Search help to return multiple values

Hi all,
I've created a search help and I'd like it to return several values to different fields, I don't want these fields to be seen on the selection screen.
For example:
1. User clicks on search help for FIELD1 and selects a value from the pop-up box
2. Program populates FIELD1 depending on the user selection
3. Program also populates FIELD2 and FIELD3 which can be used in the program at a later date.
I can do 1 and 2 but I'm having an issue with 3.  I've tried selecting all fields in the search help as Export, but although that populates the fields in the search help test facility, it doesn't know which fields I want it to populate in my program.
I've also tried using FM F4IF_FIELD_VALUE_REQUEST but can only get this to return one line in table RETURN_TAB.
The screen fields are declared as:
PARAMETERS: FIELD1 LIKE TAB1-FIELD1 MATCHCODE ZSEARCH_HELP,
                         FIELD2 LIKE TAB1-FIELD2 NO-DISPLAY,
                         FIELD3 LIKE TAB1-FIELD3 NO-DISPLAY.
Any help is appreciated.
Gill

Thanks for your suggestion but what I failed to put in my original post was that FIELD1 is a description field and FIELD2 and FIELD3 are the actual key fields for the table which I need.
So, I can't do your suggestion of populating them based on FIELD1, I need to know which line the user selects to populate these key fields as FIELD1 may not be unique within the table.
Does that make sense?
That's why I wanted the search help to return all 3 values then I can populate FIELD2 and FIELD3 from that.

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    2          3
    4          5

  • Hi how will get subquery returns multiple values for main query

    Hi all ;
    here i given one sql query
    1)select decode(a.FLG,'Y','yes','N','no','null')||'] '||a.p_type||' : '|| initcap(replace(substr(b.mgr,0,instr(b.mgr,'@')-1),'.',' '))||' - '||
    b.name||' ('|| substr(a.name,0,instr(a.name,'-')-1)||')'
    from table1 a
    join table3 c on c.emptype = a.emptype
    left outer join table2 b on a.name = b.name
    where a.mgrid = 100;
    if i run this above query returning multiple values depend on sa.mgr values.
    like output coming like this
    yes:2000-anbarasan
    yes:2700-anb
    yes:2000-rasan
    yes:2807-anbarasan
    yes:2700-anbanu
    yes:2000-null
    2) this sub query i am passing with main query
    select sa.mgrid,sa.sal,(select decode(a.FLG,'Y','yes','N','no','null')||'] '||a.p_type||' : '||
    initcap(replace(substr(b.mgr,0,instr(b.mgr,'@')-1),'.',' '))||' - '||
    b .name||' ('|| substr(a.name,0,instr(a.name,'-')-1)||')'
    from table1 a
    join table3 c on c.emptype = a.emptype
    left outer join table2 b on a.name = b.name
    where a.mgrid = 100)" test " from table4 sa,table5 te ,table6 ft where sa.id(+)=te.id and sa.mgr=ft.mgr;
    my final out put required like this:
    mgrid sal test
    100 20000 yes:2000-anbarasan
    yes:2700-anb
    yes:2000-rasan
    yes:2807-anbarasan
    yes:2700-anbanu
    yes:2000-null
    but i am getting erro:
    1)missing paranths
    2)single row subquery return more then one row.
    hi kindly give me answer to me as soon as possible
    Edited by: anbarasan on Sep 29, 2008 9:48 PM

    I refuse to read all of that code and guess what error message you are getting. Apparently others feel the same way.
    Run the final SQL statement and then cut and paste the code and full error statement into a post.
    Also include your full version number to three decimal places.
    My refusal is not an unwillingness to help you but rather an unwillingness to spend 10 minutes reconstructing what you could have pasted in in a fraction of a second. We are all volunteers here and there are many people that need help. I hope you understand.

