Problem In Oracle9i Enterprise Edition

hello mike curtis
i have some problem with oracle , i hope you want to help me solve my problem,
i use oracle9i on Microsoft Windows 2000 Advance Server,
on dell power edge server with dual pentium III 1.2 GB,1 GB RAM,Raid Disk
everything configure correctly,
the problem is when i configure parallel_min_server
and parallel_max_server in init.ora file(s)
why the plan table did not get an affect , i mean's there no difference
between i use parallel query and not, but as you know the response time
is difference between parallel and no parallel,
and i run show parameter in sql*plus
parallel_max_server has been set to 8
parallel_min_server has been set to 4
but when i try this
explain plan for select count(*) from mytable;
commit;
select other_tag from plan_table
the empty row is affected,please help me , why it's happened ? may be you can help
me and show me where my fault is ?,
thank's for your time to read my email, i hope you want to answer my problem to
my email([email protected] or [email protected])
and with that step everything is ok on oracle8i(8.1.7)
yahya yanuar

We recommend that you post your question in the appropriate Database Forum. The OTN Suggestions/Feedback forum answers questions about the OTN site and other general site issues.
Best Regards, OTN Team

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Message was edited by:
user448268

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Data in bold are numbers with last character that is calculated like the example below.
First number format is S9(2)V999999 -> 0100000é le signe est sur l'avant dernier octet C(+) D(-)
Example 1, en hexa :
0100000é => +01,000000
FFFFFFFC S99V999999
01000000
Second number format is S9(13)V99 -> 00000000071049é
Example 2, en hexa
00000000071049é
FFFFFFFFFFFFFFC
000000000710490 => +0000000007104,90
S9999999999999V99
other example:
example 00ACESIEUR10100000é00000000087498I
en hexa:
00000000087498I
FFFFFFFFFFFFFFC
000000000874989 => +0000000008749,89
S9999999999999V99
I need help with creating a function that will transform from "00000000087498I" to real number like "+0000000008749,89", but I really don't know how to do that.
Can anyone help me with my problem or explain to me how to do that?
Thanks for your time and best regards

No it is not so simple. This "le signe est sur l'avant dernier octet" means that the sign is last character in number.
The sign "é" and "I" are just in my example and they are somehow calculated but I don't know how?
If I take my example there is field with format S9(13)V99 and with value 00000000071049é (and with last sign "é") and I think the last sign is somehow calculated from number. And then from this value I get the number.
00000000071049é
FFFFFFFFFFFFFFC
000000000710490 => +0000000007104,90
S9999999999999V99
Everything I try, calculating from binary to hex, or anything other, I don't get the result or the last sign and I wonder if there is some function in PL/SQL that I can use to get the result I want?
Or if you have some idea how to help me to get from "00000000071049é" to "+0000000007104,90" from example above?
Here are some other examples, just for help:
000000204592D
000000183882D
000000139441C
000000182979H
000000083361F
000000083361F
000000083361F
000000059033F
000000066273E
000000069011G
000000102615B
000000092362F
000000138215‚
000000138215‚
000000138215‚
000000138215‚
000000106760C
000000106760C
000000106760C
000000115024A
000000115024A
000000115024A
000000115024A
000000115024A
000000088149B
000000084459I

Problem In Oracle9i Enterprise Edition

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