Simple code?...I think?

Question

Please look at the code below. I am familiar with how the increment operators work, but can anyone explanin to me how in the world "t" ends up being 4.
public class TeSet {
     public static void main(String args[]) {
          int m = 2;
          int p = 1;
          int t = 0;
          for(;p < 5;p++) {
               if(t++ > m) {
                    m = p + t;
          System.out.println("t equals " + t);
}

Answer 1

Ok, here goes.
int m = 2;
int p = 1;
int t = 0;
for(;p < 5;p++) {    // p=1 through 4
if(t++ > m) {// executed 4 times
m = p + t;
}First run: m==2, p==1 and t==0, then we hit the if-statement. where we check to see if t(0) is greater then m(2) which is false, but t++ makes t==1. The "m=p+t;" is not run this time.
the last thing the for-loop does is p++, so now p==2
Second run: m==2, p==2 and t==1;
if-statement: Is t>m? Is 1 > 2? NO! but t++ makes t==2.
The "m=p+t;" not run.
the last thing the for-loop does is p++, so now p==3
Third run: m==2, p==3 and t==2;
if-statement: Is t>m? Is 2 > 2? NO! but t++ makes t==3.
The "m=p+t;" not run.
the last thing the for-loop does is p++, so now p==4
Third run: m==2, p==4 and t==3;
if-statement: Is t>m? Is 3 > 2? YES! still t++ makes t==4.
The "m=p+t;" IS run: so now m == 4+4 i.e. 8.
the last thing the for-loop does is p++, so now p==5
Fourth run: m==8, p==5 and t==4;
Now the for-loop statement "p < 5" i.e. "5 < 5" returns false so we skip the for-loop and continues down to the "System.out...." section and print the "t equals 4" bit.
As for m, it did not do any difference in this case...
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