Remove Duplicate Rows from Left Outer Join
Hi All,
I am new to Oracle..I have two tables as follow:
TableA(EmpID, Empname)
TableB(EmpID, DeptID, DeptName). A employee can work in multiple dept.
table A has 1 row as EmpID 1 and TableB has two rows for EmpID 1.
I have a search page which takes dept ID as parameter and return employee name...Dept ID is not mandatory feld for Search. If DeptID is passed it should return the employee who belongs to that Dept otherwise it should return 1 employee..
Now I have used as follow:
:IN_DEPTID is passed as parameter
Select EmpName from TableA Left Join tableB on a.EmpID = B.EmpID
WHERE
CASE WHEN :IN_DEPTID IS NULL
IN_DEPTID IS NULL
ELSE|
DEPTID = :IN_DEPTID
Now problem is when Dept ID is passed it correctly returns a row but if no deptid is passed it returns 2 rows but i want ony one row as there is only one employee.
Please help;
Edited by: user10239708 on 10 Sep, 2008 12:24 AM
Edited by: user10239708 on 10 Sep, 2008 12:28 AM
Try this
Select
from
tableA a
where
(exists (select 1 from tableB b where a.empid = b.empid and deptid = :IN_DEPTID )
or
:IN_DEPTID is null) you database design is not good you should keep the emp, department mapping in different table.
Regards
Singh
Similar Messages
-
First attempt to remove duplicate rows from a table...
I have seen many people asking for a way to remove duplicate rows from data. I made up a fairly simple script. It adds a column to the table with the cell selected in it, and adds the concatenation of the data to the left into that new column. then it reads that into a list, and walks through that list to find any that are listed twice. Any that are it marks for DELETE.
It then walks through to find each one marked for delete and removes them (you must go from bottom to top to do this, otherwise your row markings for delete don't match up to the original rows anymore). Last is to delete the column we added.
tell application "Numbers"
activate
tell document 1
-- DETERMINE THE CURRENT SHEET
set currentsheetindex to 0
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of (tables whose selection range is not missing value)
end tell
if x is not 0 then
set the currentsheetindex to i
exit repeat
end if
end repeat
if the currentsheetindex is 0 then error "No sheet has a selected table."
-- GET THE TABLE WITH CELLS
tell sheet currentsheetindex
set the current_table to the first table whose selection range is not missing value
end tell
end tell
log current_table
tell current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
repeat with i from 1 to (z - 1)
set m to m & value of (cell i of row j)
end repeat
set value of cell z of row j to m
end repeat
set MyRange to value of every cell of column z
repeat with i from 1 to (count of items of MyRange)
set n to item i of MyRange
if n is in list1 then
set end of list1 to "Delete"
else
set end of list1 to n
end if
end repeat
repeat with i from (count of items of list1) to 1 by -1
set n to item i of list1
if n = "Delete" then remove row i
end repeat
remove column z
end tell
end tell
Let me know how it works for y'all, it worked good on my machine, but I know localization is causing errors sometimes when I post things.
Thanks,
Jason
Message was edited by: jaxjasonHi jason
I hope that with the added comments it will be clear.
Ask if something is always opaque.
set {current_Range, current_table, current_Sheet, current_Doc} to my getSelection()
tell application "Numbers09"
tell document current_Doc to tell sheet current_Sheet to tell table current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
tell row j
repeat with i from 1 to (z - 1)
set m to m & value of cell i
end repeat
set value of cell z to m
end tell
end repeat
set theRange to value of every cell of column z
repeat with i from (count of items of theRange) to 1 by -1
(* As I scan the table backwards (starting from the bottom row),
I may remove a row immediately when I discover that it is a duplicate *)
set n to item i of theRange
if n is in list1 then
remove row i
else
set end of list1 to n
end if
end repeat
remove column z
end tell
end tell
--=====
on getSelection()
local _, theRange, theTable, theSheet, theDoc, errMsg, errNum
tell application "Numbers09" to tell document 1
set theSheet to ""
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of tables
if x > 0 then
repeat with y from 1 to x
(* Open a trap to catch the selection range.
The structure of this item
«class
can't be coerced as text.
So, when the instruction (selection range of table y) as text
receive 'missing value' it behaves correctly and the lup continue.
But, when it receive THE true selection range, it generates an error
whose message is errMsg and number is errNum.
We grab them just after the on error instruction *)
try
(selection range of table y) as text
on error errMsg number errNum (*
As we reached THE selection range, we are here.
We grab the errMsg here. In French it looks like:
"Impossible de transformer «class
The handler cuts it in pieces using quots as delimiters.
item 1 (_) "Impossible de transformer «class » "
item 2 (theRange) "A2:M25"
item 3 (_) " of «class NmTb» "
item 4 (theTable) "Tableau 1"
item 5 (_) " of «class NmSh» "
item 6 (theSheet) "Feuille 1"
item 7 (_) " of document "
item 8 (theDoc) "Sans titre"
item 9 ( I drop it ) " of application "
item 10 ( I drop it ) "Numbers"
item 11 (I drop it ) " en type string."
I grab these items in the list
{_, theRange, _, theTable, _, theSheet, _, theDoc}
Yes, underscore is a valid name of variable.
I often uses it when I want to drop something.
An alternate way would be to code:
set ll to my decoupe(errMsg, quote)
set theRange to item 2 of ll
set theTable to item 4 of ll
set theSheet to item 8 of ll
set theDoc to item 10 of ll
it works exactly the same but it's not so elegant.
set {_, theRange, _, theTable, _, theSheet, _, theDoc} to my decoupe(errMsg, quote)
exit repeat (*
as we grabbed the interesting datas, we exit the lup indexed by y.*)
end try
end repeat -- y
if theSheet > "" then exit repeat (*
If we are here after grabbing the datas, theSheet is not "" so we exit the lup indexed by i *)
end if
end tell -- sheet
end repeat -- i
(* We may arrive here with two kinds of results.
if we grabbed a selection, theSheet is something like "Feuille 1"
if we didn't grabbed a selection, theSheet is the "" defined on entry
and we generate an error which is not trapped so it stops the program *)
if theSheet = "" then error "No sheet has a selected table."
end tell -- document
(* Now, we send to the caller the interesting datas :
theRange "A2:M25"
theTable "Tableau 1"
theSheet "Feuille 1"
theDoc "Sans titre" *)
return {theRange, theTable, theSheet, theDoc}
end getSelection
--=====
on decoupe(t, d)
local l
set AppleScript's text item delimiters to d (*
Cut the text t in pieces using d as delimiter *)
set l to text items of t
set AppleScript's text item delimiters to "" (*
Resets the delimiters to the standard value. *)
(* Send the list to the caller *)
return l
end decoupe
--=====
Have fun
And if it's not clear enough, you may ask for more explanations.
