Rank function use in MDX

Hi Expert,
Could you please let me know how can I use rank function in MDX to achieve the result in below format. Highest value should be ranked as 1
Actual/Expected Dataset appears as:
Thanks Chandan

Hi C,
You can use the mdx RANK() function. For example, this query has ranking of cities by sales amount. You could create two sets, and two calcs with RANK() functions for your challenge.
WITH
SET OrderedCities AS Order
([Geography].[City].[City].members
, [Measures].[Reseller Sales Amount], BDESC
MEMBER [Measures].[City Rank] AS Rank
([Geography].[City].CurrentMember, OrderedCities)
SELECT {[Measures].[City Rank],[Measures].[Reseller Sales Amount],[Measures].[City Rank]} ON 0
,[Geography].[City].[City].MEMBERS
ON 1
FROM [Adventure Works]
Hope that helps,
Richard

Similar Messages

@Rank function using EVALUATE

Hi short question,
I'm trying to get the @rank function to work in combination with OBIEE 10.1.3.4 (using EVALUATE). Anyone here already tried using this with Essbase version 9.2? In some of the documentation it states this can not be done using anything below Essbase 9.3 but the @Rank function is available within v9.2 Is there any limit on using this from the OBIEE side?
I used this reference:
(how to:) http://oraclebizint.wordpress.com/2008/04/28/oracle-bi-ee-101332-handling-sort-order-in-hyperion-essbase-931-evaluate-and-mdx/
(Essbase 9.2 doc --> @Rank available) http://download.oracle.com/docs/cd/E12032_01/doc/epm.921/html_techref/techref.htm
Evaluate function I'm trying to launch is:
EVALUATE(’RANK(%1.dimension.currentmember,%2.members)’ AS INTEGER,Period."PeriodGen4",Period."PeriodGen4")
Am I doing something wrong here, or am I trying to do things which can't be done?
Thanks in advance,
Mathijs

I tried the syntax
EVALUATE ('RANK(%1,%2)' as integer,"Account"."Gen4,Account Default","Account"."Gen4,Account Default")
but still i am getting the error as:-
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 43113] Message returned from OBIS. [nQSError: 96002] Essbase Error: Syntax error in input MDX query on line 6 at token 'RANK' (HY000)
SQL Issued: SELECT s_0, s_1, s_2, s_3, s_4, s_5, s_6, s_7 FROM ( SELECT 0 s_0, "FINRPTC#1"."Account"."Gen3,Account Default" s_1, "FINRPTC#1"."Account"."Gen4,Account Default" s_2, "FINRPTC#1"."FinancialYear"."Gen2,FinancialYear" s_3, "FINRPTC#1"."Period"."Gen3,Period" s_4, EVALUATE ('RANK(%1,%2)' as integer,"FINRPTC#1"."Account"."Gen4,Account Default","Account"."Gen4,Account Default") s_5, "FINRPTC#1"."FINRPTC"."Actual" s_6, REPORT_AGGREGATE("FINRPTC#1"."FINRPTC"."Actual" BY "FINRPTC#1"."Account"."Gen3,Account Default","FINRPTC#1"."Account"."Gen4,Account Default","FINRPTC#1"."FinancialYear"."Gen2,FinancialYear","FINRPTC#1"."Period"."Gen3,Period") s_7 FROM "FINRPTC#1" WHERE (("FinancialYear"."Gen2,FinancialYear" = 'FY12') AND ("Period"."Gen3,Period" = 'Nov') AND ("Account"."Gen3,Account Default" = 'Net Cost of Services')) ) djm

Rank function used in Evaluate-aggr in RPD gives error

Hi,
In RPD, in my fact table for a logical column in BMM, I have, EVALUATE_AGGR(‘RANK() OVER (PARTITION BY %2 ORDER BY %1 DESC)’ AS INTEGER,”main”.”proj_date”,”main”.”project_id”)
but in answers when I use this as a filter and say equal to 1, I am getting the following error ‘Window Functions are not permitted’
Thanks for your time and help.

