Read every font topic, but I still need help
I have been at this for about 4 hours, and I need help.
I read Flash Help and every font forum topic, which say
Static Text need not use embedded fonts.
Links to .fla and .swf files below.
Everything shows up fine in 'Control/Test Movie'
Using Arial font, I cannot see static text in my test .swf
file.
I then embedded Arial (24 pt, bold, italic - 'ArialEmbedded'
in the library).
Using that font on Static text, can see the text, but not in
Arial. It is in TimesNewRoman, regular, non-italic.
I then used the embedded font in text I described as dynamic,
but could not see any text.
Everything shows up fine in Control/Test Movie.
I get around this by building .gifs using graphics packages
and importing them,
but the results are less than desirable. (see layer ".gif
from outside appl."
Links:
http://www.ph4d.com/FlashFonts/TestingText3.fla,
and
http://www.ph4d.com/FlashFonts/TestingText3.swf
I hope it's something I overlooked, and I appreciate any help
provided.
Thanks,
vinceg
Update.....
I still cannot see text in .swf on my local machine, but I
can see it on the web, after posting it, but the text looks awful.
(The same text in Word lookas fine -
http://ph4d.com/FlashFonts/TestingText3.doc)
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Have I done this correct, but I still need help on #7
1. Provide a SQL statement that displays the FIRSTNAME and LASTNAME of each customer separated by a comma. The FIRSTNAME and LASTNAME should be capitalized and concatenated together with a column alias of “Full Name”. The output should be sorted in ascending order by LASTNAME.
SELECT FIRSTNAME||','||LASTNAME "FULL NAME"
FROM CUSTOMERS;
FULL NAME
BONITA,MORALES
RYAN,THOMPSON
LEILA,SMITH
THOMAS,PIERSON
CINDY,GIRARD
MESHIA,CRUZ
TAMMY,GIANA
KENNETH,JONES
JORGE,PEREZ
JAKE,LUCAS
REESE,MCGOVERN
WILLIAM,MCKENZIE
NICHOLAS,NGUYEN
JASMINE,LEE
FULL NAME
STEVE,SCHELL
MICHELL,DAUM
BECCA,NELSON
GREG,MONTIASA
JENNIFER,SMITH
KENNETH,FALAH
20 rows selected.
2. Provide a SQL statement that displays the current date in the format MM/DD/YY.
SELECT TO_CHAR( '10/25/06')
FROM DUAL
TO_CHAR(
10/25/06
3. Provide a SQL statement that displays the TITLE and publisher NAME of each book in the “COMPUTER” CATEGORY.
SELECT TITLE, CATEGORY
FROM BOOKS, PUBLISHER
WHERE CATEGORY = 'COMPUTER'
TITLE CATEGORY
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
TITLE CATEGORY
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
20 rows selected.
4. Provide a SQL statement that displays the CUSTOMER# and LASTNAME for each customer along with the ORDER# of any order that the customer placed. The statement should include all customers including those that have not placed any orders.
SELECT LASTNAME,ORDER#
FROM CUSTOMERS C, ORDERS O
WHERE C.CUSTOMER#=O.CUSTOMER#
ORDER BY O.ORDER#
LASTNAME ORDER#
GIRARD 1000
LUCAS 1001
MCGOVERN 1002
MORALES 1003
FALAH 1004
MONTIASA 1005
SMITH 1006
GIANA 1007
PIERSON 1008
GIRARD 1009
SMITH 1010
LUCAS 1011
NELSON 1012
LEE 1013
LASTNAME ORDER#
GIANA 1014
FALAH 1015
SMITH 1016
SCHELL 1017
MORALES 1018
MONTIASA 1019
JONES 1020
21 rows selected.
5. Provide a SQL statement that displays the total QUANTITY of books ordered.
SELECT CUSTOMER#, FIRSTNAME, LASTNAME
FROM ORDERS NATURAL JOIN ORDERITEMS NATURAL JOIN CUSTOMERS
HAVING SUM(QUANTITY)=ALL
(SELECT MAX(SUM(QUANTITY))
FROM ORDERS NATURAL JOIN ORDERITEMS GROUP BY CUSTOMER#)
GROUP BY CUSTOMER#, FIRSTNAME, LASTNAME;