Yvan KOENIG (from FRANCE mardi 27 janvier 2009 21:49:19) -
Removing duplicate rows from SELECT
Hi, I was wondering if there was any way to remove duplicate rows from a select statement.
My table looks like this:
CREATE TABLE CUS_ID_TO_PC_ID (
CUSTOMER_ID VARCHAR2 (10) NOT NULL,
PC_ID VARCHAR2 (25) NOT NULL,
PASSWORD VARCHAR2 (25) NOT NULL,
REG_DATE DATE,
PRODUCT_DESC VARCHAR2 (25),
EXPIRE_DATE DATE,
SERIAL_NBR VARCHAR2 (12),
LDAP_USER VARCHAR2 (200),
COMMENTS VARCHAR2 (2000),
PC_ID_5_4 VARCHAR2 (25),
PC_ID_6_0 VARCHAR2 (25),
PASSWORD_5_4 VARCHAR2 (25),
PASSWORD_6_0 VARCHAR2 (25),
PC_ID_6_1 VARCHAR2 (25),
PASSWORD_6_1 VARCHAR2 (25),
OPERATING_SYSTEM VARCHAR2 (20),
STATUS VARCHAR2 (1)
Basically, I want to retrieve all columns from the table but remove all duplicate variations of
the pc_id/serial_nbr combinations.
For example, given this data:
PC_ID SERIAL_NBR CUSTOMER_NO
1234567 AAA C345
1234567 AAA C567
3333333 BBB C456
only the 1st and 3rd rows would be returned.
Any ideas?Try something like this:
select * from your_table yt
where rowid in (select max(rowid)
from your_tabel yt2
where yt2.pc_id = yt.pc_id
and yt2.serial_nbr = yt.serial_nbr); -
Need to remove duplicate rows from a table
Hi Gurus ,
I am using oracle 11.2.0.3 .
SQL> desc osstage.S_EVT_ACT_X;
Name Null? Type
ROW_ID NOT NULL VARCHAR2(15 CHAR)
LAST_UPD NOT NULL DATE
PAR_ROW_ID NOT NULL VARCHAR2(15 CHAR)
ATTRIB_17 NUMBER(22,7)
ATTRIB_26 DATE
ATTRIB_02 VARCHAR2(100 CHAR)
PROCESS_TIMESTAMP TIMESTAMP(6);
now when i give the below command it gives the error as someone has disabled the constraint accidently .
alter table s_evt_act_x enable constraint S_EVT_ACT_X_P1;
Error starting at line 3 in command:
alter table s_evt_act_x enable constraint S_EVT_ACT_X_P1
Error report:
SQL Error: ORA-02437: cannot validate (OSSTAGE.S_EVT_ACT_X_P1) - primary key violated
02437. 00000 - "cannot validate (%s.%s) - primary key violated"
*Cause: attempted to validate a primary key with duplicate values or null
values.
*Action: remove the duplicates and null values before enabling a primary
key.
Can you please guide me with this issue .Please refer
Script: Deleting Duplicate Rows from a Table (Doc ID 31413.1)
How to Find or Delete Duplicate Rows in a Table (Doc ID 1004425.6) -
Need to remove duplicate rows from distinct query
Hello,
I have the following query:
SELECT tiab.abnr abnr, tiab.namn namn, (CAST(tiab.GATUNR||' '||tiab.gata AS VARCHAR2(254))) ADR, tiab.boxpnr boxpnr, tiab.boxort boxort,
(CAST(tiab.RIKTNRDISPLAY AS VARCHAR2(254))) RIKTNR, (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) TELNR,
DECODE((select count(tior.tigilopnr) from tis.tior where abnr = tiab.abnr and inplnr IN (3797886)),0 ,NULL , 1, tior.tigilopnr, 'N/A') tigilopnr
FROM tis.tiab
JOIN tis.tior on tiab.abnr = tior.abnr
WHERE tior.inplnr IN (3797886)
ORDER BY tiab.ABNR )
ORDER BY abnr;
It returns the following:
14684940 Pizza Station Inc The Lafayette 26170 St Marys 304 684-2411
15123161 Chris Test 554 Easy St n 43333 Columbus 614 555-5555
15123162 Chris Test2 5556 Easy St 43333 Columbus 614 555-5151 2553304 --> keep this one
15123162 Chris Test2 5556 Easy St 43333 Columbus 614 555-5151 -- not show this
I have tried several different things as well as looking through the forums but have not found anything that will only give me unique records based only on the first column. This query works fine as long as there
are not 2 records returned with column1 being identical.
