Problem sorting a List

Didn't realize there was a separate Generics forum.
http://forum.java.sun.com/thread.jspa?threadID=769681&tstart=0

Hi,
What version are you using?
I am facing the same problem in 7.1.1.5.
Regards,
Tine

Similar Messages

Problem sorting list with virtual layout = false (and also with true)

Hi,
I've a problem sorting a list... or better... I've a problem showing the sorted list ;-)
I've a list of xml item. The list is shown with an item renderer.
my needs: a button to refresh data and a button to sort data.
useVirtualLayout = false
-> refresh works correctly, sort does not affect the view (even if the list is sorted correctly when printed with trace)
useVirtualLayout = true
-> sort works correctly, refresh reverse the list each time I press it (even if the list remain the same when printed with trace)
does any one have an idea?
thank you!!
MXML
<s:List dataProvider="{xmlListCollection}" width="100%" itemRenderer="myRenderer" minHeight="0" id="test" useVirtualLayout="false" >
<s:layout>
<s:VerticalLayout clipAndEnableScrolling="true"/>
</s:layout>
</s:List>
XML example
<unit sortField1="First Floor" sortField2="7">
<employee>
    <id>3040684</id>
    <name>PIFFARETTI Vasco</name>
    <birthdate>20.05.1983</birthdate>
    <beginDate>2012-02-25 08:55:00</beginDate>
    <endDate>9999-12-31 00:00:00</endDate>
    <annotation/>
</employee>
</unit>

You can tell when the scroll position has changed by handling the propertyChange event coming from the DataGroup:
<s:Application xmlns:fx="http://ns.adobe.com/mxml/2009"
               xmlns:s="library://ns.adobe.com/flex/spark"
               creationComplete="list1.dataGroup.addEventListener('propertyChange', handle)">
    <fx:Script>
        <![CDATA[
            import mx.events.PropertyChangeEvent;
            private function handle(e:PropertyChangeEvent):void {
                if (e.property == 'verticalScrollPosition'){
                    trace('vsp changed');
                if (e.property == 'horizontalScrollPosition'){
                    trace('hsp changed');
        ]]>
    </fx:Script>
    <s:List id="list1" width="100" height="50">
        <s:layout>
            <s:VerticalLayout />
        </s:layout>
        <s:dataProvider>
            <s:ArrayList>
                <fx:String>0</fx:String>
                <fx:String>1</fx:String>
                <fx:String>2</fx:String>
                <fx:String>3</fx:String>
                <fx:String>4</fx:String>
                <fx:String>5</fx:String>
                <fx:String>6</fx:String>
                <fx:String>7</fx:String>
            </s:ArrayList>
        </s:dataProvider>
    </s:List>
</s:Application>
You might also want to read and consider voting for http://bugs.adobe.com/jira/browse/SDK-21357

Open a SharePoint List item in Modal Pop up in SP 2013 fails after you filter or sort the list

