Query regarding Manager & secretary feature.

My requiremnet is given below,
Secretary should be able to pick up managers phone and also if the manager doesn’t answer the call in 3 rings it should be forwared to secretaries extension.
We dont want to user IMPA feature.
Thanks

Sunil, I can think of following options if you dont want IPMA..
1. Configure a shared line ( with privacy feature ) among Manager & Sec's phone line. If mgr doesnt pickup, sec will.
2. Use Call Pickup feature by adding these 2 phones in one pickup group. But here the sec shd be able to see/hear the mgr's phone ringing, so that she picks it up if mgr is away from desk etc.
3. Mgr's phone can be fwded to sec's phone using CFNA setting equivalent to 3 ring duration. So that if mgr doesnt answer call for 3 rings, call gets diverted to sec's phone.
Please refere CUCM Feature & Services guide for these.
GP.
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Ok, I will clear myself with the following example :
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int a;
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b) In case 2, we have a non-static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a. However, since obj1.a and obj2.a are the same, thus we will indeed obtain sychronisation.
Kindly correct me I am wrong anywhere in the above.
c) In case 3, we have a static function , synchronized on a non-static object. However, Java does not allow functions of this type, so we may safely move forward.
d) In case 4, we have a static function, synchronized on a static object.
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First, Kindly correct me I am wrong anywhere in the above.
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Or am I being dumb ?
Looking forward to replies..
Ashutosh

a) In case 1, we have a non-static function, synchronized on a non-static object. Thus, effectively, there is no-synchronisationThere is no synchronization between distinct First objects, but that's what you specified. Apart from the coding bug noted below, there would be synchronization between different threads using the same instance of First.
b) In case 2, we have a non-static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.obj1/2 don't call methods or try to obtain locks. The two different threads do that. And you mean First.b, not obj1.b and obj2.b, but see also below.
d) In case 4, we have a static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.Again, obj1/2 don't call methods or try to obtain locks. The two different threads do that. And again, you mean First.b. obj1.b and obj2.b are the same as First.b. Does that make it clearer?
Now, I have a query : what happens if the call is made in a classically static manner, i.e. using the statement "First.func_four;".That's what happens in any case whether you write obj1.func_four(), obj2.func)four(), or First.func_four(). All these are identical when func_four(0 is static.
Now, consider this, suppose we have the same reference obj1, in two threads, and the call "obj1.func_four;" happens to occur at the same time from each of these threads. Thus, we have obj1 rying to obtain lock for obj1.aNo we don't, we have a thread trying to obtain the lock on First.b.
and again obj1 trying to obtain lock for obj1.aYou mean obj2 and First.b, but obj2 doesn't obtain the lock, the thread does.
which are the same locks. So, if obj1.a of the first thread obtains the lock, then it will enter the function no-doubt, but the call from the second thread will also succeed.Of course it won't. Your reasoning here makes zero sense..Once First.b is locked it is locked. End of story.
Thus, effectively, our synchronisation is broken.No it isn't. The second thread will wait on the same First.b object that the first thread has locked.
However in any case you have a much bigger problem here. You're autoboxing your local 'int' variable to a possibly brand-new Integer object every call, so there may be no synchronization at all.
You need:
Object a = new Object();
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