "Web Application Modules" .
2) Clicked "Deploy new Web Application Module"
3) Navigated to the location of your web application folder (Suresh). There was a radio button next to it indicating that I can select that folder as a valid web application.
4) I Clicked that radio button and clicked "Target Module".
5) It informed that my web application "Suresh" will be deployed to myServer.It asked a name for my web application deployment. By default it was "Suresh"
I clicked Deploy.
6) After deployment, my web application "Suresh" appeared in the "Web Application Modules" tree on the left.
I Clicked on "Suresh"( my web application) then clicked the testing tab, then clicked the link shown there(http://localhost:7001/Suresh-2).
It was not showing my servlet (showed a 403 error)
Error - 403
This status code is commonly used when the server does not wish to reveal exactly why the request has been refused, or when no other response is applicable.
I think so it came b'coz I don't have an index.html or index.jsp page.
7)Instead,I added my servlet on to the URL it provided.
http://localhost:7001/Suresh-2/Suresh
It is showing these error code: Http: 505 resource not allowed
The page cannot be displayed
The page you are looking for cannot be displayed because the address is incorrect.
Please try the following:
If you typed the page address in the Address bar, check that it is entered correctly.
Open the localhost:7001 home page and then look for links to the information you want.
Click Search to look for information on the Internet.
when i just type : http://localhost:7001/ -> Error 404 not found error
it's showing
Error 404--Not Found
From RFC 2068 Hypertext Transfer Protocol -- HTTP/1.1:
10.4.5 404 Not Found
The server has not found anything matching the Request-URI. No indication is given of whether the condition is temporary or permanent.
If the server does not wish to make this information available to the client, the status code 403 (Forbidden) can be used instead. The 410 (Gone) status code SHOULD be used if the server knows, through some internally configurable mechanism, that an old resource is permanently unavailable and has no forwarding address.
I want to run my web application & any help would be appreciated.
Thanks in advance.
with regards,
S.SayeeNarayanan.
Note: I even deployed my war file, which i got by execution of (jar cv0f webapp.war . ) command from the root directory of my web application i.e. Suresh
Then executed my webapplication it is showing
error-505 resource not allowed.
--------------------------------------------------------------------------------------------

try a fully qualified path to the pem file

How do I define my web application path in Tomcat6

Hi friends,
Can anybody tell me how to define and where to define my web-application path in tomcat 6 server?
I absolutely don't want to change any files inside tomcat6\conf\ folder (like its server.xml or context.xml)
My problem comes in the following scenario:
i) My Webapplication path is c:\tomcat6\webapps\test-servletii) I have one html form file registration.html in c:\tomcat6\webapps\test-servlet\registration.htmliii) I have a form processing servlet in path c:\tomcat6\webapps\test-servlet\WEB-INF\classes\pkg_register\Process_Registration.classiv) web.xml file inside WEB-INF\ has contents
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
   version="2.5">
<servlet>
     <servlet-name>Process_Registration</servlet-name>
     <servlet-class>pkg_register.Process_Registration</servlet-class>
</servlet>
<servlet-mapping>
     <servlet-name>Process_Registration</servlet-name>
     <url-pattern>/Process_Registration</url-pattern>
</servlet-mapping>
</web-app>PROBLEM : In html <form action="/test-servlet/Process_Registration"> works fine.
But every time I don't want to give my web application folder name in URLs( not in web.xml or in form action, it should be default relative path).
I want to give just, <form action="/Process_Registration"> in registration.html file's form action.
Any help is appreciated.
Thanks.
---Sujoy

Thanks...
It solved the problem by putting <form action="Process_Registration"> instead of <form action="/Process_Registration">When I was using <form action="/Process_Registration"> it was directly taking me to
http://localhost:8888/Process_Registration .
But, now when i use <form action="Process_Registration"> it takes me to
http://localhost:8888/test-servlet/Process_Registration which IS CORRECT.
But, still i don't know why the <form action="/Process_Registration"> was taking me out of my current webapplication path. It should have given me ERROR.
--Sujoy

