Problem with Grid agent

Hi,
I installed Grid control on Instance A and grid agent at Instance B where im able to monitor Instance B from Grid control ,but when i tried to install another grid agent an say Instance C during installtion when i gave the INstance C details its not connecting with INstance C when i tried to ping from Instance A(where i installed Grid control) im able to ping from A--->B
Please help me in to solve this issue
Regards,
Pradeee

Whats exactly the error it throw

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    Why is it happens?
    Also I set windows environment (ORACLE_SID, ORACLE_HOME, TNS_ADMIN) to correct path and values.

    Hi
    I am also facing the same issue but in a different flavor. Installed 10g on my Win2K and EM was working fine. Could create a dummy table and execute statements using iSQLPLUS. Later installed Oracle 9iDS on a different home. From then on EM isn't working. I get TNS-12538: no such protocol error. Verified the ORACLE_HOME registry and was pointing to 10g path.
    Were you able to solve your issue? Can you pl. suggest your solution? I found similar issue elsewhere
    http://ora-12538.ora-code.com/msg/36848.html
    Thanks

  • Installation problems with SAPCCM4X Agent

    Hi!
    I would like to install a SAPCCM4x agent on windows and have two problems.
    By one of the systems when i execute the commando for the installation sapccm4x -R pf=...
    I get the following error message:
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    I have looked into the log files I do not detect any problems.
    Can some one help to solve the problems ?
    Thank you very much!
    regards
    Thom

    Hi,
    I could install XE in my (physical) machine with FC4 without any particular issue (just had to add some swap space); I also had to remove reference to ORACLE* environment variables prior to install the rpm (the rpm install warned me about both of the issues)
    I just miss the menu icons that are correctly installed in suse: did you manage to have them?
    Regards,
    Andrea

  • Big problem with ARD agent and versions.

    This is going to be a bit lengthy so please bear with me. At my company I'm in charge of our 6 production G5 computers. My boss has permitted me to install ARD on them so that I can run the specialty programs we have on one without having to walk all the way across the department time and time again. The computers are from varying times in terms of processor speed and RAM but they are all running the same OS with all the same updates. All were running the ARD 3.0 Agent as it was in an update from apple not too long ago. I have uninstalled the agent and used a custom client install pack from ARD 2.2.
    My computer is a dual 2GHz G5 and is the oldest of the 6. (here on referred to as Mac2) The other computer with problems is a dual 2.5GHz G5 and is called Mac7.
    Mac2 is supposed to have the admin program on it, and I can install it but the program fails to start because it was either installed wrong or the computer needs a restart. I had this same error on my laptop at home but that is a MBP which is Intel. To solve the problem on intel computers i've been told to remove the remote-management folder from core-services and let ARD reinstall it on launch. This has not worked for the G5 at work. Furthermore at one point i could get control of Mac2 remotely from another computer, but after trying to reinstall the admin program again I cannot do that anymore. Even if i reset all ARD software and use the custom client install .pkg again.
    As for Mac7, that computer was being run with the 3.0 agent on it and i could connect fine but couldn't lock the screen because of the mismatch. I did the exact same uninstall and reinstall of the ARD Agent that I did on the other computers and now I can't access that one either.
    At the very least I need to be able to control these two computers, and I would like to have the Admin software work on Mac2 if possible. I see no reason why these problems should be occurring.
    All systems are running 10.4.10 and have no third party remote software installed on them. On both Mac2 and 7 the ARD menu drop-down is showing as not active. All sharing preferences have been set right and there is no firewall. All accounts on both computers have been given all the rights possible for control.
    If anyone has any advice please reply to this.

    OK, I am still a bit confused - Mac2 is your computer, the one on which you want run the admin app to control other computers, correct? If ARD 2.2 will not start on that one, does it give an error message? I really suspect there are traces of 3.x agent causing the trouble, as I have had this problem myself. In essence, if you have version 2.2 admin, there is no reason to have 3.x agent for any reason whatsoever, it will just cause problems both on the admin and client side since Apple completely rewrote the way it works.
    And, based on the first paragraph of your initial inquiry, I wonder if ARD is worth the trouble anyway, since it seems you could accomplish what you need with a simple VNC viewer (my up and coming favorite is JollysFastVNC). If you can't connect with a simple VNC viewer, you also won't be able to use ARD, as it's an extension of the VNC protocol.
    However, if you want to make this work, let's work on Mac2 - follow the instructions at this page, down at the bottom: http://docs.info.apple.com/article.html?artnum=108021
    It says: "Mac OS X 10.2 clients" but it's also the correct procedure for a complete and clean removal in 10.3 and 10.4
    Then reinstall ARD 2.2 admin (you may have an earlier version installer, then install the admin updater). Don't mess with your custom client installer stuff. Just install the 2.2 admin app, and it will install the client it needs. I think this will make Mac2 work for you.