Final results should look like this:
14684940 Pizza Station Inc The Lafayette 26170 St Marys 304 684-2411
15123161 Chris Test 554 Easy St n 43333 Columbus 614 555-5555
15123162 Chris Test2 5556 Easy St 43333 Columbus 614 555-5151 2553304
Thanks in advance for the assistance.Hello,
Try:
SELECT abnr, namn, ADR, boxpnr, boxort,RIKTNR, TELNR,tigilopnr
FROM (
SELECT tiab.abnr abnr, tiab.namn namn, (CAST(tiab.GATUNR||' '||tiab.gata AS VARCHAR2(254))) ADR, tiab.boxpnr boxpnr, tiab.boxort boxort,
(CAST(tiab.RIKTNRDISPLAY AS VARCHAR2(254))) RIKTNR, (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) TELNR,
DECODE((select count(tior.tigilopnr) from tis.tior where abnr = tiab.abnr and inplnr IN (3797886)),0 ,NULL , 1, tior.tigilopnr, 'N/A') tigilopnr,
ROW_NUMBER () OVER (PARTITION BY tiab.abnr ORDER BY (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) NULLS LAST) row_num
FROM tis.tiab
JOIN tis.tior on tiab.abnr = tior.abnr
WHERE tior.inplnr IN (3797886))
WHERE row_num <= 1
ORDER BY abnr;Or, with your current query:
SELECT abnr, namn, ADR, boxpnr, boxort,RIKTNR, TELNR,tigilopnr
FROM (
SELECT distinct tiab.abnr abnr, tiab.namn namn, (CAST(tiab.GATUNR||' '||tiab.gata AS VARCHAR2(254))) ADR, tiab.boxpnr boxpnr, tiab.boxort boxort,
(CAST(tiab.RIKTNRDISPLAY AS VARCHAR2(254))) RIKTNR, (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) TELNR,
DECODE((select count(tior.tigilopnr) from tis.tior where abnr = tiab.abnr and inplnr IN (3797886)),0 ,NULL , 1, tior.tigilopnr, 'N/A') tigilopnr,
ROW_NUMBER () OVER (PARTITION BY tiab.abnr ORDER BY (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) NULLS LAST) row_num
FROM tis.tiab
JOIN tis.tior on tiab.abnr = tior.abnr
WHERE tior.inplnr IN (3797886))
WHERE row_num <= 1
ORDER BY abnr; -
Removing Duplicate Rows from resultSet
I have a query pulling data from 5 tables in 12 columns. I have rows where all of the data is duplicated with the exception of one date column. How would I go about deleting rows that are duplicates with the exception of this one column? I still need to pull the date from the date column with the Max(date).
i.e.
Bob Smith 1 2 3 4 12-Jul-2006
Bob Smith 1 2 3 4 02-Aug-2006
Bob Smith 1 2 3 4 21-Jan-2006
Form this resultset I only want one row
Thanks.this example might be of help.
SQL> select * from employees;
YEAR EM NAME PO
2001 02 Scott 91
2001 02 Scott 01
2001 02 Scott 07
2001 03 Tom 81
2001 03 Tom 84
2001 03 Tom 87
6 rows selected.
SQL> select year, empcode, name, position,
2 row_number() over (partition by year, empcode, name
3 order by year, empcode, name, position) as rn
4 from employees;
YEAR EM NAME PO RN
2001 02 Scott 01 1
2001 02 Scott 07 2
2001 02 Scott 91 3
2001 03 Tom 81 1
2001 03 Tom 84 2
2001 03 Tom 87 3
6 rows selected.
SQL> Select year, empcode, name, position
2 From (Select year, empcode, name, position,
3 row_number() over (partition by year, empcode, name
4 order by year, empcode, name, position) as rn
5 From employees) emp
6 Where rn = 1;
YEAR EM NAME PO
2001 02 Scott 01
2001 03 Tom 81
SQL> Delete From employees
2 Where rowid in (Select emp.rid
3 From (Select year, empcode, name, position,
4 rowid as rid,
5 row_number() over (partition by year, empcode, name
6 order by year, empcode, name, position) as rn
7 From employees) emp
8 Where emp.rn > 1);
4 rows deleted.
SQL> select * from employees;
YEAR EM NAME PO
2001 02 Scott 01
2001 03 Tom 81
SQL> if you can post a sample create tables and data it will help us provide you a some solutions. -
Left Outer Join on same table clarification
HI,
I have a table that gets populated from 3<sup>rd</sup> party system. We don’t have control over it. So, the table has master record (master) and children. Master type is 78 and children’s type is 64. So, it looks like this. In the 3<sup>rd</sup>
party system, if Master transaction gets cancelled, it is recorded as type 178. If child is cancelled, then it is 164. Once the child is cancelled and created again using one process then newly created transaction will have 65 as type. Same thing with Master
cancelled transaction also. It will be 79. So, to summarize:
Master:
Brand New Transaction type = 78
Cancelled Transaction type = 178
Cancelled with creation transaction type = 79
Child:
Brand New Transaction type = 64
Cancelled Transaction type = 164
Cancelled with creation transaction type = 65
I don’t have to bother about master records. I need to focus on only children for my query.
ID
TxnID
Master
Type
TDate
Location
193075
211554
211543
64
20140805
ABC
193076
211555
211543
64
20140805
NBC
193077
211556
211543
64
20140805
ABC
193080
211559
211558
64
20140805
ABC
193081
211562
211561
64
20140805
ABC
193082
211565
211564
64
20140805
CBC
193083
211565
211564
164
20140805
CBC
193084
211566
211564
65
20140805
AZC
--drop
table #Transactions
CREATE
TABLE #Transactions
ID
int,
TxnID
int,
mstTicket
int,
Typecode
int,
Tdate
datetime,
Location
varchar(10)
select
* from
#Transactions
Insert
into #Transactions
(ID,
TxnID,
mstTicket,Typecode,Tdate,Location)
Select 193075, 211554,211543,64,'2014-08-05','ABC'
UNION ALL
Select 193076, 211555,211543, 64,
'2014-08-05',
'NBC' UNION ALL
Select 193077, 211556, 211543, 64,
'2014-08-05',
'ABC' UNION
ALL
Select 193080, 211559, 211558, 64,
'2014-08-05',
'ABC' UNION
ALL
Select 193081, 211562, 211561, 64,
'2014-08-05',
'ABC' UNION
ALL
Select 193082, 211565, 211564, 64,
'2014-08-05',
'CBC' UNION
ALL
Select 193083, 211565, 211564, 164,
'2014-08-05',
'CBC' UNION
ALL
Select 193084, 211566, 211564, 65,
'2014-08-05',
'AZC'
select
T.TxnID,
T.TypeCode,
T.Location,
TL.TxnID
From
#Transactions T
Left Outer
JOIN #Transactions
TL ON
TL.TxnID
= T.TxnID
and TL.TypeCode
= 164
select
T.TxnID,
T.TypeCode,
T.Location,
TL.TxnID
From
#Transactions T
Left Outer
JOIN #Transactions
TL ON
TL.TxnID
= T.TxnID
and TL.TypeCode
= 164
Where
T.typecode
in (64, 65)
I need a clarification regarding left Outer Join.
