Problem in the output of J1INQEFILE

Dear All,
I am facing a problem to capture the WHT amount in J1INQEFILE.
I m working on 4.7.
we have seperate tax types & seperate tax codes for every section code. WHT cycle is working fine till J1INQEFILE, which is a eTDS returs. System is giving me the total amount of TDS deducted for every vendor, which is shown as per the every document. If i drill down from the report i can see the document entry.
But the standard SAP report have columns for TDS, surcharge & Ecess.
When I execute the J1NQEFILE, The TDS column is capturing the values of
TDS Base amount + S. Ecess
and the Surcharge of 10% and the ECess of 2% is calculating Perfectly.
I have also applied note no: 1097621, yet the problem is persisting.
The OUTPUT I want to have is the
TDS Column to show just the TDS base amount only
and the
E Cess column to show the E. Cess + S. Ecess
and
Surcharge remaining unchanged
What changes do I need to do further to pull the desired output
Thanks & Advance,
ABAPer

refer to sap note: 984623, from the above note pick notes relvevant for version 4.7
Ur problem will be resolved.

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Hi Sushil,
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hi LM,
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Extracting Images from EPS - Problem with the Output

Hello,
I got a big problem extracting images from an EPS, which has been made in InDesign. The image does not appear correct.
Source code:
%ALDImageFileName: Speicher:image.jpg
%ALDImageDimensions: 30 30
%ALDImageCropRect: 0 0 30 30
%ALDImageCropFixed: 0 0 30 30
%ALDImagePosition: 203.8677 344.8913 203.8677 359.2913 218.2677 359.2913 218.2677 344.8913
%ALDImageType: 4 8
%%BeginObject: image
[14.4 0 0 14.4 203.868 344.891 ]ct
snap_to_device
Adobe_AGM_Image/AGMIMG_fl cf /ASCII85Decode fl /RunLengthDecode filter ddf
<<
/T 1
/W 30
/H 30
/M[30 0 0 -30 0 30 ]
/BC 8
/D[0 1 0 1 0 1 0 1 ]
/DS [
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
/O 3
>>
%%BeginBinary: 1
img
p&G-p!<E*"!<<3"!!!&i!!30$!Vl`q!V$-m!WW3&!r`0#!Wh]h!!20]!WW3$qZ$^!!!!&f!!30$!WE'!
!WE'$!<<*#nc/[l!W<!#!WW3%h>dNVnGiXl!<<-)!!*'"!<<2f!<*$!!<3)a!!!&t!!*-%kl:\ar;Zm"
!!2He#6G2G(D[>Z!<*#e!!WKUEK,/l!r`0"!V$.!!Wi?'-t[mD-NjDN!!2Zk!!3#u"T\]4$OR%8!!!&h
!!<6)*\I@D!\,8pq>g3h%KQP0';ta-rr2ho&-2b3mf3Y*Q/q,jk2D[9"76'h!=o#B!Y,22n,Nn!!!=Q!
0.ee,0/"XS!VHHl!!E<'!"[l]rrUsd!Ug!r&'a/!k3(mej38#8mJm8&'`/UF'`J.(!"8l.+"o,p/hSe-
/M8.8!!<6%!i#Yn!<2rs!2Ao^$NZFPk2tpjkND!jP3r;O%29TU'`o-b%e'H-!=:8,0/"h-.kN>(.gkeH
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!!2Ng$3K)as8N&tjT#8]m/R@3k2b[ck03)j!>?4H'`\p6!!**(r[e6p.kWIZmJm:h!#kk:#.sp7ru_:B
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jlEuS!!2Ng#S7^d%KHtR'bTm7!s/H(/-mj['`\n!/1Ukk!"985s8@'?Du]k7%KHP#!"8l0$KC71C'%l,
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!3>;FU]CPd!!<]G'bL?E!tZ.^&+9K$!\#`P)?'U>'eM$g!!2Zk!W`9$$g.KhLB.ATL&_2?"7Q9n!RU)n
I/X*KGN@l9"Rc<t',;8j!!!$,'bhAP!!WQ+!"US5%fQG1%PKFQn,NUm!*fL'9)\en8,rO]!V-4"!rrBu
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D;u0+!!<qtS-&0["T\T'$5EXA!!33:%da5t!<<]/!!3u<!V$-o!<<*#!FZ$-!!A;d!!2ipq#CKu!<?7$
!!WK)KEM8T"RZ6i$2so,!<<Q0li77k!!30$!<</h!!!'!!!E<'!!!&c!"8o/!!*'#"98E'!WW;h!!!'!
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rVup!q#Gp~>
%%EndBinary
%%EndObject
Orginal image Size 553,9 KB
After decoding the size is only 1,8 KB
First try.
public class ASCII85Decode {
private ByteBuffer buf;
* initialize the decoder with byte buffer in ASCII85 format
private ASCII85Decode(ByteBuffer buf) {
this.buf = buf;
* get the next character from the input.
* @return the next character, or -1 if at end of stream
private int nextChar() {
// skip whitespace
// returns next character, or -1 if end of stream
while (buf.remaining() > 0) {
char c = (char) buf.get();
if (!isWhiteSpace(c)) {
return c;
// EOF reached
return -1;
public static boolean isWhiteSpace(int c) {
return (c == ' ' || c == '\t' || c == '\r' || c == '\n'
