Scope of a non-static method printing a vector of objects

Question

Hello everyone,
I'm new to using the java.util.Vector package. I wanted to create a print out of all the objects of class "Student" that I created within a "students" vector. My problem is that scope is causing a compile error when calling the print method acting on the students vector. Anybody got any ideas? Further to this I'd like to keep my printVec() generic enough so that I can create a class "Teachers" and a "teachers" array and make the the printVec() method able to print both, ie;
teachers.printVec()
students.printVec()My code is below;
import java.io.*;
import java.lang.*;
import java.util.*;
class Example {
   public static void main(String[] args){
      Vector<Student> students = new Vector<Student>();
      students.addElement(new Student("Billy"));
      students.addElement(new Student("Ryan"));
      students.addElement(new Student("William"));
      students.addElement(new Student("Jason"));
      //the below print algorithm works...
      for(int i=0;i<students.size();i++)
         System.out.println(i+" "+students.elementAt(i).getName());
         //however i can't get this following one to work...
//       students.printVec();
         //uncomment above line
   public void printVec(){
//      for(int i=0;i<students.size();i++)//uncomment these lines
//         System.out.println(i+" "+students.elementAt(i).getName());//uncomment these lines
        //uncomment above two lines
class Student{
   //constructors
   public Student(String name){
      this.name = name;
      this.subjectNumber = -1;
      this.tutorialNumber = -1;
   //methods
   public String getName(){
      return name;
   //fields
   private String name;
   private int subjectNumber;
   private int tutorialNumber;
}

Answer 1

You should use an Iterator, not get(). And youshould
prefer ArrayList over Vector.Why are you telling me this? I know this already... I
was reusing the OP's way so that he/she/it could see
it done his/her/its way.I have no way of knowing what you do or don't know. I only saw crap code, so I corrected it.
>
That won't work if more than one student has thesame
name, and it's a very counterintuitive way to
approach the problem.Um... yes, it will work if more than one student has
the same name. It will not work if students in the
Vector share memory. It searches for memory, not the
name.Actually, we're both wrong.
If Student overrides equals to be based on name, then it won't work as I described. If not, then it will work.
It only looks at "memory" if Student does not override equals.
I didn't think that there would be a problem with
memory, but if there is, simply add a counter:????
What are you talking about?
public static void printVec(Vector<Student> students)
int count = 0;
for (Student s : students) {
System.out.println((count++) + " " +
+ " " + s.getName());
}That's the right way to do it, but that has nothing to do with "a problem with memory."