Regular Expressions and Numbers in Strings

Looking for someone who has had experience in using Regular Expressions in the Classification Rule Builder.
We have an eVar that is collecting the number of search results in this fashion:
<Total Results>_<# of Item 1>_<# of Item 2>_<# of Item 3>_<# of Item 4>
Example output would look like this:
150_50_0_25_75
What we've done is initially create a Regular Expression that looks like this:
^(.+)\_(.+)\_(.+)\_(.+)\_(.+)$
The problem is, it appears in situations where the output contains a zero in one of the slots, the value is ignored and it receives the value in the next place over. Using the example output shown above, I would end up with values like this:
$0 150_50_0_25_75
$1 150
$2 50
$3 25
$4 75
$5 {null}
Here's the weird part. When I perform a test of a single record, it appears like it will work just fine, but when it actually runs in Omniture, it's not working as expected. Here's something else I'd like to know if it's possible to address. The five-place string is only the newest iteration of this approach. In the past, we started out with a two-place version, then three-place and then four. Any recommendations for handling all scenarios?
Any and all advice is welcome. Thanks in advance!

Doing some playing around on rubular.com and thinking the Regular Expression should be build this way instead:
^(\d+)\_(\d+)\_(\d+)\_(\d+)\_(\d+)$
Again, still looking for any additional guidance from more experienced individuals. Thanks!

Similar Messages

Using Regular Expressions in Numbers 09?

Is there any way to use regular expressions in Numbers 09 in Find & Replace?

kilowattradio wrote:
Is there any way to use regular expressions in Numbers 09 in Find & Replace?
NO !
_Go to "Provide Numbers Feedback" in the "Numbers" menu_, describe what you wish.
Then, cross your fingers, and wait _at least_ for iWork'10
Yvan KOENIG (VALLAURIS, France) vendredi 25 septembre 2009 14:49:49

Juniper MX Regular expressions and user permissions ACS 5.4

Hi everyone!
Im having some trouble with regular expressions and permissions on our Juniper MX routers through ACS 5.4, and i would like some insight/help/poitners!!
We have a team of engineers that should only have read only permissions (important: show configuration) and also be able to just change the description on interfaces.
Thus far with the following regular expressions set for the shell profile they are going through i have managed the above, however the problem is when an engineer inputs "Show configuration", only the interfaces descriptions configuration is shown! The rest of the configuration will not be printed.
deny-commands1=.*.
allow-commands1=configure
deny-configuration1=.*.
allow-commands2=interfaces .*. description .*$
allow-configuration1=interfaces .*. description .*$
allow-commands2=show configuration.*
allow-commands3=show configuration
(some of these regex i know that are not needed, i was just playing around to check everything before posting)
Any pointers as to why or how to resolve this?
example output with the above:
show configuration
## Last commit: 2014-01-09 09:34:44 EET by someone
interfaces {
    xe-0/0/0 {
    xe-0/0/1 {
        description xxxx;
    xe-0/1/0 {
        description xxxx;
    xe-0/1/1 {
        description xxxx;
    xe-0/2/0 {
        disable;
    xe-0/2/1 {
        description xxxx;
    xe-0/3/0 {
        description xxxx;
    xe-0/3/1 {
        description xxxx;
    ae0 {
        description "xxxx";
    ae1 {
        description xxxx;
    demux0 {
    lo0 {
{master}
Thanks in advance!
Spyros

You are absolutely right!! I was doing research online after posting the above. The correct RADIUS attribute to use is actually CVPN3000/ASA/PIX7.x-Group-Based-Address-Pools. Then create the pool in ASA, and call that pool's name in ACS under that RADIUS attribute. Someone explained this perfectly in this community before. Much appreciate your answer!
Here's from another post last year:
ACS 5 does not have the feature of IP pools. Logically its always good to setup pools locally on vpn server and if you want user to pick ip from specific local pool you can configure acs to push that attribute.
On ACS Go to > Policy Elements -> Network Access ->   Authorization Profiles -> Create ->
Name of the Policy ->Dictionary Type: Radius-Cisco VPN 3000/ASA/PIX7.x
Attribute Type : CVPN3000/ASA/PIX7.x-Group-Based-Address-Pools
Attribute Type: String
Attribute Value : Static MYPOOL (Name of the Pool which is defined on the ASA)
Access Policies ->Default Network Access -> Authorization -> Create -> Under result section call the Authorization p

