Query to find the top ranked student in each class ?? table given
i/p table:
studentid classid marks
1 1 400
2 1 500
3 2 600
4 2 700
5 3 800
6 3 900
o/p table :
studentid classid marks
2 1 500
4 2 700
6 3 900
You dump your homework in a forum of volunteers without even trying to resolve it, and now you start flaming in your very first thread?
Please find assistance elsewhere, where they are more tolerant to the lazy-ones.
Sybrand Bakker
Senior Oracle DBA
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From iPhone Apps Store I could go to each category and find the top 300 games, how could I find the top iPad games in each category in iPad Apps Store? Thanks!
i downloaded it already but it should have the iTunes U App in my homepage as a shortcut. now, it doesn't have this icon in my apps pages. when i need to use it, i have to open the App store and search it out every time. For example, after downloaded the Facebook App, it would have a FB App in my homepage. my Question is I DON'T HAVE THE ITUNES U App IN MY HOMEPAGE NOW. T___T do you have any method to get it in my homepage.
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Query to find the latest two transactions for each Group
Hi All,
Consider the following sets of records in a table test.
Group---Tran_Dt---SlNo
c1 10/10/2003 1
c1 10/10/2003 2
c1 10/10/2003 3
c1 11/10/2003 1
c2 10/10/2003 1
c2 10/10/2003 2
c2 11/10/2003 1
c2 11/10/2003 2
c2 11/10/2003 3
c3 10/10/2003 1
c3 10/10/2003 2
c3 10/10/2003 3
I want to list out the latest two transactions for each group irrespective of the slno and trans_dt as below:
group tran_dt SlNo
c1 11/10/2003 1
c1 10/10/2003 3
c2 11/10/2003 3
c2 11/10/2003 2
c3 10/10/2003 3
c3 10/10/2003 2
Any help on this would be appreciated.
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Walter Nicholas THi Walter,
Please try following query.
select Group,tran_dt,sino from
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) where rank between 1 and 2
Thanks,
Samir -
Query to find the no of columns in a table
Is there a query to find the total number of columns in a table?
Dou you know read?
-- the number of rows in a table named yourtable:
select count(1) from yourtable;
-- the number of columns in a table
-- If is a user's table:
select count(1)
from user_tab_columns
where table_name='YOURTABLE'
--If it is´t
select count(1)
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Query to find the class name that has the maximum number of students ?
I need the query to find the [class Name] which has the most number of students. please look below at the tables
Students Table
StudentId StudentName ClassID
1 xxx 1
2 yyy 1
3 zzz 1
4 fff 2
5 ttt 2
Classes Table
ClassID ClassNane
1 CSHARP
2 JSHARP
The result should be : CSHARP
since there are 3 students in CSHARP and 2 students in JSHARP class
Appreciate your help
ThanksTry:
DECLARE @Classes TABLE (
ClassID INT identity(1, 1) PRIMARY KEY
,ClassName VARCHAR(50)
INSERT INTO @Classes (ClassName)
VALUES ('CSharp')
,('JSharp')
DECLARE @Students TABLE (
StudentID INT identity(1, 1) PRIMARY KEY
,StudentName VARCHAR(10)
,ClassID INT
INSERT INTO @Students (
StudentName
,ClassID
VALUES (
'xxx'
,1
'yyy'
,1
'zzz'
,1
'fff'
,2
'ttt'
,2
SELECT TOP (1)
WITH TIES C.ClassName
FROM @Classes C
INNER JOIN @Students S ON C.ClassID = S.ClassID
GROUP BY C.ClassID
,C.ClassName
ORDER BY COUNT(S.StudentID) DESC
For every expert, there is an equal and opposite expert. - Becker's Law
My blog
My TechNet articles -
Connect by - find the top level by pasing in any other level
I have a connect by loop.
select parent,
child
from parentchild
start with parent = :passed_in_parameter
connect by nocycle prior child = parentThis works fine but i have an addiitional requirement to find the top level of this tree. By passing in any other level.
i.e.
if i have data as follows:
parent child
1 2
2 3
3 4
4
hierachy
1
2
3
4
Then I need my query to always give me the value 1 (top level) even if i pass in 1, 2, 3 or 4.