In the first left outer join query both 64 and 164 both have TL.TxnID populated. Why is that?. What I understand from
left outer join is that ‘Returns all the rows’ from left table and only matching data from right table.
Here, matching row from right table is 211565 and 164 record (id 193083). So, only it should have TxnID populated. But row 211565 and 64 has TL.txnID getting populated (ID 193082).
Why is it? Am I not understanding left out join properly?
Thanks,Thank you Shailesh. I understood what join does in left outer join. I was thinking
Left Outer JOIN #Transactions TL ON TL.TxnID = T.TxnID and TL.TypeCode = 164 is same as
Left Outer JOIN #Transactions TL ON TL.TxnID = T.TxnID and TL.TypeCode = T.TypeCode
and TL.TypeCode = 164
#Transactions
T
Left
Outer
JOIN
#Transactions
TL
ON
TL.TxnID
=
T.TxnID
and
TL.TypeCode
= 164
Where
T.typecode
in
(64,
65) -
Nested Left Outer Join : Data Set
Hi All
I am bit confused about data set used by Nested Left outer join.
Can anyone help me.
Here is sample data:
Tables (Name, 3 Column each, total rows and matched rows if any):
Table 1
A B C
Total 20 Rows
Table 2
A D E
Total 50 Rows and 10 Matching on 2.A = 1.A
Table 3
D M N
Total 15 Rows and 15 Matching on 3.D = 2.D
Table 4
M X Y
Total 20 Rows and 10 Matching on 4.M = 3.M
Sql
select *
From Table 1
Left Outer Join on Table 2 on
2.A = 1.A
-- Data set 1 will contain 20 Rows (10 matching and 10 non matching)
Left Outer Join on Table 3 on
3.D = 2.D
-- What will be data set? 20 Rows of Data set 1 or 15 Matching Rows?
Left Outer Join on Table 4 on
4.M = 3.M
-- What will be data set? X Rows of Data set 2 or 10 Matching Rows?
Please have a look and clear my understanding.SeshuGiri wrote:
I have two tables defined (below). Emp table has data and there is no data in Emp_Type table yet! Right now it is empty.
I want to write a query that returns data from both the tables even though there is no data in Emp_type table. I am using left outer join but it returning nothing. Anyone can help?
select *
from emp e
left outer join emp_Type t
on e.empid = t.empid
WHERE t.type_id = 1
and t.end_date is null;
The join is including all rows from emp, just like you want.
The WHERE clause is discarding all of those rows. Since all the columns from emp_type (alias t) are NULL, the condition "t.type_id = 1" in the WHERE clause is never true.
Perhaps you meant to include all those conditions in the join conditions, like this:
select *
from emp e
left outer join emp_Type t
on e.empid = t.empid
and t.type_id = 1
and t.end_date is null;Edited by: Frank Kulash on Jan 30, 2012 3:56 PM -
Left outer join using date range returns too many rows
I am trying to pull data for a website.
Names table:
company_name varchar2(30)
julian_day varchar2(3)
logins number(3)
login_errors number(3)
Given a julian date range (e.g. 250-252), I am displaying the information from the Names table.
The problem is that I also need to display changes (increases/decreases) in the data. I do that by coloring the text based on a 10% increase/decrease. Data for the 3 days 250-252 would be compared to data for the previous 3 days 247-249.
Not all companies will report data on all days, so some gaps in the data may exist. Therefore, I cannot do just a simple join.
I am trying to write a query that will give me this information if the user chooses days 250-252.
Company_name
sum(logins) for days 250-252
sum(login_errors) for days 250-252
sum(logins) for days 247-249
sum(login_errors) for days 247-249
The query I'm using is:
select cur.company_name, sum(cur.logins),
sum(cur.login_errors), sum(old.logins), sum(old.login_errors)
FROM names cur LEFT OUTER JOIN names old
ON cur.company_name = old.company_name
WHERE cur.adate>='250' and cur.adate<='252'
and old.adate>='247' and old.adate<='249'
GROUP by cur.company_name
Given this data:
Company_name adate logins login_errors
ABC 247 10 10
ABC 248 20 20
ABC 249 30 30
ABC 250 15 15
ABC 251 25 25
ABC 252 35 35
My problem is that it returns:
adate cur.logins cur.login_err old.logins old.login_err
250 15 15 60 60
251 25 25 60 60
252 35 35 60 60
How can I get it to only give me the one "old" day's data? I went with the LEFT OUTER JOIN because it's possible that there is no data for an "old" day.
Thanks in advance.....Your problem stems from the join itself, and would be the same even without the OUTER JOIN. With your data, there are 3 records in cur and 3 records in old. The join matches each record in cur to each record in old resulting in 9 records in total. Without the SUM, this is clear:
SQL> SELECT cur.company_name, cur.logins, cur.login_errors,
2 old.logins, old.login_errors, cur.adate cad, old.adate oad
3 FROM names cur LEFT OUTER JOIN names old
4 ON cur.company_name = old.company_name
5 WHERE cur.adate>=250 and cur.adate<=252 and
6 old.adate>=247 and old.adate<=249;
COMPANY_NA LOGINS LOGIN_ERRORS LOGINS LOGIN_ERRORS CAD OAD
ABC 35 35 10 10 252 247
ABC 25 25 10 10 251 247
ABC 15 15 10 10 250 247
ABC 35 35 20 20 252 248
ABC 25 25 20 20 251 248
ABC 15 15 20 20 250 248
ABC 35 35 30 30 252 249
ABC 25 25 30 30 251 249
ABC 15 15 30 30 250 249
9 rows selected.You can do this with only one reference to the table.
SELECT company_name,
SUM(CASE WHEN adate BETWEEN 250 and 252 THEN logins ELSE 0 END) curlog,
SUM(CASE WHEN adate BETWEEN 250 and 252 THEN login_errors ELSE 0 END) curerr,
SUM(CASE WHEN adate BETWEEN 247 and 249 THEN logins ELSE 0 END) oldlog,
SUM(CASE WHEN adate BETWEEN 247 and 249 THEN login_errors ELSE 0 END) olderr
FROM names
WHERE adate BETWEEN 247 and 252
GROUP BY company_nameHTH
John -
Need to specify LEFT OUTER JOIN while using data from logical database BRM?