Regular expression and XML

Hello,
I have an XML file containing regular expressions and i parse the file, extract the pattern from it and search for it using java regex package. The problem is it works fine when patterns are words but when the pattern is something like
write \\d+ (write followed by a space followed by one or mre digits) it doesn't work.
I wrote the same code but with the pattern embedded in it,ie. without using XML and it worked. But when extracting with XML it fails.
Also if the pattern is write[0-9] it only extracts write[0-9 and gives an error of no closing bracket.
Could anyone please tell me what i am missing out
Thank you

thank you for your replies. Well i have still no got over the problem so i am posting my code here and hoping it can get solved
import org.xml.sax.*;
import org.xml.sax.helpers.*;
import java.io.*;
import java.util.regex.*;
class textextractor extends DefaultHandler{
     boolean regex=false;
public void startElement(String namespaceURI,String localName,String qn,Attributes attr)
          if(localName.equals("REGEX"))
           regex=true;
public void characters(char [] text,int start,int length)throws SAXException {
          String t=new String(text,start,length);
          boolean flag=false;
          if(regex==true)
            Pattern pattern;
            String w=new String(t);
          pattern = Pattern.compile(w);
          Matcher matcher;
          matcher=pattern.matcher("there is a bat   read write 13    error at line ");
          while(matcher.find())
           flag=true;
           System.out.println("I found the text \"" + matcher.group() +"\" starting at index "
           + matcher.start() +"and ending at index " + matcher.end() + ".");
         if(!flag)
           System.out.println("not found");
         regex=false;
public class saxt2 {
     public static void main(String args[]) {
          try {
                XMLReader parser= XMLReaderFactory.createXMLReader();
                ContentHandler handler=new textextractor();
                parser.setContentHandler(handler);
                                parser.parse("d:\\regex.xml");
              }catch (Exception e) {
               System.err.println(e);
}The xml file is
                  <RegularExpression>
                  <REGEX>write</REGEX>
                  <REGEX>write \\d+</REGEX>
                  <REGEX>read[0-9]</REGEX>
                  </RegularExpression>by running the code you can see that write is found,write \\d+ doesn't match write 13 in the string and read[0-9] gives and error.
Any help will be greatly appreciated

How to write regular expression to find desired string piece *duplicate*

Hi All,
Suppose that i have following string piece:
name:ali#lastname:kemal#name:mehmet#lastname:cemalI need
ali
mehmetI use following statement
SQL> select lst, regexp_replace(lst,'(name:)(.*)(lastname)(.*)','\2',1,1) nm from (
2 select 'name:ali#lastname:kemal#name:mehmet#lastname:cemal' as lst from dual
3 );
LST NM
name:ali#lastname:kemal#name:mehmet#lastname:cemal ali#lastname:kemal#name:mehmet#
SQL> But it does not return names correctly. When i change 5th parameter(occurence) of regexp_replace built-in function(e.g. 1,2), i may get ali and mehmet respectiveley.
Any ideas about regexp?
Note : I can use PL/SQL instr/substr for this manner; but i do not want to use them. I need regexp.
Regards...
Mennan
Edited by: mennan on Jul 4, 2010 9:53 PM
thread was posted twice due to chrome refresfment. Please ignore the thread and reply to How to write regular expression to find desired string piece

The approach is to do cartesian join to a 'number' table returning number of records equal to number of names in the string.I have hardcoded 2 but you can use regexp_count to get the number of occurrences of the pattern in the string and then use level <=regexp_count(..... .
See below for the approach
with cte as(
select
'name:ali#lastname:kemal#name:mehmet#lastname:cemal' col ,level lev
from dual connect by level <=2)
select substr(regexp_substr('#'||col,'#name:\w+',1,lev),7)
from cte
/

Regular expression and output format

hi all,
i have following scenario-
regular expression: [0-9]{3}-[0-9]{3}-[0-9]{4}
generated value by the above regular expression: 123-234-6789
output format to display the generated above value: xxx-xxx-$1
now i need to display the generated value (123-234-6789) in the specified output format (xxx-xxx-$1) and the final output will be xxx-xxx-6789
how is it possible?
Note: here regular expression and output format can vary
br,
bashar

Hi, Bashar
You can solve this problem by using the Data Masking Technique.
Masking data means replacing certain fields with a Mask character (such as an X). This effectively disguises the data content while preserving the same formatting on front end screens and reports. For example, a column of credit card numbers might look like:
4346 6454 0020 5379
4493 9238 7315 5787
4297 8296 7496 8724
and after the masking operation the information would appear as:
4346 XXXX XXXX 5379
4493 XXXX XXXX 5787
4297 XXXX XXXX 8724
The masking characters effectively remove much of the sensitive content from the record while still preserving the look and feel. Take care to ensure that enough of the data is masked to preserve security.
It would not be hard to regenerate the original credit card number from a masking operation such as: 4297 8296 7496 87XX since the numbers are generated with a specific and well known checksum algorithm.
Best Regards,
Mahfuz Khan