hi,
your syntax seems to be wrong not sure.Try with sum function
EVALUATE_AGGR('DB_Aggregate_Function(%1)',{comma separated Expression})
Windows functions : http://developer.postgresql.org/pgdocs/postgres/tutorial-window.html
Thanks,
saichand.v

MDX Rank function

I am having some trouble getting expected results when using the RANK function. My MDX is below with the result set that gets created.
The [SF OCC Rank] results are correct but the [Net Rentals Rank] is not. I am wanting to rank each of the measures to be able to identify which Site is ranked highest in [SF Occ %] and then which site is ranked highest in [Net Rentals].
My data has in total 43 sites. In my filter I am limiting it to the Sites in [Site Groups].[Site Group Name].&[12]. There are only 14 sites that should display. It looks like the [Net Rentals Rank] is ranking all 43 sites instead of
just the 14 that I am wanting.
Any help is greatly appreciated. Thanks!
WITH
MEMBER [Measures].[SF Occ Rank] as RANK(([Unit].[Site Name].CurrentMember),ORDER(([Unit].[Site Name].[Site Name].Members),[Measures].[SF Occ %], BDESC))
MEMBER [Measures].[Net Rentals Rank] as RANK(([Unit].[Site Name].CurrentMember),ORDER(([Unit].[Site Name].[Site Name].Members),[Measures].[Net Rentals], BDESC))
select {[Measures].[SF OCC %],[Measures].[SF Occ Rank],
           [Measures].[Net Rentals], [Measures].[Net Rentals Rank]} on COLUMNS,
    filter( [Unit].[Site Name].[Site Name].Members,[Site Groups].[Site Group Name].&[12]) on ROWS
from [CUBE]
where ( [Date].[Calendar].[Month of Year].&[201412],[Site Groups].[Site Group Name].&[12])

Hi rocko,
You are correct the Net Rentals Rank will be calculated for all the Sites and will display the result for the current Sites being selected. Do some changes to the query so that you will get the ranks for only the sites you selected.
WITH
MEMBER [Measures].[SF Occ Rank] as RANK(([Unit].[Site Name].CurrentMember),ORDER(([Unit].[Site Name].[Site Name].Members),[Measures].[SF Occ %], BDESC))
MEMBER [Measures].[Net Rentals Rank] as RANK([Unit].[Site Name].CurrentMember,ORDER( Exists( [Unit].[Site Name].[Site Name].Members,[Site Groups].[Site Group Name].&[12]),[Measures].[Net Rentals], BDESC))
select {[Measures].[SF OCC %],[Measures].[SF Occ Rank],
           [Measures].[Net Rentals], [Measures].[Net Rentals Rank]} on COLUMNS,
    Exists( [Unit].[Site Name].[Site Name].Members,[Site Groups].[Site Group Name].&[12]) on ROWS
from [CUBE]
where ( [Date].[Calendar].[Month of Year].&[201412],[Site Groups].[Site Group Name].&[12])
Regards,
Venkata Koppula

How to use "Rank" function in Oracle?

I need to display Top 15 records by using rank function.
Here is my query...I need to pull top 15 FAQ's using the below query.. How can I use RANK function to display the Top 15 FAQ"s in the list.
Select distinct SUb1.FAQ,Sub1.FAQ_Hits,GU.display_Name_FMLS as displayname,ev.ParentLinkrecordid,ev.userid from User GU
Join Event ev
ON LOWER (ev.userid) IN (LOWER (GU.lanid), LOWER (Gu.racfid))
Join (Select distinct sm.stem as FAQ,Sum(ev.Eventresults) as FAQ_Hits,ev.ParentLinkrecordid as Topic_ID from Event ev
Join SubjectMatter sm
ON (TO_CHAR (sm.smrecordid) = ev.eventdetail1) AND ev.eventdetail1 IS NOT NULL AND sm.smtype = 1
Where (Upper(ev.eventsubtype) in (Upper('FAQ'),Upper('OPENFAQ')))
AND TO_DATE (eventdatetime, 'yyyy-mm-dd hh24:mi:ss') >= TO_DATE ('20100601', 'yyyymmdd')
and TO_DATE (eventdatetime, 'yyyy-mm-dd hh24:mi:ss') <= TO_DATE ('20100831', 'yyyymmdd')
Group by sm.stem,ev.Parentlinkrecordid
order by FAQ )sub1
ON Sub1.Topic_ID = ev.ParentLinkrecordid)