|| c == 0 || c == 12);
// 0=nul, 12=ff
* decode the next five ASCII85 characters into up to four decoded
* bytes. Return false when finished, or true otherwise.
* @param baos the ByteArrayOutputStream to write output to, set to the
* correct position
* @return false when finished, or true otherwise.
private boolean decode5(ByteArrayOutputStream baos)
throws PDFParseException {
// stream ends in ~>
int[] five = new int[5];
int i;
for (i = 0; i < 5; i++) {
five[i] = nextChar();
if (five[i] == '~') {
if (nextChar() == '>') {
break;
} else {
throw new PDFParseException(
"Bad character in ASCII85Decode: not ~>");
} else if (five[i] >= '!' && five[i] <= 'u') {
five[i] -= '!';
} else if (five[i] == 'z') {
if (i == 0) {
five[i] = 0;
i = 4;
} else {
throw new PDFParseException(
"Inappropriate 'z' in ASCII85Decode");
} else {
throw new PDFParseException(
"Bad character in ASCII85Decode: " + five[i]
+ " (" + (char) five[i] + ")");
if (i > 0) {
i -= 1;
int value = five[0] * 85 * 85 * 85 * 85 + five[1] * 85 * 85
* 85 + five[2] * 85 * 85 + five[3] * 85 + five[4];
for (int j = 0; j < i; j++) {
int shift = 8 * (3 - j);
baos.write((byte) ((value >> shift) & 0xff));
return (i == 4);
* decode the bytes
* @return the decoded bytes
private ByteBuffer decode() throws PDFParseException {
// start from the beginning of the data
buf.rewind();
// allocate the output buffer
ByteArrayOutputStream baos = new ByteArrayOutputStream();
// decode the bytes
while (decode5(baos)) {
return ByteBuffer.wrap(baos.toByteArray());
* decode an array of bytes in ASCII85 format.
* 
* In ASCII85 format, every 5 characters represents 4 decoded
* bytes in base 85. The entire stream can contain whitespace,
* and ends in the characters '~>'.
* @param buf the encoded ASCII85 characters in a byte buffer
* @param params parameters to the decoder (ignored)
* @return the decoded bytes
public static ByteBuffer decode(ByteBuffer buf)
throws PDFParseException {
ASCII85Decode me = new ASCII85Decode(buf);
return me.decode();
2. Try
public class Ascii85Decode {
private final FileOutputStream fos;
private Ascii85Decode() throws FileNotFoundException {
File f = new File("/home/markus/1/test/bild.jpg");
fos = new FileOutputStream(f);
@Override
protected void finalize() throws Throwable {
fos.close();
super.finalize();
public static byte[] decode(byte[] in) throws FileNotFoundException, IOException {
Ascii85Decode ascii85Decode = new Ascii85Decode();
ascii85Decode.setData(in);
ascii85Decode.decode85();
return null;
static long pow85[] = {85 * 85 * 85 * 85, 85 * 85 * 85, 85 * 85, 85, 1};
private byte[] in;
private void setData(byte[] in) {
this.in = in;
void wput(long tuple, int bytes) throws IOException {
switch (bytes) {
case 4:
putchar((int) (tuple >> 24));
putchar((int) (tuple >> 16));
putchar((int) (tuple >> 8));
putchar((int) tuple);
break;
case 3:
putchar((int) (tuple >> 24));
putchar((int) (tuple >> 16));
putchar((int) (tuple >> 8));
break;
case 2:
putchar((int) (tuple >> 24));
putchar((int) (tuple >> 16));
break;
case 1:
putchar((int) (tuple >> 24));
break;
void decode85() throws IOException {
long tuple = 0;
int c, count = 0;
int i=0;
for (;;) {
switch (c = in[i]) {
default:
if (c < '!' || c > 'u') {
System.err.println("%s: bad character in ascii85 region: %#o\n");
System.exit(1);
tuple += (c - '!') * pow85[count++];
if (count == 5) {
wput(tuple, 4);
count = 0;
tuple = 0;
break;
case 'z':
if (count != 0) {
System.err.println("%s: z inside ascii85 5-tuple\n");
System.exit(1);
putchar(0);
putchar(0);
putchar(0);
putchar(0);
break;
case '~':
if (in[i+1] == '>') {
if (count > 0) {
count--;
tuple += pow85[count];
wput(tuple, count);
c = in[i+1];
return;
System.err.println("%s: ~ without > in ascii85 section\n");
System.exit(1);
case '\n':
case '\r':
case '\t':
case ' ':
case '\0':
case '\f':
case '\b':
case 0177:
break;
i++;
private void putchar(int l) throws IOException {
//System.out.write(l);
fos.write(l);
Does anybody have an idea to solve the problem?

