Removing last character of a string

Hi Gurus,
Is there any way to remove the last character of staring other that finding the string length and doing it?
waiting for reply
Ravi

HI,
yaa u can do this by one logic
wht u do is concatenate one special symbol like $ to the string wht u have and in the next statement by using tht special symbol u can find fdpos i.e. field postion i.e. at which lenght it is there and then in again another statement u can increa fdpos by one and u can cut the string at tht length
i think u got my logic
further if u have any quiries u can contact me on [email protected]
plzz reward if it is usefull....

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Truncating last character in a string

I am making a dialpad. It is just for display so I am using a
string for the numbers selected. I am trying to make a back button
that would clear the last number added. I tried mystring.length-1
but that doesn't seem to be doing the trick. Is there a simple way
to truncate the last character in a string, of variable
length??

Here's an example
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How to delete last character in a string

Guys i have a question...
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String newString = myString.substring(0, myString.length()-1);

How we can find the last character in a string(Urgent Plz!)

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Use the substr() and length() functions -
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Testing the last character of a string using .endsWith

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javadocs:
String's endsWith method takes a string argument.
endsWith
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LAST CHARACTER OF A STRING

Hi Gurus,
I want to get the last character of a String.For Ex.
I have name = 'ZXCDFG":?'
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Thanks in Advance.

Hi Pradeep,
Just find the String Length and use the offset commands
DATA : DATA TYPE CHAR20 'ABCDEFG',
DATA : DATA1,
DATA : LEN TYPE I.
LEN = STRLEN( DATA ).
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DATA1 = DATA+LEN(1).
Regards
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Deleting last character of a string

Hi Abapers,
I want to delete the last character of my workarea and then store into table.
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hi
do this in following way
frist find the String length
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w_str = 'sdn is wonderfull'
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How to remove last char in a string by space

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123
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Graphics2D g = (Graphics2D)window.getGraphics();
AttributedString as = new AttributedString(string, map);
g.drawString(as.getIterator(),x,y);
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Thanks and regards

Deja vu. I saw this kind of post before, and I'm sure
it was today.http://forum.java.sun.com/thread.jspa?threadID=588110&tstart=0
Here it is.

To delete first and last character of a string???

Hi Everybody !!!
Do you know a method that can permit to delete in a string the first and the last character?
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Look at the substring method of the String class.
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How to remove certain character from a string?

Follows the table:
CT_TRABALH
400rj101
400rj102
400rj103
400rj104
400rj105
400rj106
400rj107
400rj108
400rj109
400rj1010
400rj1011
I woulld like to make the following with its values. For example the value 400rj1010
I would like to remove its last character (400rj101) and then relace the last zero for the last number(400rj111) by query. Is there any way I can achieve this?

I would write something a little more generic :
SCOTT@demo102> with tbl as
2      (select '400rj101' as CT_TRABALH from dual union all
3       select '400rj102' from dual union all
4       select '400rj103' from dual union all
5       select '400rj104' from dual union all
6       select '400rj105' from dual union all
7       select '400rj106' from dual union all
8       select '400rj107' from dual union all
9       select '400rj108' from dual union all
10       select '400rj109' from dual union all
11       select '400rj1010' from dual union all
12       select '400rj10120' from dual union all
13       select '400rj14120' from dual union all
14       select '412rj14120' from dual union all
15       select '400rj1011' from dual )
16 select CT_TRABALH,
17         case when substr(CT_TRABALH,-1,1) = '0'
18              then decode(instr(substr(CT_TRABALH,1,length(CT_TRABALH)-1),0,-1),
19                           0, substr(CT_TRABALH,1,length(CT_TRABALH)-1),
20                              substr(CT_TRABALH,1,instr(substr(CT_TRABALH,1,length(CT_TRABALH)-1),0,-1)-1)
21                              ||substr(CT_TRABALH,-2,1)
22                              ||substr(CT_TRABALH,instr(substr(CT_TRABALH,1,length(CT_TRABALH)-1),0,-1)+1,
23                               length(CT_TRABALH)-instr(substr(CT_TRABALH,1,length(CT_TRABALH)-1),0,-1)-1))
24              else CT_TRABALH
25              end as CT_TRABALH_0
26 from tbl;
CT_TRABALH CT_TRABALH_0
400rj101   400rj101
400rj102   400rj102
400rj103   400rj103
400rj104   400rj104
400rj105   400rj105
400rj106   400rj106
400rj107   400rj107
400rj108   400rj108
400rj109   400rj109
400rj1010 400rj111
400rj10120 400rj1212
400rj14120 402rj1412
412rj14120 412rj1412
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14 rows selected.
SCOTT@demo102> Nicolas.

