Query regarding Folder Sharing

Hi Experts,
I have created Folder(sampleFolder1) by User A (folder path is : /domain/container/workspace/sampleFolder1). What steps do i need to do to share that folder with other users..... so that when other users log on... they should be able to see the shared folder.
Thanks
parker.

Hope this helps
http://ticklingmind.blogspot.com/2010/03/content-and-user-information-from.html

Similar Messages

  • A query regarding synchronised functions, using shared object

    Hi all.
    I have this little query, regarding the functions that are synchronised, based on accessing the lock to the object, which is being used for synchronizing.
    Ok, I will clear myself with the following example :
    class First
    int a;
    static int b;
    public void func_one()
    synchronized((Integer) a)
    { // function logic
    } // End of func_one
    public void func_two()
    synchronized((Integer) b)
    { / function logic
    } // End of func_two
    public static void func_three()
    synchronized((Integer) a)
    { // function logic
    } // End of func_three, WHICH IS ACTUALLY NOT ALLOWED,
    // just written here for completeness.
    public static void func_four()
    synchronized((Integer) b)
    { / function logic
    } // End of func_four
    First obj1 = new First();
    First obj2 = new First();
    Note that the four functions are different on the following criteria :
    a) Whether the function is static or non-static.
    b) Whether the object on which synchronization is based is a static, or a non-static member of the class.
    Now, first my-thoughts; kindly correct me if I am wrong :
    a) In case 1, we have a non-static function, synchronized on a non-static object. Thus, effectively, there is no-synchronisation, since in case obj1 and obj2 happen to call the func_one at the same time, obj1 will obtain lock for obj1.a; and obj2 will obtain lock to obj2.a; and both can go inside the supposed-to-be-synchronized-function-but-actually-is-not merrily.
    Kindly correct me I am wrong anywhere in the above.
    b) In case 2, we have a non-static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a. However, since obj1.a and obj2.a are the same, thus we will indeed obtain sychronisation.
    Kindly correct me I am wrong anywhere in the above.
    c) In case 3, we have a static function , synchronized on a non-static object. However, Java does not allow functions of this type, so we may safely move forward.
    d) In case 4, we have a static function, synchronized on a static object.
    Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a. However, since obj1.a and obj2.a are the same, thus we will indeed obtain sychronisation. But we are only partly done for this case.
    First, Kindly correct me I am wrong anywhere in the above.
    Now, I have a query : what happens if the call is made in a classically static manner, i.e. using the statement "First.func_four;".
    Another query : so far we have been assuming that the only objects contending for the synchronized function are obj1, and obj2, in a single thread. Now, consider this, suppose we have the same reference obj1, in two threads, and the call "obj1.func_four;" happens to occur at the same time from each of these threads. Thus, we have obj1 rying to obtain lock for obj1.a; and again obj1 trying to obtain lock for obj1.a, which are the same locks. So, if obj1.a of the first thread obtains the lock, then it will enter the function no-doubt, but the call from the second thread will also succeed. Thus, effectively, our synchronisation is broken.
    Or am I being dumb ?
    Looking forward to replies..
    Ashutosh

    a) In case 1, we have a non-static function, synchronized on a non-static object. Thus, effectively, there is no-synchronisationThere is no synchronization between distinct First objects, but that's what you specified. Apart from the coding bug noted below, there would be synchronization between different threads using the same instance of First.
    b) In case 2, we have a non-static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.obj1/2 don't call methods or try to obtain locks. The two different threads do that. And you mean First.b, not obj1.b and obj2.b, but see also below.
    d) In case 4, we have a static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.Again, obj1/2 don't call methods or try to obtain locks. The two different threads do that. And again, you mean First.b. obj1.b and obj2.b are the same as First.b. Does that make it clearer?
    Now, I have a query : what happens if the call is made in a classically static manner, i.e. using the statement "First.func_four;".That's what happens in any case whether you write obj1.func_four(), obj2.func)four(), or First.func_four(). All these are identical when func_four(0 is static.
    Now, consider this, suppose we have the same reference obj1, in two threads, and the call "obj1.func_four;" happens to occur at the same time from each of these threads. Thus, we have obj1 rying to obtain lock for obj1.aNo we don't, we have a thread trying to obtain the lock on First.b.
    and again obj1 trying to obtain lock for obj1.aYou mean obj2 and First.b, but obj2 doesn't obtain the lock, the thread does.
    which are the same locks. So, if obj1.a of the first thread obtains the lock, then it will enter the function no-doubt, but the call from the second thread will also succeed.Of course it won't. Your reasoning here makes zero sense..Once First.b is locked it is locked. End of story.
    Thus, effectively, our synchronisation is broken.No it isn't. The second thread will wait on the same First.b object that the first thread has locked.
    However in any case you have a much bigger problem here. You're autoboxing your local 'int' variable to a possibly brand-new Integer object every call, so there may be no synchronization at all.
    You need:
    Object a = new Object();
    static Object b = new Object();

