Program for DMEE

Hi all,
Can anyone tell me which program is running behind the tcode DMEE.

Hi
it's SAPMDMEE_ABA
br, Guido

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    * @version 1.0
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    * Return the NO. of philosopher who is sitting at the left side of this philosopher
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    * Return the NO. of philosopher who is sitting at the right side of this philosopher
    * @return the NO. of the right philosopher
    private int getRight(){
    int ret = (pherNo+1)>=PHER_NUM ? 0 :(pherNo+1);
    return ret;
    private void testPher(int no){
    while(true){
    if(pherState[no]==HUNGRY
    &&pherState[getLeft()]!=EATING
    &&pherState[getRight()]!=EATING) {
    pherState[no] = EATING;
    //Print and check the philosophers' state
    printPher(pherState);
    return;
    }else{
    try {
    System.out.println(" Philosopher "+this.pherNo+"is waiting a fork");
    threadLock.wait();
    }catch (java.lang.InterruptedException ex) {
    System.out.println(" Philosopher "+this.pherNo+"is interrupted and woken up to take fork");
    //when it is interrupted, do nothing. Just let it continue!
    }//end of while(true)
    * Print and check the philosophers' state.
    * To insure there are no two philosophers sit side by side
    * are eating at the same time.
    private static void printPher(int[] phers){
    System.out.print(" philosophers' state��");
    for (int i = 0; i < phers.length; i++) {
    System.out.print(" "+phers);
    System.out.println("");
    for (int i = 0; i < phers.length-1; i++) {
    if (phers[i]==EATING && phers[i+1]==EATING){
    System.err.println(i+" and "+(i+1)+"two of philosophers sitted side by side are eating at the same time!");
    if (phers[0]==EATING && phers[PHER_NUM-1]==EATING){
    System.err.println("0 and "+PHER_NUM+"two of philosophers sitted side by side are eating at the same time!");
    public static void main(String[] args) {
    for (int i = 0; i < PHER_NUM; i++) {
    PhilosopherEating.pherState[i] = THINKING;
    PhilosopherEating aPhilosopherEating = new PhilosopherEating();
    for (int i = 0; i < PHER_NUM; i++) {
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    philosophers[i].start();
    try {
    Thread.sleep(30000);
    catch (InterruptedException ex) {
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    //End all the threads of philosophers
    PhilosopherEating.finished = true;

    this problem is about learning how to use threads/synchronise objects etc, the efficiency of the code isn't really an issue, if that's what you mean. As for the efficiency of the solution, it's very hard to tell how efficient it is, but as long as all the philosphers get to eat there's no problem. I haven't really scrutized your code, but I'm not sure that you have a deadlock free solution: as long as it is possible for all the phils to pick up one fork at the same time there's a problem, and it seems from your code that each philosopher will pick up "his" fork. Again, I could be wrong, I haven't really looked. If you haven't come up with a solution, try drawing it on paper and working it out, or if you're lazy a quick google will probably give you the answer, but I'm pretty sure nobody here will :)

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