Hope this makes sense
ThanksHi,
ngac_auk wrote:
... Im trying to prevent a continous loop problem (connect by error) by checking the entire tree (as there can be as many levels as they require) for the entry the user is trying to sabe and if the entry exists then prevent them from adding the new parent child entry.
I thought the best way to do this is by first establishing the top level of the tree (hence my original question) then use another query passing the top level in, to ensure the new entry they want to put in does not already exist.
Is this the best way of doing what i reauire or can people think of a better solution?If there is a loop, then it isn't a tree, and there won't be a top. That's exactly what a loop means: every member of the loop is the ancestor (and descendant) of every member.
Sorry, I don't know enough (yet) about your application to answer your question.
Whenever you have a question, post a little sample data, and the results you want from that data.
In the case of a DML question (like this one: how to prevent DML that causes a loop) post some INSERT statements that show the table without any problems.
For the results, post a series of DML statements (INSERT, UPDATE and or DELETE) to be executed in order, and say whether you want each one to fail or not, and why.
Make sure your sample data resembles your real data. For example, if your real table allows children to have more than one parent, make sure your sample data has an example of that.
There's no need to post a lot of data. If your real trees can go to 50 levels deep, you can post a tree that only goes 3 or 4 levels, and just explain that they can actually go deeper. -
How to find the top ten reports consuming the high response times in st03n?
HI Basis Gurus,
Please could anybody tell me "How can one find the top ten high response time consuming reports in st03n transaction or in is there any other way to find out this.Please help me its urgent....
Advance thanks....hi Meghadoot,
below is an example for your request.
ST03N
Expert mode
Server name - Day- double clicdk Today
In analysis view - Ranking lists-double click Top Response time
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Query to find the list of users having access to a particular scenario
Hi,
I am learning Hyperion Planning 9.2 x version. I wanted to know the query to find the list of users having access to Plan Iteration - 1 scenarion.
As I am new to Hyperion Essbase and Hyperion Planning, I am assuming these ideas work out to get the desired result.
1) As Hyperion Planning uses Relational DB to store the User Security information, we can query the list of users who is having access to Plan Iteration - 1 Scenario.
I am not sure if this solution works. Please correct me If I am wrong.
2) We can also query from the essbase editor to find out who all having access to this scenario.
If the above is correct, can you please provide me the query.
I am really need of this and I will be happy if any one provide the solution.
Thanks & Regards,
Upendra. BesthaHi,
If you are looking for some SQL to retrieve the access rights by member then you can use something like (SQL Server code though can easily be modified for Oracle)
SELECT usr.object_name as Username,mem.object_name as Member,
'Access Rights' = CASE acc.access_mode
WHEN -1 THEN 'None'
WHEN 1 THEN 'Read'
WHEN 2 THEN 'Write'
WHEN 3 THEN 'Write'
ELSE 'Unknown' END,
'Relation' = CASE acc.flags
WHEN 0 THEN 'Member'
WHEN 5 THEN 'Children'
WHEN 6 THEN 'Children (inclusive)'
WHEN 8 THEN 'Descendants'
WHEN 9 THEN 'Descendants (inclusive)'
ELSE 'Unknown' END
FROM
hsp_access_control acc, hsp_object mem, hsp_object usr
WHERE acc.object_id = mem.object_id
AND acc.user_id = usr.object_id
AND mem.object_name = 'Plan Iteration - 1'
Cheers
John
http://john-goodwin.blogspot.com/ -
Query to find the memory of database in oracle,sql
Hi All,
Please let me know the query to find the memory of database in oracle,sql.
Thanks,
sajithHow do I find the overall database size?