A scan from string function can be used as per the attachment. The double \ ('\\') is in the format string in order to interpret the '\' characters in your input string as literal characters and not special formatting.
Message Edited by Dennis Knutson on 07-10-2006 03:53 PM
Attachments:
Scan From String.JPG ‏5 KB

Problem with the output ports of the data service !!!!! attention

Hi,
I have created a functional module x using abap programming.
The functional module x with one input and one output table.It successfully executed in abap.
Later i activated and used it in visual composer 7.1 .It worked perfectly fine.
The input port displayed was :Hollow Diamond shape
The output port displayed was: Filled Square shape.
Then i thought of changing the abap program by adding one more input and one more output table.
So i have two inputs and tow output tables.
The abap program exceuted correctly.
But when i used it in visual composer 7.1 . It didn't work.
As
The input port displayed was :Hollow Diamond shape ( correct )
The output port displayed was: Filled circle shape.( Not a correct display ).
So i couldn't drag the table output from the circled port.
But When i test the data service then it gives perfect results.
Later i created a new functional module Y with same two inputs and same two output tables. It worked fine.
Please help me . When ever i add new tables to already activated data service i face the same problem.
Kindly advice.
Regards
Tekumalla

Hi,
Following is an image of a slide describing the port types in Visual Composer:
http://img116.imageshack.us/img116/2465/portshapesrt7.png
Which port is appearing on your service?
Would it be possible for you to send a screen shot of your service in VC?
Thanks,
Shai

Problem with the output volume

I installed StartupSound.prefPane
http://www5e.biglobe.ne.jp/~arcana/StartupSound/BETA/index.en.html
on my macbook in order to control the startup chime's volume. Next I uninstalled it, because didn't like. Now, the output volume is not working; I cannot modify the level of volume on the Sound preferences (System Preferences). Any idea to solve this problem? Thanks in advance. PS: to uninstall this software, I did double click on the unistaller that software provides.
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Message was edited by: HREsquivelO

Hello,
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Problem in the output Excel sheet.

I have a requirement of adding two bands to the existing report.The output sheet is Excel which is off 4 sheets formatted with colors and headings as ouput which is done by calling the XML Classes.
I am not able to find my two fields which are added in the output excel.
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check the structures, if you made changes is the correct structure or not...
make sure data is beeing pulled into you tables before passing to excel FM..

Problem printing the output

i'm writing a getClassMean() which is going to compute the Mean score of the whole class. in the following myLines is a ArrayList object that stores each String from my input file, which look something like:
Stevens, Frank, Z.; 87, 86, 92, 78, 86
Franklin, Susan, A.; 98, 88, 94, 98, 95
Bowers, Brett, B.; 85, 78, 83, 84, 89
This is the method in the Mean class:
protected ArrayList<Double> classGrades = new ArrayList<Double>();
public double getClassMean(){
 String gb;
 String[] array, grades;
 double mean;
 double score;
 for(String l : myLines) {
 array = l.split("; ");
 gb = array[1]; //gb --grade block
 grades = gb.split(", ");
 for(String scoreStr : grades ) {
 score = Double.parseDouble(scoreStr);
 classGrades.add(score);
 double sum = 0.0;
 for(double d : classGrades) {sum += d;}
 mean = sum / classGrades.size();
 return mean;
 }and the Driver program has this:
Mean m = new Mean();
double classMean = mean.getClassMean();
System.out.println(classMean);but the output print something i don't understand:
NaN
can someone tell me what's going on? thanks!