"Match Regular Expression" and "Match Pattern" vi's behave differently

Hi,
I have a simple string matching need and by experimenting found that the "Match Regular Expression" and "Match Pattern" vi's behave somewhat differently. I'd assume that the regular expression inputs on both would behave the same. A difference I've discovered is that the "|" character (the "vertical bar" character, commonly used as an "or" operator) is recognized as such in the Match Regular Expression vi, but not in the Match Pattern vi (where it is taken literally). Furthermore, I cannot find any documentation in Help (on-line or in LabVIEW) about the "|" character usage in regular expressions. Is this documented anywhere?
For example, suppose I want to match any of the following 4 words: "The" or "quick" or "brown" or "fox". The regular expression "The|quick|brown|fox" (without the quotes) works for the Match Regular Expression vi but not the Match Pattern vi. Below is a picture of the block diagram and the front panel results:
The Help says that the Match Regular Expression vi performs somewhat slower than the Match Pattern vi, so I started with the latter. But since it doesn't work for me, I'll use the former. But does anyone have any idea of the speed difference? I'd assume it is negligible in such a simple example.
Thanks!
Solved!
Go to Solution.

Yep-
You hit a point that's frustrated me a time or two as well (and incidentally, caused some hair-pulling that I can ill afford)
The hint is in the help file:
for Match regular expression "The Match Regular Expression function gives you more options for matching
strings but performs more slowly than the Match Pattern function....Use regular
expressions in this function to refine searches....
Characters to Find
Regular Expression
VOLTS
VOLTS
A plus sign or a minus sign
[+-]
A sequence of one or more digits
[0-9]+
Zero or more spaces
\s* or * (that is, a space followed by an asterisk)
One or more spaces, tabs, new lines, or carriage returns
[\t \r \n \s]+
One or more characters other than digits
[^0-9]+
The word Level only if it
appears at the beginning of the string
^Level
The word Volts only if it
appears at the end of the string
Volts$
The longest string within parentheses
The first string within parentheses but not containing any
parentheses within it
$[^()]*$
A left bracket
A right bracket
cat, cag, cot, cog, dat, dag, dot, and dag
[cd][ao][tg]
cat or dog
cat|dog
dog, cat
dog, cat cat dog,cat
cat cat dog, and so on
((cat )*dog)
One or more of the letter a
followed by a space and the same number of the letter a, that is, a a, aa aa, aaa aaa, and so
on
(a+) \1
For Match Pattern "This function is similar to the Search and Replace
Pattern VI. The Match Pattern function gives you fewer options for matching
strings but performs more quickly than the Match Regular Expression
function. For example, the Match Pattern function does not support the
parenthesis or vertical bar (|) characters.
Characters to Find
Regular Expression
VOLTS
VOLTS
All uppercase and lowercase versions of volts, that is, VOLTS, Volts, volts, and so on
[Vv][Oo][Ll][Tt][Ss]
A space, a plus sign, or a minus sign
[+-]
A sequence of one or more digits
[0-9]+
Zero or more spaces
\s* or * (that is, a space followed by an asterisk)
One or more spaces, tabs, new lines, or carriage returns
[\t \r \n \s]+
One or more characters other than digits
[~0-9]+
The word Level only if it begins
at the offset position in the string
^Level
The word Volts only if it
appears at the end of the string
Volts$
The longest string within parentheses
The longest string within parentheses but not containing any
parentheses within it
([~()]*)
A left bracket
A right bracket
cat, dog, cot, dot, cog, and so on.
[cd][ao][tg]
Frustrating- but still managable.
Jeff

Regular expressions and sql

I have working regular expressions and a working sql connection, but I don�t know how to stop the info from getting into the database when input doesent match the regular expression.
For instans, you put in an e-mail without an "@" and my program writes and error message. But the info still gets in to the database.
Any help would be much apreciated as I dont know where to start. If you have links or code examples that would be great to.
Thanx.

Well, the obvious answer is "only write the data to the database if the input doesn't match the regular expression."
Presumably you're really asking how to do that - but it depends upon how your application is structured in the first place, and you haven't told us anything at all about that.