The biggest portion of a database's size comes from the datafiles. To find out how many megabytes are allocated to ALL datafiles:
select sum(bytes)/1024/1024 "Meg" from dba_data_files;
To get the size of all TEMP files:
select nvl(sum(bytes),0)/1024/1024 "Meg" from dba_temp_files;
To get the size of the on-line redo-logs:
select sum(bytes)/1024/1024 "Meg" from sys.v_$log;
Putting it all together into a single query:
select a.data_size+b.temp_size+c.redo_size "total_size"
from ( select sum(bytes) data_size
from dba_data_files ) a,
( select nvl(sum(bytes),0) temp_size
from dba_temp_files ) b,
( select sum(bytes) redo_size
from sys.v_$log ) c;
Another query ("Free space" reports data files free space):
col "Database Size" format a20
col "Free space" format a20
select round(sum(used.bytes) / 1024 / 1024 ) || ' MB' "Database Size"
, round(free.p / 1024 / 1024) || ' MB' "Free space"
from (select bytes from v$datafile
union all
select bytes from v$tempfile
union all
select bytes from v$log) used
, (select sum(bytes) as p from dba_free_space) free
group by free.p
This is what I use :P From http://www.orafaq.com/wiki/Oracle_database_FAQ#How_do_I_find_the_overall_database_size.3F -
Query to find the latest record with respect to the current status
Dear gurus
I have the following data in a table
Customernum
bkcode
reqtdate
Prevstat
currstat
The data will be like this
CustomerNum bkcode reqdate prevstat currstat
5900 1 03-Aug-12 0 1
5900 1 06-Aug-12 1 0
5900 5 22-Jun-12 0 1
If a customer has an issue to solved, a record is added with bkcode , register date and currstat will be 1
If the issue is resolved for the bookingcode,a new record is added, the currentstatus will become 0. and prev stat will show 1. Row no 1 and 2 reflects this case
If this table is queried for finding the unresolved issues. the output should be only the Last row of the above example. since issue with bookingcode 1 has been resolved
I have trying hard to get this thing confused what to use Lead or Max
Kindly guide meHi,
one way here:
WITH mytable(CustomerNum, bkcode, reqdate, prevstat, currstat)
AS
SELECT 5900, 1, TO_DATE('03-Aug-12', 'DD-Mon-YY'), 0, 1 FROM DUAL UNION ALL
SELECT 5900, 1, TO_DATE('06-Aug-12', 'DD-Mon-YY'), 1, 0 FROM DUAL UNION ALL
SELECT 5900, 5, TO_DATE('22-Jun-12', 'DD-Mon-YY'), 0, 1 FROM DUAL
SELECT CustomerNum, bkcode, reqdate, prevstat, currstat
FROM (SELECT a.*
, ROW_NUMBER() OVER (PARTITION BY CustomerNum, bkcode
ORDER BY reqdate DESC) AS rn
FROM mytable a
WHERE rn=1
AND currstat=1;
CUSTOMERNUM BKCODE REQDATE PREVSTAT CURRSTAT
5900 5 22-JUN-12 0 1Regards.
Al
Edited by: Alberto Faenza on Dec 18, 2012 5:23 PM
Changed again!! Previous logic was wrong -
Query to find the Salary table details HRMS 11i
I am looking query to find the persons salary details in Oralce EBS 11i.
I tried the below query bu it didn'ty work.
SELECT papf.employee_number
,papf.full_name
,pj.NAME job
,haou.NAME ORGANIZATION
,ppp.proposed_salary_n salary
FROM per_all_people_f papf
,per_all_assignments_f paaf
,per_jobs pj
,hr_all_organization_units haou
,per_position_definitions ppd
,per_all_positions pap
,per_pay_proposals ppp
WHERE 1 = 1
AND SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date
AND papf.current_employee_flag = 'Y'
AND papf.employee_number IS NOT NULL
AND paaf.person_id = papf.person_id
AND SYSDATE BETWEEN paaf.effective_start_date AND paaf.effective_end_date
AND paaf.job_id = pj.job_id
AND paaf.organization_id = haou.organization_id
AND paaf.position_id = pap.position_id
AND pap.position_definition_id = ppd.position_definition_id
AND ppp.pay_proposal_id = (SELECT MAX (pay_proposal_id)
FROM per_pay_proposals
WHERE assignment_id = paaf.assignment_id)
In our case all the below tables have 0 records..
select count(*) from PER_PAY_PROPOSALS ;
COUNT(*)
0
select count(*) from pay_element_entry_values_f;
COUNT(*)
0
select count(*) from PAY_ELEMENT_ENTRY_VALUES_F;
COUNT(*)
0
select count(*) from PAY_ELEMENT_ENTRIES_F;
COUNT(*)
0Hi,
Your results clearly states that there is no salary data which is been captured as well as there are no element entries which are assigned to any assignment.