Sorry for the long post. This has been killing me. I had this script working perfectly fine in SharePoint 2010 (online) and basically i have a source custom list (list A) with a hyperlink column and a Destination List with say title and my name.
Source List (list A) looks like this with these 2 columns
Title Test Link
A Link 1
B Link 2
C Link 3
Each of these links link to the actual list item in the destination list, so for example, link 1 is/sites/2013DevSite/Lists/Destination%20List/EditForm.aspx?ID=1
So basically i want anytime the Link are clicked that point to another list's item to open in a modal dialog and the script below worked perfectly fine in SharePoint 2010 (online)
<script language="javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js" type="text/javascript"></script>
<script language ="javascript" type="text/javascript">
jQuery(document).ready(function() {
jQuery('a[href*="EditForm.aspx"]').each(function (i, e) {
// Store the A tag's current href in a variable
var currentHref = jQuery(e).attr('href');
jQuery(e).attr({
'href': 'javascript:void(0);',
// Use the stored href as argument for the ShowInModal functions parameter.
'onclick': 'ShowInModal("' + currentHref + '");'
function ShowInModal(href) {
SP.UI.ModalDialog.showModalDialog({title: "Edit Item", url: href});
</script>
All it does is find the href tags for that particular value Editform.aspx and the pop modal works in SP 2010 online. So the site page is designed in such a way there is a content editor web part with the reference to this javascript file and the sharepoint
list is right beneath it and this worked perfectly opening in modal windows in SP 2010.
Since migration to 2013, this is what exactly happens
1.) when you come to the site page, the modal works,
2.) If you filter or sort on say the Title or Test Link column in Source list (lets say you select the Value A), the script does not fire at all, if i hover over the hyperlink, the who hyperlink is shown and does not open the hyperlink in the modal pop up.
- This is important because i want to be able to sort on a particular item...
Could someone please let me know what am i doing wrong and why is this not working when i sort the list. Thanks for all the help.
Once again i am trying to open a sharepoint list item in Sharepoint 2013 from another list using Jquery

A ListItem has its own unique row id so in all likelihood, an insert with the same data will result in a new list entry. The Lists Web Service however, has an UpdateListItem method which will take an update request. [refer
http://msdn.microsoft.com/en-us/library/office/websvclists.lists.updatelistitems(v=office.15).aspx ]
There is another note in the conference (marked answered) to your List Item Update problem. Probably worth a try too. [refer
http://social.msdn.microsoft.com/Forums/en-US/bee8f6c6-3259-4764-bafa-6689f5fd6ec9/how-to-update-an-existing-item-in-a-sharepoint-list-using-the-wss-adapter-for-biztalk?forum=biztalkgeneral ]
Regards.

Help with using mergesort to sort a list of names alphabetically?

Hi, I'm trying to sort a list of names alphabetically, case-insensitive by using the mergesort technique.
I wrote this code and when I trace it through on paper with an example array of names, it should work, but when I run it with an actual txt file, it's not correctly alphabetical.
I'd appreciate it if someone could take a look at my code and give me some ideas on what my problem might be.
Thanks in advance! (note: I also posted this question to java-forums.org, as I've been working on this little problem for over five hours and am in desperate need of some help!)
public static void mergeSort(String[] names)
        if (names.length >= 2)
            String[] left = new String[names.length/2];
            String[] right = new String[names.length-names.length/2];
            for (int i = 0; i < left.length; i++)
                left[i] = names;
for (int i = 0; i < right.length; i++)
right[i] = names[i + names.length/2];
mergeSort(left);
mergeSort(right);
merge(names, left, right);
// pre : result is empty; list1 is sorted; list2 is sorted
// post: result contains result of merging sorted lists;
// add merge method below
public static void merge(String[] names, String[] left, String[] right)
int i1 = 0;
int i2 = 0;
for (int i = 0; i < names.length; i++)
if (i2 >= right.length || (i1 < left.length && left[i1].compareToIgnoreCase(right[i1])<0))
names[i] = left[i1];
i1++;
} else
names[i] = right[i2];
i2++;

Welcome to the forum.
Please read this to learn hot to format your code (and other things relevant for this forum):
https://forums.oracle.com/forums/ann.jspa?annID=1535
923566 wrote:
Hi, I'm trying to sort a list of names alphabetically, case-insensitive by using the mergesort technique.
I wrote this codeDo you know the <tt>TreeSet</tt> class?
http://docs.oracle.com/javase/7/docs/api/java/util/TreeSet.html
With that sorting Strings is a two liner:
http://www.java2s.com/Code/Java/Collections-Data-Structure/TreeSetDemo.htm
bye
TPD

Project 2013 - How do you sort the list of Enterprise Templates in Project Pro?

