Printing Non-Work Intervals (Necking)
Hello,
I have enabled the Activity non-work intervals in the Bar Necking Settings within Bar Settings. Although the 'necks' appear on screen, they do not appear in a PDF printout or a regular print. Is there a setting or workaround for this issue?
Please advise.
Thanks!
AMA,
You've stumbled upon yet another P6 glitch. We use a couple of tricks to attempt to overcome problems like these.
1. Before printing, Move your cursor onto the right hand side of the screen (gantt chart) and scroll down the entire schedule..then select print preview & print.
2. Try increasing the row height on those "necked" activities.
3. Make sure that you have both "bar necking settings" checked within the "format bars" menu
FYI, we use the remaining bar located on row #1 to display our necked activities.....This seems to work for us when publishing in Adobe pdf formats.
Good luck,
Hope this helps
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I ran each version of the cleanup tool, and for each I had it clean up Reader and Acrobat (i.e. 4 separate cleanup operations). I then rebooted the machine, and installed Reader 11.0.3.
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I then uninstalled Reader 11.0.3, rebooted, and re-installed Reader 9: printing works fine now.
There is definitely something in Reader 10 and Reader 11 that breaks printing in some environments. (As you alluded to...I have seen a number of postings online about printing problems in Reader.)
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Greetings all,
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Groups having non-overlapping intervals
Hi there,
I need help on some mind boggling overlap problem, or perhaps non-overlap problem.
Having the sample data below, I need to put together subcodes in groups having non-overlapping
intervals [MIN_VAL;MAX_VAL[
I have this table:
SQL>create table t (product varchar2(1) not null
2 ,subcode number(1) not null, constraint subcode_chk check (subcode >= 0)
3 ,min_val number(2) not null, constraint min_val_chk check (min_val >= 0)
4 ,max_val number(2) not null, constraint max_val_chk check (max_val >= 0)
5 ,constraint t_pk primary key (product, subcode)
6 ,constraint t_val_chk check (min_val < max_val));
Table created.
SQL>
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 0, 0, 99);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 1, 0, 99);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 2, 18, 67);
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SQL>insert into t (product, subcode, min_val, max_val) values ('A', 3, 20, 65);
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SQL>insert into t (product, subcode, min_val, max_val) values ('A', 4, 0, 99);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 5, 45, 60);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 6, 20, 40);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 7, 0, 99);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 8, 60, 65);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 9, 0, 99);
1 row created.
SQL>commit
2 /
Commit complete.
SQL>
SQL> select product, subcode, min_val, max_val
2 from t
3 where product = 'A'
4 order by product, subcode;
PRODUCT SUBCODE MIN_VAL MAX_VAL
A 0 0 99
A 1 0 99
A 2 18 67
A 3 20 65
A 4 0 99
A 5 45 60
A 6 20 40
A 7 0 99
A 8 60 65
A 9 0 99
10 rows selected.
SQL>The records of interest are subcodes 5,6,8 since they in certain cases can be considered as one subcode.
It is OK, that MAX_VAL of one record = MIN_VAL of other record. The main thing is that the subcodes
within a group are mutual disclosing on MIN_VAL, MAX_VAL.
SQL> select product, subcode, min_val, max_val
2 from t
3 where product = 'A'
4 and subcode in (5,6,8)
5 order by min_val;
PRODUCT SUBCODE MIN_VAL MAX_VAL
A 6 20 40
A 5 45 60
A 8 60 65
SQL>I have started out by trying to solve it using lag/lead analytical functions, but without luck.
Next, I've come up with this hierarchial query, but I don't quite understand it myself, and that bothers me!
SQL> select distinct -- This, distinct, bothers me!
2 product
3 ,subcode
4 ,min_val
5 ,max_val
6 -- ,connect_by_isleaf
7 -- ,connect_by_root subcode
8 from t
9 where connect_by_isleaf = 1 -- Why does this help me?
10 start with -- This, start with, seems "clumpsy"
11 min_val in ( select min_val
12 from t
13 group by product, subcode, min_val)
14 connect by nocycle -- This, nocycle, really bothers me!
15 min_val > prior min_val
16 and max_val <= prior max_val
17 and product = prior product
18 and subcode <> prior subcode
19 order by product
20 ,subcode
21 ,min_val
22 ,max_val;
PRODUCT SUBCODE MIN_VAL MAX_VAL
A 5 45 60
A 6 20 40
A 8 60 65
SQL>Currently I'm struggling with just identifying the three subcodes. In the perfect world this would be better output
PRODUCT SUBCODE MIN_VAL MAX_VAL GROUP_FLAG
A 0 0 99
A 1 0 99
A 2 18 67
A 3 20 65
A 4 0 99
A 5 45 60 1
A 6 20 40 1
A 7 0 99
A 8 60 65 1
A 9 0 99Or even better, if using herarchial query:
PRODUCT SUBCODE MIN_VAL MAX_VAL ROOT_SUBCODE
A 0 0 99 0
A 1 0 99 1
A 2 18 67 2
A 3 20 65 3
A 4 0 99 4
A 5 45 60 6
A 6 20 40 6
A 7 0 99 7
A 8 60 65 6
A 9 0 99 9Any help and inspiration would be much appreciated. But please don't get offended if I don't follow up the next 12-14 hrs.
Regards
Peter
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64biEdited by: Peter on May 19, 2009 12:52 PM
- Changed line 15 in hierarchial queryBrillant as always, Frank. Ten points and mange tak for you.