I'm trying to extract data for external processing using SQVI. The fields required are in tables BKPF (Document Header) and BSEG (document detail) so I'm using logical database BRM. Note: required fields include the SPGR* (blocking reasons) which don't appear to be in BSIS/BSAS/BSID/BSAD/BSIK/BSAK, hence I can't just use a Table Join on any of these but have to use BSEG, hence BRM.
If the document type is an invoice, I also need to include the PO number from table EKKO (PO header), if present, hence I'd like to add this to the list. However, if I do this, it seems that some records are no longer display, e.g. AB documents.
The interesting thing is that not all records are suppressed, so it's not a simple case of the logical database using an effective INNER JOIN, but the effect is similar.
In any event, is there a way to specify that the link to table EKKO should be treated as an effective LEFT OUTER JOIN, i.e. records from BKPF/BSEG should be included irrespective of whether any records from EKKO/EKPO exist or not?
Alternatively, is there some other way to get the SPGR* fields (for example) from BSEG and still join the BKPF? Of course, one solution is to use multiple queries, but I was hoping to avoid this.Thanks for everyone's responses, I know how to work around the problem with sql, I am wanting to see if there is a way to make the outer joins filter go in the join clause instead of the where clause with Crystal Reports standard functionality.
We have some Crystal Reports users that are not sql users, i.e. benefit specialists, payroll specialists and compensation analysts who have Crystal Reports. I was hoping this functionality was available for them. I just made my example a simple one, but often reports have multiple outer joins with maybe 2 or three of the outer joins needing a filter on them that won't make them into an inner join.
Such as
Select person information
outer join address record
outer join email record
outer join tax record (filter for active state record & filter for code = STATE )
outer join pay rates record
outer join phone#s (filter for home phone#)
I thought maybe the functionality may be available, that I just don't know how or where to use it. Maybe it is just not available.
If it is not available, I will probably need to setup some standard views for them to query, rather than expecting them to pull the tables together themselves. -
Query slow when exctract column from a left outer join
Hi,
in my 2008 i've a query like this:
select a1, a2,a3
from ....
LEFT OUTER JOIN (select a2,a3....
from my_tab_with_170Milionrecords
if I exclude a2,a3 from principal select the elapsed is about 1
If I include a2,a3 the elapsed is abount 40s
How can solve this?
RegardsI posted an example how re-write it
select a1, a2,a3
from ....
LEFT OUTER JOIN
my_tab_with_170Milionrecords ON ........
Instead of subquery LEFT JOIN user the standard LEFT JOIN..
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
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Using Command to fix null / left outer join issue
Hi
I was told awhile ago that it's possible to fix crystal's issue with left outer join and null records being eliminated.
I think i remember most of how this goes, but i can't seem to duplicate it.
1) You can't have any select expert -- record
2) You create the report normally and then make a new report using the SQL Query
- Can't remember if its the whole report or upto the tables that have hisotry (null results)
3) You move parts from WHERE to FROM
Hopefully someone can help correct the steps i'm doing wrong or add what i'm missing from this.
Below is the Query from my comlpeted report, but when i run it with the last LEFT OUTER JOIN added it removes all the products with no sales during that year.
Any help would be greatly appreciated even if it's to say this can't be done.
SELECT
"prod_warehouse"."pw_whs_id",
"prod_warehouse"."pw_prodline_id",
"prod_warehouse"."pw_prod_id",
"prod_warehouse"."pw_bin_location1",
"prod_warehouse"."pw_min_onhand_qty",
"prod_warehouse"."pw_max_onhand_qty",
"prod_warehouse"."pw_onhand_qty",
"product_lookup"."prlkp_lang1_1_desc",
"prod_customer"."prcu_cust_part_num",
"contract_details"."cond_level1_amt",
"sales_history"."sah_year"
FROM (((("sisl_data05"."dbo"."products" "products"
LEFT OUTER JOIN "sisl_data05"."dbo"."prod_warehouse" "prod_warehouse"
ON ("products"."pr_prod_id"="prod_warehouse"."pw_prod_id")
AND ("products"."pr_prodline_id"="prod_warehouse"."pw_prodline_id"))
LEFT OUTER JOIN "sisl_data05"."dbo"."product_lookup" "product_lookup"
ON ("products"."pr_prod_id"="product_lookup"."prlkp_prod_id")
AND ("products"."pr_prodline_id"="product_lookup"."prlkp_prodline_id"))
LEFT OUTER JOIN "sisl_data05"."dbo"."prod_customer" "prod_customer"
ON ("products"."pr_prod_id"="prod_customer"."prcu_prod_id")
AND ("products"."pr_prodline_id"="prod_customer"."prcu_prodline_id"))
LEFT OUTER JOIN "sisl_data05"."dbo"."contract_details" "contract_details"
ON "prod_warehouse"."pw_prod_id"="contract_details"."cond_prod_id")
LEFT OUTER JOIN "sisl_data05"."dbo"."sales_history" "sales_history"
ON (("prod_warehouse"."pw_whs_id"="sales_history"."sah_sortkey1")
AND ("prod_warehouse"."pw_prod_id"="sales_history"."sah_sortkey2"))
AND ("prod_warehouse"."pw_prodline_id"="sales_history"."sah_sortkey3")
WHERE
"prod_warehouse"."pw_whs_id"='20123'
AND ("prod_warehouse"."pw_onhand_qty"<>0
OR "prod_warehouse"."pw_bin_location1"<>' '
OR "prod_warehouse"."pw_max_onhand_qty">0)
AND "sales_history"."sah_year"=2014
ORDER BY "prod_warehouse"."pw_bin_location1", "prod_warehouse"."pw_prod_id"Try this:
SELECT
prod_warehouse.pw_whs_id,
prod_warehouse.pw_prodline_id,
prod_warehouse.pw_prod_id,
prod_warehouse.pw_bin_location1,
prod_warehouse.pw_min_onhand_qty,
prod_warehouse.pw_max_onhand_qty,
prod_warehouse.pw_onhand_qty,
product_lookup.prlkp_lang1_1_desc,
prod_customer.prcu_cust_part_num,
contract_details.cond_level1_amt,
sales_history.sah_year
FROM sisl_data05.dbo.products products
LEFT OUTER JOIN sisl_data05.dbo.prod_warehouse prod_warehouse
ON products.pr_prod_id=prod_warehouse.pw_prod_id
AND products.pr_prodline_id=prod_warehouse.pw_prodline_id
LEFT OUTER JOIN sisl_data05.dbo.product_lookup product_lookup
ON products.pr_prod_id=product_lookup.prlkp_prod_id)
AND products.pr_prodline_id=product_lookup.prlkp_prodline_id
LEFT OUTER JOIN sisl_data05.dbo.prod_customer prod_customer
ON products.pr_prod_id=prod_customer.prcu_prod_id
AND products.pr_prodline_id=prod_customer.prcu_prodline_id
LEFT OUTER JOIN sisl_data05.dbo.contract_details contract_details
ON prod_warehouse.pw_prod_id=contract_details.cond_prod_id
LEFT OUTER JOIN sisl_data05.dbo.sales_history sales_history
ON prod_warehouse.pw_whs_id=sales_history.sah_sortkey1
AND prod_warehouse.pw_prod_id=sales_history.sah_sortkey2
AND prod_warehouse.pw_prodline_id=sales_history.sah_sortkey3
AND sales_history.sah_year = 2014
WHERE prod_warehouse.pw_whs_id='20123'
AND (prod_warehouse.pw_onhand_qty<>0
OR prod_warehouse.pw_bin_location1<>' '
OR prod_warehouse.pw_max_onhand_qty>0)
Take a look at what I've done with the last line of the last join. The issue is that when you left join to a table and you use that table in the Where clause, you've basically turned your you left outer join into an inner join because the record has to be there in order to get the value in the filter. By moving the filter into the join, you'll still get the rest of the data when there is no corresponding record.