Create a new web application, how shall I update the file server.xml

Hi,
I will create a new web application, i.e named newApp. Then I create a file structure as follows:
- <server-root>/newApp
- <server-root>/newApp/WEB-INF
- <server-root>/newApp/WEB-INF/classes
Then I must tell the server that I have created a new web application. Then I must update my file server.xml, How shall I do this and where in the file shall I type in the new information?
I use windows XP Pro, and Tomcat 4.1.27.
My server.xml file looks like below:



<Server port="8005" shutdown="SHUTDOWN" debug="0">


<Listener className="org.apache.catalina.mbeans.ServerLifecycleListener"
debug="0"/>
<Listener className="org.apache.catalina.mbeans.GlobalResourcesLifecycleListener"
debug="0"/>

<GlobalNamingResources>

<Environment name="simpleValue" type="java.lang.Integer" value="30"/>

<Resource name="UserDatabase" auth="Container"
type="org.apache.catalina.UserDatabase"
description="User database that can be updated and saved">
</Resource>
<ResourceParams name="UserDatabase">
<parameter>
<name>factory</name>
<value>org.apache.catalina.users.MemoryUserDatabaseFactory</value>
</parameter>
<parameter>
<name>pathname</name>
<value>conf/tomcat-users.xml</value>
</parameter>
</ResourceParams>
</GlobalNamingResources>


<Service name="Tomcat-Standalone">


<Connector className="org.apache.coyote.tomcat4.CoyoteConnector"
port="8080" minProcessors="5" maxProcessors="75"
enableLookups="true" redirectPort="8443"
acceptCount="100" debug="0" connectionTimeout="20000"
useURIValidationHack="false" disableUploadTimeout="true" />




<Connector className="org.apache.coyote.tomcat4.CoyoteConnector"
port="8009" minProcessors="5" maxProcessors="75"
enableLookups="true" redirectPort="8443"
acceptCount="10" debug="0" connectionTimeout="0"
useURIValidationHack="false"
protocolHandlerClassName="org.apache.jk.server.JkCoyoteHandler"/>












<Engine name="Standalone" defaultHost="localhost" debug="0">



<Logger className="org.apache.catalina.logger.FileLogger"
prefix="catalina_log." suffix=".txt"
timestamp="true"/>


<Realm className="org.apache.catalina.realm.UserDatabaseRealm"
debug="0" resourceName="UserDatabase"/>







<Host name="localhost" debug="0" appBase="webapps"
unpackWARs="true" autoDeploy="true">





<Logger className="org.apache.catalina.logger.FileLogger"
directory="logs" prefix="localhost_log." suffix=".txt"
timestamp="true"/>

<DefaultContext reloadable="true"/>

<Context path="" docBase="ROOT" debug="0"/>

<Context path="/examples" docBase="examples" debug="0"
reloadable="true" crossContext="true">
<Logger className="org.apache.catalina.logger.FileLogger"
prefix="localhost_examples_log." suffix=".txt"
timestamp="true"/>
<Ejb name="ejb/EmplRecord" type="Entity"
home="com.wombat.empl.EmployeeRecordHome"
remote="com.wombat.empl.EmployeeRecord"/>




<Environment name="maxExemptions" type="java.lang.Integer"
value="15"/>
<Parameter name="context.param.name" value="context.param.value"
override="false"/>
<Resource name="jdbc/EmployeeAppDb" auth="SERVLET"
type="javax.sql.DataSource"/>
<ResourceParams name="jdbc/EmployeeAppDb">
<parameter><name>username</name><value>sa</value></parameter>
<parameter><name>password</name><value></value></parameter>
<parameter><name>driverClassName</name>
<value>org.hsql.jdbcDriver</value></parameter>
<parameter><name>url</name>
<value>jdbc:HypersonicSQL:database</value></parameter>
</ResourceParams>
<Resource name="mail/Session" auth="Container"
type="javax.mail.Session"/>
<ResourceParams name="mail/Session">
<parameter>
<name>mail.smtp.host</name>
<value>localhost</value>
</parameter>
</ResourceParams>
<ResourceLink name="linkToGlobalResource"
global="simpleValue"
type="java.lang.Integer"/>
</Context>
</Host>
</Engine>
</Service>
</Server>