NaN is "Not a Number" it comes from doing operations with undefined results, like 0.0 / 0.0 .
Print out sum and classGrades.size() before doing that division, then trace backwards (add more print statements if you need to) to find your bug.

Problems with the output of an array

Hallo,
I have got problems with giving out an array.
I declared two arrays and puted them out, but with the
resultarray it doesn�t work. Cansomebody help me?
Here is a runtime output:
Grad eingeben!
1
Koeffizienten eingeben!
1
2
1x^0 + 2x^1 +
1
Grad eingeben!
3
Koeffizienten eingeben!
2
3
4
5
2x^0 + 3x^1 + 4x^2 + 5x^3 +
3
p:1
this:3
And here is the source code
// Die Klasse Polynom dient dem Umgang mit dem Polynom
//Sie enth�llt die Methoden:
// > public void readCoeffizients()
// > public void show()
// > public int getGrad()
// > public Polynom add(Polynom p)
//Und den Konstruktor:
// > public Polynom(int n)
public class Polynom
private int grad;
int [] coeffizient;
private Polynom q1;
public Polynom(int n) //Konstruktor mit Stanard-Initialisierung
 this.grad = -1;
 this.coeffizient = new int [n+1];
 for(int i=1; i<(n+1); i++)
 this.coeffizient[i] = 0;
public void readCoeffizients() // Methode zum Einlesen der Koeffizienten
 this.grad = (coeffizient.length)-1;
 System.out.println("Koeffizienten eingeben!");
 for(int i=0; i<(grad+1);i++)
 this.coeffizient[i] = Eingabe.intValue();
public void show() // Methode zum Ausgeben des Polynoms
 for (int i=0; i<(this.getGrad()+1);i++)
 System.out.print(coeffizient[i] + "x^" + i + " + ");
 System.out.println();
public int getGrad()
 return this.grad;
public Polynom add(Polynom p) // Methode zum Addieren zweier Polynome
 System.out.println("\np:" + p.getGrad());
 System.out.println("this:" + this.getGrad());
 if(p.getGrad() >= this.getGrad()) // Vorgehen falls p.getGrad() gr��er als this.getGrad()
 q1 = new Polynom(p.getGrad());
 grad = p.getGrad();
 for(int i=0; i<(this.getGrad()+1);i++)
 q1.coeffizient[i] = this.coeffizient[i] + p.coeffizient;
for(int i=(this.getGrad()+1);i<(p.getGrad()+1);i++)
q1.coeffizient[i] = p.coeffizient[i];
else // Vorgehen falls this.getGrad() gr��er als p.getGrad()
q1 = new Polynom(this.getGrad());
grad = this.getGrad();
for(int i=0; i<(p.getGrad()+1);i++)
q1.coeffizient[i] = this.coeffizient[i] + p.coeffizient[i];
for(int i=(p.getGrad()+1);i<(this.getGrad()+1);i++)
q1.coeffizient[i] = this.coeffizient[i];
return q1; // R�ckgabe des Ergebnisspolynoms
// Diese Klasse testet die Klasse Polynom
public class Test
public static void main(String[] args)
System.out.println("Grad eingeben!");
Polynom p1 = new Polynom(Eingabe.intValue());
p1.readCoeffizients();
p1.show();
System.out.println(p1.getGrad());
System.out.println("Grad eingeben!");
Polynom p2 = new Polynom(Eingabe.intValue());
p2.readCoeffizients();
p2.show();
System.out.println(p2.getGrad());
//Polynom p3 = (p2.add(p1));
//p3.show();
(p2.add(p1)).show();
Thanks for your help!

Ehm, this should really be obvious: because in the
first two cases you are using the constructor
and readCoeffizients(), whereas in the third
case you are only using the constructor.You?re right, but I initiate grad in the add method.Then look again: you don't! You are calling the constructor, but the constructor is not assigning grad in a proper way. If you are refering to the line grad = p.getGrad();this is in fact equal to this.grad = p.getGrad();But this.grad is not q1.grad (which is private). Assign grad in the constructor only (where it belongs) or better still don't use grad at all and derive the degree of the polynom from the length of the coefficients array.