  • How will get subquery return multiple values and passing to the main query

    Hi all ;
    here i given one sql query
    1)select decode(a.FLG,'Y','yes','N','no','null')||'] '||a.p_type||' : '|| initcap(replace(substr(b.mgr,0,instr(b.mgr,'@')-1),'.',' '))||' - '||
    b.name||' ('|| substr(a.name,0,instr(a.name,'-')-1)||')'
    from table1 a
    join table3 c on c.emptype = a.emptype
    left outer join table2 b on a.name = b.name
    where a.mgrid = 100;
    if i run this above query returning multiple values depend on sa.mgr values.
    like output coming like this
    [yes]:2000-anbarasan
    [yes]:2700-anb
    [yes]:2000-rasan
    [yes]:2807-anbarasan
    [yes]:2700-anbanu
    [yes]:2000-null
    2) this sub query i am passing with main query
    select sa.mgrid,sa.sal,(select decode(a.FLG,'Y','yes','N','no','null')||'] '||a.p_type||' : '||
    initcap(replace(substr(b.mgr,0,instr(b.mgr,'@')-1),'.',' '))||' - '||
    b .name||' ('|| substr(a.name,0,instr(a.name,'-')-1)||')'
    from table1 a
    join table3 c on c.emptype = a.emptype
    left outer join table2 b on a.name = b.name
    where a.mgrid = 100)" test " from table4 sa,table5 te ,table6 ft where sa.id(+)=te.id and sa.mgr=ft.mgr;
    my final out put required like this:
    mgrid sal test
    100 20000 [yes]:2000-anbarasan
    [yes]:2700-anb
    [yes]:2000-rasan
    [yes]:2807-anbarasan
    [yes]:2700-anbanu
    [yes]:2000-null
    but i am getting erro:
    1)missing paranths-it solved
    2)single row subquery return more then one row.
    give me the correct solution.how will solve this problem
    Edited by: anbarasan on Sep 29, 2008 6:49 AM
    Edited by: anbarasan on Sep 29, 2008 6:51 AM
    Edited by: anbarasan on Sep 29, 2008 6:53 AM
    Edited by: anbarasan on Sep 29, 2008 6:56 AM
    Edited by: anbarasan on Sep 29, 2008 6:58 AM

    Hi,
    It doesn't look like you posted either the complete query or the complete error message (including line number). Try again.
    "single row subquery return more then one row" usually means you are using a sub-query in a place where a single expression is expected, for example the column called avg_sal in this query:
    SELECT  ename
    ,       sal
    ,       (SELECT  AVG (sal) FROM scott.dept WHERE deptno = e.deptno) AS avg_sal  -- Scalar-sub-query
    FROM    scott.emp  e; The error occurs when the sub-query returns more than one row
    If the sub-querry really is supoosed to be returning only one row, the solution is to fix the sub-query, usually be adding something to the WHERE clause.
    If the sub-query is supposed to return more than one row, then the main query has to be re-written, perhaps as a join.
    Post a little sample data and the results you want from that data if you need help.

  • Single query return multiple value

    Hi ALL,
    I have a sql query as below :
    select order_number,
    (select decode(hcp.contact_point_purpose,'ABC',hcp.email_address,'CDE',hcp.email_address,null)
    from hz_contact_points,
    hz_parties hz
    WHERE hz.party_id=hcp.owner_table_id) Email
    FROM oe_order_headers_all h
    WHERE h.order_number='102'
    Actually the problem i am facing is the inner select query is returning multiple row , so my main query is erroring out, i need to capture the multiple row.
    in the above example the inner decode statement returning two mail address, i need to capture that, but while executing the whole query it is erroring out as saying single query returns multiple values.
    please help me on this to capture multiple values
    Thanks

    >
    select order_number,
    (select decode(hcp.contact_point_purpose,'ABC',hcp.email_address,'CDE',hcp.email_address,null)
    from hz_contact_points,
    hz_parties hz
    WHERE hz.party_id=hcp.owner_table_id
    /* a join is missing here that points to table oe_order_headers_all h*/) Email
    FROM oe_order_headers_all h
    WHERE h.order_number='102'
    >
    I can see a join missing in your select sub query.
    However, if you you are still getting the single query return multiple value error then you need to replace the sql sub query
    select decode(hcp.contact_point_purpose,'ABC',hcp.email_address,'CDE',hcp.email_address,null)
    from hz_contact_points,
    hz_parties hz
    WHERE hz.party_id=hcp.owner_table_id)by decode(hcp.contact_point_purpose,'ABC',hcp.email_address,'CDE',hcp.email_address,null)
    and join the two tables in you main query..
    Regards
    Biju
    ED: Provide test script and your expected output to get what you want exacly!
    Edited by: biju2012 on Sep 7, 2012 12:06 AM

  • Returning multiple values from a table

    Hi there i am working on a bit of sql which will return values when they exist in a table.
    The code I have returns the correct value when there is only one entry in the tbl_studentmodules table, as soon as there is more than one entry in this table it displays no rows at all :(.
    Can anyone point out how I go about returning multiple values?
                 select modulename from tbl_modulefeedback
    where 1 = (select count(*) from tbl_studentmodules
           where upper(:APP_USER) = upper(student_id))
    and 1 = (select count(*) from tbl_modulefeedback, tbl_studentmodules
          where tbl_modulefeedback.modulecode = tbl_studentmodules.modulecode)Thanks in advance!
    Ashleigh