Please do the below which will insert records in salary as well as element entries table:
1. Add a salary proposal to any active employee (People Enter and Maination --> Search for any employee --> Assignment --> Salary) - This will insert a record in PER_PAY_PROPOSALS table
2. Add an element entry to any active assignment (People Enter and Maination --> Search for any employee --> Assignment --> Entries) - This will insert a record in PAY_ELEMENT_ENTRIES_F and PAY_ELEMENT_ENTRY_VALUES_F table
Hope this clarifies.
Thanks,
Sanjay -
Query to find the second maximum date in a table
please give me the query to find the second maximum date in a table
You can try with this
SELECT empno
,hiredate
FROM emp a
WHERE 2 = (SELECT COUNT(DISTINCT hiredate)
FROM emp b
WHERE b.hiredate >= a.hiredate
OR
SELECT empno
,hiredate
FROM (SELECT ROWNUM row_num
,empno
,hiredate
FROM emp a
ORDER BY hiredate ASC
WHERE row_num = 2;Regards
Arun -
Sql query to find the space in between the sentense
hi,
can anybody tell me the query to find the space in between the data
chandanNot sure what you mean, but you might want to take a look at INSTR, like in
instr (txt, ' ') -
Sql query to find the balances for a customer account wise.
Hi,
Could someone help me with the sql query to find the balances for each customer account wise. This is need to generate the report.
presently we are using this query, but the output doesnot return the expected result.
SELECT sum(nvl(ps.acctd_amount_due_remaining,0)) "Balance"
FROM ra_cust_trx_line_gl_dist_all gld,
gl_code_combinations c,
ar_payment_schedules_all ps,
RA_CUSTOMER_TRX_ALL rat,
ra_customers rc
WHERE c.CHART_OF_ACCOUNTS_ID = 101
and gld.code_combination_id = c.code_combination_id
and rat.CUSTOMER_TRX_ID=gld.CUSTOMER_TRX_ID
and rat.CUSTOMER_TRX_ID=ps.CUSTOMER_TRX_ID
and ps.customer_id=rc.customer_id
and ps.status='OP'
and ps.gl_date <= :PDATE
and ps.org_id=:PORGID
and ps.class in ('GUAR','INV','DM','DEP')
and c.SEGMENT4=:Account_id
and ps.customer_id=:Customer_id
Thanks in advance.
Kalyan.Can someone help us with this.
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Can anybody provide the SQL query to find the files uploaded in a particular folder?
Hi All,
Can anybody provide the SQL query to find the documents (document name) uploaded in a particular folder? While clicking on folder in
GUI I'm hitting the Timeout error. I would like to find the files uploaded into this folder from SQLPLUS.
Any help is greatly appreciated.
With best regards,
NevinNevin,
Be great if we could know the version of Portal. For Rel. 1, here's the query
select id,masterthingid from wwv_things
where siteid = &site
and cornerid = &corner
&site - Content Area id
&corner - Folder id
if you don't know the folder id, use
select id from wwv_corners where siteid = &site
and name = &folder
Hope this helps. I have run into this situation before. Usually, the culprits were
one of the following:
1. Junk Characters in description of item (caused due to Copy-Paste)
2. Special Characters in the File name
Hi All,
Can anybody provide the SQL query to find the documents (document name) uploaded in a particular folder? While clicking on folder in
GUI I'm hitting the Timeout error. I would like to find the files uploaded into this folder from SQLPLUS.
Any help is greatly appreciated.
With best regards,
Nevin
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