To use servlets u have indeed to update your web.xml...Well I'm not sure this is relevant to your case anyway.
You have to add a <servlet> element to this file.
Something like this:
<servlet>
<servlet-name>blabla</servlet-name>
<servlet-class>blablapackage.Blablaclass</servlet-class>
<init-param>...</init-param>
</servlet>
Now this may not solve your problem. Make sure you refer to your servlets using their full qualified names.btw, just to be sure, what is your definition of "servlet"? (i mean: any java class or only javax.servlet.Servlet)

Problem with Configuring Tomcat for running jsp web applications..Plz HELP

I am using Tomcat 5.5 and Jdk 1.5.0_12 and Oracle 10g. I am using jdbc-odbc bridge connection
to connect to the database. I have placed my project folder called
tdm under the webapps folder in Tomcat. This 'tdm' folder consists of
a collection of html pages,jsp pages and images of my project. Also I created a
WEB-INF folderand in that I have lib folder which contains catalina-root.jar
, classes12.jar and nls_charset.jar files. And also in the WEB-INF folder I have the web.xml
file which looks like this
<?xml version="1.0" encoding="ISO-8859-1"?>

<web-app>
<resource-ref>
<description>Oracle Datasource example</description>
<res-ref-name>jdbc/gdn</res-ref-name>
<res-type>javax.sql.DataSource</res-type>
<res-auth>Container</res-auth>
</resource-ref>
</web-app>
My Server.xml file in Tomcat\conf folder is as follows



<Server port="8005" shutdown="SHUTDOWN">

<Listener className="org.apache.catalina.mbeans.ServerLifecycleListener" />
<Listener className="org.apache.catalina.mbeans.GlobalResourcesLifecycleListener" />

<GlobalNamingResources>

<Environment name="simpleValue" type="java.lang.Integer" value="30"/>

<Resource name="UserDatabase" auth="Container"
type="org.apache.catalina.UserDatabase"
description="User database that can be updated and saved"
factory="org.apache.catalina.users.MemoryUserDatabaseFactory"
pathname="conf/tomcat-users.xml" />
<Resource name="jdbc/gdn" auth="Container"
type="javax.sql.DataSource" driverClassName="sun.jdbc.odbc.JdbcOdbcDriver"
url="jdbc:odbc:gdn"
username="system" password="tiger" maxActive="20" maxIdle="10"
maxWait="-1"/>
</GlobalNamingResources>


<Service name="Catalina">


<Connector
port="5050" maxThreads="150" minSpareThreads="25" maxSpareThreads="75"
enableLookups="false" redirectPort="8443" acceptCount="100"
connectionTimeout="20000" disableUploadTimeout="true" />

     



<Connector port="8009"
enableLookups="false" redirectPort="8443" protocol="AJP/1.3" />






<Engine name="Catalina" defaultHost="localhost">




<Realm className="org.apache.catalina.realm.UserDatabaseRealm"
resourceName="UserDatabase"/>







<Host name="localhost" appBase="webapps"
unpackWARs="true" autoDeploy="true"
xmlValidation="false" xmlNamespaceAware="false">









