Problem with percentage query
Hi there,
I would like to calculate percentage data in my sql query but it doesn't work. My table structure is the following :
RESOURCE TABLE:
ID_RES | ICD | CONSENT | SAMPLE_DATE
So, the goal of query is to calculate of percentage of yes with the total number. In the first step I did :
Compte ICD | Reponse | Code
2 | NON | C76.4
5 | OUI | C76.4
3 | OUI | C26.9
with the following query :
SELECT
count(RES.ICD) AS "Compte CODE en 2010",
RES.CONSENT AS "reponse",
RES.ICD AS "CODE"
FROM
RESOURCE RES
WHERE
trunc(RES."SAMPLE_DATE", 'DD') > TO_DATE('10/12/2010', 'DD-MM-YYYY')
AND RES.ICD IS NOT NULL
GROUP BY (RES.ICD, RES.CONSENT)
ORDER BY
RES.ICD
The problem is that I don't know how to integrate percentage calculus in my query in order to obtain the following result :
Compte ICD | Reponse | Code | Pourcentage oui
2 | NON | C76.4 |
5 | OUI | C76.4 | 71.42
3 | OUI | C26.9 | 100
Does anybody could help me please ?
Regards,
Jarod.
You'd need to use the analytic sum function, something like:
with sample_table as (select 2 compte_icd, 'NON' response, 'C76.4' code from dual union all
select 5 compte_icd, 'OUI' response, 'C76.4' code from dual union all
select 3 compte_icd, 'OUI' response, 'C26.9' code from dual)
-- end of mimicking your data in a table called sample_table. See query below:
select compte_icd,
response,
code,
case when response = 'OUI' then
round(compte_icd*100/sum(compte_icd) over (partition by code), 2)
end pourcentage_oui
from sample_table;
COMPTE_ICD RESPONSE CODE POURCENTAGE_OUI
3 OUI C26.9 100
2 NON C76.4
5 OUI C76.4 71.43ETA: analytic functions are very useful - if you've never come across or used them before, I suggest you research them. They're incredibly useful when you want to refer to other rows in the table, much as you're trying to do in your query, without having to do a self join.
As Tom Kyte would say, Analytic functions rock and roll!
Edited by: Boneist on 15-Dec-2010 16:33
ETA2: here's a link I've found useful in the past: http://www.orafaq.com/node/55
Edited by: Boneist on 15-Dec-2010 16:41
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and a1.header_id=a.header_id) WHT,
sum(dr),
sum(cr)
from temp_tab a
group by header_id
,countryIt's kinda hard to follow what your query does... maybe because I'm only at my second coffee..
Edited by: Alex Nuijten on Oct 2, 2009 8:07 AM -
Hi gurus,
I have a problem in a query
I have a lot of records that are the same and I dont want to sum the value of them more than once. How can this be done??
The following table should illustrate my problem:
DEPT--MONTHCFBID----SCORE
ALST--APR100--
3
ALST--MAY100--
3
ALST--JUN101--
4
ALST--APR102--
5
Overall Score 15
I want the Overall Score to be 12. (only summing up unique records Of CFBID).
Any help will be greatly appreciated.
Regards
Supraja.KHi,
I had Done with Formula with Excveption Aggregation as Average And reference charecterstic as CFBID
DEPT--MONTHCFBID----SCORE
ALST--APR100--
3
ALST--MAY100--
3
ALST--JUN101--
4
ALST--APR102--
5
Overall Score 15
I want the Average Score12/3 = 4.
but I am getting as 15/3 = 5
What to Do any other Solution please -
I have a problem with Oracle 10.2.0.5.0 and 11.2.0.1.0. Query result is wrong.
SELECT t.id
FROM (SELECT t.ID, MAX(t.nom) AS nom
FROM (SELECT 2 AS ID, 200 AS nom
FROM dual
UNION ALL
SELECT 3 AS ID, 0 AS nom FROM dual) t
LEFT JOIN (SELECT 0 AS ID_1, 0 AS nom_1 FROM dual) s
ON s.id_1 = t.ID
WHERE t.ID IN (2, 3)
GROUP BY t.ID
HAVING MAX(t.nom) != 0) t;Return nothing.
But on Oracle 10.2.0.4.0 result is correct:
ID NOM
2 200Looks like a bug related to ANSI joins.
Check Oracle Support, maybe it's fixed in 11.2.0.2.
It works with Oracle join syntax :
Connected to Oracle Database 11g Enterprise Edition Release 11.2.0.1.0
Connected as dev
SQL>
SQL> SELECT t.id
2 FROM (SELECT t.ID, MAX(t.nom) AS nom
3 FROM (SELECT 2 AS ID, 200 AS nom
4 FROM dual
5 UNION ALL
6 SELECT 3 AS ID, 0 AS nom FROM dual) t
7 ,(SELECT 0 AS ID_1, 0 AS nom_1 FROM dual) s
8 WHERE t.ID IN (2, 3)
9 AND s.id_1(+) = t.ID
10 GROUP BY t.ID
11 HAVING MAX(t.nom) != 0) t;
ID
2
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