Re: Getting the current server name

If you are running inside the server as a startup class or a server side
component, you can use weblogic.management.Admin.getServerName().
-Sabha
Anand Shukla wrote:
Hi,
How can i get the running weblogic server name.
Anand

How do I get the server and domain names for the current server-side component on a newer version that no longer has this class? I could get it from and MBean, but I need to know the servername to locate the MBean.

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How to get the current schema name

Hi,
Can anybody please tell me how to get the current schema name, there is some inbuilt function for this,but i am not getting that. Please help me.
Thanks
Jogesh

ok folks, I found the answer at Tom's as usual.
http://asktom.oracle.com/tkyte/who_called_me/index.html
I rewrote it into a function for kicks. just pass the results of DBMS_UTILITY.FORMAT_CALL_STACK to this function and you will get back the owner of the code making the call as well some extra goodies like the name of the code and the type of code depending on the parameter. This ignores the AUTHID CURRENT_USER issues which muddles the schemaid. Quick question, does the average user always have access to DBMS_UTILITY.FORMAT_CALL_STACK or does this get locked down on some systems?
cheers,
paul
create or replace
FUNCTION SELF_EXAM (
   p_call_stack VARCHAR2,
   p_type VARCHAR2 DEFAULT 'SCHEMA'
) RETURN VARCHAR2
AS
   str_stack   VARCHAR2(4000);
   int_n       PLS_INTEGER;
   str_line    VARCHAR2(255);
   found_stack BOOLEAN DEFAULT FALSE;
   int_cnt     PLS_INTEGER := 0;
   str_caller VARCHAR2(30);
   str_name    VARCHAR2(30);
   str_owner   VARCHAR2(30);
   str_type    VARCHAR2(30);
BEGIN
   str_stack := p_call_stack;
   -- Loop through each line of the call stack
   LOOP
     int_n := INSTR( str_stack, chr(10) );
     EXIT WHEN int_cnt = 3 OR int_n IS NULL OR int_n = 0;
     -- get the line
     str_line := SUBSTR( str_stack, 1, int_n - 1 );
     -- remove the line from the stack str
     str_stack := substr( str_stack, int_n + 1 );
     IF NOT found_stack
     THEN
        IF str_line like '%handle%number%name%'
        THEN
           found_stack := TRUE;
        END IF;
     ELSE
        int_cnt := int_cnt + 1;
         -- cnt = 1 is ME
         -- cnt = 2 is MY Caller
         -- cnt = 3 is Their Caller
         IF int_cnt = 1
         THEN
            str_line := SUBSTR( str_line, 22 );
            dbms_output.put_line('->' || str_line);
            IF str_line LIKE 'pr%'
            THEN
               int_n := LENGTH('procedure ');
            ELSIF str_line LIKE 'fun%'
            THEN
               int_n := LENGTH('function ');
            ELSIF str_line LIKE 'package body%'
            THEN
               int_n := LENGTH('package body ');
            ELSIF str_line LIKE 'pack%'
            THEN
               int_n := LENGTH('package ');
            ELSIF str_line LIKE 'anonymous%'
            THEN
               int_n := LENGTH('anonymous block ');
            ELSE
               int_n := null;
            END IF;
            IF int_n IS NOT NULL
            THEN
               str_type := LTRIM(RTRIM(UPPER(SUBSTR( str_line, 1, int_n - 1 ))));
             ELSE
               str_type := 'TRIGGER';
             END IF;
             str_line := SUBSTR( str_line, NVL(int_n,1) );
             int_n     := INSTR( str_line, '.' );
             str_owner := LTRIM(RTRIM(SUBSTR( str_line, 1, int_n - 1 )));
             str_name := LTRIM(RTRIM(SUBSTR( str_line, int_n + 1 )));
          END IF;
       END IF;
   END LOOP;
   IF UPPER(p_type) = 'NAME'
   THEN
      RETURN str_name;
   ELSIF UPPER(p_type) = 'SCHEMA.NAME'
   OR    UPPER(p_type) = 'OWNER.NAME'
   THEN
      RETURN str_owner || '.' || str_name;
   ELSIF UPPER(p_type) = 'TYPE'
   THEN
      RETURN str_type;
   ELSE
      RETURN str_owner;
   END IF;
END SELF_EXAM;

How to get the current function name in java

How to get the current function name in java.
In c it is done as
printf("%s",__func__);
Thanx in advance.

j0o wrote:
System.out.println("Class Name: " + new Exception().getStackTrace()[0].getClassName() +
"/n Method Name : " + new Exception().getStackTrace()[0].getMethodName() +
"/n Line number : " + new Exception().getStackTrace()[0].getLineNumber());
I pointed the OP at this approach yesterday in one of his multi-posts. I still have not been given my Dukes!

How to get the current class name in static method?