<Context path="/tdm" docBase="tdm" debug="0" reloadable="true" />
</Host>
</Engine>
</Service>
</Server>
I have set the context path to /tdm in the server.xml file. Should this be placed in context.xml?
My first page in the project is called Homepage.html. To start my project I give http://localhost:5050/tdm/homepage.html
in a browser. Here I accept a username and password from the user and then do the validation in
a valid.jsp file, where I connect to the database and check and use jsp:forward to go to next pages
accordingly. However when I enter the username and password and click Go in the homepage, nothing is
displayed on the next page. The URL in the browser says valid.jsp but a blank screen appears.
WHY DOES IT HAPPEN SO? DOES IT MEAN THAT TOMCAT IS NOT RECOGNIZING JAVA IN MY SYSTEM OR IS IT A PROBLEM
WITH THE DATABASE CONNECTION OR SOMETHING ELSE? I FEEL THAT TOMCAT IS NOT EXECUTING JSP COMMANDS?
IS IT POSSIBLE?WHY WILL THIS HAPPEN?
I set the JAVA_HOME and CATALINA_HOME environment to the jdk and tomcat folders resp.
Is there any other thing that I need to set in classpath? Should I have my project as a
WAR file in the webapps of TOMCAT or just a folder i.e. directory structure will fine?

I am using Tomcat 5.5 and Jdk 1.5.0_12 and Oracle 10g. I am using jdbc-odbc bridge connection
to connect to the database. I have placed my project folder called
tdm under the webapps folder in Tomcat. This 'tdm' folder consists of
a collection of html pages,jsp pages and images of my project. Also I created a
WEB-INF folderand in that I have lib folder which contains catalina-root.jar
, classes12.jar and nls_charset.jar files. And also in the WEB-INF folder I have the web.xml
file which looks like this
<?xml version="1.0" encoding="ISO-8859-1"?>

<web-app>
<resource-ref>
<description>Oracle Datasource example</description>
<res-ref-name>jdbc/gdn</res-ref-name>
<res-type>javax.sql.DataSource</res-type>
<res-auth>Container</res-auth>
</resource-ref>
</web-app>
My Server.xml file in Tomcat\conf folder is as follows



<Server port="8005" shutdown="SHUTDOWN">

<Listener className="org.apache.catalina.mbeans.ServerLifecycleListener" />
<Listener className="org.apache.catalina.mbeans.GlobalResourcesLifecycleListener" />

<GlobalNamingResources>

<Environment name="simpleValue" type="java.lang.Integer" value="30"/>

<Resource name="UserDatabase" auth="Container"
type="org.apache.catalina.UserDatabase"
description="User database that can be updated and saved"
factory="org.apache.catalina.users.MemoryUserDatabaseFactory"
pathname="conf/tomcat-users.xml" />
<Resource name="jdbc/gdn" auth="Container"
type="javax.sql.DataSource" driverClassName="sun.jdbc.odbc.JdbcOdbcDriver"
url="jdbc:odbc:gdn"
username="system" password="tiger" maxActive="20" maxIdle="10"
maxWait="-1"/>
</GlobalNamingResources>


<Service name="Catalina">


<Connector
port="5050" maxThreads="150" minSpareThreads="25" maxSpareThreads="75"
enableLookups="false" redirectPort="8443" acceptCount="100"
connectionTimeout="20000" disableUploadTimeout="true" />

     



<Connector port="8009"
enableLookups="false" redirectPort="8443" protocol="AJP/1.3" />






<Engine name="Catalina" defaultHost="localhost">




<Realm className="org.apache.catalina.realm.UserDatabaseRealm"
resourceName="UserDatabase"/>







<Host name="localhost" appBase="webapps"
unpackWARs="true" autoDeploy="true"
xmlValidation="false" xmlNamespaceAware="false">









<Context path="/tdm" docBase="tdm" debug="0" reloadable="true" />
</Host>
</Engine>
</Service>
</Server>
I have set the context path to /tdm in the server.xml file. Should this be placed in context.xml?
My first page in the project is called Homepage.html. To start my project I give http://localhost:5050/tdm/homepage.html
in a browser. Here I accept a username and password from the user and then do the validation in
a valid.jsp file, where I connect to the database and check and use jsp:forward to go to next pages
accordingly. However when I enter the username and password and click Go in the homepage, nothing is
displayed on the next page. The URL in the browser says valid.jsp but a blank screen appears.
WHY DOES IT HAPPEN SO? DOES IT MEAN THAT TOMCAT IS NOT RECOGNIZING JAVA IN MY SYSTEM OR IS IT A PROBLEM
WITH THE DATABASE CONNECTION OR SOMETHING ELSE? I FEEL THAT TOMCAT IS NOT EXECUTING JSP COMMANDS?
IS IT POSSIBLE?WHY WILL THIS HAPPEN?
I set the JAVA_HOME and CATALINA_HOME environment to the jdk and tomcat folders resp.
Is there any other thing that I need to set in classpath? Should I have my project as a
WAR file in the webapps of TOMCAT or just a folder i.e. directory structure will fine?