In Project Pro 2013, click File > New > Enterprise I see the list of templates from our project server. We have a global installation with 40-50 templates. These are displayed in a random order and reading through the whole list to find the one I
want is quite tedious. Is there a way to sort this list alphabetically? Can the list be displayed as a "details" view rather than icons?

Greg --
Guillaume is totally correct. The display order of enterprise templates is by the date they were created. I have tested this on a Project Server 2013 system that has the latest Cumulative Updates applied. The problem is that in the
Microsoft Project 2013 desktop application, Microsoft has ditched the Templates dialog we used to see and replaced it with a page in the Backstage. I am afraid that in doing so, they have eliminated the sorting capabilities that we found in earlier versions.
Out of curiosity, I have sent an e-mail to my MPV contacts within the Microsoft Project Server development team at Microsoft, asking if there is any intention of changing this functionality to allow for sorting by template name. If I get an answer,
I will post it in this user forum.
Your question is a good one, and the sorting problem (or lack of sorting) can be a real problem in any organization that has a sizable number of enterprise templates. Hope this additional bit helps.
Dale A. Howard [MVP]

Problem sorting data in a file?

I have a problem sorting this file alphabetically by second name. Basically, my method sorts each column alphabetically but i would like to sort the file according to the second name. I really really need help. Thanks
File:
Moe     Carl
Saul     Sergio
Rocky     Louis
Ike     Ziken
This is how my method sorts the file:
Ike          Carl
Moe          Louis
Rocky          Sergio
Saul          ziken
Instead
Moe     Carl
Rocky      Louis
Saul     Sergio
Ike     Ziken
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.io.*;
import java.util.*;
class thedata implements Comparable
          private String firstname;
          private String secondname;
    public void setFirstname(String firstname)
             this.firstname = firstname;
    public String getFirstname()
              return firstname;
    public void setSecondname(String secondname)
            this.secondname = secondname;
    public String getSecondname()
            return secondname;
    public int compareTo(Object Student) throws ClassCastException
            if (!(Student instanceof ShowData))
            throw new ClassCastException("Error");
            String sn = ((ShowData) Student).getSecondname();
            return this.secondname.compareTo(sn);
public class sort {
        public static void main(String[] args) {
        sortmethod();
        public static void sortmethod(){
          int j = 0;
          thedata data[] = new thedata[4];
         try
                  FileInputStream fstream = new FileInputStream("datafile.txt");
                  DataInputStream in = new DataInputStream(fstream);
                  BufferedReader br = new BufferedReader(new InputStreamReader(in));
                  String line;
                  String[] firstname = new String[4];
                  String[] secondname = new String[4];
                  ArrayList<String> list = new ArrayList<String>();
                  while ((line = br.readLine()) != null)
                          list.add(line);
                  Iterator<String> itr = list.iterator();
                  int k = 0;
                  for (itr = list.iterator(); itr.hasNext();)
                          String str = itr.next().toString();
                          String[] splitSt = str.split("\t");
                 for (int i = 0; i < splitSt.length; i++)
                             firstname[k] = splitSt[0];
                             secondname[k] = splitSt[1];
                  k++;
                  arraysort(firstname);
                  arraysort(secondname);
                     for(j = 0;j < 4;j++)
                             data[j] = new thedata();
                             data[j].setFirstname(firstname[j]);
                             data[j].setSecondname(secondname[j]);
                  for (int i = 0; i < 4; i++)
                             thedata show = data;
                         String firstname1 = show.getFirstname();
                         String secondname1 = show.getSecondname();
                              System.out.println(firstname1 + "\t\t" + secondname1);
                    catch (Exception e)
     private static void arraysort(String[] array)
          for(int i=0; i<array.length; i++)
               for(int j=0; j<array.length-1-i; j++)
                    if(array[j].compareTo(array[j+1])>0)
                              String temp1 ="";
temp1= array[j];
array[j] = array[j+1];
array[j+1] = temp1;
Edited by: 999363 on Apr 11, 2013 3:41 AM

You're not sorting your objects, you're only sorting the firstname and secondname arrays separately, so they get scrambled. Sort the array of `thedata` objects.
BTW this:
    public int compareTo(Object Student) throws ClassCastException
            if (!(Student instanceof ShowData))
            throw new ClassCastException("Error");
            String sn = ((ShowData) Student).getSecondname();
    }contains a complete waste of time. You should just remove 'throws ClassCastException' and the first two lines of the method. The test and throw happens anyway at the cast. If Student isn't an instance of ShowData the cast will fail with the same exception (and a much better error message).