Hi,
I'd like to get the current class name in a static method. This class is intended to be extended. So I would expect that the subclass need not to override this method and at the runtime, the method can get the subclass name.
getClass() doesn't work, because it is not a static method.
I would suggest Java to make getClass() static. It makes sense.
But in the mean time, does anybody give an idea to work around it?
Thank you,
Bill

Why not create an instance in a static method and use getClass() of the instance?
public class Test {
public static Class getClassName() {
return new Test().getClass();

How to get the report server name in Forms 10g.

How to get the report server name in Forms 10g.
I'm using the Application Server 10g 10.1.2.

Hello,
I do not think that you can get this value from anywhere. A solution is to put the Reports server name in an environment variable stored in the /forms/server/default.env file, then to query it at Forms runtime with the TOOL_ENV.Getvar() built-in.
Francois

Get the current space name

hi,
i am working on webcenter space application.i need to pass current space name to bean.how can i get the current space name??
Regards
Vinay Kumar

No, that will not compile. You probably need to do:
SpacesContext sc = SpacesContext.getCurrentInstance();
String spaceName = sc.getCurrentSpaceName();
Beware that the doc says "Return the SpacesContext instance for the request that is being processed by the current thread, if any."
So the SpacesContext might be null.
Jaap

How to get the current user name in Provider hosted app using appOnlyAccessToken

Hi,
Please help me, how to get the HostWeb UserName in Provider Hosted App
i have Provider hosted App, and Anonymous Authentication is enabled on AppWeb, using appOnlyAccessToken
Below code does not return current user who Log in in hostweb, it is returning
SharePoint App (app@sharepoint)
Web web = clientContext.Web;
clientContext.Load(web);
clientContext.ExecuteQuery();
clientContext.Load(web.CurrentUser);
clientContext.ExecuteQuery();
clientContext.Web.CurrentUser.LoginName;
Below code gives a blank name when Anonymous Authentication is enabled, if Anonymous Authentication is disabled
app prompts for credentials
HttpContext.Current.User.Identity.Name
Thanks
Ram

Hi,
Since you are using a provider Hosted app if you want to get the current logged in name than do not use AppOnlyAccessToken else use AccessToken which is App + user Context AccessToken.
then
Web web = clientContext.Web;
clientContext.Load(web);
clientContext.ExecuteQuery();
clientContext.Load(web.CurrentUser);
clientContext.ExecuteQuery();
clientContext.Web.CurrentUser.LoginName;will return proper user Name.
HttpContext.Current.User.Identity.Name will never return the user as this object is related to IIS server of your App Server not sharepoint.you should set this as Anonymous in case of provider hosted app.you can download the below sample which uses the AccessToken which has user name in it.https://code.msdn.microsoft.com/Working-provider-hosted-8fdf2d95
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Uix frameset - how to get the current frame name?

I have a frameset with 3 different frames in it. a top, center and bottom.
There is a menu in the top frame that changes the contents of the center or bottom frame.
How can I get the value of the frame name for the current frame into a bound value like a httpsession or page?
for example if I change the center frame to "listadmin.uix" how can I load a bound value with the frames new source?
Is there a way to pass javascript to a boundvalue? I could get the frames new properties from javascript

In Jdev 9.0.3 you could do something like this:<frameBorderLayout>
<start>
 <frame name="sideFrame">
 <boundAttribute name="source">
 <ctrl:pageURL name="sideFramePage">
 <ctrl:properties>
 <ctrl:property key="currentFrame"
 value="sideFrame"/>
 </
 </
 </
 </
</
</then in startFramePage.uix you can access the current frame name by doing:<styledText data:text="currentFrame@ctrl:page"/>

Where can i get the report server name in Reports 10g

Where can i get my report server name in 10G ?

Thanks ..
When i opened the bat file :
i did not find any report server name ...
This is my file :-
@echo off
REM $Header: rwdiag.bat 13-may-2005.03:21:21 sunaraya Exp $
REM
REM rwdiag.bat
REM
REM Copyright (c) 2005, Oracle. All rights reserved.
REM
REM NAME
REM rwdiag.bat - rw diagnostic tool
REM
REM DESCRIPTION
REM Script to run the diagnostic tool used to locate servers / monitor packets on the network
REM
REM NOTES
REM Usage: rwdiag.bat -find <server name> | -findAll [-conf <config file>] [-timeout <timeout in sec>]
REM
REM Usage: rwdiag.bat -monitor [-log <logfile>] [-conf <config file>]
REM
REM MODIFIED (MM/DD/YY)
REM sunaraya 05/13/05 - Added rwrun.jar to the classpath for bug 4361664
REM sunaraya 04/22/05 - Provided execute permission to the script for bug 4323789
REM sunaraya 04/14/05 - sunaraya_bug-4221172
REM sunaraya 04/14/05 - Creation
REM
set ORA_HOME=C:\ORANT
if "%ORA_HOME%"=="" goto ERROR
set CLASSPATH=%ORAHOME%\jlib\zrclient.jar;%ORA_HOME%\reports\jlib\rwrun.jar
%ORA_HOME%\jdk\bin\java -DORACLE_HOME=%ORA_HOME% -classpath %_CLASSPATH% oracle.reports.utility.DiagServerLocator %*
goto END
:ERROR
echo "ORACLE_HOME is not set"
echo.
:END

How to get the current user name of the host who is occupying a specific VM?

