Search and replace string problems

Hi to all,
I have problem with Search and replace string function. It shows me a wrong Value (Number) from 15 to 100 is everything OK (15=0, 30=1, 45=2, 100=3), but after 100 ........
Take look in VI and if you have any ideas post them please
THX
Igor
Attachments:
indexing.vi ‏10 KB

there will be no 15115 string, but 15 or 115 and 15 is 0, 115 is 4. Anyway, i have changed string input format and now its working THX for your help
Attachments:
indexing.vi ‏10 KB

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Search and Replace String throwing the wrong error message with regexp?

This came up in a LAVA thread, and I'm not sure if there's a bug here or not. When using Search and Replace string, and using a regular expression of [(G[b|i])], LabVIEW throws error -4622, "There is an unmatched parenthesis in a regular expression." There are obviously no unmatched parenthesis in that expression, so it seems to me that the wrong error is being thrown. I'm just not sure if that's a syntactically valid regexp. The problem seems to be with nesting [ ]'s inside ( )'s inside [ ]'s. I've tried a couple of regexp resources on the Web, and one suggests it's valid, while the other seems to think it isn't.
Message Edited by eaolson on 03-13-2007 10:33 AM
Attachments:
ATML_StandardUnit2.vi ‏10 KB
regexp.png ‏5 KB

adambrewster wrote:
I think your regexp is invalid.
In regexps, brackets are not the same as parentheses. Parens are for grouping, while brackets are for matching one of a class of characters. Brackets can not be nested.
If the regexp is replaced with [G[bi]], there is no error, so it's not a matter of nested brackets. I couldn't find anything on the PCRE man page that forbids nested brackets specifically, but it makes sense.
Your expression "[(G[bi])]", therefore parses as a character class which matches '(', 'G', '[', 'b', or 'i' followed by an unmatched paren, and an unmatched bracket.
I don't believe that's the case. Replace the regexp with [(Gbi)], and the error goes away. So it's not a matter of the '(' being literal, and then encountering a ')' without a matching '('.
daveTW wrote:
what string exactly you want to replace? I think the round braces are not right in this case, since they mark partial matches which are given back by "match regular expression". But you don't want to extract parts of the string, you want to replace them (or delete, with empty <replace string>). So if you leave the outer [( ... )] then your RegEx means all strings with either "Gb" or "Gi".
It's not my regular expression. A poster at LAVA was having problems with one of his (a truly frightening one), and this seemed to be the element that was causing the problem. I'm pretty sure that the originator of the regexp meant to use G(b|i), which seems like a complicated way of matching "Gb" or "Gi", if you ask me.

Search and replace strings in a file while ignoring substrings

Hi:
I have a java program that searches and replaces strings in a file. It makes a new copy of the file, searches for a string in the copy, replaces the string and renames the new copy to the original file, thereafter deleting the copy.
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try
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Hi:
I have a java program that searches and replaces
strings in a file. It makes a new copy of the file,
searches for a string in the copy, replaces the
string and renames the new copy to the original file,
thereafter deleting the copy.
Now searching for "abcd", for eg works fine, but
searching for "Topabcd" and replacing it doesnot work
because there is a match for "abcd" in a different
search scenario. How can I modify the code such that
if "abcd" is already searched and replaced then it
should not be searched for again or rather search for
"abcd" as entire string and not if its a substring of
another string.
In the below code output, all instances of "abcd" and
the ones of "Topabcd" are replaced by ABCDEFG and
TopABCDEF respectively, whereas according to the
desired output, "abcd" should be replaced by ABCDEFG
and "Topabcd" should be replaced by REPLACEMEFIRST.
try
String find_productstring = "abcd";
String replacement_productstring = "ABCDEFG";
compsXml = new FileReader(compsLoc);
compsConfigFile = new
BufferedReader(compsXml);
File compsFile =new File("file.xml");
File compsNewFile =new File("file1.xml");
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FileWriter("file1.xml"));
while ((compsLine =
compsConfigFile.readLine()) != null)
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replacement_productstring);
out.write(new_compsLine);
out.write("\n");
out.close();
compsConfigFile.close();
compsFile.delete();
compsNewFile.renameTo(compsFile);
catch (IOException e)
//since "Topabcd" contains "abcd", which is
the search above and hence the string "Topabcd" is
not replaced correctly
try
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String replacement_producttopstring =
topstring = "REPLACEMEFIRST";
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compsConfigFile = new
gFile = new BufferedReader(compsXml);
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               File compsNewFile =new File("file1.xml");
BufferedWriter out =new BufferedWriter(new
dWriter(new FileWriter("file1.xml"));
while ((compsLine =
compsLine = compsConfigFile.readLine()) != null)
new_compsLine
new_compsLine
=compsLine.replaceFirst(find_producttopstring,
replacement_producttopstring);
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out.write("\n");
out.close();
compsConfigFile.close();
compsFile.delete();
compsNewFile.renameTo(compsFile);
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Thanks a lot!I tried the matches(...) method but it doesnt seem to work.
while ((compsLine = compsConfigFile.readLine()) != null)
if(compsLine.matches(find_productstring))
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out.write(new_compsLine);
out.write("\n");
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     out.write(compsLine);
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Hi,
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Right click on the Search And Replace String function. There is an option to use Regular Expressions. Then give this a try.
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Hello, I am using the "search and replace string" function and it does nt seem to work consistently for me. I am using it in a situation where I am taking an array of strings, converting this into a spreadsheet string then deleting all of the commas. Has anyone experienced the same behavior? I have searched through other posts and found other simular faults but none of the fixes worked for this. I can post the code it needed.
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How to get numeric result from 'search and replace' string function