How do I access files within projects of the same web application?

Using JDeveloper Studio 11.1.1.1.0
I'm creating a web application using the Model-View-Controller design pattern. Model represents data, View represents data display, and Controller is control...
In my application, I created two projects: EJBModel and UserInterface. EJBModel contains the model aspect so it has entity objects and beans to access/manipulate the data. The UserInterface project stores the web interface - mostly jsps. In the UserInterface project, I need a managed bean that calls methods from the beans created in the EJBModel project. I can do this using the @EJB annotation and creating an instance of the class, but since the files are in separate projects that can't see each other and JDeveloper shows an error because it can't find the necessary file. It is best practice to create two projects as it keeps both elements distinct.
So I wanted to know the best way to access the files stored in separate projects within the same application. Is there a way to package them together?
Thanks...

In the UI project, go to project properties->dependencies and add a dependency on the model project.
This way JDeveloper will know what classes you are referencing.

Need help!!!! Best solution for a web application to customize teamsport apparel online

Help!!!!
Hi I am a web designer at beginners stage with web
devlopment. I am seeking guidance on how to develop a customized
interactive web application so that the end user can change color
and patterns of apparel on vector images such as teamsports
uniforms and tshirts. Once the design is customized to their liking
they can save it with all of the spec information in a file to
there desktop or to a database to send to the manufacturer.
Also looking for a possible way to use a CMS so I can upload
templates of the garment easily for the end user to customize
online. Can this be done and if so how? This is an example the kind
of application I am looking for:
http://www.dynamicteamsports.com/elite/placeorder.jsp
I am in desperate need of some brilliant developer to help
with this.
Thanks in advance for anyone who is willing to assist or give
me guidance,
Danka
"Reap what you sew"

Something like what you are attempting is not simple.
Flash, Flex would be ideal for creating the UI and
manipulating the vectors.