CUSTOMER# FIRSTNAME LASTNAME
1007 TAMMY GIANA
6. Provide a SQL statement that displays the TITLE of all books that COST more than the average cost of all books.
SELECT TITLE,AVG(COST)
FROM BOOKS
GROUP BY TITLE
TITLE AVG(COST)
BIG BEAR AND LITTLE DOVE 5.32
BODYBUILD IN 10 MINUTES A DAY 18.75
BUILDING A CAR WITH TOOTHPICKS 37.8
COOKING WITH MUSHROOMS 12.5
DATABASE IMPLEMENTATION 31.4
E-BUSINESS THE EASY WAY 37.9
HANDCRANKED COMPUTERS 21.8
HOLY GRAIL OF ORACLE 47.25
HOW TO GET FASTER PIZZA 17.85
HOW TO MANAGE THE MANAGER 15.4
PAINLESS CHILD-REARING 48
REVENGE OF MICKEY 14.2
SHORTEST POEMS 21.85
THE WOK WAY TO COOK 19
14 rows selected.
7. Provide a SQL statement that displays each SHIPSTATE along with the number of orders shipped to each state. Include only those states that more than 3 orders were shipped to.
8. Provide a SQL statement that displays each book CATEGORY in the database. The category should only appear once in the output.
SELECT TITLE, CATEGORY
FROM BOOKS
TITLE CATEGORY
BODYBUILD IN 10 MINUTES A DAY FITNESS
REVENGE OF MICKEY FAMILY LIFE
BUILDING A CAR WITH TOOTHPICKS CHILDREN
DATABASE IMPLEMENTATION COMPUTER
COOKING WITH MUSHROOMS COOKING
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
PAINLESS CHILD-REARING FAMILY LIFE
THE WOK WAY TO COOK COOKING
BIG BEAR AND LITTLE DOVE CHILDREN
HOW TO GET FASTER PIZZA SELF HELP
HOW TO MANAGE THE MANAGER BUSINESS
SHORTEST POEMS LITERATURE
14 rows selected.3. Provide a SQL statement that displays the TITLE and publisher NAME of each book in the “COMPUTER” CATEGORY.
TITLE CATEGORY
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
TITLE CATEGORY
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
20 rows selected.
Result is wrong - you have a catrtesian product between books and publisher i.e. each book is repeated for each publisher. You need to join books to publisher and you need to select the publisher name
4. Provide a SQL statement that displays the CUSTOMER# and LASTNAME for each customer along with the ORDER# of any order that the customer placed. The statement should include all customers including those that have not placed any orders.
SELECT LASTNAME,ORDER#
FROM CUSTOMERS C, ORDERS O
WHERE C.CUSTOMER#=O.CUSTOMER#
ORDER BY O.ORDER#This is wrong, you need to use an outer join between customers and orders to satisfy the requirement:
The statement should include all customers including those that have not placed any orders.
5. Provide a SQL statement that displays the total QUANTITY of books ordered.
SELECT CUSTOMER#, FIRSTNAME, LASTNAME
FROM ORDERS NATURAL JOIN ORDERITEMS NATURAL JOIN CUSTOMERS
HAVING SUM(QUANTITY)=ALL
(SELECT MAX(SUM(QUANTITY))
FROM ORDERS NATURAL JOIN ORDERITEMS GROUP BY CUSTOMER#)
GROUP BY CUSTOMER#, FIRSTNAME, LASTNAME;
CUSTOMER# FIRSTNAME LASTNAME
1007 TAMMY GIANA
I can't see a quantity here and you should avoid NATURAL JOINs like the plague:
SELECT CUSTOMER#, FIRSTNAME, LASTNAME, SUM(QUANTITY)
I'm not exactly sure what you're attempting with the
HAVING SUM(QUANTITY)=ALL
(SELECT MAX(SUM(QUANTITY))
FROM ORDERS NATURAL JOIN ORDERITEMS GROUP BY CUSTOMER#)
GROUP BY CUSTOMER#, FIRSTNAME, LASTNAME;bit.
6. Provide a SQL statement that displays the TITLE of all books that COST more than the average cost of all books.
SELECT TITLE,AVG(COST)
FROM BOOKS
GROUP BY TITLEThis doesn't do what was asked, it just selects the average cost of each book - which will be exactly the same as the actual cost of each book. You need to use a sub query here.
8. Provide a SQL statement that displays each book CATEGORY in the database. The category should only appear once in the output.
The title does not need to be in the output here and you need to use distinct.
HTH
David -
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Hello guy! Sorry to trouble you with the same problem again,
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If you put each item that you are comparing into a list, it
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You will see it return 1 which means True. Next, make the R
in the field
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will return 0
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code to find
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I'm still having a problem with the flash player, please read my last post below:
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Date: Thu, 29 Oct 2009 18:52:38 -0600
From: [email protected]
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