Simple byte question

Question

Hi there! I have a class to implement some kind of byte manipulation, here it is:
class ParDecimal {
private byte bNum;
public ParDecimal() {
     this(0,0);
public ParDecimal(int firstDig){
     this(0,firstDig);
public ParDecimal(int firstDig, int secDig){
     byte bA = (byte)(firstDig << 4);
     byte bB = (byte)secDig;
     bNum = (byte)(bA+bB);
public int getFirstDig(){
     int Dig = (int)(bNum >> 4);
     return Dig;
public int getSecondDig(){
     return ???
public class Exemple1 {
public static void main (String[] args) {
ParDecimal pn = new ParDecimal(1,2);
System.out.println("First: " + pn.getFirstDig());
System.out.println("Second: " + pn.getSecondDig());
Well, My problem is to return the second digit. I'm really confused here. As you can see in this example my class transforms the 1,2 arguments into a byte 0001 = 1 + 0010 = 2; together 00010010 = 18. All I need now is to return only the second portion of the byte, the first one i used the >> 4 operator, but how to return the 2nd one?
Thanks

Answer 1

Well, it doesn't matter, but people won't be willing to help you out the next time if you don't reward them the dukes they earn. Someone's even started a black list.
The <<, >> and >>> are shift operators. Shifting 00010010 4 places to the left will not yield 0010, of course. The binary and will (0xF is hex F is 15):00010010
    1111
00000010But you're better off reading some tutorials (java.sun.com/docs/books/tutorial).
Kind regards,
Levi