A few bits that I noticed in the query ...
in (Upper('FAQ'),Upper('OPENFAQ'))1) Do you really a upper for a string which is already in upper case.
Select distinct sm.stem as FAQ,Sum(ev.Eventresults) as FAQ_Hits,ev.ParentLinkrecordid as Topic_ID2) Do you need a distinct when you are using a GROUP function viz. SUM ?
You rank query is as follows, I am not very good at the ANSI style JOIN so changed it slightly ... :-)
Also notice the usage rank function in the "sub1" query.
select distinct sub1.faq,
 sub1.faq_hits,
 gu.display_name_fmls as displayname,
 ev.parentlinkrecordid,
 ev.userid
from user gu, event ev,
(select rank() over (order by sum(ev.eventresults) desc) rnk,
 sum(ev.eventresults) as faq_hits,
 sm.stem as faq,
 ev.parentlinkrecordid as topic_id
 from event ev, subjectmatter sm
 where (to_char(sm.smrecordid) = ev.eventdetail1)
 and ev.eventdetail1 is not null
 and sm.smtype = 1
 AND upper(ev.eventsubtype) in ('FAQ', 'OPENFAQ')
 and to_date(eventdatetime, 'yyyy-mm-dd hh24:mi:ss') >= to_date('20100601', 'yyyymmdd')
 and to_date(eventdatetime, 'yyyy-mm-dd hh24:mi:ss') <= to_date('20100831', 'yyyymmdd')
 group by sm.stem, ev.parentlinkrecordid
 order by faq) sub1
where lower(ev.userid) in (lower(gu.lanid), lower(gu.racfid))
and sub1.topic_id = ev.parentlinkrecordid)
and sub1.rnk <= 15;Like mentioned above, some sample data would have helped.

Prob in using rank in pl/sql ,need logic same of rank function in any way

I have a query as of the following 
 
SELECT sr_no,cod_acct_no,dat_arrears_due,amt_arrear_due 
FROM ( select cod_acct_no,dat_arrears_due,sum(amt_arrears_due) amt_arrear_due,rank() over (partition by cod_acct_no order by dat_arrears_due asc) sr_no 
 from arrears_table 
 where amt_arrears_due > 0 
and dat_arrears_due <= to_date('31/10/2006','dd/mm/yyyy') 
and COD_ARREAR_TYPE = 'C' 
 group by cod_acct_no,dat_arrears_due 
 ) Z 
WHERE z.sr_no <=5 
 
I have to use this in a cursor in pl/sql but because i have rank analytic function 
I am facing a compilation error ORA-06550: error 
 
Can you give me a logic which gives same output as of above 
 
Regards 
vamsi krishna 
 
 

[1]: (Error): ORA-06550: line 5, column 28: PLS-00103: Encountered the symbol "(" when expecting one of the following: , from 
 
My oracle version is 
Oracle8i Enterprise Edition Release 8.1.6.0.0 - Production 
PL/SQL Release 8.1.6.0.0 - Production 
CORE 8.1.6.0.0 Production 
TNS for 32-bit Windows: Version 8.1.6.0.0 - Production 
NLSRTL Version 3.4.1.0.0 - Production 
 I think it is comming for rank function it self 
 will this version support analytic (rank) function's in pl/sql cursors 
Regards 
vamsi krishna

How to use RANK function ?