NOTE: Crystal adds all sorts of "extra" stuff like quotes and parentheses that you don't need and which I have removed to make the query easier to read.
-Dell -
Performance difference between left outer join / inner join
Hi,
I've got a complex query which among other things accesses quite a large table. If I use inner join to join this table, the response is quite fast and execution plan shows it uses nested loops to gather the data.
If I change inner join to left outer join, I get a big performance drop. Cost of query goes from 1441 to 28544.
I don't uderstand why there's such a difference. For inner join, database has to remove all the rows that don't have match in inner-joined table. For left join it can keep all records and just return NULL values for records that don't have a match. In my mind left join should be faster, as it seems simpler. And the access plan could be the same, couldn't it?
Execution plan for inner join:
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
| 0 | SELECT STATEMENT | | 1 | 288 | 1441 (1)| 00:00:18 |
| 1 | HASH GROUP BY | | 1 | 288 | 1441 (1)| 00:00:18 |
| 2 | NESTED LOOPS OUTER | | 1 | 288 | 1440 (1)| 00:00:18 |
| 3 | NESTED LOOPS | | 1 | 261 | 1438 (1)| 00:00:18 |
| 4 | NESTED LOOPS | | 318 | 74412 | 508 (1)| 00:00:07 |
| 5 | NESTED LOOPS | | 318 | 51834 | 189 (0)| 00:00:03 |
| 6 | TABLE ACCESS BY INDEX ROWID| RESURCE | 1 | 106 | 1 (0)| 00:00:01 |
|* 7 | INDEX UNIQUE SCAN | RESURCE_PRINCIPAL_NAME_INDEX | 1 | | 0 (0)| 00:00:01 |
| 8 | TABLE ACCESS BY INDEX ROWID| TASK_USES_RESURCE | 318 | 18126 | 188 (0)| 00:00:03 |
|* 9 | INDEX RANGE SCAN | TASK_USES_RESUR_IDX$$_0CDC0002 | 318 | | 3 (0)| 00:00:01 |
| 10 | TABLE ACCESS BY INDEX ROWID | TASK | 1 | 71 | 1 (0)| 00:00:01 |
|* 11 | INDEX UNIQUE SCAN | TASK_PK | 1 | | 0 (0)| 00:00:01 |
| 12 | TABLE ACCESS BY INDEX ROWID | TASK_WORK_HISTORY | 1 | 27 | 3 (0)| 00:00:01 |
|* 13 | INDEX RANGE SCAN | TASK_WORK_HISTORY_INDEX1 | 1 | | 2 (0)| 00:00:01 |
| 14 | TABLE ACCESS BY INDEX ROWID | TASK_USES_RESURCE | 1 | 27 | 2 (0)| 00:00:01 |
|* 15 | INDEX UNIQUE SCAN | TASK_USES_RESURCE_UK1 | 1 | | 1 (0)| 00:00:01 |
For left outer join:
| Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)| Time |
| 0 | SELECT STATEMENT | | 318 | 1596K| | 28544 (2)| 00:05:43 |
|* 1 | HASH JOIN OUTER | | 318 | 1596K| 1584K| 28544 (2)| 00:05:43 |
| 2 | VIEW | | 318 | 1580K| | 508 (1)| 00:00:07 |
| 3 | NESTED LOOPS | | 318 | 74412 | | 508 (1)| 00:00:07 |
| 4 | NESTED LOOPS | | 318 | 51834 | | 189 (0)| 00:00:03 |
| 5 | TABLE ACCESS BY INDEX ROWID| RESURCE | 1 | 106 | | 1 (0)| 00:00:01 |
|* 6 | INDEX UNIQUE SCAN | RESURCE_PRINCIPAL_NAME_INDEX | 1 | | | 0 (0)| 00:00:01 |
| 7 | TABLE ACCESS BY INDEX ROWID| TASK_USES_RESURCE | 318 | 18126 | | 188 (0)| 00:00:03 |
|* 8 | INDEX RANGE SCAN | TASK_USES_RESUR_IDX$$_0CDC0002 | 318 | | | 3 (0)| 00:00:01 |
| 9 | TABLE ACCESS BY INDEX ROWID | TASK | 1 | 71 | | 1 (0)| 00:00:01 |
|* 10 | INDEX UNIQUE SCAN | TASK_PK | 1 | | | 0 (0)| 00:00:01 |
| 11 | VIEW | | 1480K| 73M| | 23431 (2)| 00:04:42 |
|* 12 | HASH JOIN RIGHT OUTER | | 1480K| 76M| 38M| 23431 (2)| 00:04:42 |
| 13 | TABLE ACCESS FULL | TASK_USES_RESURCE | 1486K| 21M| | 2938 (2)| 00:00:36 |
| 14 | VIEW | | 1445K| 53M| | 15031 (2)| 00:03:01 |
| 15 | HASH GROUP BY | | 1445K| 37M| 110M| 15031 (2)| 00:03:01 |
| 16 | TABLE ACCESS FULL | TASK_WORK_HISTORY | 1445K| 37M| | 3897 (2)| 00:00:47 |
--------------------------------------------------------------------------------------------------------------------------...continued
Complete execution plan for left join:
| Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)| Time |
| 0 | SELECT STATEMENT | | 318 | 1594K| | 28544 (2)| 00:05:43 |
|* 1 | HASH JOIN OUTER | | 318 | 1594K| 1584K| 28544 (2)| 00:05:43 |