(1) What is your concept of "group" in this problem? In what sense do subcodes 5, 6 and 8 form a group? Is it that they share the quality of not overlapping with some other row with the same product? That is, will there be at most two groups per product: rows that overlap with every other row, and rows that don't?By group I mean, that when isolated from other subcodes, a group does not overlap. For product A, I have 10 different subcodes. In certain situations I'm allowed to consider 5,6 and 8 as one, since they don't overlap. In general the data presented results in 8 groups, 7 groups having 1 subcode, 1 group having 3 subcodes.
(2) What you mean by "mutually disclosing"? Is it that the min_val to max_val ranges do not overlap?Yes. They are however allowed to be equal.
As to your query. Seems you're right, it might actually be that "simple". I changed slightly, allowing >= and <=
SQL> SELECT m.*,
2 CASE
3 WHEN
4 EXISTS (
5 SELECT NULL
6 FROM t
7 WHERE product = m.product
8 AND ( min_val >= m.max_val
9 OR max_val <= m.min_val
10 )
11 )
12 THEN 1 END group_flag
13 FROM t m;
PRODUCT SUBCODE MIN_VAL MAX_VAL GROUP_FLAG
A 0 0 99
A 1 0 99
A 2 18 67
A 3 20 65
A 4 0 99
A 5 45 60 1
A 6 20 40 1
A 7 0 99
A 8 60 65 1
A 9 0 99
10 rows selected.
SQL>
This assumes that min_val <= max_val on each row.Your assumption is perfectly correct, as expessed in check constraint on table t.
>
The rest of this message concerns the CONNECT BY query you posted, in case you want to understand it better.
When I run the CONNECT BY query you posted, I get these results:
P SUBCODE MIN_VAL MAX_VAL
A 0 0 99
A 1 0 99
A 4 0 99
A 5 45 60
A 6 20 40
A 7 0 99
A 8 60 65
A 9 0 99
Ouch, my bad. Somehow I posted the wrong query. I have edited line 15 from
15 min_val >= prior min_valinto
15 min_val > prior min_val
The START WITH clause includes all rows: you might as well not have a START WITH clause:
10 start with -- This, start with, seems "clumpsy"
11 min_val in ( select min_val
12 from t
13 group by product, subcode, min_val)
That's great, somehow I was misled to believe that wew should always have a START WITH.
Thank you for your remainding comments on hierarchial query. I'll definitely have to play around with it to fully understand. With the edit mentioned, and
without a START WITH it now looks as,
SQL> select distinct -- This, distinct, bothers me!
2 product
3 ,subcode
4 ,min_val
5 ,max_val
6 from t
7 where connect_by_isleaf = 1 -- Why does this help me?
8 connect by nocycle -- This, nocycle, really bothers me!
9 min_val > prior min_val
10 and max_val <= prior max_val
11 and product = prior product
12 and subcode <> prior subcode -- Not necessary
13 order by product
14 ,subcode
15 ,min_val
16 ,max_val;
PRODUCT SUBCODE MIN_VAL MAX_VAL
A 5 45 60
A 6 20 40
A 8 60 65
3 rows selected.
SQL>One final question. In your solution with EXISTS, you use < and >. In my rewritten example I use <= and >=. It seems that it still works, even without a condition on subcode != m.subcode in the subquery.
Maybe I'm too tired by now, but why is that? - just don't get it
Regards
Peter -
I would like to buy a HP printer that works with Windows 8 preview.
Understand that HP will not release drivers for existing printers until August at earliest and that is OK....I have 3 HP Laserjet 1020s that have been great and will buy a new HP printer if it will work now with Windows 8 preview. Any suggestions or any fixes/patches for 1020 that work. Also interested in any non-HP printers that work with Windows 8 preview? Prefer HP but will buy first printer that works from any mfg. as I would like to give Windows 8 a real try. Believe HP is missing boat by not putting a patch out for some of their printers as soon as possible as I am not the only HP user looking to buy any printer that works with Windows 8.
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Can PB native calendar objects show non-working days?
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I have a question about the native controls of PB, who functoin as date pickers.
Is there a way to make them show holidays in different color?
I am working on PB11.5 and PB12.5 - non-pfc
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ArcadyHi,
Welcome to SDN...!!!
Please find below a list of tables for factory calendar:
TFACD Factory calendar definition
TFACS Factory calendar (display)
TFACT Factory calendar texts
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TFAIT Calendar: Text for factory calendar intervals
THOC Public Holiday Calendar
THOCD Public holiday definitions
THOL Public Holidays
THOLT Public holiday text
Check last two tables it will help you for non-working days.
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Alok Tiwari -
Hp 1000 j110 deskjet installed worked fine tried to install hp laser jet 1000 none work xp pro
hp 1000 j110 deskjet installed worked fine tried to install hp laser jet 1000 now none work win xp pro
any ideas printer port probs???
Thanks
JohnHello jpihl1
The product you have is a commercial printer. I suggest posting in the forum for HP Business Support for a better chance at finding a solution.
You may find the Commercial Laserjet board here.
http://h30499.www3.hp.com/t5/Printers-LaserJet/bd-p/bsc-413Hello jpihl1
Don't forgot to say thanks by giving "Kudos" to those that help solve your problems.
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Dv9500t system board identifica​tion
I need to replace the system of my HP Pavillion dv9500 t laptop. the service manual provides two possible part numbers viz. one for a board "with 256MB of videp system memory for laptops with discrete video system memory" and a second where the 256MB
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HP Photosmart 7520 prints text too tiny to read
I bought an HP Photosmart 7520 all-in-one Printer a couple months ago. I have tried EVERYTHING I can, using my PC settings to any printer settings, to enlarge the text/font printout... all to no avail!! The printer is set up as a wireless printer t