Regarding downloading a file on application server

Hi experts,
I have a scenerio for downloading files on aplication server. The name of the file will be created in program itself. we have to give only the path on selection screen.
how can we validate the path enter on selection screen. But do remember the path should be like this C:\DOCUMENTS AND SETTINGS\145546\DESKTOP
because it will be converted to C:\DOCUMENTS AND SETTINGS\145546\DESKTOP\100001.pdf in program itself.
so when user enter C:\DOCUMENTS AND SETTINGS\145546\DESKTOP on selection screen i want to validate wheather that path exists or not.
please help me out.Its urgent.
Thanks
Azad.

Local Data
  DATA: L_RC TYPE C,
        L_PATH TYPE STRING.
***P_DIR is Parameter
You can put the below code in AT Selection-screen event
  L_PATH = P_DIR.
  CALL METHOD CL_GUI_FRONTEND_SERVICES=>DIRECTORY_EXIST
    EXPORTING
      DIRECTORY            = L_PATH
    RECEIVING
      RESULT               = L_RC
    EXCEPTIONS
      CNTL_ERROR           = 1
      ERROR_NO_GUI         = 2
      WRONG_PARAMETER      = 3
      NOT_SUPPORTED_BY_GUI = 4
      OTHERS               = 5.
  IF SY-SUBRC <> 0.
    EXIT.
  ELSE.
  Error if the directory doesn't exist
    IF L_RC = SPACE.
      MESSAGE E002 WITH L_PATH.
    ENDIF.
  ENDIF.

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         errmsg(40)  type c,
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         len                        type i,
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         help2(120)                 type c,
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            endif.
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  • Regarding Reading the file from Application Server

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  • Regarding uploading the file from Application Server

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  • About download the file into application server

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  • How to download a file from application server in webdynpro

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  • Issue in downloading the file to application server (background)

    i am downloading the PIR records to the application server.
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    regards
    venkat.

    Hi,
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    Regards,
    Santhosh.

  • Urgent : Download file from Application Server via Process Chain.

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    Hi Sailekha,
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    Regards,
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    thanks for the points you choose to assign.

  • Japanese character problem while downloading file to application server

    Hello All,
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    Thanks!

    Hi
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  • Background Job - Requirement to download file to application server

    Dear All,
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    Atanu

    Hi,
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    reward if helpful
    Regards,
    Rahul

  • Downloading file to application server

    Hi,
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    Hi,
    If you are downloading the file from application server, you have to use OPEN DATASET CLOSE DATASET.
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    IF NOT p_pathdl is initial.
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          CLEAR:     v_filename,
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          CONCATENATE c_mf018
                      v_date
                      v_time
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                 INTO v_filename.
    Conactenating File Name and File Path for Dataset parameter.
          CONCATENATE p_pathdl
                      c_slash
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                 INTO v_path.
        ELSE.                                        "IF search help was called.
          v_path = p_pathdl.
        ENDIF.
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        DATA v_string  TYPE string.
    Creating a file of given name at given path on apllication server.
        OPEN DATASET v_path FOR OUTPUT IN TEXT MODE ENCODING DEFAULT.
        IF sy-subrc = 0.
    Building header and transfering it to the file.
          CONCATENATE text-004 c_sep text-005 c_sep text-006 c_sep
                      text-007 c_sep text-008 c_sep text-009 c_sep
                      text-010 c_sep text-011 c_sep text-012 c_sep
                      text-013 c_sep text-014 c_sep text-015 c_sep
                 INTO v_string.
          TRANSFER v_string TO v_path.
          CLEAR v_string.
    Reading data from internal table & transfering to file.
          LOOP AT i_output INTO w_output.
            CONCATENATE w_output-lifnr      c_sep w_output-banksrec   c_sep
                        w_output-bankkrec   c_sep w_output-banknrec   c_sep
                        w_output-waers      c_sep w_output-bankssnd   c_sep
                        w_output-bankksnd   c_sep w_output-chainno    c_sep
                        w_output-chainbankt c_sep w_output-chainbanks c_sep
                        w_output-chainbankk c_sep w_output-chainbankn
                  INTO v_string.
            TRANSFER v_string TO v_path.
            CLEAR: v_string,
                   w_output.
          ENDLOOP.
        ELSE.
          MESSAGE i000 WITH text-040.
          EXIT.
        ENDIF.
        MESSAGE i000 WITH text-038 v_path.
      ELSE.
        MESSAGE i000 WITH text-048.
      ENDIF.
      ELSE.
        MESSAGE i000 WITH text-041.
      ENDIF.
    ENDFORM.                    " APL_DOWNLOAD