  • [SOLVED] a problem with gpg-agent and ssh keys

    I'm baffled by a strangle problem:
    My setup is as follows: I use gpg-agent with --enable-ssh-support, so that my ssh keys are handled by it. All was fine (when I ssh'ed to another machine, a pinentry window popped up, asked for a password, and if I entered the correct one, gpg-agent would decrypt its copy of my private ssh key and use it for identification). But: I needed to change my ssh key, and so I generated a new one. Next, I ssh-add'ed it to gpg-agent (one password to decrypt the private key, then twice another password for gpg-agent). I uploaded the public key to a server. The setup should be complete.
    The problem is that when I ssh to a machine, a pinentry window comes up, but it does not accept my password (the one that I entered twice when ssh-add'ing the key). I tried adding with various different passwords (always deleting ~/.gnupg/private-keys-v1.d/*, since 'ssh-add -d ~/.ssh/id_rsa.pub' would not work for some reason - it would not make gpg-agent forget the key), different pinentry programs ( -qt4, -gtk-2, -curses), and still the same problems. Pinentry itself seems to work fine, since if I enter two different things when it asks for a new passphrase for the key, it detects that there's a problem.
    So, can anyone help? What could I try (please don't post just to say that I could/should use ssh-agent, or keychain, or anything else. I have used various things, and I like this setup the most. It worked before, and I would like to find out why it stopped working and how to get it back to speed.)
    Thanks.
    Last edited by bender02 (2010-02-15 09:52:54)

    Thats a known bug with the new gpg version.
    http://lists.gnupg.org/pipermail/gnupg- … 38045.html
    You could use an older version of gpg or use a development version.

  • Problem with grid display in ALV for dynamic internal tables

    Hi,
    I am using dynamic internal tables in my program. To display it in grid format after populating it, I have used the following class and method. Here Im getting sy-subrc = 0 but, the grid is not getting displayed. Can some one pls help me with this.,
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    DATA: w_tabname TYPE w_tabname.
    CREATE OBJECT W_GRID
    EXPORTING I_PARENT = CL_GUI_CONTAINER=>SCREEN0.
    CALL METHOD W_GRID->SET_TABLE_FOR_FIRST_DISPLAY
      EXPORTING
       I_BUFFER_ACTIVE               =
       I_BYPASSING_BUFFER            =
       I_CONSISTENCY_CHECK           =
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       IS_PRINT                      =
       IT_SPECIAL_GROUPS             =
       IT_TOOLBAR_EXCLUDING          =
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       IT_ALV_GRAPHICS               =
       IT_EXCEPT_QINFO               =
       IR_SALV_ADAPTER               =
      CHANGING
        IT_OUTTAB                     = <FS_1>
        IT_FIELDCATALOG               = LT_FIELDCATALOG2
       IT_SORT                       =
       IT_FILTER                     =
      EXCEPTIONS
        INVALID_PARAMETER_COMBINATION = 1
        PROGRAM_ERROR                 = 2
        TOO_MANY_LINES                = 3
        others                        = 4
    IF SY-SUBRC <> 0.
    MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
               WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
    ENDIF.
    Here, <FS_1> is the field symbol of table type and it holds all my data. and LT_FIELDCATALOG2  is the structure of my fieldcatalog
    Thanks and Regards,
    Avinash

    Hi Avinash,
    Either use parameter
    I_STRUCTURE_NAME = W_TABNAME
    or
    IT_FIELDCATALOG = LT_FIELDCATALOG2
    Both are not required.
    At the end of ur program simply use a write statement like below. Your program will work.
    IF SY-SUBRC 0.
    MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
    WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
    ENDIF.
    Write /.      <----
    Thanks,
    Edited by: Sap Fan on Oct 6, 2009 7:17 AM

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