Repost as question for points: What did I do wrong? (Try and Catch program)

Question

This has to be a try and catch program.
This is the given output sample:
OUTPUT SAMPLE #2 for input.txt: 12345 222256 -3 123 -56784 555557 6345678 x x x 81234 121212 x x 123434 x x 1009098 2099
Please input the name of the file to be opened: input.txt
For number 12345 the sum of digits is: 15
For number 222256 the sum of digits is: 19
Found an integer (-3), but it is negative. Will ignore!
For number 123 the sum of digits is: 6
Found an integer (-56784), but it is negative. Will ignore!
For number 555557 the sum of digits is: 32
For number 6345678 the sum of digits is: 39
For number 81234 the sum of digits is: 18
For number 121212 the sum of digits is: 9
For number 123434 the sum of digits is: 17
For number 1009098 the sum of digits is: 27
For number 2099 the sum of digits is: 20
Here is what I have so far.
import java.util.Scanner;
  import java.io.*;// FileNotFoundException
public class Assignment3b {
  public static void main (String[]args){
    Boolean fileOpened = true; 
    String fileName;
    int n,mod=0,sum=0,t=0;
    Scanner inputFile = new Scanner(System.in);
    System.out.print("Please input the name of the file to be opened: ");
    fileName = inputFile.nextLine();
    System.out.println();
    try {
            inputFile = new Scanner(new File(fileName));
        catch (FileNotFoundException e) {
            System.out.println("--- File Not Found! ---");
            fileOpened = false;
        if (fileOpened) {
          while (inputFile.hasNext()){
            if (inputFile.hasNextInt()){
              n = inputFile.nextInt();
              t=n;
              while(n>0){
                mod = n % 10;
                sum = mod + sum;
                n = n/10;
              System.out.println ("For number " + t + " the sum of digits is : " + sum);
              mod = 0;
              sum = 0;
              while (n<0) {
                System.out.println ("Found an integer (" + t + "), but it negative. Will ignore!");
                inputFile.next();
                n = inputFile.nextInt();
            else {
              inputFile.next();
}Everything seems to work fine until, it is time to deal with negative numbers. How can I fix this. Please put your reply in layman's terms to the best of your ability.
Thanks and God Bless.

Answer 1

// COSC 236                                Assignment # 3
// YOUR NAME: Anson Castelino
// DUE-DATE:
// PROGRAM-NAME: Assignment # 3 Prt2
//import packages
  import java.util.Scanner;
  import java.io.*;// FileNotFoundException
public class Assignment3b {
  public static void main (String[]args){
    Boolean fileOpened = true; 
    String fileName;
    int n,mod=0,sum=0,t=0;
    Scanner inputFile = new Scanner(System.in);
    System.out.print("Please input the name of the file to be opened: ");
    fileName = inputFile.nextLine();
    System.out.println();
    try {
            inputFile = new Scanner(new File(fileName));
        catch (FileNotFoundException e) {
            System.out.println("--- File Not Found! ---");
            fileOpened = false;
        if (fileOpened) {
          while (inputFile.hasNext()){
            if (inputFile.hasNextInt()){
              n = inputFile.nextInt();
              t=n;
              while(n>0){
                mod = n % 10;
                sum = mod + sum;
                n = n/10;
              System.out.println ("For number " + t + " the sum of digits is : " + sum);
              mod = 0;
              sum = 0;
              if (n<0) {
                System.out.println ("Found an integer (" + t + "), but it is negative. Will ignore!");
                inputFile.next();
              inputFile.hasNext();
            else {
              inputFile.next();
}Updated code.
current output is as follows:
Please input the name of the file to be opened: [DrJava Input Box]
For number 12345 the sum of digits is : 15
For number 222256 the sum of digits is : 19
For number -3 the sum of digits is : 0 <-------- this part is not suppose to be here.
Found an integer (-3), but it is negative. Will ignore!
For number -56784 the sum of digits is : 0 <-------- this part is not suppose to be here.
Found an integer (-56784), but it is negative. Will ignore!
For number 6345678 the sum of digits is : 39
For number 81234 the sum of digits is : 18
For number 121212 the sum of digits is : 9
For number 123434 the sum of digits is : 17
For number 1009098 the sum of digits is : 27
For number 2099 the sum of digits is : 20
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