I'm developing a winform app with c# code to manage Hyper-V. I need to remind someone if he/she would take a VM which has already been occupied by others.
Is there any powershell cmd or WMI interface to get the current user of a specific VM?
Thanks!

Hiya,
from cmd there are quser(Query user) and qwinsta(Query Session)
which should give you that. Don't know how you can incoorperate that in C#, but that should give you something to work with :)
https://technet.microsoft.com/en-us/library/cc785434.aspx
https://technet.microsoft.com/en-us/library/cc788125.aspx

Indesign CS3: How to get the current document name?

Hallo!
How do I get the name of the current document loaded in Indesign?
Thanks,
Alois Blaimer

...Plese Ignore the last post... docRef is the UIDRef of the document. Plese consider the following code IDocument *docFrom = Utils<ILayoutUIUtils>()->GetFrontDocument(); if (docFrom == NULL ) break; UIDRef docRef = GetUIDRef(docFrom )); InterfacePtr<IDocument> iDocument (docRef, IID_IDOCUMENT); if(iDocument == nil) break; PMString docName; iDocument->GetName(docName);

How to get the current view name is displaying?

Hi Experts,
I have a requirement that I have to know the current view is displaying. At the header of the page, there is a component (BTCHIST) which is fix and common for the all others. It has a button called Finish. When the user clicks on it, it has a different behavior depending on the current view.
Does anyone know any method in order to get this information? I searched up in CRM_UI_FRAME, however I didnu2019t find anything.
Regards,
André

Hi,
You need to redefine the method IF_BSP_WD_HISTORY_STATE_DESCR~GET_STATE_DESCRIPTION of the controller class to change the view description. Unfortunately, the effort is huge and we cannot do it dynamically and needs to be done for each view in question.
Regards
Prasenjit

Getting the HTTP server name, port and context name inside the init()

I have a servlet which is initialized when the Web server comes up. Is there any way I can print the complete URL from this servlet?
I am aware that this can be done by using request object. But note that in this case, there is no request object. All we have is the ServletConfig and ServletContext.
Pasting a part of my code here.
public class MyInit extends HttpServlet
private ServletContext m_servletContext = null;
public void init(ServletConfig config) throws ServletException
super.init(config);
m_servletContext = config.getServletContext();
//System.out.println("Print the URL here...")
}

Only a request has a URL. It's possible for servlets to be mapped to respond to more than one URL, and the server can be configured to respond to more than one host and at more than one port. So none of those things you are asking for have any meaning without an actual request.

Get the current file name of uploaded file

I'm looking for a way (an API?) to use files in content areas in
portlets, dynamic pages and html. ie <img
src='http://he130r.us.oracle.com/pls/portal30/docs/FOLDER/CUSTOM/
IMAGES/app1.gif"> This syntax works until I delete the file
and/or replace with a new one.... At that time the file name
becomes app1_0.gif..... Is there a way to find the proper URL
based on the display name? I've looked at the wwsbr_all_items
view but can't figure out where to find the path... If this
view is the right place do you have some sample queries?
thx

While some of the info is in that table I can not create a
complete picture of how to find the file. I need to recreate a
vaild url based upon the display name of the file.
wwdoc_document$ contains a column called filename which holds in
my case 'CONTACTS.GIF' while the file is displayed
as 'Contacts.gif'.... The name column holds the
value '755.GIF'... I would really like an API that I can pass
the value 'Contacts.gif' to and it
returns 'http://he130r.oracleads.com/pls/portal30/doc/FOLDER/CUST
OM/IMAGE/Contacts_1.gif' or whatever.... Short of that I need
to create a procedure that I can call that will build this url
based on the display name I pass it..... HELP! Any ideas?

How to get the current EAR name in a servlet ?

Greetings,
In a servlet, I need to retrive the EAR name. Using the ServerRuntimeMBean I can retrieve the list of the applications via the ApplicationsRuntime attribute. But I don't find any CurrentApplicationRuntime attribute or something similar. Many thanks in advance for any help.
Kind regards,
Nicolas

j0o wrote:
System.out.println("Class Name: " + new Exception().getStackTrace()[0].getClassName() +
"/n Method Name : " + new Exception().getStackTrace()[0].getMethodName() +
"/n Line number : " + new Exception().getStackTrace()[0].getLineNumber());
I pointed the OP at this approach yesterday in one of his multi-posts. I still have not been given my Dukes!

Re: Getting the current server name

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