Hello everyone,
here is the query I run in sql developer using RANKFunction.
SELECT Empno, Ename, Job, Mgr, Hiredate, Sal
FROM
(SELECT Empno, Ename, Job, Mgr, Hiredate, Sal,
*RANK*() OVER
(ORDER BY SAL Desc NULLS LAST) AS Emp_Rank
FROM Emp
ORDER BY SAL Desc NULLS LAST)
WHERE Emp_Rank < 6;How I can use this query in my report in obiee or is there any replacement of RANK() function in obiee so that I can use that to get my same above result.
Thanks

Kuldip wrote:
Thanks, you are absolutely correct. However, By doing this I am getting my output as whic I was not expecting.
Students Marks Rank
student1 95 1
student2 95 1
student3 93 3
student4 93 3
student5 91 5
The output should be as instead
Students Marks Rank
student1 95 1
student2 95 1
student3 93 2
student4 93 2
student5 91 3
Can It be done like this ?
Thanks.
Edited by: Kuldip on Mar 15, 2012 11:51 PMHi Boss,
I think you copied the above scenario from this site..
http://oracle-bi.siebelunleashed.com/articles/rank-and-dense-rank-functionsobiee/
Then why asking how to do this? Are you testing us? Doesn't that site say how to achieve this?

Sql tuning using rank function

Hi,
Can someone help me in writing the below qry using rank() function?
DELETE FROM stc_calllog_ext a
WHERE a.stc_save_status = 'CT'
AND ROWID IN (SELECT a.ROWID
FROM stc_calllog_ext a, calllog_ext b
WHERE a.prod_line_code= b.prod_line_code
AND a.brand_code = b.brand_code
AND a.model_number = b.model_number
AND a.stc_save_status != b.stc_save_status
AND trunc(a.stc_start_time) = trunc(b.stc_start_time)
AND a.stc_start_time BETWEEN TRUNC(SYSDATE-8) AND TRUNC(SYSDATE)
AND a.call_taker_userid = b.call_taker_userid
AND a.cons_telephone_no =b.cons_telephone_no
)

With the information you have provided, I've come up with the following.
SELECT A.ACCOUNT_NO, A.PAYMENT_TYPE, A.INSTALLMENT_TYPE, A.DATE_CHANGE
FROM
 (SELECT account_no, payment_type, installment_type, date_change,
 LEAD( (payment_type), 1)
 over (partition by account_no order by account_no, DATE_CHANGE) LEAD_PAY,
 LEAD( (installment_type), 1)
 over (partition by account_no order by account_no, DATE_CHANGE) LEAD_INST
 from T_ACCNTS ) A
WHERE A.PAYMENT_TYPE <> NVL(A.LEAD_PAY,99)
 OR A.INSTALLMENT_TYPE <> NVL(A.LEAD_INST,99)
ORDER BY 1, 4;

Error using Rank function in Answers

Hi All,
Am trying to generate a report in Answers which lists Top Accounts with Revenue.
I Ranked the Revenue field and it is returning me correct values. ( Rank(account.revenue) )
But, when I try to filter on this field and restrict the rows which shows only top 10 Accounts, it is returning the following error:
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 17001] Oracle Error code: 1792, message: ORA-01792: maximum number of columns in a table or view is 1000 at OCI call OCIStmtExecute. [nQSError: 17010] SQL statement preparation failed. (HY000)
Can any one help me on this.
Thanks in Advance,
Imtiaz.