  • Read Tab delimited File from Application server

    Hi Experts,
    I am facing problem while reading file from Application server.
    File in Application server is stored as follows, The below file is a tab delimited file.
    ##K#U#N#N#R###T#I#T#L#E###N#A#M#E#1###N#A#M#E#2###N#A#M#E#3###N#A#M#E#4###S#O#R#T#1###S#O#R#T#2###N#A#M#E#_#C#O###S#T#R#_#S#U#P#P#L#1###S#T#R#_#S#U#P#P#L#2###S#T#R#E#E#T###H#O#U#S#E#_#N#U#M#1
    i have downloaded this file from Application server using Transaction CG3Y. the Downloaded file is a tab delimited file and i could not see "#' in the file,
    The code is as Below.
    c_split  TYPE abap_char1 VALUE cl_abap_char_utilities=>horizontal_tab.
    here i am using IGNORING CONVERSION ERRORS in order to avoid Conversion Error Short Dump.
    OPEN DATASET wa_filename-file FOR INPUT IN TEXT MODE ENCODING DEFAULT IGNORING CONVERSION ERRORS.
          IF sy-subrc = 0.
            WRITE : /,'...Processing file - ', wa_filename-file.   
           DO.
          Read the contents of file
              READ DATASET wa_filename-file INTO wa_file-data.
              IF sy-subrc = 0.
                SPLIT wa_file-data AT c_split INTO wa_adrc_2-kunnr
                                                   wa_adrc_2-title
                                                   wa_adrc_2-name1
                                                   wa_adrc_2-name2
                                                   wa_adrc_2-name3
                                                   wa_adrc_2-name4
                                                   wa_adrc_2-name_co
                                                   wa_adrc_2-city1
                                                   wa_adrc_2-city2
                                                   wa_adrc_2-regiogroup
                                                   wa_adrc_2-post_code1
                                                   wa_adrc_2-post_code2
                                                   wa_adrc_2-po_box
                                                   wa_adrc_2-po_box_loc
                                                   wa_adrc_2-transpzone
                                                   wa_adrc_2-street
                                                   wa_adrc_2-house_num1
                                                   wa_adrc_2-house_num2
                                                   wa_adrc_2-str_suppl1
                                                   wa_adrc_2-str_suppl2
                                                   wa_adrc_2-country
                                                   wa_adrc_2-langu
                                                   wa_adrc_2-region
                                                   wa_adrc_2-sort1
                                                   wa_adrc_2-sort2
                                                   wa_adrc_2-deflt_comm
                                                   wa_adrc_2-tel_number
                                                   wa_adrc_2-tel_extens
                                                   wa_adrc_2-fax_number
                                                   wa_adrc_2-fax_extens
                                                   wa_adrc_2-taxjurcode.
    WA_FILE-DATA is having below values
    ##K#U#N#N#R###T#I#T#L#E###N#A#M#E#1###N#A#M#E#2###N#A#M#E#3###N#A#M#E#4###S#O#R#T#1###S#O#R#T#2###N#A#M#E#_#C#O###S#T#R#_#S#U#P#P#L#1###S#T#R#_#S#U#P#P#L#2###S#T#R#E#E#T###H#O#U#S#E#_#N#U#M#1
    And this is split by tab delimited and moved to other variables as shown above.
    Please guide me how to read the contents without "#' from the file.
    I have tried all possible ways and unable to get solution.
    Thanks,
    Shrikanth

    Hi ,
    In ECC 6 if all the unicode patches are applied then UTF 16 will defintly work..
    More over i would suggest you to ist replace # with some other  * or , and then try to see in debugging if any further  # appears..
    and no # appears then try to split now.
    if even now the # appears after replace statement then try to find out what exactly is it... wheather it is a horizantal tab etc....
    and then again try to replace it and then split..
    Please follow the process untill all the # are replaced...
    This should work for you..
    Let me know if you further face any issue...
    Regards
    Satish Boguda

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