Read binary file in as string to perform RegEx

Question

I have a python script that I use to gather data from a particular data file. I want to convert the script into a java application so I can add a gui and make it more distributable. I am particularly struggling on how to read the binary file into java and convert it to a string for the regex searching.
import re
dat = 'c:/projects/test.dat'
all_the_data = open(dat,'rb').read()
pattern = 'title="(.*?)".*?value="(.*?)"'
rx = re.compile(pattern, re.IGNORECASE|re.MULTILINE|re.DOTALL)
result = rx.findall(all_the_data)
for title, value in result:
    print "%-25s: %s" % (title, value)

Answer 1

Hi infraray.
Check my post out: Cyclomatic Complexity Using Regex .
This will help.
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import java.io.*;
1) static BufferedReader keyboard = new BufferedReader(new InputStreamReader(System.in));
2) protected String txtFileName;
3) System.out.println("Enter file name to be read: " );
4) txtFileName = new String(keyboard.readLine());
5) reader = new BufferedReader(new FileReader(txtFileName));
// Your Pattern |
V
6) Pattern pattern = Pattern.compile("if|for|while|case|switch",Pattern.MULTILINE);
7) Matcher m = pattern.matcher(txtFileName);
8) boolean b = m.matches(); // return true if match found !
9) String line = null;
10) while((line = reader.readLine()) !=null)
m.reset(line);
if(m.find())
// Change line below to suit your need
System.out.println("Your message " + " found " + " start of line: " + m.start() + " ends at line: " +m.end());
reader.close(); // close buffered reader!
Hope this gives you some direction.