Problem with select max(FIELD)

Question

I have a table with the following fields:
PARTID     ART_TYP     AEC     SERVICE     PLANT     STATUS
4711     A     A     2     P     230
4711     A     B     0     P     230
4712     A     B     2     P     230
4713     A     B     0     P     230
I need a sqlscript where I get the records with MAX(SERVICE)
In this example
4711     A     A     2     P     230
4712     A     B     2     P     230
4713     A     B     0     P     230
I tried this with:
select distinct partid,
     art_typ,
     aec,
     max(service),
     plant,
     status
from t_msltmp
group by partid,art_typ,aec,plant,status
But I get both records of partid=4711
Can someone help me with this problem
kind regards
Menk Slot

Answer 1

ROW_NUMBER() requires explicit ORDER BY clause in OVER:
http://download-uk.oracle.com/docs/cd/B10501_01/server.920/a96540/functions105a.htm#86312
SQL> select partid, art_typ, aec, mx, plant, status
  2  from(select partid,
  3                art_typ,
  4                aec,
  5                max(service) over (partition by partid) mx,
  6                row_number() over (partition by partid order by service desc) rn
  7                plant,
  8                status
  9         from t_t)
10  where rn = 1
11  /
    PARTID A A         MX P     STATUS
      4711 A A          2 P        230
      4712 A B          2 P        230
      4713 A B          0 P        230Rgds.
P.S.
Another way to get this (more tedoius):
SQL> select partid,
  2  max(art_typ) keep (dense_rank first order by service desc) art_typ,
  3  max(aec) keep (dense_rank first order by service desc) aec,
  4  max(service) service,
  5  max(plant) keep (dense_rank first order by service desc) plant,
  6  max(status) keep (dense_rank first order by service desc) status
  7  from t_t
  8  group by partid
  9  /
    PARTID A A    SERVICE P     STATUS
      4711 A A          2 P        230
      4712 A B          2 P        230
      4713 A B          0 P        230Message was edited by:
dnikiforov