Hi Joe,
This is the Physical query generated when I use Rank function and the report is fine.
select distinct D1.c1 as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c4 as c4,
D1.c5 as c5,
D1.c6 as c6,
D1.c7 as c7,
D1.c8 as c8,
D1.c9 as c9,
D1.c10 as c10,
D1.c11 as c11,
D1.c12 as c12,
D1.c13 as c13,
D1.c14 as c14,
D1.c15 as c15
from
(select D1.c1 as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c4 as c4,
D1.c5 as c5,
D1.c6 as c6,
D1.c7 as c7,
D1.c8 as c8,
D1.c9 as c9,
D1.c10 as c10,
D1.c11 as c11,
D1.c12 as c12,
D1.c13 as c13,
D1.c14 as c14,
D1.c15 as c15
from
(select Case when D1.c1 is not null then Rank() OVER ( ORDER BY D1.c1 DESC NULLS LAST ) end as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c1 as c4,
D1.c4 as c5,
D1.c5 as c6,
D1.c6 as c7,
D1.c7 as c8,
D1.c8 as c9,
D1.c9 as c10,
D1.c10 as c11,
D1.c11 as c12,
D1.c12 as c13,
D1.c13 as c14,
D1.c14 as c15,
ROW_NUMBER() OVER (PARTITION BY D1.c1, D1.c2, D1.c3, D1.c4, D1.c5, D1.c6, D1.c7, D1.c8, D1.c9, D1.c10, D1.c11, D1.c12, D1.c13, D1.c14 ORDER BY D1.c1 ASC, D1.c2 ASC, D1.c3 ASC, D1.c4 ASC, D1.c5 ASC, D1.c6 ASC, D1.c7 ASC, D1.c8 ASC, D1.c9 ASC, D1.c10 ASC, D1.c11 ASC, D1.c12 ASC, D1.c13 ASC, D1.c14 ASC) as c16
from
(select distinct T690.SUM_REVN_AMT as c1,
T690.NAME as c2,
T2216.NAME as c3,
T690.X_PETROFAC_REVN as c4,
T690.SUM_WIN_PROB as c5,
T690.X_PERCENT_GET as c6,
T690.SUM_WIN_PROB * T690.X_PERCENT_GET / nullif( 100, 0) as c7,
T690.X_EC_PRIORITY as c8,
T19028.LOGIN as c9,
T690.X_COUNTRY as c10,
T690.X_REGION as c11,
T18311.NAME as c12,
T18641.NAME as c13,
T18238.NAME as c14
from
SIEBEL.S_BU T18238 left outer join (
SIEBEL.S_USER T19028 left outer join (
SIEBEL.S_OPTY T690 left outer join SIEBEL.S_STG T2216 On T690.CURR_STG_ID = T2216.ROW_ID) left outer join SIEBEL.S_ORG_EXT T1189 On T690.PR_DEPT_OU_ID = T1189.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18311 /* Competitor */ On T690.PR_CMPT_OU_ID = T18311.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18641 /* Partner */ On T690.PR_PRTNR_ID = T18641.ROW_ID) left outer join SIEBEL.S_POSTN T19114 On T690.PR_POSTN_ID = T19114.PAR_ROW_ID) left outer join SIEBEL.S_OPTY_BU T18280 On T690.ROW_ID = T18280.OPTY_ID) left outer join SIEBEL.S_OPTY_X T19415 On T690.ROW_ID = T19415.PAR_ROW_ID) On T19028.PAR_ROW_ID = T19114.PR_EMP_ID) On T18238.ROW_ID = T18280.BU_ID
) D1
) D1
where ( D1.c16 = 1 )
) D1
order by c1 desc
But When I apply Filter on this Rank column then it gives me the error. THis is the Physical query for that
select distinct Case when D1.c1 is not null then Rank() OVER ( ORDER BY D1.c1 DESC NULLS LAST ) end as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c1 as c4,
D1.c4 as c5,
D1.c5 as c6,
D1.c6 as c7,
D1.c7 as c8,
D1.c8 as c9,
D1.c9 as c10,
D1.c10 as c11,
D1.c11 as c12,
D1.c12 as c13,
D1.c13 as c14,
D1.c14 as c15
from
(select D1.c1 as c1,
D1.c2 as c2,
D1.c3 as c3,
D1.c4 as c4,
D1.c5 as c5,
D1.c6 as c6,
D1.c7 as c7,
D1.c8 as c8,
D1.c9 as c9,
D1.c10 as c10,
D1.c11 as c11,
D1.c12 as c12,
D1.c13 as c13,
D1.c14 as c14
from
(select T690.SUM_REVN_AMT as c1,
T690.NAME as c2,
T2216.NAME as c3,
T690.X_PETROFAC_REVN as c4,
T690.SUM_WIN_PROB as c5,
T690.X_PERCENT_GET as c6,
T690.SUM_WIN_PROB * T690.X_PERCENT_GET / nullif( 100, 0) as c7,
T690.X_EC_PRIORITY as c8,
T19028.LOGIN as c9,
T690.X_COUNTRY as c10,
T690.X_REGION as c11,
T18311.NAME as c12,
T18641.NAME as c13,
T18238.NAME as c14,
Case when T690.SUM_REVN_AMT is not null then Rank() OVER ( ORDER BY T690.SUM_REVN_AMT DESC NULLS LAST ) end as c15
from
SIEBEL.S_BU T18238 left outer join (
SIEBEL.S_USER T19028 left outer join (
SIEBEL.S_OPTY T690 left outer join SIEBEL.S_STG T2216 On T690.CURR_STG_ID = T2216.ROW_ID) left outer join SIEBEL.S_ORG_EXT T1189 On T690.PR_DEPT_OU_ID = T1189.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18311 /* Competitor */ On T690.PR_CMPT_OU_ID = T18311.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18641 /* Partner */ On T690.PR_PRTNR_ID = T18641.ROW_ID) left outer join SIEBEL.S_POSTN T19114 On T690.PR_POSTN_ID = T19114.PAR_ROW_ID) left outer join SIEBEL.S_OPTY_BU T18280 On T690.ROW_ID = T18280.OPTY_ID) left outer join SIEBEL.S_OPTY_X T19415 On T690.ROW_ID = T19415.PAR_ROW_ID) On T19028.PAR_ROW_ID = T19114.PR_EMP_ID) On T18238.ROW_ID = T18280.BU_ID
) D1
where ( D1.c15 <= 10 )
) D1
order by c2, c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15
Thanks,
Imtiaz