| 2 | VIEW | | 318 | 1578K| | 508 (1)| 00:00:07 |
| 3 | NESTED LOOPS | | 318 | 74412 | | 508 (1)| 00:00:07 |
| 4 | NESTED LOOPS | | 318 | 51834 | | 189 (0)| 00:00:03 |
| 5 | TABLE ACCESS BY INDEX ROWID| RESURCE | 1 | 106 | | 1 (0)| 00:00:01 |
|* 6 | INDEX UNIQUE SCAN | RESURCE_PRINCIPAL_NAME_INDEX | 1 | | | 0 (0)| 00:00:01 |
| 7 | TABLE ACCESS BY INDEX ROWID| TASK_USES_RESURCE | 318 | 18126 | | 188 (0)| 00:00:03 |
|* 8 | INDEX RANGE SCAN | TASK_USES_RESUR_IDX$$_0CDC0002 | 318 | | | 3 (0)| 00:00:01 |
| 9 | TABLE ACCESS BY INDEX ROWID | TASK | 1 | 71 | | 1 (0)| 00:00:01 |
|* 10 | INDEX UNIQUE SCAN | TASK_PK | 1 | | | 0 (0)| 00:00:01 |
| 11 | VIEW | | 1480K| 73M| | 23431 (2)| 00:04:42 |
|* 12 | HASH JOIN RIGHT OUTER | | 1480K| 76M| 38M| 23431 (2)| 00:04:42 |
| 13 | TABLE ACCESS FULL | TASK_USES_RESURCE | 1486K| 21M| | 2938 (2)| 00:00:36 |
| 14 | VIEW | | 1445K| 53M| | 15031 (2)| 00:03:01 |
| 15 | HASH GROUP BY | | 1445K| 37M| 110M| 15031 (2)| 00:03:01 |
| 16 | TABLE ACCESS FULL | TASK_WORK_HISTORY | 1445K| 37M| | 3897 (2)| 00:00:47 |
Query Block Name / Object Alias (identified by operation id):
1 - SEL$1AFB0324
2 - SEL$58A6D7F6 / from$_subquery$_005@SEL$8
3 - SEL$58A6D7F6
5 - SEL$58A6D7F6 / RESURCEWORKER@SEL$2
6 - SEL$58A6D7F6 / RESURCEWORKER@SEL$2
7 - SEL$58A6D7F6 / TASKUSESRESURCE@SEL$1
8 - SEL$58A6D7F6 / TASKUSESRESURCE@SEL$1
9 - SEL$58A6D7F6 / TASK@SEL$1
10 - SEL$58A6D7F6 / TASK@SEL$1
11 - SEL$7EBCC247 / TRW@SEL$3
12 - SEL$7EBCC247
13 - SEL$7EBCC247 / TUR@SEL$4
14 - SEL$6 / TRW_IN@SEL$5
15 - SEL$6
16 - SEL$6 / TWH@SEL$6
Predicate Information (identified by operation id):
1 - access("TRW"."RESURCE_ID"(+)="TASKUSESRESURCE"."RESURCE_ID" AND "TRW"."TASK_ID"(+)="TASK"."ID")
6 - access("RESURCEWORKER"."USER_PRINCIPAL_NAME"=U'jernej')
8 - access("TASKUSESRESURCE"."RESURCE_ID"="RESURCEWORKER"."ID")
10 - access("TASKUSESRESURCE"."TASK_ID"="TASK"."ID")
12 - access("TUR"."RESURCE_ID"(+)="TRW_IN"."RESURCE_ID" AND "TUR"."TASK_ID"(+)="TRW_IN"."TASK_ID") Jonathan, I've been to one of your workshops in Ljubljana. I'm still trying to understand everything you explained and use it, but there's much I have to learn and understand.
The way I see this query it should fist join and filter the first three tables and only then join the trw subquery. The problem with this subqrey is task_work_history table, which is accessed in very different ways in different places, so there will always be many reads to gather required data. For now, however, I'd be hapy to just bring the performance of inner join to left join... -
Problem with XMLTABLE and LEFT OUTER JOIN
Hi all.
I have one problem with XMLTABLE and LEFT OUTER JOIN, in 11g it returns correct result but in 10g it doesn't, it is trated as INNER JOIN.
SELECT * FROM v$version;
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
PL/SQL Release 11.2.0.1.0 - Production
"CORE 11.2.0.1.0 Production"
TNS for Linux: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production
--test for 11g
CREATE TABLE XML_TEST(
ID NUMBER(2,0),
XML XMLTYPE
INSERT INTO XML_TEST
VALUES
1,
XMLTYPE
<msg>
<data>
<fields>
<id>g1</id>
<dat>data1</dat>
</fields>
</data>
</msg>
INSERT INTO XML_TEST
VALUES
2,
XMLTYPE
<msg>
<data>
<fields>
<id>g2</id>
<dat>data2</dat>
</fields>
</data>
</msg>
INSERT INTO XML_TEST
VALUES
3,
XMLTYPE
<msg>
<data>
<fields>
<id>g3</id>
<dat>data3</dat>
</fields>
<fields>
<id>g4</id>
<dat>data4</dat>
</fields>
<fields>
<dat>data5</dat>
</fields>
</data>
</msg>
SELECT
t.id,
x.dat,
y.seqno,
y.id_real
FROM
xml_test t,
XMLTABLE
'/msg/data/fields'
passing t.xml
columns
dat VARCHAR2(10) path 'dat',
id XMLTYPE path 'id'
)x LEFT OUTER JOIN
XMLTABLE
'id'
passing x.id
columns
seqno FOR ORDINALITY,
id_real VARCHAR2(30) PATH '.'
