Query to find no of peoples with the same age(using distinct)

query to find no of peoples with the same age(using distinct)
Edited by: swordfish3 on Mar 7, 2009 9:24 PM

it would be helpful if you posted some proper sample data with proper expected results.
The easier you make it for us to help you, the more likely you will get helped.

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id      number primary key,
name      varchar2(100));
-- child table
CREATE TABLE employee (
id          number primary key,
name      varchar2(100));
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manager_id          NUMBER,
employee_id      NUMBER,
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CONSTRAINT manager_fk FOREIGN KEY (manager_id) REFERENCES manager(id),
CONSTRAINT employee_fk FOREIGN KEY (employee_id) REFERENCES employee(id)
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INSERT INTO manager (id, name) VALUES (2, 'Bob');
INSERT INTO manager (id, name) VALUES (3, 'Mary');
INSERT INTO manager (id, name) VALUES (4, 'Sue');
INSERT INTO manager (id, name) VALUES (5, 'Alan');
INSERT INTO manager (id, name) VALUES (6, 'Mike');
-- Insert some employees
INSERT INTO employee (id, name) VALUES (101, 'Paul');
INSERT INTO employee (id, name) VALUES (102, 'Simon');
INSERT INTO employee (id, name) VALUES (103, 'Ken');
INSERT INTO employee (id, name) VALUES (104, 'Kevin');
INSERT INTO employee (id, name) VALUES (105, 'Jack');
INSERT INTO employee (id, name) VALUES (106, 'Jennifer');
INSERT INTO employee (id, name) VALUES (107, 'Tim');
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INSERT INTO join_table (manager_id, employee_id) VALUES (1, 101);
INSERT INTO join_table (manager_id, employee_id) VALUES (1, 102);
INSERT INTO join_table (manager_id, employee_id) VALUES (1, 103);
-- Bob manages Paul, Simon, Kevin, Jack
INSERT INTO join_table (manager_id, employee_id) VALUES (2, 101);
INSERT INTO join_table (manager_id, employee_id) VALUES (2, 102);
INSERT INTO join_table (manager_id, employee_id) VALUES (2, 104);
INSERT INTO join_table (manager_id, employee_id) VALUES (2, 105);
-- Mary manages Jennifer, Tim
INSERT INTO join_table (manager_id, employee_id) VALUES (3, 106);
INSERT INTO join_table (manager_id, employee_id) VALUES (3, 107);
-- Sue manages Jennifer, Tim
INSERT INTO join_table (manager_id, employee_id) VALUES (4, 106);
INSERT INTO join_table (manager_id, employee_id) VALUES (4, 107);
-- Alan manages Paul, Simon, Ken, Jennifer, Tim
INSERT INTO join_table (manager_id, employee_id) VALUES (5, 101);
INSERT INTO join_table (manager_id, employee_id) VALUES (5, 102);
INSERT INTO join_table (manager_id, employee_id) VALUES (5, 103);
INSERT INTO join_table (manager_id, employee_id) VALUES (5, 106);
INSERT INTO join_table (manager_id, employee_id) VALUES (5, 107);
-- Mike manages Paul, Simon, Ken
INSERT INTO join_table (manager_id, employee_id) VALUES (6, 101);
INSERT INTO join_table (manager_id, employee_id) VALUES (6, 102);
INSERT INTO join_table (manager_id, employee_id) VALUES (6, 103);
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CREATE UNIQUE INDEX employee_name_uidx ON employee(name);So if I'm querying for manager John, I want to find the other managers who manage the exact same list of employees.
Answer should be Mike.
If I'm querying for manager Mary, answer should be Sue.
This query will give me the list of managers who manage some of the same employees as John, but not the exact same employees...
SELECT DISTINCT m.name AS manager
FROM manager m, join_table jt, employee e
WHERE m.id = jt.manager_id
AND jt.employee_id = e.id
AND e.id IN (
     SELECT e.id
     FROM manager m, join_table jt, employee e
     WHERE m.id = jt.manager_id
     AND jt.employee_id = e.id
     AND m.name = 'John')
ORDER BY 1;I thought about using set operations to find managers whose list of employees minus my employees is null and where my employees minus their list of employees is null. But surely there's a simpler more elegant way.
Any ideas?
Btw, I need to run this as a batch job against tables with >20 million rows so query efficiency is key.

What about...
WITH manager_list AS
SELECT name,
        LTRIM(MAX(SYS_CONNECT_BY_PATH(id,','))
        KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
FROM   (SELECT m.name,
                e.id,
                ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr,
                ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev
         FROM   manager m,
                join_table jt,
                employee e
WHERE m.id           = jt.manager_id
AND   jt.employee_id = e.id
AND   m.name = :P_MANAGER)
GROUP BY name
CONNECT BY prev = PRIOR curr AND name = PRIOR name
START WITH curr = 1
), all_list AS
SELECT name,
        LTRIM(MAX(SYS_CONNECT_BY_PATH(id,','))
        KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
FROM   (SELECT m.name,
                e.id,
                ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr,
                ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev
         FROM   manager m,
                join_table jt,
                employee e
WHERE m.id           = jt.manager_id
AND   jt.employee_id = e.id)
GROUP BY name
CONNECT BY prev = PRIOR curr AND name = PRIOR name
START WITH curr = 1
SELECT a.*
FROM   manager_list m,
       all_list a
WHERE m.employees = a.employeesWould be easier in 11g, but I don't have an installation here so this is based on 10g.
Cheers
Ben

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Query to find no of peoples with the same age(using distinct)

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