Problem calling servlet from JSP

Hi All,
I am running Tomcat 4.1.31 + Apache 2.0.54 for a web app. I have a jsp in a folder in my context root that is calling a servlet. My web.xml looks like this
<?xml version="1.0" encoding="ISO-8859-1" ?>
<!DOCTYPE web-app (View Source for full doctype...)>
- <web-app>
<display-name>Web Application</display-name>
- 
- <servlet>
<servlet-name>Controller</servlet-name>
<description>Testing Servlets</description>
<servlet-class>servlets.Controller</servlet-class>
<load-on-startup />
</servlet>
- <servlet-mapping>
<servlet-name>Controller</servlet-name>
<url-pattern>/Controller</url-pattern>
</servlet-mapping>
</web-app>
and my jsp is as below:
<form name="loginForm" id="loginForm" action="/Controller" method="post">
<table border="1" cellpadding="5" width="300">
<tr>
<td>User Id </td>
<td><input type="text" name="userid" size="20" maxlength="15"/></td>
</tr>
<tr>
<td>Password</td>
<td>
<input type="password" name="passwd" size="20" maxlength="10"/>
</td>
</tr>
<tr>
<td colspan="2">
<input type="submit" name="submit" id="submit" value="Submit"/>
</td>
</tr>
</table>
<input type="hidden" name="action" id="action" value="login"/>
</form>
However, this doesnt work at all. Whenever I hit the submit button I get a 404 File not Found error.
I have to give the entire url starting with the context root in the JSP for the servlet to work. Is that how it is supposed to work?? I was under the impression that once everything is defined correctly, Tomcat will figure out that the JSP and the servlet belong to the same app and get it from there.
Can anyone help me please???
Let me know if anything is not clear enough.
Thank you!
amrutaa

Actually this is just an example app ... but I am going to have other jsps that will call the controller servlet ..
Thanks a lot for your help. I really appreciate it.
What stumps me is that the call to the servlet was working day before yesterday and yesterday it just wouldnt!
and I am sure I touched only the servlet in the meanwhile + restarted Apache as well as Tomcat.
Thanks again!
-Amruta

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