SQL Developer 1.5.1 - Sorting Table / List of Columns - Why So Slow

Hi All,
why is it so slow to sort the list of columns names in a table.
It appears to be going back and querying the database again. - shouldn't it just be doing a local sort of the JTable ?
Thanks
Bill
Edited by: wfs on Oct 28, 2008 2:31 PM

Yes, it does query again - as it does with everything else being sorted.
You're right they could implement local sorting on a little, complete set, but that should be requested at the announced SQL Developer Exchange, since I recon that would get pretty tedious (taking in count NLS sorting settings).
Then mind you have to query again anyway if a result set is not complete (by default, fetches are 50 records at a time), or fetch everything before being able to apply the local sort, which will give you even more problems on large tables.
Regards,
K.

LINQ sorting on List Object - Various Object Type

I try to sort a List<Object> where the Object are different classes but all share the same Property Name for instance.
I got a Base Class where Class A and Class B inherit from the Base Class.
So during the Linq query I cannot specify with object type this is.
Problem here "from ?????Entry_Global?????? list in Entries"
Thanks for helping.
////Entries is a List<Object> which consist of class object as following\\\\\
public abstract class EntryBase<T>
private string _Name;
public string Name
get { return this._Name; }
set { this.SetProperty(ref this._Name, value); }
public class Entry_Global : EntryBase<Entry_Global>
public class Entry_CC : EntryBase<Entry_CC>
private string _url; //Web url
public string Url
get { return this._url; }
set { this.SetProperty(ref this._url, value.Contains("http") ? value : "http://" + value); }
public List<Object> SortBy()
IEnumerable<KeyedList<string, object>> groupedEntryList = null;
//The proble reside in the fact that list is not only one type
//so when comes in the orderby "Name" it doesn't know Name
//or any other properties which are all common to all those class
//It does not want to convert Entry_CC or Entry_Global to EntryBase
groupedEntryList =
from ?????Entry_Global?????? list in Entries
orderby list.Name
orderby list.CategoryRef.Name
group list by list.CategoryRef.Name into listByGroup
select new KeyedList<string, object>(listByGroup);
return groupedEntryList.ToList<object>();

Entry_Global and Entry_CC don't share the same base class since EntryBase<Entry_Global> and EntryBase<Entry_CC> are two totally different types so you cannot cast the objects in the List<object> to a common base class in this case.
You could cast from object to dynamic though:
public List<Object> SortBy()
List<object> objects = new List<object>();
objects.Add(new Entry_Global { Name = "K" });
objects.Add(new Entry_CC { Name = "A" });
objects.Add(new Entry_Global { Name = "I" });
objects.Add(new Entry_CC { Name = "C" });
var sortedObjectsByName = (from o in objects
let t = (dynamic)o
orderby t.Name
select o).ToList();
return sortedObjectsByName;
The dynamic keyword makes a type bypass static type checking at compile-time:
https://msdn.microsoft.com/en-us/library/dd264736.aspx. This basically means that a dynamic type is considered to have any property of any name at compile time. Of course you will get an exception at runtime if the type doesn't have a Name property but
providied that all objects in the List<T> to be sorted are of type EntryBase<T> you will be safe as long as the EntryBase<T> type defines the Name property that you sort by.
Please remember to close your threads by marking helpful posts as answer and please start a new thread if you have a new question.