My First Web Application is not Working

I have tried to design a webapplication. the index file just presents two input fields and a submitt button, but when i press submitt, the browser displays '.../FirstServlet' not found. I think there is something wrong with allocation of files in the proper directories. or something else....? I have tried to deploy WAR File generated by NetBeans through Apache-Tomcat but same is the result?
The Error Header is as under:
HTTP Status 404 /MyApp/%E2%80%9Chttp:/localhost:808/FirstServlet"
The code is as under:
*1) Index.html:*
{color:#ff0000}+<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">+{color}
{color:#ff0000}+<html>+{color}
{color:#ff0000}+<body>+{color}
{color:#ff0000}+<form method="POST" ACTION = "http://localhost:8080/FirstServlet" NAME="myForm">+{color}
{color:#ff0000}+<h2> Enter your name</h2>+{color}
{color:#ff0000}+<INPUT TYPE="text" name="name"/>+{color}
{color:#ff0000}+
+{color}
{color:#ff0000}+<h2> Salary</h2>+{color}
{color:#ff0000}+<INPUT TYPE="text" name="salary"/>+{color}
{color:#ff0000}+
+{color}
{color:#ff0000}+<INPUT type="submit" value="Submit"/>+{color}
{color:#ff0000}+</form>+{color}
{color:#ff0000}+</body>+{color}
{color:#
*+{color:#000000}FormServlet.java is as under:+*
*+{color}+{color}{color:#ff0000}+{color:#000000}
{color:#ff0000}import java.io.*;{color}
{color:#ff0000}import java.net.*;{color}
{color:#ff0000}import javax.servlet.*;{color}
{color:#ff0000}import javax.servlet.http.*;{color}
{color:#ff0000}public class FirstServlet extends HttpServlet {{color}
{color:#ff0000}// this method is being called by both doGet() and doPost(){color}
{color:#ff0000}protected void processRequest(HttpServletRequest request, HttpServletResponse response){color}
{color:#ff0000}throws ServletException, IOException {{color}
{color:#ff0000}// getting value of salary text filed of the HTML form{color}
{color:#ff0000}String salary = request.getParameter("salary");{color}
{color:#ff0000}// converting it to the integer.{color}
{color:#ff0000}int sal = Integer.parseInt(salary);{color}
{color:#ff0000}// calculating 15% tax{color}
{color:#ff0000}int tax = (int)(sal * 0.15);{color}
{color:#ff0000}// converting tax into string{color}
{color:#ff0000}String taxValue = tax + "";{color}
{color:#ff0000}// request object can store values in key-value form, later it{color}
{color:#ff0000}// can be retrieved by using getAttribute() method{color}
{color:#ff0000}request.setAttribute("tax", taxValue);{color}
{color:#ff0000}// getting object of servletContext{color}
{color:#ff0000}ServletContext sContext = getServletContext();{color}
{color:#ff0000}// getting object of request dispatcher{color}
{color:#ff0000}RequestDispatcher rd ={color}
{color:#ff0000}sContext.getRequestDispatcher("/secondservlet");{color}
{color:#ff0000}// calling forward method of request dispatcher{color}
{color:#ff0000}rd.forward(request, response);{color}
{color:#ff0000}}{color}
{color:#ff0000}// This method is calling processRequest(){color}
{color:#ff0000}protected void doGet(HttpServletRequest request,{color}
{color:#ff0000}HttpServletResponse response){color}
{color:#ff0000}throws ServletException, IOException {{color}
{color:#ff0000}processRequest(request, response);{color}
{color:#ff0000}}{color}
{color:#ff0000}// This method is calling processRequest(){color}
{color:#ff0000}protected void doPost(HttpServletRequest request,{color}
{color:#ff0000}HttpServletResponse response){color}
{color:#ff0000}throws ServletException, IOException {{color}
{color:#ff0000}processRequest(request, response);{color}
{color:#ff0000}}{color}
{color:#ff0000}}{color}
+*
*+{color:#000000}This servlet is intended to call the Second Servlet:{color}
{color:#ff0000}import java.io.*;{color}
{color:#ff0000}import java.net.*;{color}
{color:#ff0000}import javax.servlet.*;{color}
{color:#ff0000}import javax.servlet.http.*;{color}
{color:#ff0000}public class SecondServlet extends HttpServlet {{color}
{color:#ff0000}// this method is being called by both doGet() and doPost(){color}
{color:#ff0000}protected void processRequest(HttpServletRequest request,{color}
{color:#ff0000}HttpServletResponse response){color}
{color:#ff0000}throws ServletException, IOException {{color}
{color:#ff0000}response.setContentType("text/html");{color}
{color:#ff0000}PrintWriter out = response.getWriter();{color}
{color:#ff0000}// obtaining values of name and salary text fields of index.html{color}
{color:#ff0000}String name = request.getParameter("name");{color}
{color:#ff0000}String salary = request.getParameter("salary");{color}
{color:#ff0000}/* getting attribute value that has been set by the calling{color}
{color:#ff0000}servlet i.e. FirstServlet */{color}
{color:#ff0000}String tax = (String)request.getAttribute("tax");{color}
{color:#ff0000}// generating HTML tags using PrintWriter{color}
{color:#ff0000}out.println("<html>");{color}
{color:#ff0000}out.println("<head>");{color}
{color:#ff0000}out.println("<title>SecondServlet</title>");{color}
{color:#ff0000}out.println("</head>");{color}
{color:#ff0000}out.println("<body>");{color}
{color:#ff0000}out.println("<h1> Welcome " + name+ "</h1>");{color}
{color:#ff0000}out.println("<h3> Salary " + salary+ "</h3>");{color}
{color:#ff0000}out.println("<h3> Tax " + tax+ "</h3>");{color}
{color:#ff0000}out.println("</body>");{color}
{color:#ff0000}out.println("</html>");{color}
{color:#ff0000}out.close();{color}
{color:#ff0000}}{color}
{color:#ff0000}// This method is calling processRequest(){color}
{color:#ff0000}protected void doGet(HttpServletRequest request,{color}
{color:#ff0000}HttpServletResponse response){color}
{color:#ff0000}throws ServletException, IOException {{color}
{color:#ff0000}processRequest(request, response);{color}
{color:#ff0000}}{color}
{color:#ff0000}// This method is calling processRequest(){color}
{color:#ff0000}protected void doPost(HttpServletRequest request,{color}
{color:#ff0000}HttpServletResponse response){color}
{color:#ff0000}throws ServletException, IOException {{color}
{color:#ff0000}processRequest(request, response);{color}
{color:#ff0000}}{color}
{color:#ff0000}}{color}
+*
*+
{color}+{color}*

