Scanimage -L lists same device multiple times

well i finally got my epson perfection v500 photo scanner working. i admit to having more problems then i should have heh.
arch 86_64
i installed iscan from aur
*important* i downloaded iscan-plugin-gt-x770-2.1.1-2.c2.x86_64.rpm from epson site http://www.avasys.jp/lx-bin2/linux_e/scan/DL2.do and used rpm2targz to unpack. then placed the libesint7C* (should be 3 files) files in /usr/lib/iscan/ and the esfw7C.bin file in /usr/share/iscan
i then followed directions in https://bbs.archlinux.org/viewtopic.php?id=77802
and it worked
it wasn't workng before as i was installing the driver from aur (iscan-plugin-gt-x770) howerver i think that does not work for x86_64.
my question is that the same device is listed 5 times now. i reinstalled things multiple times and i know its because of that. i assume it was from multiple #iscan-registry commands
example:
$ scanimage -L
device `epkowa:interpreter:001:006' is a Epson Perfection V500 flatbed scanner
device `epkowa:interpreter:001:006' is a Epson Perfection V500 flatbed scanner
device `epkowa:interpreter:001:006' is a Epson Perfection V500 flatbed scanner
device `epkowa:interpreter:001:006' is a Epson Perfection V500 flatbed scanner
device `epkowa:interpreter:001:006' is a Epson Perfection V500 flatbed scanner
device `v4l:/dev/video0' is a Noname UNKNOWN/GENERIC virtual device
xsane and iscan both ask to pick from the 5 epkowa devices listed, all will work. is there a way to remove all but one of them? i assume its under /dev or /proc but cant seem to find them.
thank you for any help.

I've been burned by this
do a
iscan-registry -h
then do a remove about 4 times, till you only have one instance.
It's kinda like this- iscan-registry --remove interpreter usb <vendor-id> <product-id> <plugin> [<firmware>]
vender and product IDs from a lsusb
I think plugin is in /usr/share/esci /
I think fimware is in /usr/lib/esci/
or it could be the other way around. You could look at the script in the RPM for the iscan-registry --add command and reference that.

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