Purchased a Movie, which has just disappeared - PLEASE HELP!!!

Question

I really need some help here please,
A few hours ago, I purchased a Movie from the iTunes store which took 3 hours to download to my iPod touch which cost £6.99. A soon as it finished, I took then plugged it into my PC to transfer the purchase to my iTunes library, for a backup.
Whilst I was doing this, iTunes (as per usual) froze on me when it was syncing and did not respond at all when I moved and clicked an area of the open window. Because of this, I was forced to quit iTunes and re-open it again, to try and get the film onto my PC.
When I connected my iPod to iTunes again, the Movie disappeared from my iPod and there was no sign of it anywhere on my PC either. Where is it?!
Because of this and un-aware I had to pay £7 again to download the movie on my iPod, I repeated the whole process and as before, the file just went missing on both my iPod and PC.
You may ask "Why didn't you purchase it through iTunes on your PC?" and the reason why is because the iTunes Store doesn't work on the PC any more. I've tried hundreds of new and old solutions to fix this and none of them seem to work. I've disabled EVERY type of firewall that could potentially be blocking me using the store, disabled all spyware programs and it still won't work.
I feel very angry and annoyed here, as I've spent £14 on 1 film I've tried to get twice and attempting to find a missing file that never appeared on my PC.
So how do I resolve this constant freezing probelm with iTunes, how do I get the iTunes Store working again, and most importantly, is there any way of me getting my £14 back? Please help!
Any answer will be greatly appreciated.
Martin.

Answer 1

girikavali wrote:
I'm a begineer in labview. I want to evaluate an equation which has complex numbers through text code.. 
Are you saying you don't want to use LabVIEW to evaluate this? In which case I suggest asking on a different forum.
for(f=0;f<=2560;f=f+0.3125)
     R=((H12-e^(-i*k))/(e^(i*k)-H12))*e^(i*k);
There is no 'f' in the loop, I don't understand what the loop would evaluate, unless k is a constant in which case the loop is redundant.
            k         function of frequency
            f          frequency 
If k is a function of frequency you need to say what that function is. For example if you are evaluating 'k' for changing 'f' and applying it to the equation for R. I don't know what the best procedure would be but my first port of call would be nested loops: 'R' for each 'k' for each 'f' ?
In the absence of a function for k this vi would evaluate you formula for k=f, I don't know if this wil help any.