Sorting linked lists - Help

I am writing a program for an assignment that reads a file containing population growth for all the Counties in the U.S. I'm required to use a link list to store the data. They want me to sort the data based on certain criteria. My first problem is that as each new County instance is created, it is to be inserted into this linked list in alphabetical order first by county name.
My understanding of linked lists is that they cannot be randomly accessed like a vector or an array. So is it possible to do this without using a vector or an array? And how would I go about it?
thanks.

Can you create a second, sorted linked list?The prof. didn't specify whether or not I can use a second list.
Are you prohibited from using the collections framework (probably, if it is a school assignment!)Not really sure on this one. Again it is not specified in the assignment
(Why would they have you store this data in a linked list??)I their reasoning is to have us learn how to implement linked list because it can grow or shrink when necessary.(Other than that I don't understand the practicality of it either)
Are you using a doubly linked list (forwards and backwards)?The assignment does not specify a certain linked list to use.
Did your prof mention any sort algorithms you might use? He states later in the assignment that I have to generate different growth reports by using MergeSort.
I appreciate your help and comments. Unfortunately my prof. is very vague about the assignment and its implementation in his outline. He just kind of throws us into it hoping that we will figure it out.

Sorting a List containing Symbols?

Hi,
My problem relates to ordering results from a Hibernate query.
I'm using Hibernate to return all records from a specific database table in the form of a List. The query contains an "order by" clause, and so my results look something like this (results ordered firstly alphanumerically, then alphabetically):
1
2
9
A
B
C
Z
The "problem" occurs when I retrieve records that contain symbols. I was hoping that such records would appear at the beginning of my retrieved records, and indeed that is the case for the majority of symbols, i.e.
$
1
2
9
A
B
C
Z
However, for some reason, certain symbols are appearing at the END of my results. So my list of results looks something like this...
$
1
2
9
A
B
C
Z
�
I assume that this ordering is the default one for Oracle.
I want to sort my list of results so that ALL symbols appear at the beginning of the list. I was thinking about using some sort of Comparator, i.e.
List result = Collections.sort(q.list(), new YourComparator());
However, I'm not sure what code would go inside YourComparator() to compare symbols and order them accordingly. Perhaps comparing the ASCII codes might be an idea(?)
Another solution might be to loop through each of my results and add the symbols and "non symbols" to separate lists, then order each list separately and combine them at the end. However this would probably have a major processing overhead.
Any other (simpler) suggestions?
Thanks in advance.

If there are non-ASCII characters in your data, ASCII values probably won't do the job. If so, look at some of the static methods of the Character class. You should be able to build your own Comparator.