hii
i am using search and replace function to get output.my output is of form ' *X0123.3 ' .here i am replacing the term *X01 with space because i need only 23.3 as a result.but i am unable to get that out in the output indicator.i used lot of functions like string to number and so on but i am getting output as zero .can you please suggest me wt to do.i am attaching a copy of my file.
Attachments:
Untitled 1.vi ‏25 KB

Your problem is the fact that you are converting it to an integer, thus loosing the fractional part. You need to use "Fract/Exp String To Number" instead and create a DBL so yor data is 23.3 instead of 23.
You also don't need to manipulate the string if the initial part is of constant lenght. Just use the offset input as in the figure below.
Message Edited by altenbach on 07-31-2006 07:02 AM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
ToDBL.png ‏2 KB

Using a variable in a Powershell search and replace string

Hi
a couple of days ago I posted a question about doing a search and replace with wildcards
Search and repalce with Widcards
I got a swift and very helpful answer but now I need to build on it.
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Can anyone help??
Thanks
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Here's one way:
$replace = 'it will aways say this'if ( $text -match '(.*Server) .+? (Language.*)' )
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Match case in search and replace string

Hi !
Attached, my problem.
I am searching "toto" in input string "toto+tototi" and replace "toto" by "A0".
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Does it exist options allowing to match case ?
BR,
Vincent
Solved!
Go to Solution.
Attachments:
MatchCase.vi ‏8 KB

Please fill all your controls with typical strings, make the new values the default, save the VI under a new name, and attach it again.
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LabVIEW Champion . Do more with less code and in less time .

Search and replace string not work as per required

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Attachments:
Replace String.vi ‏8 KB
Replace String.vi ‏8 KB

You haven't configured the strings to be "default". Hence, all string elements in your attached vi's are empty.
I have no idea what you try to achieve without those strings....
Norbert
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I need to replace every instance of a space or series of spaces in a multi line string with commas (or tabs) so I can dump it into a spreadsheet.
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Right click on the search string and change it to '\' Code Display. Enter the space character (\s) correctly - you've got \\s right now.

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Thanks for your reply Kenneth, but that is not what I'm trying to accomplish. I'm looking for the HTML entities that exist in the source code which are & shy ; and & nbsp ; (without the spaces). As I mentioned above, if I enter them manually in the search box, I will get the corrrect results. If I save the search and then reload it, the special characters are no longer in HTML and the search is now useless.
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Your syntax is not correct. Example:
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How to search and replace in an xml file using java

Hi all,
I am new to java and Xml Programming.
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Edited by: Karthik84 on Aug 19, 2008 3:15 AM

Using XPath to locate the elements you are after is very easy.
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Search and replace string problems

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