Regular Expression and PL/SQL help

I am using Oracle 9i, does 9i support regular expression? What functions are there?
My problem is the birth_date column in my database comes from teleform ( a scan program that reads what people wrote on paper), so the format is all jacked up.... 50% of them are 01/01/1981, 10% are 5/14/1995, 10% are 12/5/1993, 10% are 1/1/1983, 10% are 24-JUL-98. I have never really used regular expression and pl/sql, can anybody help me convert all of them to 01/01/1998?
Does Oralce 9i support regular expression? What can I do if oralce 9i does not support regular expression? Thank you very much in advance.

9i doesn't support regular expressions (at least not in the 10g regular expressions sense. There is an OWA_PATTERN_MATCH package that has some facilities for regular expressions). But it doesn't look like this is a regular expressions problem.
Instead, this is probably a case where you need to
- enumerate the format masks you want to try
- determine the order you want to try them
- write a small function that tries each format mask in succession until one matches.
Of course, there is no guarantee that you'll ever be able to convert the data to the date that the user intended because some values will be ambiguous. For example, 01/02/03 could mean Feb 1, 2003 or Jan 2, 2003 or Feb 3, 2001 depending on the person who entered the data.
Assuming you can define the order, your function would just try each format mask in turn until one generated a valid date, i.e.
BEGIN
BEGIN
    l_date := TO_DATE( p_string_value, format_mask_1 );
    RETURN l_date;
EXCEPTION
    WHEN OTHERS THEN
      NULL;
END;
BEGIN
    l_date := TO_DATE( p_string_value, format_mask_2 );
    RETURN l_date;
EXCEPTION
    WHEN OTHERS THEN
      NULL;
END;
BEGIN
    l_date := TO_DATE( p_string_value, format_mask_3 );
    RETURN l_date;
EXCEPTION
    WHEN OTHERS THEN
      NULL;
END;
BEGIN
    l_date := TO_DATE( p_string_value, format_mask_N );
    RETURN l_date;
EXCEPTION
    WHEN OTHERS THEN
      NULL;
END;
RETURN NULL;
END;Justin

Regular expressions and backreference

Hello!
I am trying to use backreferences in REGEXP in the PERL-style, where I want to match my regular expression and later refer to the grouped values. I can read that those are referecenced with \1 .. \9, but I simply cant get it to work. Here is an example in PL/SQL:
SELECT REGEXP_SUBSTR(l_users.adresse,'([A-Z]+)\s+(\d+)')
INTO l_dummy_varchar2
FROM dual;
OR I could do things like:
l_dummy_varchar2 := REGEXP_SUBSTR(l_users.adresse,'([A-Z]+)\s+(\d+)');
It seems to work, but I cant figure out how to get the backreferenced value.
I would love to do things like:
dbms_output.put_line('my value ='||\1)
but this doesnt work.
Help is very much appreciated.
Best regards
Dannie

Likewise you can extract things using the
REGEXP_SUBSTR, but you don't need back
referencing...backreferencing is better than additional function (ltrim) use, and BTW be careful with this "ltrims":
SQL> set serveroutput on
SQL>
SQL> DECLARE
2       v_txt VARCHAR2(100);
3     BEGIN
4       v_txt := ltrim(regexp_substr('HERE IS AN ASCII CHARACTER', 'IS AN [[:alnum:]]*'),'IS AN ');
5       DBMS_OUTPUT.PUT_LINE('Word after IS AN: '||v_txt);
6 END;
7 /
Word after IS AN: CII
PL/SQL procedure successfully completed
SQL>
SQL> DECLARE
2       v_txt VARCHAR2(100);
3     BEGIN
4       v_txt := regexp_replace('HERE IS AN ASCII CHARACTER', 'IS AN ([[:alnum:]]*)|.','\1');
5       DBMS_OUTPUT.PUT_LINE('Word after IS AN: '||v_txt);
6 END;
7 /
Word after IS AN: ASCII
PL/SQL procedure successfully completed
SQL> -----------
VB
http://volder-notes.blogspot.com/

Can somebody help me in getting some good material for Regular Expressions and IP Community list

can somebody help me in getting some good material for Regular Expressions and IP Community list

I'm not sure what you mean by "IP Community list", but here are 3 reference sites for Regular Expressions:
Regular Expression Tutorial - Learn How to Use Regular Expressions
http://www.regular-expressions.info/tutorial.html
Regular Expressions Cheat Sheet by DaveChild
http://www.cheatography.com/davechild/cheat-sheets/regular-expressions/
Regular Expressions Quick Reference
http://www.autohotkey.com/docs/misc/RegEx-QuickRef.htm

Find text using regular expression and add highlight annotation

Hi Friends
Is it possible to find text using regular expression and add highlight annotation using plugin

A plugin can use the PDWordFinder to get a list of the words on a page, and their location. That's all that the API offers for searching. Of course, you can use a regular expression library to work with that word list.

