Printing Data File name on report...
I need the datafile names to print on a report - we give the user serval files to choose from on the report and it would be nice to have the one selected as a note on the report
we use a formula that alowes the to select say a file named New or Current. Both data files are layed out te same just different data. We have a internal formula.
Formula: tsAskFile
Description Use the tsAskFile formula to limit the file types the operator can choose when
the report runs. This formula applies to the main report. It also applies to all
subreports unless you use the tsSubAskFile formula on the subreports. This
formula does not have file merging capabilities. If you use the following formula
example on a report design, the report will prompt the operator to choose
between the New.glt file and the Current.glt file when the report runs. Without
the formula on the report, the operator could choose whatever file codes are
available.
Syntax u201C[<file type>(<file code name>[,<file code name>]*)]u201D
<file type> = the abbreviation of the data file type; for example: BLI, GLT, APT,
etc.
<file code name> = the file code name of the data file; for example: new, current,
history, active, standard, etc.
Example @tsAskFile = u201CGLT(new,current)u201D or u201CGLT(new, current)JCT(current)u201D
So we want to know which one the choose.
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Arun kumarHi,
Still you are facing any problem with this code expalin the problem with details , otherwise close this thread.
Use Method <b>cl_gui_frontend_services=>directory_list_files</b> to read file names for a given directory
after reading the files then Use FM : <b>RSPO_SX_OUTPUT_TEXTDATA</b> to create spool from internal table data and print the data.
<b>sample code :</b>
data: desktop_dir type string.
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data: xfiles type string.
data: count type i.
data: filepath type string.
call method cl_gui_frontend_services=>get_desktop_directory
changing
desktop_directory = desktop_dir .
call method cl_gui_cfw=>flush.
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exporting
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DATA : x_name LIKE tsp03d-name,
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x_rows LIKE sxpcklsti1-body_num VALUE 0,
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Regards
Appana
*Reward Points for helpful answers
Message was edited by: L Appana -
How to store data file name in one of the columns of staging table
My requirement is to load data from .dat file to oracle staging table. I have done following steps:
1. Created control file and stored in bin directory.
2. Created data file and stored in bin directory.
3. Registered a concurrent program with execution method as SQL*Loader.
4. Added the concurrent program to request group.
I am passing the file name as a parameter to concurrent program. When I am running the program, the data is getting loaded to the staging table correctly.
Now I want to store the filename (which is passed as a parameter) in one of the columns of staging table. I tried different ways found through Google, but none of them worked. I am using the below control file:
OPTIONS (SKIP = 1)
LOAD DATA
INFILE '&1'
APPEND INTO TABLE XXCISCO_SO_INTF_STG_TB
FIELDS TERMINATED BY ","
OPTIONALLY ENCLOSED BY '"'
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COUNTRY_NAME
,COUNTRY_CODE
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,RECORD_STATUS CONSTANT "N"
I want to store file name in the column FILE_NAME stated above. I tried with and without constant using "$1", "&1", ":$1", ":&1", &1, $1..... but none of them worked. Please suggest me the solution for this.
Thanks,
AbhayPl post details of OS, database and EBS versions. There is no easy way to achieve this.
Pl see previous threads on this topic
SQL*Loader to insert data file name during load
Sql Loader with new column
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Please refer notes:
SQL*Loader - How To Load A Date Column With Fractions Of Second (Doc ID 1276259.1)
Script To Generate SQL*Loader Control File (Doc ID 1019523.6)
SQL*Loader performance tips (Doc ID 28631.1)
How To use the Sequence Function of SQL*Loader (Doc ID 1058895.6)
How to Get Data from Existing Table to Flat File Usable by SQL*Loader (Doc ID 123852.1)
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10 Oracle SQLLDR Command Examples (Oracle SQL*Loader Tutorial)
Thanks &
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-- HarveyHello Harvey.
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