  • Urgent query regarding performance

    hi
    i have one query regarding performance.iam using interactive reporting and workspace.
    i have all the linsence server,shared services,and Bi services and ui services and oracle9i which has metadata installed in one system(one server).data base which stores relationaldata(DB2) on another system.(i.e 2 systems in total).
    in order to increase performance i made some adjustments
    i installed hyperion BI server services, UI services,license server and shared services server such that all web applications (that used web sphere 5.1) such as shared services and UI services in server1(or computer1).and remaining linsence and bi server services in computer2 and i installed database(db2) on another computer3.(i.e 3 systems in total)
    my query : oracle 9i which has metadata where to install that in ( computer 1 or in computer 2 )
    i want to get best performance.where to install that oracle 9i which has metadata stored in it.
    for any queries please reply mail
    [email protected]
    9930120470

    You should know that executing a query is always slower the first time. Then Oracle can optimise your query and store it temporary for further executions. But passing from 3 minutes to 3 seconds, maybe your original query is really, really slow. Most of the times I only win few milliseconds. If Oracle is able to optimize it to 3 seconds. You must clearly rewrite your query.
    Things you should know to enhance your execution time : try to reduce the number of nested loops, nested loops give your an exponential execution time which is really slow :
    for rec1 in (select a from b) loop
      for  rec2 in (select c from d) loop
      end loop;
    end loop;Anything like that is bad.
    Try to avoid Cartesian products by writing the best where clause possible.
    select a.a,
             b.b
    from  a,
            b
    where b.b > 1This is bad and slow.

  • Beehive enhancement for tomorrow: re-add the OBEO sub folder sharing option

    OK, I inadvertently posted a comment meant for an enhancement to be posted tomorrow, so here we go with tomorrows enhancement of the day:
    Talking once more about delegation... There's quite a big fly in the ointment we need to talk about:
    While delegation granting dialogues in OBEO and bcentral take care of permissions for default folders like inbox, sent items, drafts etc. and pseudo folders like calendar or contacts, it does not so for non-default folders.
    We have the case of a superior that has a widely ramified folder structure and granted his secretary access to parts of it. When the secretary changed he changed delegation, and this did not change the non-default acls.
    So far nothing unspectacular. The issue is, that there is no option in OBEO to define permissions tree-wise (nor is there in beectl), so the superior had to walk the whole directory hierarchy to adapt the permissions, each folder requiring multiple clicks.
    There was a permissions dialogue for that in OBEO 1.5, but has been dropped.
    There is an enhancement request I'd ask you to second through MOS:
    10065126: READD THE SUB FOLDER SHARING OPTION TO OBEO
    This ER had the status approved for future release, but product management changed its plans and put it to "Suggestion Rejected".
    a related ER is the following:
    12557969: OBEO PERMISSIONS DIALOGUE SHOULD HAVE A TREE OPTION
    "The Beehive platform is designed from the ground up to be easy to manage." (cited from "Oracle Beehive: A Flexible Collaboration Platform for the Enterprise") - let's hope product management will give us tree perms management, at least in OBEO.
    Thanks, Tom