I'm having problems Sorting Objects

Hello everyone!
I'm having problems sorting objects. Here is what I got at moment... I'm trying using "Collections.sort" with objects, and I think my problem is there but I don't know how to do in other way the sorting.
Some help will be appreciated! Thank you!
Movie.java
import java.util.ArrayList;
public class Movie
         public int itemNum;
         private String title;
         public String director;
         public Movie()
             itemNum = -1;
             title = "";
             director = "";
         public Movie(int itemNum, String title, String director)
            this.itemNum = itemNum;
            this.title = title;
            this.director = director;
         public int getItemNum()
             return itemNum;
         public String getTitle()
             return title;
         public String getDirector()
             return director;
           public void setItemNum(int a)
              itemNum = a;
         public void setTitle(String b)
             title = b;
         public void setDirector(String c)
             director = c;
         public String toString()
               String MovieInfo = title + "\t" + itemNum + "\t" + director ;
               return MovieInfo;
}MovieCollection.java
import java.util.*;
public class MovieCollection
    private ArrayList Movies;
     public MovieCollection()
            Movies = new ArrayList();
     public ArrayList getMovies()
            return Movies;
     public void add(Movie aMovie)
            Movies.add(aMovie);
}MovieCollectionMenu.java
import java.io.*;
import java.util.*;
public class MovieCollectionMenu
          private MovieCollection model;
          public MovieCollectionMenu ()
               model = new MovieCollection();
        public MovieCollection getModel()
            return model;
         private static Scanner Insert = new Scanner(System.in);
          public static void main (String[] args)
              MovieCollectionMenu menu = new MovieCollectionMenu();
               while(true)
             System.out.println("Movies Menu");
             System.out.println("");
             System.out.println("1 - Add Movie");
             System.out.println("2 - List Movies");
             System.out.println("3 - Sort Movies");
             System.out.println("0 - Exit");
                System.out.print("\nSelect your option: ");
             int option = Insert.nextInt();
                  switch(option)
                       case 0:   System.exit(0);break;
                     case 1:   menu.addMovie(); break;
                     case 2:   menu.listMovies(); break;
                     case 3:   menu.sortMovie(); break;
                     default: System.out.println("Invalid Selection!");
                  System.out.println("\n");
          private void addMovie()
               Movie aMovie = new Movie();
            System.out.print("\nEnter movie name: ");
               aMovie.setTitle(Insert.next());
             System.out.print("Enter number of copies: ");
            aMovie.setItemNum(Insert.nextInt());
            System.out.print("Enter director name: ");
            aMovie.setDirector(Insert.next());
            model.add(aMovie);
        private void listMovies()
               ArrayList Movies = model.getMovies();
               for (int i=0; i<Movies.size(); i++)
                    System.out.println(Movies.get(i).toString());
          private void sortMovie()
             ArrayList Movies = model.getMovies();
             Collections.sort(Movies);
}