)y ON 1=1
ID DAT SEQNO ID_REAL
1 data1 1 g1
2 data2 1 g2
3 data3 1 g3
3 data4 1 g4
3 data5 Here's everything fine, now the problem:
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
PL/SQL Release 10.2.0.1.0 - Production
"CORE 10.2.0.1.0 Production"
TNS for HPUX: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - Production
--exactly the same environment as 11g (tables and rows)
SELECT
t.id,
x.dat,
y.seqno,
y.id_real
FROM
xml_test t,
XMLTABLE
'/msg/data/fields'
passing t.xml
columns
dat VARCHAR2(10) path 'dat',
id XMLTYPE path 'id'
)x LEFT OUTER JOIN
XMLTABLE
'id'
passing x.id
columns
seqno FOR ORDINALITY,
id_real VARCHAR2(30) PATH '.'
)y ON 1=1
ID DAT SEQNO ID_REAL
1 data1 1 g1
2 data2 1 g2
3 data3 1 g3
3 data4 1 g4As you can see in 10g I don't have the last row, it seems that Oracle 10g doesn't recognize the LEFT OUTER JOIN.
Is this a bug?, Metalink says that sometimes we can have an ORA-0600 but in this case there is no error returned, just incorrect results.
Please help.
Regards.Hi A_Non.
Thanks a lot, I tried with this:
SELECT
t.id,
x.dat,
y.seqno,
y.id_real
FROM
xml_test t,
XMLTABLE
'/msg/data/fields'
passing t.xml
columns
dat VARCHAR2(10) path 'dat',
id XMLTYPE path 'id'
)x,
XMLTABLE
'id'
passing x.id
columns
seqno FOR ORDINALITY,
id_real VARCHAR2(30) PATH '.'
)(+) y ;And is giving me the complete output.
Thanks again.
Regards. -
Left outer join problem -- need feedback
using crystal 2008
haveing prolbems with a left outerjoin to get a blank field(null) to show up.
basically i have some po line have have long descriptions or text fields that i want to include with the report. Below is my sql statement. I have written a formula with a join between 2 fields to get the report to work- this does but- it leave the polines off that do not have a long description. I have tried left outer joins but seem to be having problems. The long description field where the data is actually at is under my po.line table, although serveral area have long description fields -
*one note i had to add a duplicate table to the field to get some items in my header to work properly - not sure if this is effecting the report or not.
OK- when I set up the link to a LO join enforce from = to
and dont add the ldtext.field to the report the left outjoin works(but no long description)and all my line items show up.
1. when I keep the same join and add either just the ld.text field to the report it comes back with a error saying invalid table
2. when i use my formula that joins the ld.text and po.line and place it in the report with the same left outerjoin i get the same failure.
3. when i dont reference the ldtext(field) at all in the report it works fine w/ the lo join
4. when i Dont use a left outer join and use my formula(see below)
if not isnull(({LONGDESCRIPTION.LDTEXT }))
then {POLINE.DESCRIPTION}+{LONGDESCRIPTION.LDTEXT}
else {POLINE.DESCRIPTION}
and link from poline.ld
to ld.ldtext - my formula works and populates the po.line and the ld.text together - except that any po.line with no description will not show up. Like its not there.
Not sure what to do?
here is my current sql statement with the longdescription field in the select statement
here is the error statement i am getting:
Failed to retrieve data from the database:
Details:42000[intersolv][odb sql base driver][sql base] 00906 itn invalid table name[database vendor code:906]
sql statement:
SELECT "PO"."PONUM", "PO"."STATUS", "PO"."VENDOR",
"COMPANIES"."NAME", "COMPANIES"."ADDRESS1",
"COMPANIES"."ADDRESS2", "COMPANIES"."ADDRESS3",
"COMPANIES"."ADDRESS4", "COMPANIES"."PHONE",
"COMPANIES"."FAX", "COMPANIES_1"."NAME",
"COMPANIES_1"."ADDRESS1", "COMPANIES_1"."ADDRESS2",
"COMPANIES_1"."ADDRESS3", "COMPANIES_1"."ADDRESS4",
"COMPANIES_1"."CONTACT", "COMPANIES_1"."PHONE",
"COMPANIES_1"."FAX", "PO"."PURCHASEAGENT",
"PO"."ORDERDATE",
"PO"."REQUIREDDATE", "PO"."PAYMENTTERMS",
"PO"."SHIPVIA", "PO"."FREIGHTTERMS", "PO"."FOB",
"POLINE"."DESCRIPTION", "POLINE"."ITEMNUM",
"POLINE"."ORDERQTY", "POLINE"."UNITCOST",
"POLINE"."LOADEDCOST", "POLINE"."POLINENUM",
"PO"."SHIPTOATTN", "LONGDESCRIPTION"."LDTEXT"
FROM ("MAXIMO"."PO" "PO" LEFT OUTER JOIN
"MAXIMO"."LONGDESCRIPTION" "LONGDESCRIPTION" ON "PO"."LDKEY"="LONGDESCRIPTION"."LDKEY"),
"MAXIMO"."POLINE" "POLINE",
"MAXIMO"."COMPANIES" "COMPANIES_1",
"MAXIMO"."COMPANIES" "COMPANIES"
WHERE ("PO"."PONUM"="POLINE"."PONUM") AND ("PO"."VENDOR"="COMPANIES_1"."COMPANY") AND ("PO"."SHIPTO"="COMPANIES"."COMPANY") AND "PO"."PONUM"='3386-053'If you took the time to read this thanks.... turns out... and I just want to pull my hair out over this. My connection had a old odbc driver so somehow it would not allow a left outer join....go figure - weeks of agony over that..... thanks ....have to say love this forum.
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