    I'm not quite sure I understand what you are looking for, but I think a simple join may be what you need. something like:
    select modulename
    from tbl_modulefeedback mfb
       join tbl_studentmodules sm
          on mfb.modulecode = sm.modulecode
    where upper(sm.student_id) = upper(:APP_USER)This will return the module name for all modules that the given student has provided feeedback for. If there is a possibility that a student/module combination could appear in tbl_studentmodules more than once, something like this might be better to show the modulename only once.
    select modulename
    from tbl_modulefeedback mfb
    where mfb.modulecode in (select sm.modulecode
                             from tbl_studentmodules sm
                             where mfb.modulecode = sm.modulecode and
                                   upper(sm.student_id) = upper(:APP_USER))If this is not what you want, then post some sample data (preferrable in the form of insert statements or a with clause) and the results you expect rom that sample data.
    John

  • Return multiple values from a function to a SELECT statement

    I hope I've provided enough information here. If not, just let me know what I'm missing.
    I am creating a view that will combine information from a few tables. Most of it is fairly straightforward, but there are a couple of columns in the view that I need to get by running a function within a package. Even this is fairly straightforward (I have a function named action_date in a package called rp, for instance, which I can use to return the date I need via SELECT rp.action_date(sequence_number).
    Here's the issue: I actually need to return several bits of information from the same record (not just action_date, but also action_office, action_value, etc.) - a join of the tables won't work here as I'll explain below. I can, of course, run a separate function for each statement but that is obviously inefficient. Within the confines of the view select statement however, I'm not sure how to return each of the values I need.
    For instance, right now, I have:
    Table1:
    sequence_number NUMBER(10),
    name VARCHAR(30),
    Table2:
    Table1_seq NUMBER(10),
    action_seq NUMBER(10),
    action_date DATE,
    action_office VARCHAR(3),
    action_value VARCHAR(60),
    I can't simply join Table1 and Table2 because I have to do some processing in order to determine which of the matching returned rows I actually need to select. So the package opens a cursor and processes each row until it finds the one that I need.
    The following works but is inefficient since all of the calls to the package will return columns from the same record. I just don't know how to return all the values I need into the SELECT statement.
    CREATE VIEW all_this_stuff AS
    SELECT sequence_number, name,
    rp.action_date(sequence_number) action_date,
    rp.action_office(sequence_number) action_office,
    rp.action_value(sequence_number) action_value
    FROM table1
    Is there a way to return multiple values into my SELECT statement or am I going about this all wrong?
    Any suggestions?
    Thanks so much!

    Hi,
    What you want is a Top-N Query , which you can do using the analytic ROW_NUMBER function in a sub-query, like this:
    WITH     got_rnum     AS
         SELECT     action_seq, action_dt, action_office, action_type, action_value
         ,     ROW_NUMBER () OVER ( ORDER BY  action_date
                                   ,            action_seq
                             ,            action_serial
                           ) AS rnum
         FROM     table2
         WHERE     action_code     = 'AB'
         AND     action_office     LIKE 'E'     -- Is this right?
    SELECT     action_seq, action_dt, action_office, action_type, action_value
    FROM     got_rnum
    WHERE     rnum     = 1
    ;As written, this will return (at most) one row.
    I suspect you'll really want to get one row for each group , where a group is defined by some value in a table to which you're joining.
    In that case, add a PARTITION BY clause to the ROW_NUMBER function.
    If you'd post a little sample data (CREATE TABLE and INSERT statements), I could show you exactly how.
    Since I don't have your tables, I'll show you using tables in the scott schema.
    Here's a view that has data from the scott.dept table and also from scott.emp, but only for the most senior employee in each department (that is, the employee with the earliest hiredate). If there happens to be a tie for the earliest hiredate, then the contender with the lowest empno is chosen.
    CREATE OR REPLACE VIEW     senior_emp
    AS
    WITH     got_rnum     AS
         SELECT     d.deptno
         ,     d.dname
         ,     e.empno
         ,     e.ename
         ,     e.hiredate
         ,     ROW_NUMBER () OVER ( PARTITION BY  d.deptno
                                   ORDER BY          e.hiredate
                             ,                e.empno
                           ) AS rnum
         FROM     scott.dept     d
         JOIN     scott.emp     e     ON     d.deptno     = e.deptno
    SELECT     deptno
    ,     dname
    ,     empno
    ,     ename
    ,     hiredate
    FROM     got_rnum
    WHERE     rnum     = 1
    SELECT     *
    FROM     senior_emp
    ;Output:
    .    DEPTNO DNAME               EMPNO ENAME      HIREDATE
            10 ACCOUNTING           7782 CLARK      09-JUN-81
            20 RESEARCH             7369 SMITH      17-DEC-80
            30 SALES                7499 ALLEN      20-FEB-81 
    By the way, one of the conditions in the query you posted was
    action_office     LIKE 'E'which is equivalent to
    action_office     = 'E'(LIKE is always equivalent to = if the string after LIKE doesn't contain any wildcards.)
    Did you mean to say that, or did you mean something like this:
    action_office     LIKE 'E%'instead?

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