JBStonehenge, Melanie_Green, paulcw thank u so much for ur support!!!!
I did many changes in my code, and I think in a simple way... I can sort the strings, but I'm having problems to sort the integers from the array I created..
I read a lot of sorting and this was the best I could do, please can you change my code to sort the integers?
Thank u people!
Here it is my code:
import java.io.*;
import java.util.*;
public class MyMovies {
     public static void main(String[] args) {
          MyMovies Movies = new MyMovies();
          Movies.runEverything();
     private static final int MAX_SIZE = 100;
     private static int numberOfMovies = 0;
     private static Movie[] array = new Movie[MAX_SIZE];
     public void runEverything(){
          Scanner input = new Scanner(System.in);
          while (true) {
               Menu();
               int option;
               try {
                    option = Integer.parseInt(input.nextLine());
               } catch (NumberFormatException e) {
                    System.out.println("You must enter a number!");
                    continue;
switch (option) {
               case 1:
                    addMovie(input);
                    System.out.println("\nThis movie was added:");
                    printMovie(numberOfMovies - 1);
                    break;
               case 2:
                    sortMoviesByTitle();
                    break;
               case 3:
                    sortMoviesByYear();
                    break;
               case 4:
                    sortMoviesByDirector();
                    break;
               case 5:
                    printAllMovies();
                    break;
               case 6:
                    System.out.println("You logout with success!");
                    input.close();
                    System.exit(0);
                    break;
          default:
                    System.out.println("You entered a wrong option! Please try again.");
                    break;
     private static void Menu() {
          System.out.println("\n1 - Add a movie");
          System.out.println("2 - Sort movies by name");
          System.out.println("3 - Sort movies by year");
          System.out.println("4 - Sort movies by director");
          System.out.println("5 - Display movies");
          System.out.println("6 - Quit");
          System.out.print("\nPlease enter an option:");
          private static void printMovie(int i) {
          if (i < numberOfMovies) {
               System.out.println("\"" + array.getTitle() + "\", " + array[i].getYear() + ", \"" + array[i].getDirector() + "\"");
     private void printAllMovies() {
          for (int i = 0; i < numberOfMovies; i++) {
               System.out.print(String.valueOf(i+1) + "-");
               printMovie(i);
     private static void addMovie(Scanner input) {
          System.out.print("Enter movie:");
          String title = input.nextLine();
          int year = 0;
          while (true) {
               try {
                    System.out.print("Enter the year of movie:");
                    year = Integer.parseInt(input.nextLine());
                    break;
               } catch (NumberFormatException e) {
                    System.out.println("You must enter an integer!");
                    continue;
          System.out.print("Please enter the director:");
          String director = input.nextLine();
          array[numberOfMovies] = new Movie(title, year, director);
          numberOfMovies++;
     private void sortMoviesByTitle(){
     boolean swapped = true;
          int i = 0;
          String tempTitle, tempDirector;
          int tempYear;
          while (swapped) {
               swapped = false;
               i++;
               for (int j = 0; j < numberOfMovies - i; j++) {
                    if ( array[j].getTitle().compareToIgnoreCase(array[j + 1].getTitle()) > 0) {
                         tempTitle = array[j].getTitle();
                         tempYear = array[j].getYear();
                         tempDirector = array[j].getDirector();
                         array[j].setTitle(array[j + 1].getTitle());
                         array[j].setYear(array[j + 1].getYear());
                         array[j].setDirector(array[j + 1].getDirector());
                         array[j + 1].setTitle(tempTitle);
                         array[j + 1].setYear(tempYear);
                         array[j + 1].setDirector(tempDirector);
                         swapped = true;
          System.out.println("The movies are sorted by title.");
     private void sortMoviesByYear(){
     boolean swapped = true;
          int i = 0;
          String tempTitle, tempDirector;
          int tempYear;
          while (swapped) {
               swapped = false;
               i++;
               for (int j = 0; j < numberOfMovies - i; j++) {
                    if ( array[j].getYear().compareToIgnoreCase(array[j + 1].getYear()) > 0) {
                         tempTitle = array[j].getTitle();
                         tempYear = array[j].getYear();
                         tempDirector = array[j].getDirector();
                         array[j].setTitle(array[j + 1].getTitle());
                         array[j].setYear(array[j + 1].getYear());
                         array[j].setDirector(array[j + 1].getDirector());
                         array[j + 1].setTitle(tempTitle);
                         array[j + 1].setYear(tempYear);
                         array[j + 1].setDirector(tempDirector);
                         swapped = true;
          System.out.println("The movies are sorted by year.");
     private void sortMoviesByDirector(){
     boolean swapped = true;
          int i = 0;
          String tempTitle, tempDirector;
          int tempYear;
          while (swapped) {
               swapped = false;
               i++;
               for (int j = 0; j < numberOfMovies - i; j++) {
                    if ( array[j].getDirector().compareToIgnoreCase(array[j + 1].getDirector()) > 0) {
                         tempTitle = array[j].getTitle();
                         tempYear = array[j].getYear();
                         tempDirector = array[j].getDirector();
                         array[j].setTitle(array[j + 1].getTitle());
                         array[j].setYear(array[j + 1].getYear());
                         array[j].setDirector(array[j + 1].getDirector());
                         array[j + 1].setTitle(tempTitle);
                         array[j + 1].setYear(tempYear);
                         array[j + 1].setDirector(tempDirector);
                         swapped = true;
          System.out.println("The movies are sorted by director.");
/* ----- My Movie Class ----- */
class Movie {
     private String title;
     private int year;
     private String director;
     public Movie(String title, int year, String director) {
          setTitle(title);
          setYear(year);
          setDirector(director);
     public String getTitle() {
          return title;
     public void setTitle(String title) {
          this.title = title;
     public int getYear() {
          return year;
     public void setYear(int year) {
          this.year = year;
     public String getDirector() {
          return director;
     public void setDirector(String director) {
          this.director = director;
}Edited by: AntiSignIn on Mar 24, 2010 7:30 PM

I would like to create a playlist of some of my voicememos to hear on my iphone5. I have no problem creating the list and can listen on playlist on computer but not when i sync to my phone. How can I listen to voicememos in a playlist on my iPhone?