Syed_Asad wrote:
here is the XML :
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<servlet>
<servlet-name>FirstServlet</servlet-name>
<servlet-class>FirstServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>FirstServlet</servlet-name>
<url-pattern>/FirstServlet</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<servlet>
<servlet-name>FirstServlet</servlet-name>
<servlet-class>FirstServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>FirstServlet</servlet-name>
<url-pattern>/FirstServlet</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>I'm assuming you accidentally posted your xml file twice. That is, the file should end at the first instance of </web-app>.
But what I also notice is that you don't appear to be using packages. You need to indicate the fully qualified class name of the servlet as the value of the <servlet-class> element inside the <servlet> tag. And fully qualified class names include packages. It's important when developing web applications to place your class files in packages. It's important generally, but specifically with web app development.
Edited by: nantucket on Jul 12, 2008 9:16 PM

Deploying a web application on Sun One app server 7

Hi,
I am not able to deploy a web application on sun one server using Sun java studio.
I have created Jsp, Servlet, Session bean and entity bean.
When I am creating a web_module in the directory where JSP are kept, it is giving me error "directory is already mounted.
I have already created EJB modules for both the Session and entity bean.
Can some one tell me the cause / solution of this problem.

Hi Amol,
Thank you very much for replying my question. The contents in my application.xml are:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE application PUBLIC "-//Sun Microsystems, Inc.//DTD J2EE Application 1.3//EN" "http://java.sun.com/dtd/application_1_3.dtd">
<application>
<display-name>testwsapp</display-name>
<description>J2EE Application testwsapp</description>
<module>
<web>
<web-uri>testws_War.war</web-uri>
<context-root>testws</context-root>
</web>
<alt-dd>testws_War.xml</alt-dd>
</module>
</application>
The contents in jaxrpc-ri-runtime.xml are:
<?xml version="1.0" encoding="UTF-8"?>
<endpoints xmlns='http://java.sun.com/xml/ns/jax-rpc/ri/runtime' version='1.0'>
<endpoint
name='testws'
interface='contactws.testwsGenServer.testwsRPC'
implementation='contactws.testwsGenServer.testwsRPCBean'
tie='contactws.testwsGenServer.testwsRPC_Tie'
model='null'
wsdl='/WEB-INF/testws.wsdl'
service='{urn:testws/wsdl}Testws'
port='{urn:testws/wsdl}testwsRPCPort'
urlpattern='/testws'
</endpoint></endpoints>
I tried to access and check the web service using:
http://servername:port/testws/testws
The first testws is contextroot named and the second testws is url pattern, which was exactly like what you mentioned but I got "404 Not Found" error.
By the way, using the same ear to deploy to Windows Sun ONE App. Server 7 env. and then using the same url, I can access the web service. I am wondering if there is any special for deploying Web Service on Unix Sun ONE app. Server 7 env. or I missed something?
I hope I can hear from you soon.
Thank you again,
Jackie

PRG Pattern in web applications

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