Want to single out the last character of a string

There is a field where there are many strings of varying length. E.g.: AB001XUV, AB003XUK, DJ8933FXUV etc.
From these strings I need to create a virtual column where only the last character is shown. So it shall be V, K, V for values from the above example.
Can anyone please suggest me how to achieve this.
Regards
Hawker

SQL> with t as (
2 select 'AB001XUV' col from dual
3 union
4 select 'AB003XUK' col from dual
5 union
6 select 'DJ8933FXUV' col from dual
7 )
8 select substr(col,-1,1) from t
9 /
S
V
K
V
SQL> create table temp(id number,
                  col varchar2(10),
                  VIRTUAL_COL VARCHAR2(1)   GENERATED ALWAYS AS (substr(col,-1,1)) VIRTUAL
SQL> insert into temp(id,col) values(1, 'AB001XUV') ;
SQL> select * from temp ;
        ID COL        V
         1 AB001XUV   V
SQL> Edited by: Azhar Husain on Aug 16, 2011 1:17 PM

Select last character of a string

Hello,
I would like to select the last character of an address string. For example, in '165 John Ave W' -- select result 'W'. I tried to use RIGHT but it doesn't work. I'm using SQL Plus.
SELECT RIGHT(ADDRESS,1) FROM addresses;
ORA-00904: "RIGHT": invalid identifier
I can't find the appropriate select statement to achieve the result I want. Ideas?
Thanks!

The SUBSTR function can take a negative start parameter, which counts in from the end of the string
http://www.techonthenet.com/oracle/functions/substr.php - that should get you going, let me know if you get stuck.
Carl

The last character of a string

How to judge the last char of a string is " ?
if (s.endsWith("""))or
if (s.endsWith("/""))

bet
you just copied and pasted what the OP had written
and quickly put that
backslash in, hit post without previewing first just
to make me look like
a slow old sod! It's not fair ;-)
kind regards,
JosNope, I used the Alt-[numeric code] combinations to manually type each character. Cut-n-paste is for wimps, and actually typing single-stroke keys is for milquetoasts.
Alt-[numeric code] is for real men ;-)

To remove last '/' character

I need to remove '/' character and string comes after it. I will give an example.
CREATE TABLE TAB (COL1 VARCHAR2(50));
INSERT INTO TAB VALUES ('hIA/SS/TTTT/FFFF');
INSERT INTO TAB VALUES ('hDFF/AA/S/AAAAAAAA');
I should remove the last '/' and string comes after it so when i query , i should get result as
hiA/SS/TTTT
hDFF/AA/S
Please help me

Hi,
Welcome to the forum!
Here's one way:
SELECT     col1    -- if wanted
,     REGEXP_REPLACE ( col1
                 , '/[^/]*$'
                 )     AS up_to_last_slash
FROM     tab
;Regular expressions can be very convenient, but they can also be slow. If performance is a problem, try this instead:
SELECT     col1    -- If wanted
,     NVL ( SUBSTR ( col1
                      , 1
                      , INSTR (col1, '/', -1) - 1
         , col1
         )                  AS up_to_last_slash
FROM     tab
;This is basically what Chris posted earlier, except that it returns col1 unchanged when col1 does not contain a '/'.
Thanks for posting the CREATE TABLE and INSERT statements; that's very helpful!
Edited by: Frank Kulash on Oct 8, 2012 7:32 AM

Removing last 2 characters from string field

I am trying to remove the last 2 characters of a string field.
there is no consistant length in the field
316R1
12364R1
i want to remove everything after R
i tried instrrev but i that didnt do it.
is there a way to say
start position1 and go the R
thanks

formula,
left (field, length_formula) is the solution
the length_formula is the number of chars form left
f.i
left(field, length (field)-2)
left (field, InstrRev, field,"R")
of course a combination with Right is also possible

Removing last character of a string

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