Re: Safari Freeze with open and closing repeatly!!! HELP

Hi guys, I'm new here and it's because of Lion.
Recently I'm facing some freeze problem on my Lion when I opening Safari and Mail. It will freeze up my Mac and eventually shutting it off by the "hard way".
But today, my safari freeze once every 10times of opening (average) which is really annoying.
I have verify my disk verify whatever there have in disk utility. Reformated the hardisk, Installed Snow leopard and reinstalled Lion 3 times and it does not help the safari. And ofcourse I did whatever updates there have.
Besides, I have tried "APPLE HARDWARE TEST". everythings is fine here.
But when I create a new guest account on Lion, the safari there won't freeze and run smoothly. But I wouldn't want to move all my stuff there.
It's been really annoying since today as I hardly able to launch Safari and type this out.
PLEASE HELP ME ALL THE EXPECT OUT THERE !!!!

Just for the record, this had nothing to do with Safari.
facebook was down for a number hours today:
http://www.bbc.co.uk/news/technology-17284437

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  • Intersperse daily totals with opening and closing balance

    Hi All
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        select 1 as daynum, 'CR' as trantype, 200 as amount from dual union all
        select 1 as daynum, 'DR' as trantype, -300 as amount from dual union all
        select 2 as daynum, 'CR' as trantype, 800 as amount from dual union all
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        select 4 as daynum, 'CR' as trantype, 900 as amount from dual union all
        select 4 as daynum, 'DR' as trantype, -500 as amount from dual union all
        select 5 as daynum, 'CR' as trantype, 900 as amount from dual union all
        select 5 as daynum, 'DR' as trantype, -500 as amount from dual
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             case when ttype in ( 'close', 'open' )
                  then sum(samt) over (order by daynum, r)
              end theamount
        from (
      select data.daynum,
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                  else t.trantype
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             case when (t.trantype = 'CR' and r = 2) or (t.trantype = 'DR' and r=1)
                  then t.amount
              end amt,
             case when (t.trantype = 'DR' and r = 2)
                  then sum(case when r=1 then t.amount end) over (partition by data.daynum)
                  else 0
              end samt
      from   t, data
      where data.daynum (+) = t.daynum
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             1          1 DR          -300          
             1          2 CR           200          
             1          2 close                  -100
             2          1 open                   -100
             2          1 DR          -200          
             2          2 CR           800          
             2          2 close                   500
             3          1 open                    500
             3          1 DR          -500          
             3          2 CR           900          
             3          2 close                   900
             4          1 open                    900
             4          1 DR          -500          
             4          2 CR           900          
             4          2 close                  1300
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                          DR  Here's a solution using partitioned outer join:
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                    select 3 as daynum, 'DR' as trantype, -500 as amount from dual union all
                    select 4 as daynum, 'CR' as trantype, 900 as amount from dual union all
                    select 4 as daynum, 'DR' as trantype, -500 as amount from dual union all
                    select 5 as daynum, 'CR' as trantype, 900 as amount from dual union all
                    select 5 as daynum, 'DR' as trantype, -500 as amount from dual),
          dummy as (select 1 id, 'Opening Balance' descr from dual union all
                    select 2 id, 'CR' descr from dual union all
                    select 3 id, 'DR' descr from dual union all
                    select 4 id, 'Closing Balance' descr from dual)
    select mt.daynum,
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                        4, amount + lag(amount, 2) over (partition by mt.daynum order by d.id)) amount
    from   my_tab mt
           left outer join dummy d partition by (id, descr) on (mt.trantype = d.descr)
    where  (d.id = 1 and mt.trantype = 'CR')
    or     (d.id = 2 and mt.trantype = 'CR')
    or     (d.id = 3 and mt.trantype = 'DR')
    or     (d.id = 4 and mt.trantype = 'DR')
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             1 Opening Balance          0
             1 CR                     200
             1 DR                    -300
             1 Closing Balance       -100
             2 Opening Balance          0
             2 CR                     800
             2 DR                    -200
             2 Closing Balance        600
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             3 Closing Balance        400
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             4 CR                     900
             4 DR                    -500
             4 Closing Balance        400
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             1 CR              CR              400
             1 CR              CR              200
             1 DR              DR             -300
             1 DR              DR             -500
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             2 DR              DR             -200
             2 Closing Balance CR              600
             3 Opening Balance CR                0
             3 CR              CR              900
             3 DR              DR             -500
             3 Closing Balance CR              400
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             4 Closing Balance CR              900
             5 Opening Balance CR                0
             5 CR              CR              900
             5 CR              CR              200
             5 DR              DR             -500
             5 Closing Balance CR              600
             6 Opening Balance DR                0
             6 DR              DR             -200
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