Prefix problem in the Output XML

Hi,
I am working on iIdoc to file scenario.
For the Target file structure I have created XSD as it contains a prefix wmb in every field. But when I test , I cud see the prefix as ns0 in MONI. How do I replace the Prefix ns0 with WMB
I think the probable solutions could be using XSLT Mapping or use XMLAnonymizerBean Module
Any Inputs would be appreciated.
Regards,
Varun

Hi Varun,
> For the Target file structure I have created XSD as it contains a prefix wmb in every field. But when I test , I cud see the prefix as ns0 in MONI. How do I replace the Prefix ns0 with WMB
No need to create external XSD, follow the standard process. XMLAnonymizerBean provides an easy solution.
Use the following settings at Receiver communication channel
Module tab
Module Name : AF_Modules/XMLAnonymizerBean
Type :Local Enterprise Bean
Module Key
Module Configuration
1. Module Key : 0
Parameter Name : anonymizer.acceptNamespaces
Parameter Key : <interface> WMB
2. Module Key : 0
Parameter Name : anonymizer.quote
Parameter Key : '
Regards,
Sunil Chandra

Problem in the output when the table name is explicitly assigned.

hi
Am using a procedure to copy the information's in a table to a flat file. my aim is to achieve this copy function by assigning the table name from user explicitly.
this is the program:
create or replace procedure jk(table_name in varchar2) is
sel_table varchar2(30);
l_bool BOOLEAN;
irows INTEGER := 1;
buffer LONG;
f utl_file.file_type;
BEGIN
sel_table:='select * from '||table_name;
f := utl_file.fopen('SAMPLE','tablename.txt','W');
OWA.cgi_var_name (1) := 1;
OWA.cgi_var_val (1) := 1;
OWA.init_cgi_env (1, OWA.cgi_var_name, OWA.cgi_var_val);
HTP.adddefaulthtmlhdr (FALSE);
l_bool :=
OWA_UTIL.tableprint (ctable => sel_table,
cattributes => '',
ntable_type => OWA_UTIL.pre_table,
ccolumns => '*',
cclauses => '',
ccol_aliases => '',
nrow_min => 0,
nrow_max => 500
WHILE (irows != 0)
LOOP
buffer := HTP.get_line (irows);
utl_file.put_line(f,buffer);
/* do whatever you like with the contents of the buffer */
/* You may write to a file or simply print it out */
DBMS_OUTPUT.put_line (buffer);
END LOOP;
END;
the error during execution:
SQL> @for.sql
Procedure created.
SQL> exec jk('CUST');
BEGIN jk('CUST'); END;
ERROR at line 1:
ORA-00931: missing identifier
ORA-06512: at "SYS.DBMS_UTILITY", line 125
ORA-06512: at line 2
ORA-06512: at "SYS.DBMS_SYS_SQL", line 1120
ORA-06512: at "SYS.DBMS_SQL", line 323
ORA-06512: at "SYS.OWA_UTIL", line 595
ORA-06512: at "SYS.OWA_UTIL", line 689
ORA-06512: at "SYS.OWA_UTIL", line 1222
ORA-06512: at "XMLUSER.JK", line 14
ORA-06512: at line 1
thanks in advance
karthik.J

You better don't supply the whole select statement to OWA_UTIL.tableprint but only the table name!

How to filter the output of a query according to the language

Hi guys,
I have the following tables joined togheter: VBAK ,VBKD ,TVZBT.
The problem is, the output gives any record as many times as many languages exist in table TVZBT
I tried with the following instruction but it doesn't work,no matter in which event I put it:
check tvzbt-spras eq sy-langu.
Thanks,Christian

Hello Christian Baldari,
You have to add that check in where clause like :
select ....
from ...
where
tvzbt~spras eq sy-langu.
why because in ur select query you are using innerjoin operation. so you are using TILD (~) operator for alias. you have to check the spras using the alias as mentioned above.
Reward If Hepful.
Regards
Sasidhar Reddy Matli.

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I use the SAME pdf output setting. The output pdf file from "export (pdf)" it is abvious better than the one from " print as booklet"
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