[Essbase] - using TopCount MDX function

Hi,
I would like to use the TopCount MDX function in an ASO cube.
I did manage to write the MDX query but did not find how to "convert" it as a MDX formula on the "MEASURE" dimension (well I am guessing).
I thank you for your help!
Thomas
MDX query :
IND_HITS is from the MEASURE dimension
A2008 is from the YEAR dimension
M1013210 is from the MESSAGE dimension
SELECT
[MOIS].Generations(1).Members
ON COLUMNS,
TopCount([USERS].Children,10, [IND_HITS] )
ON ROWS
FROM Cube_Log.Cube_Log
WHERE ([A2008], [M1013210], [PARAMETRES],[HEURES],[TYPE])

Hello
I have an aggregate measure in a cube ASO, aggregating to a minimum, I tried to use the MIN function but have not worked out as expected in the first Essbase is the sum of the data and then calculates the minimum.
This is the function used:
IIF ( NOT IsLevel ( [Hospital].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Hospital] ),[L.Unknown].Level),[PrzListinoMINInput]),
IIF ( NOT IsLevel ( [Marketing].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Marketing]),[A.Unknown].Level),[PrzListinoMINInput]),
IIF ( NOT IsLevel ( [Listini].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Listini]),[C.Unknown].Level),[PrzListinoMINInput]),
IIF ( NOT IsLevel ( [Bravo].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Bravo]),[D.Unknown].Level),[PrzListinoMINInput]),
IIF ( NOT IsLevel ( [Product Cluster].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Product Cluster]),[E.Unknown].Level),[PrzListinoMINInput]),
IIF ( NOT IsLevel ( [Area].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Area]),[F.Unknown].Level),[PrzListinoMINInput]),
IIF ( NOT IsLevel ( [Area2].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Area2]),[G.Unknown].Level),[PrzListinoMINInput]),
IIF ( NOT IsLevel ( [Area3].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Area3]),[H.Unknown].Level),[PrzListinoMINInput]),
IIF ( NOT IsLevel ( [Area4].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Area4]),[I.Unknown].Level),[PrzListinoMINInput]),
IIF ( NOT IsLevel ( [Customer].CurrentMember, 0 ),
MIN( Descendants(CurrentMember ( [Customer]),[N.Unknown].Level),[PrzListinoMINInput]),
0))))))))))
how to proceed in these cases?
Thank you

Compile forms error because using rank function

Hi,
Oracle Form 9i don't known rank function in my SQL statement. When compile forms, it alerts err message: "Encountered the symbol "(" when expecting one ..."
code:
select * from (
select group_id, acct_no, acct_desc, rank() over(order by acct_no desc) rank_no from customer
where group_id='002'
) where rank_no< 10000
Help me ASAP.
Many thank,
Bum.

