Receiver File Name with date

Hi @,
I have a requirement where I wanted to genereate the recevier file name as TestYYYYMMDD.txt format.
Note that in Receiver target structure date is not coming and output file also we dont require date data.
I tried to put the Date root node and date field in target structure and in Receiver FCC i have not put the Date root node name but still date data is generated in output file.
Since its a Comma separated file hence I can not use CUT option which is applicable for Fixed length file.
I used the time stamp option but it is giving HH.MM.SS details which i dont want.
Is there any other options available.
chirag

You can add a node 'TRAIL' with 'FILENAME' sub-node; Your target format is like this:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:MT_FILE_STRING_OUT xmlns:ns0="HTTP://WWW.XXX.COM">
   <Recordset>
      <Row>3</Row>
   </Recordset>
   <Trail>
      <Filename>DFS-XXX-20090804173307</Filename>
   </Trail>
</ns0:MT_FILE_STRING_OUT>
When mapping, the UDF can be:
(imports: java.text.SimpleDateFormat;)
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMddHHmmss");
  String ds = sdf.format(new Date(System.currentTimeMillis()));
  String filename = "DFS-ADSFCL-" + ds;
return filename;
In file adapter, you can use the adapter attributes to get the file name and the conversion to cut the trail node in the file...
Done!

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    multipartMessage(SMTP.SMTPHost) ="yoursmypserver.com";
    multipartMessage.MessagePart_2(MIME.FileName) = "Attachment_Name";
    multipartMessage(SMTP.SMTPAuthenticate) =0;
    Thanks
    Abhishek

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