Right GROUP BY clause

I wrote the view in the Original View section below. I query it with the following SELECT statement:
SELECT *
FROM ZZBUD_DEBT_SERVICE_V
WHERE action_month IN ('01','02')
AND action_year IN ('2011')
AND short_name IN( 'WHIT-18','2REDFERN')
ORDER BY action_year,action_month, group1, group2, short_name;
An get these results:
SHORT GROUP1 GROUP2 ACTION ACTION CURR CURR CURR
NAME YEAR MONTH INT INT PRIN
ACCRUED PAYMENT PAYMENT
2REDFERN     05     02 2011 01     149.39     0     0     
2REDFERN     05     02 2011 02     0     896.32 49795.84     
WHIT-18     05     01 2011 01     442.86     0     0     
WHIT-18     05     01 2011 02 442.86 2657.14 0     
I need to compute the year-to-date CURR_INT_ACCRUED, CURR_INT_PAYMENT, CURR_PRIN_PAYMENT (SUM(CURR_INT_ACCRUED), etc.) by short_name and action_year but I can't tweek my GROUP BY statement properly. What would the GROUP BY expression look like to get the sum of these columns?
Original View:
CREATE OR REPLACE VIEW ZZBUD_DEBT_SERVICE_V(short_name, group1, group2, action_year, action_month
, curr_int_acrrued, curr_int_payment, curr_prin_payment)
AS
SELECT short_name, group1, group2, action_year, action_month
, SUM(curr_int_acrrued) curr_int_acrrued
, SUM(curr_int_payment) curr_int_payment
, SUM(curr_prin_payment) curr_prin_payment
FROM (
SELECT dsa.short_name
, dsa.group1
, dsa.group2
, dsa.action_year
, dsa.action_month
, DECODE(SIGN(dsa.int_accrued),-1,0 ,0,0,dsa.int_accrued) curr_int_acrrued
, DECODE(SIGN(dsa.ytd_accrued),1,0,0,0,ABS(dsa.ytd_accrued)) curr_int_payment
, DECODE(SIGN(dsa.bond_outstand),1,0,0,0,ABS(dsa.bond_outstand)) curr_prin_payment
FROM NYC.ZZBUD_DEBT_SERVICE_MASTER DSA
WHERE dsa.bond_status = 'A'
AND dsa.group1 IN ('03', '05', '06', '07')
ORDER BY dsa.group1, dsa.group2, DSA.short_name, dsa.action_year, dsa.action_month
GROUP BY short_name,group1,group2,action_year,action_month

It depends on how you look at it. When I issue the command:
SELECT group1, group2, short_name,SUM(curr_int_acrrued) ytd_accrued_int
FROM ZZBUD_DEBT_SERVICE_V
WHERE action_month IN ('01','02')
AND action_year IN ('2011')
AND short_name IN ('BXRIVER','WILSON','WHIT-18','2REDFERN')
GROUP BY action_year,action_month,group1, group2, short_name
ORDER BY action_year,action_month, group1, group2, short_name
I'm not getting the results I want as 'WHIT-18' shows detail for both action_months and I want the SUM of 01 & 02 and the same for the other short_names. When I drop columns from the GROUP BY clause I get error ORA-0979 'Not a GROUP BY expression'.

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  • How to write a SQL Query without using group by clause

    Hi,
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    Please site an example if is it so,
    Regards

    I hope this example could illuminate danepc on is problem.
    CREATE or replace TYPE MY_ARRAY AS TABLE OF INTEGER
    CREATE OR REPLACE FUNCTION GET_ARR return my_array
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    begin
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         for i in 1..10 loop
              arr.extend;
              arr(i) := i mod 7;
         end loop;
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    select column_value
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    order by column_value;
    select column_value,count(*) occurences
    from table(get_arr)
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    order by column_value;And the output should be something like this:
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      2  /
    Tipo creato.
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      2  as
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      4  begin
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      6   for i in 1..10 loop
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    SQL>
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      3  order by column_value;
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               0
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               1
               2
               2
               3
               3
               4
               5
               6
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    SQL>
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               0          1
               1          2
               2          2
               3          2
               4          1
               5          1
               6          1
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  • How to use order by within Group by clause

    Hi All,
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    order by clause should be used at the last in any query.......but in group by clause u can't use use that becoz u group according to column then no ordering is needed there......if u want to filter something then u can use having clause and later if u need to arrange then u can use order by clause.........
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  • Problem with the query in group by clause

    hi, i have problem with group by clause, can some one please help me.
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    commit;
    Appreciate your help.
    Thanks,

    select header_id,
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    ,countryIt's kinda hard to follow what your query does... maybe because I'm only at my second coffee..
    Edited by: Alex Nuijten on Oct 2, 2009 8:07 AM

  • How to set a group by clause in ODI interface?

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  • How to include case stmt in group by clause

    Hi i have a question,
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    cd/ wrote:
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  • Count(*) in select statement having group by clause

    Hi
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    I suspect you want to look into analytic functions (assuming you have a recent version of Oracle). asktom.oracle.com has numerous examples if you do a search.
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  • Oracle 10g group by clause

    I have one SQL query using a GROUP BY clause and no ORDER BY clause is used. When executed in Oracle 8i, the query results are returned ordered by first column mentioned in the GROUP BY clause. When the same query is executed in Oracle 10g, the query results are returned withour ordering the data by the first column in the GROUP BY clause. It works only when I explicitly mention the ORDER BY clause. Can you please explain this? In Orcale 8i, is it that, by default, the data is ordered by the first column mentioned in the GROUP BY clause when ORDER BY clause is not mentioned?
    In which order does oracle 10g sorts when I use group by clause in oracle 10g

    [email protected] wrote:
    the use of group by is to group based on some column value, in this case why does the the output differs in rows. why does the output, when you use group by is not the following formatSorry, but this is a totally fruitless topic. Why are you bothering with something that is totally internal to the DBMS? If you want the data ordered, use ORDER BY, it's that simple.
    Check out this link, if you want some discussion on it:
    [http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:74320098178823]

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