Where is INTO clause ? Plz provide the actual code you are writing.
I think this type of queries not supported in Forms 9i.....try forms 10g or above.

Rank function

how to use the RANK function in oracle data integrator??

Hi,
a little google could help you..
https://forums.oracle.com/thread/2158588
Let us know

Rank Function taking a long time to execute in SAP HANA

Hi All,
I have a couple of reports with rank function which is timing out/ or taking a really long time to execute, Is there any way to get the result in less time when rank functions are involved?
the following is a sample of how the Query looks,
SQL 1:
select      a.column1,
                b.column1,
                rank () over(partition by a.column1 order by sum(b.column2) asc)
from         "_SYS_BIC"."Analyticview1"         b
                join          "Table1"            a
                  on          (a.column2 = b.column3)
group by a.column1,
b.column1;
SQL 2:
select    a.column1,
                b.column1,
                rank () over( order by min(b.column1) asc) WJXBFS1
from         "_SYS_BIC"."Analytic view2"         b
                cross join                "Table 2"               a
where      (a.column2 like '%a%'
and b.column1 between 100 and 200)
group by a.column1,
                b.column1
when I visualize the execution plan,the rank function is the one taking up a longer time frame. so I executed the same SQL without the rank() or partition or order by(only with Sum() in SQL1 and Min() in SQL 2) even that took a around an hour to get the result.
1.Does anyone have an any idea to make these queries to execute faster?
2. Does the latency have anything to do with the rank function or could it be size of the result set?
3. is there any workaround to implement these rank function/partition inside the Analytic view itself? if yes, will this make it give the result faster?
Thank you for your help!!
-Gayathri

Krishna,
I tried both of them, Graphical and CE function,
It is also taking a long time to execute
Graphical view giving me the following error after 2 hr and 36 minutes
Could not execute 'SELECT ORDER_ID,ITEM_ID,RANK from "_SYS_BIC"."EMMAPERF/ORDER_FACT_HANA_CV" group by ...' in 2:36:23.411 hours .
SAP DBTech JDBC: [2048]: column store error: search table error: [2620] executor: plan operation failed
CE function - I aborted after 40 mins
Do you know the syntax to declare local variable to use in CE function?

RANK function in Numbers

I am trying to use the rank fuction for a spreadsheet and I can't figure it out. I have it set in Excel, but I can't transfer to numbers (and still work in excel).
I have 3 values in the same column:
M13 = 346
M27 = 352
M41 = 331
I need to rank these using 1st, 2nd, 3rd, with the results posting to the following cells:
M14
M28
M42
Any help?
Thanks!

This might help: http://help.apple.com/functions/mac/5.0/#ffa5b15a6c

Rank function in a crosstab

I'm trying to rank products based on the order in which they have been bought (by purchase date).
I figured out I could use the Rank function. First problem was that Rank doesn't seem to work on Dates. I have come across this issue by using the DaysBetween function to calculate the days inbetween the first purchase date and today. This gives me a measure that I can use within the Rank function.
Works fine for single Dimention values. However, when I create a cross-tab with multiple values on top, this doesn't work anylonger.
See the example that shows where it goes wrong: [http://www.littlesister.com/example.xls]
Does anyone have any idea how to solve this?
Thanks,
Paul

Paul,
In the crosstab with the multiple values remove the sort on the rank (if it is still on) and put a break on the object which shows the data for Americas, AP, EMEA and WW.
That should show the correct ranking (at least it does in an example I build myself).
Regards,
Harry

Rank function use in MDX

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