I would like to create a playlist of some of my voicememos to hear on my iphone5. I have no problem creating the list and can listen on playlist on computer but not when i sync to my phone. How can I listen to voicememos in a playlist on my iPhone?

Hi czigrand,
Thanks for visiting Apple Support Communities.
Currently, you can gift dollar amounts or individual items (EG. songs) on the iTunes Store. See this article for more information:
In the iTunes Store, you can gift a dollar amount or specific music, movies, TV shows, or apps from your iPhone, iPod touch, iPad, Mac, or PC. Follow these steps to send a gift from the iTunes Store.
iTunes: Sending iTunes Gifts
http://support.apple.com/kb/HT2736
Best Regards,
Jeremy

Sorting a List on Parent Child Relationship

I have to sort a list on Parent Child relation
say
I have a following list
Object(Id,ParentId,.........)
obj1(1,1,........);
obj2(2,1,........);
obj3(3,3,........);
obj4(4,1,........);
obj5(5,3,........);
obj6(6,1,........);
obj7(7,3,........);
obj8(8,4,........);
Logic is such that
If Id and Parent Id is same then It is Parent Record
I want the Result like
obj1(1,1,........);
obj2(2,1,........);
obj4(4,1,........);
obj6(6,1,........);
obj3(3,3,........);
obj5(5,3,........);
obj7(7,3,........);
obj8(8,4,........);
Suggect Some Logic...............
Thanks in advance.............

sAsho wrote:
That's the question how to do that?????????????????????????One question mark is sufficient. If you're going to go out of your way to write like an idiot, people won't take you seriously.
"How do I do that?" is way to broad a question. You need to do some research, take your best shot, and post a specific question about the specific parts that are giving you trouble.
Suggest something. I did suggest something.
I suggested what you should google for to get you started. Just like writing clearly and intelligently, if you can't be bothered to read what people suggest and put in the effort to follow that suggestion and do your own research, you'll find people will quickly lose interest in trying to help you.
Now I am additionally suggesting that you 1) pay closer attention and 2) do your own research.
Recurcive sort kind of a think.................No idea what you're saying here. See my first point in this reply.

Sorting the list of value like in BEX but out of crystal report

All,
I have created a crystal report base on a BEX query where I have a variable for which i am filtering base on a field period.fiscalyear.
for the list of values that prompt you for this variable ...
l in BEX we can do the sort by either alphabetical ascending order or descending alphabetical order such as:
here is for ascending
001.2008
001.2009
or by clicking on it we can do the following: (descending)
012.2009
012.2009
however in crystal when refreshing the report in infoview it sorts the list of value base on the month
something like this :
JAN 2008 [0FISCPER].[K42008001]
FEB 2008 [0FISCPER].[K42008002]
We would like to have in crystal the same behaviour than in BEX, so in crystal we would like to be able to get the list of values sorted in either ascending order to descending order. is there a way to do so ?
notes also that we would like to avoid to create the variable in crystal
Philippe

Hi,
in Crystal Reports you have per InfoObject - depending on the definition - the key value, the description and the member unique name. In BW these objects are defined as NUMC in most cases - which means it is a character / string.
In your example the value is 001.2008 and 001.2009. What you can do in Crystal Reports is to split up the values into year and month and then sort based on the actual numbers.
Ingo

Is it possible to sort the list of Conditions/Calculations?

Is it possible to sort the list of Conditions/Calculations so that they display alphabetically in the list?
My list of conditions is getting quite long and haphazard now!
Cheers
Sapphie

I was afraid of that!. It is very disappointing because , as I am developing a set of reports for the first time, I will create conditions/calculations in quite a non-ordered way and then end up wanting to group similar ones together.
Hopefully a future version will allow this?
Lee

Problem sorting a List

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