    As currently product management does not seem to be considering
    readding the desired dialogue (nor a tree switch for beectl perms
    related commands) lets look at our workaround.
    Lets look at it in an example: user user_a has set up a delegation to
    user_b, allowing access to his inbox.
    If you have set this up (using OBEO or BCentral as alternatives) a new
    Principal Record has emanated, that you can list with "beectl
    list_users":
    bhowner@bhhost:~> beectl list_users email addr@mydomain show more
    Display Record: 1
    ===========================================
    User Identifier: user=user_a
    Family Name: user_a
    Principal Record: 6
    ===============
    Principal Identifier: pcpd=145F:5618:user:9B37CFDA0D624736B413FEF81573597400000000000E -> 145F:5618:user:D8D547BB10AD4C079CE3A2604996535B000000000000,user=user_a
    Principal Name: 145F:5618:user:9B37CFDA0D624736B413FEF81573597400000000000E -> 145F:5618:user:D8D547BB10AD4C079CE3A2604996535B000000000000
    Delegated Principal: Yes
    DELEGATOR: user=user_a
    DELEGATED TO: user=user_b
    Lock status: UNKNOWN.
    bhowner@bhhost:~>
    An ACL to the inbox has been generated:
    bhowner@bhhost:~> beectl list_local_acl --entity "fldr=Inbox,wksp=user_a's Personal Workspace,enpr=myenpr"
    ------------------------------------------------------------------+-------------
    accessor | access_types
    ------------------------------------------------------------------+-------------
    ------------------------------------------------------------------+-------------
    pcpd=145F:5618:user:9B37CFDA0D624736B413FEF81573597400000000000E | +RWDO
    -> 145F:5618:user:D8D547BB10AD4C079CE3A2604996535B000000000000,us |
    er=user_a |
    ------------------------------------------------------------------+-------------
    Listed LocalACL for entity 'fldr=INBOX,wksp=user_a's Personal Workspace,enpr=myenpr'
    bhowner@bhhost:~>
    Now we need to generated similar ACLs for all subfolders of
    exampl-fldr, which, being a non-default folder, did not receive any
    ACL:
    So let's connect to BEE_DATA on the BEEDB, preferrable through SQLDeveloper, and run
    SELECT 'beectl add_local_ace --entity "'
    ||trim(TO_CHAR(c.enterprise_id,'0XXX'))
    ||':'
    ||trim(TO_CHAR(c.site_id,'0XXX'))
    ||':'
    ||c.container_type
    ||':'
    ||c.eid
    ||'" --accessor "pcpd=145F:5618:user:9B37CFDA0D624736B413FEF81573597400000000000E -> 145F:5618:user:D55B885774B6457AA0489F596D7DF873000000000000,user=user_a" --access_types "+RWDO"'
    -- , f.name,
    -- , c.path
    FROM bee_data.ws_real_folders f,
    bee_data.ocs_containers c
    WHERE f.eid=c.eid
    AND c.path LIKE '/dla/user_a''s Personal Workspace/exampl-fldr%'
    AND c.container_type='afrh'
    This will generate the beectl commands necessary to work around the
    missing switch. You need to run those commands afterwards.
    Of course this is not supported, but your only alternative is
    right-clicking all of the subfolders of exampl-fldr and grant the new
    user access manually.
    I would be happy if Oracle would enhance this are of user and rights
    management of beehive.
    Regards, Tom
    Edited by: snmdla on Jan 23, 2012 4:20 PM

  • Does simple file and folder sharing on an iMac work with OSX Server?

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    Khurram

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  • Query regarding Explain Plan

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    GK

    Hi,
    Aman.... wrote:
    Gulshan wrote:
    Hi,
    I have a query regarding explain plan. While we gather the statistics then optimize choose the best possible plan out of the explain plans available. If we do not gather statistics on a table for a long time then which plan it choose:The same plan which it has chosen in the starting with the previous statistics. The plan won't change automatically as long as you won't refresh the statistics. This is wrong even for Oracle 9i. Here are couple of examples when a plan might change with the same optimizer statistics:
    * when you have a histogram on a column and are not a bright person to use bind variables, you might get a completely different execution plan because of a different incoming value. All that is needed to fall into this habit - a soft parse, which might be due to different reasons, for instance, due to session parameter modification (which also might change a plan even without a histogram)
    * Starting with 10g, CBO makes adjustments to cardinality estimates for out of range values appeared in predicates

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