Assistance with Regular Expression and Tcl

Assistance with Regular Expression and Tcl
Hello Everyone,
I recently began learning Tcl to develop scripts for automating network switch deployments.
In my script, I want to name the device with a location and the last three octets of the base mac address.
I can get the Base MAC address by :
show version | include Base
Base ethernet MAC Address       : 00:00:00:DB:CE:00
And I can get the last three octets of the MAC address using the following regular expression.
([0-9a-f]{2}[:-]){2}([0-9a-f]{2}$)
But I have not been able to figure out how to call the regular expression in the tcl script.
I have checked several resources but have not been able to figure it out. Suggestions?
Ultimately, I want to set the last three octets to a variable (something like below) and then call the variable when I name the switch.
set mac [exec "sh version | i Base"] (include the regular expression)
ios_config "hostname location$mac"
Thanks for any assistance in advance.
Chris

This worked for me.
Switch_1(tcl)#set result [exec show ver | inc Base]
Base ethernet MAC Address       : 00:1B:D4:F8:B1:80
Switch_1(tcl)#regexp {([0-9A-F:]{8}\r)} $result -> mac
1
Switch_1(tcl)#puts $mac
F8:B1:80
Switch_1(tcl)#ios_config "hostname location$mac"
%Warning! Hostname should contain at least one alphabet or '-' or '_' character
locationF8:B1:80(tcl)#

Regular Expressions and String variables

Hi,
I am attempting to implement a system for searching text files for regular expression matches (similar to something like TextPad, etc.).
Looking at the regular expression API, it appears that you can only match using string variables. I just wanted to make sure this is true. Some of these files might be large and I feel uneasy about loading them into ginormous Strings. Is this the only way to do it? Can I make a String as big as I want?
Thanks,
-Mike

Newlines are only a problem if you're reading the
text line-by-line and applying the regexp to each
line. It wouldn't catch expressions that span
lines.
@sabre150: your note re: CharSequence -- so what
you're suggesting is to implement a CharSequence that
wraps the file contents, and then use the regexps on
the whole thing? I like the idea but it seems like
it would only be easy to implement if the file uses a
fixed-width character set. Or am I missing
something...?You are correct for the most basic implementation. It is very easy to create a char sequence for fixed width character sets using RandomAccessFile. Once you go to character sets such as UTF-8 then more effort is required.
While ever the regex is moving forward thought the CharSequence one char at a time there is no problem because one can wrap a Reader but once it backtracks then one needs random access and one will need to have a buffer. I have used a ring buffer for this which seems to work OK but of course this will not allow the regex to move to any point in the CharSequence.
'uncle_alice' is the regex king round here so listen to him.
:-( I should read further ahead next time!
Message was edited by:
sabre150
Message was edited by:
sabre150

Regular expressions and string matching

Hi everyone,
Here is my problem, I have a partially decrypted piece string which would appear something like.
Partially deycrpted:     the?anage??esideshe?e
Plain text:          themanagerresideshere
So you can see that there are a few letter missing from the decryped text. What I am trying to do it insert spaces into the string so that I get:
                    The ?anage? ?esides he?e
I have a method which splits up the string in substrings of varying lengths and then compares the substring with a word from a dictionary (implemented as an arraylist) and then inserts a space.
The problem is that my function does not find the words in the dictionary because my string is only partially decryped.
     Eg:     ?anage? is not stored in the dictionary, but the word �manager� is.
So my question is, is there a way to build a regular expression which would match the partially decrypted text with a word from a dictionary (ie - ?anage? is recognised and �manager� from the dictionary).

I wrote the following method in order to test the matching using . in my regular expression.
public void getWords(int y)
int x = 0;
for(y=y; y < buff.length(); y++){
String strToCompare = buff.substring(x,y); //where buff holds the partially decrypted text
x++;
Pattern p = Pattern.compile(strToCompare);
for(int z = 0; z < dict.size(); z++){
String str = (String) dict.get(z); //where dict hold all the words in the dictionary
Matcher m = p.matcher(str);
if(m.matches()){
System.out.println(str);
System.out.println(strToCompare);
// System.out.println(buff);
If I run the method where my parameter = 12, I am given the following output.
aestheticism
aestheti.is.
demographics
de.o.ra.....
Which suggests that the method is working correctly.
However, after running for a short time, the method cuts and gives me the error:
PatternSyntaxException:
Null(in java.util.regex.Pattern).
Does anyone know why this would occur?

Regular Expressions and Numbers in Strings

Similar Messages

Maybe you are looking for